CN1638283A - Single crystal vibrator digital phase-locked loop device realizing E1T1 debouncing - Google Patents
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Abstract
本发明提供一种实现E1T1去抖动的单晶振数字锁相环装置,包括FIFO,读写指针比较电路,寄存器1,减法器,加法器,寄存器2,E1/T1分频电路;还包括E1/T1存储器,存储E1/T1基准值;E1/T1选择器,选择E1或T1的基准值输送给减法器。由于本发明只需采用一个晶振,E1T1采用同样的控制电路,既能对E1又能对T1去抖动,从而减少了芯片的容量,同时降低了成本。
The present invention provides a single crystal oscillator digital phase-locked loop device that realizes E1T1 dejittering, including FIFO, read and write pointer comparison circuit, register 1, subtractor, adder, register 2, E1/T1 frequency division circuit; also includes E1/T1 T1 memory stores the reference value of E1/T1; E1/T1 selector selects the reference value of E1 or T1 and sends it to the subtractor. Since the present invention only needs to use one crystal oscillator, E1T1 adopts the same control circuit, which can not only debounce E1 but also T1, thereby reducing the capacity of the chip and reducing the cost.
Description
技术领域technical field
本发明涉及光同步数字传输系统(简称SDH/SONET),具体的说,是涉及用于2M/1.5M PDH接口,实现E1T1去抖动的单晶振数字锁相环装置。The present invention relates to an optical synchronous digital transmission system (abbreviated as SDH/SONET), and specifically relates to a single-crystal oscillator digital phase-locked loop device for 2M/1.5M PDH interface to realize E1T1 dejittering.
背景技术Background technique
当VC4接收时,它被分解成63个TU12和84个TU11信号,要得到纯净荷2M/1.5M信号,必须去掉开销和塞入字节,同时在传输TU12/TU11中可能会带有指针调整,所以解映射后的2M/1.5M信号是有间隙的,如果直接输出至PDH端,会引起很大的抖动。G.783协议对2M/1.5M的PDH接口有抖动指标限制。映射片中采用的去抖动方法是去泄漏电路和数字锁相环(DPLL)结合。而当传输的信号中含有两种数据流时,需要对两种数据流进行去抖,通过检索发现很多专利都是对这两种数据流各采用一套去抖电路,并使用两个晶振,例如美国专利5289507如图3所示,采用44.736M的晶振。对于T1进行5次28,188次29分频,次数均匀分布在一帧内,根据FIFO深度进行增加或减少。美国专利5297180如图4所示采用58.32M的晶振,对于E1进行28/29分频,控制28/29分频是通过将17位常数减去FIFO深度的差进行加法运算,根据进位值来选择。两个专利这样对于E1/T1采用不同的晶振和不同的控制电路,这样路数比较多的芯片,会增加容量,同时因为有两个晶振,增加了成本。本发明是在原有美国专利5297180进行修改,让它既能应用于E1又能应用于T1。When VC4 receives it, it is decomposed into 63 TU12 and 84 TU11 signals. To get a pure 2M/1.5M signal, the overhead and stuffing bytes must be removed, and there may be pointer adjustments in the transmission TU12/TU11 , so the demapped 2M/1.5M signal has a gap, if it is directly output to the PDH end, it will cause a lot of jitter. The G.783 protocol has a jitter index limit for the 2M/1.5M PDH interface. The de-jittering method adopted in the mapping chip is a combination of de-leakage circuit and digital phase-locked loop (DPLL). When the transmitted signal contains two data streams, it is necessary to debounce the two data streams. Through searching, it is found that many patents use a set of debounce circuits for each of the two data streams, and use two crystal oscillators. For example, US Patent No. 5,289,507, as shown in Figure 3, uses a 44.736M crystal oscillator. For T1, 5 times of 28, 188 times of 29 frequency division, the times are evenly distributed in one frame, and increase or decrease according to the FIFO depth. US Patent 5297180 uses a 58.32M crystal oscillator as shown in Figure 4, and performs 28/29 frequency division for E1. The 28/29 frequency division is controlled by adding the difference between the 17-bit constant and the FIFO depth, and selecting according to the carry value. . The two patents use different crystal oscillators and different control circuits for E1/T1, so that the chip with more circuits will increase the capacity, and at the same time, because there are two crystal oscillators, the cost will be increased. The present invention is modified from the original US Patent No. 5,297,180, so that it can be applied to both E1 and T1.
