[go: up one dir, main page]

login
Revision History for A091808 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing all changes.
Given the infinite continued fraction i+(i/(i+(i/(i+...)))), where i is the square root of (-1), this is the numerator of the imaginary part of the convergents.
(history; published version)
#8 by Peter Luschny at Wed Feb 27 09:13:10 EST 2019
STATUS

editing

approved

#7 by Peter Luschny at Wed Feb 27 09:13:08 EST 2019
EXTENSIONS

More terms by _from _Peter Luschny_, Feb 27 2019

STATUS

proposed

editing

#6 by Peter Luschny at Wed Feb 27 07:56:04 EST 2019
STATUS

editing

proposed

#5 by Peter Luschny at Wed Feb 27 07:55:46 EST 2019
DATA

1, 1, 3, 6, 4, 13, 53, 111, 231, 160, 1000, 13, 4329, 693, 2083, 39014, 81188, 84477, 351597, 243893, 1522639, 3168640, 6594000, 21441, 1359821, 59426081, 123666803, 19796382, 535556412, 61916837, 2319302053, 4826511631, 10044062391, 20901884640, 14499073000

MAPLE

A091808 := n -> numer(Im(numtheory[cfrac]([I, [I, I]$n-1]))):

seq(A091808(n), n=1..35); # Peter Luschny, Feb 27 2019

MATHEMATICA

GenerateA091808[1] := I; GenerateA091808[n_] := I + I/(GenerateA091808[n-1]); GenerateNumeratorsA091808[n_] := Table[Numerator[Im[GenerateA091808[x]]], {x, 1, n}]; (* GenerateNumeratorsA091808[20] would give the first 20 terms. *)

CROSSREFS
EXTENSIONS

More terms by Peter Luschny, Feb 27 2019

STATUS

approved

editing

#4 by Jon E. Schoenfield at Thu Dec 10 02:38:14 EST 2015
STATUS

editing

approved

#3 by Jon E. Schoenfield at Thu Dec 10 02:38:11 EST 2015
COMMENTS

The sequence of complex numbers (which this sequence is part of) converges to (i+sqrt(-1+4i))/2, found by simply solving the equation A = i + (i/A) for A using the quadratic formula. When plotted in the complex plane, these numbers form a counter-clockwise counterclockwise spiral that quickly converges to a point.

EXAMPLE

a(6) = 13 since the sixth convergent is (3/5) + (13/10)i and hence the numerator of the imaginary part is 13.

STATUS

approved

editing

#2 by N. J. A. Sloane at Sun Feb 20 03:00:00 EST 2005
CROSSREFS

Cf., A123457.

KEYWORD

cofr,frac,nonn,new

#1 by N. J. A. Sloane at Sat Jun 12 03:00:00 EDT 2004
NAME

Given the infinite continued fraction i+(i/(i+(i/(i+...)))), where i is the square root of (-1), this is the numerator of the imaginary part of the convergents.

DATA

1, 1, 3, 6, 4, 13, 53, 111, 231, 160, 1000, 13, 4329, 693, 2083, 39014, 81188, 84477, 351597

OFFSET

1,3

COMMENTS

The sequence of complex numbers (which this sequence is part of) converges to (i+sqrt(-1+4i))/2, found by simply solving the equation A=i+(i/A) for A using the quadratic formula. When plotted in the complex plane, these numbers form a counter-clockwise spiral that quickly converges to a point.

EXAMPLE

a(6)=13 since the sixth convergent is (3/5)+(13/10)i and hence the numerator of the imaginary part is 13.

MATHEMATICA

GenerateA091808[1] := I; GenerateA091808[n_] := I + I/(GenerateA091808[n-1]); GenerateNumeratorsA091808[n_] := Table[Numerator[Im[GenerateA091808[x]]], {x, 1, n}]; GenerateNumeratorsA091808[20] would give the first 20 terms.

CROSSREFS

Cf., A123457.

Cf. A091806-A091809.

KEYWORD

cofr,frac,nonn

AUTHOR

Ryan Witko (witko(AT)nyu.edu), Mar 06 2004

STATUS

approved