发明内容Contents of the invention
本发明的目的在于提供只采用一个晶振,既能对E1又能对T1去抖的电路,从而减少了芯片的容量,同时降低了成本。The purpose of the present invention is to provide a circuit capable of de-jittering both E1 and T1 by using only one crystal oscillator, thereby reducing the chip capacity and cost.
为实现上述目的,本发明提出一种实现E1T1去抖动的单晶振数字锁相环装置,包括:In order to achieve the above object, the present invention proposes a single crystal oscillator digital phase-locked loop device that realizes E1T1 dejittering, including:
FIFO,存储输入数据,被输出时钟读出;FIFO, which stores input data and is read out by the output clock;
读写指针比较电路,E1/T1数据流作为写时钟,读时钟为58.32M晶振通过E1T1分频电路得出,读写指针相减得到读写速率差;Read and write pointer comparison circuit, the E1/T1 data stream is used as the write clock, the read clock is 58.32M crystal oscillator obtained through the E1T1 frequency division circuit, and the read and write pointers are subtracted to obtain the read and write rate difference;
寄存器1,存储读写指针比较电路所得到的值与E1T1分频电路余数;Register 1 stores the value obtained by the read-write pointer comparison circuit and the remainder of the E1T1 frequency division circuit;
减法器,通过选择器选择E1/T1基准值,减去寄存器1中的数据值;The subtractor selects the reference value of E1/T1 through the selector and subtracts the data value in
加法器,对减法器的差值进行加法计算;An adder, which adds and calculates the difference of the subtractor;
寄存器2,存储加法器给出的和数据;Register 2, which stores the sum data given by the adder;
E1/T1分频电路,对E1/T1信号进行分频;E1/T1 frequency division circuit, frequency division of E1/T1 signal;
还包括:Also includes:
E1/T1存储器,存储E1/T1基准值;E1/T1 memory, storing E1/T1 reference value;
E1/T1选择器,选择E1或T1的基准值输送给减法器。The E1/T1 selector selects the reference value of E1 or T1 and sends it to the subtractor.
由此,本发明的显著效果是只需采用一个晶振,E1T1采用同样的控制电路,从而减少了芯片的容量,同时降低了成本。Therefore, the remarkable effect of the present invention is that only one crystal oscillator is used, and the E1T1 uses the same control circuit, thereby reducing the capacity of the chip and reducing the cost at the same time.
附图说明Description of drawings
图1本发明实现E1T1去抖动的单晶振数字锁相环装置的电路框图;Fig. 1 the present invention realizes the circuit block diagram of the single crystal oscillator digital phase-locked loop device of E1T1 dejitter;
图2本发明E1T1分频流程图;Fig. 2 E1T1 frequency division flow chart of the present invention;
图3美国专利5289507的电路框图;The circuit block diagram of Fig. 3 US Patent No. 5,289,507;
图4美国专利5297180的电路框图。Fig. 4 is a circuit block diagram of US Patent 5,297,180.
具体实施方式Detailed ways
E1T1为慢速的数据流,为了保证输出时钟的均匀性,必须用一个高速时钟进行分频,本发明采用的是58.32M晶振。而输入速率与输出速率总会有偏差,为了保证数据流的正确,必须采用FIFO来吸收两边的差距,同时可以通过读写指针差来得知输入和输出数据流的偏差。并将之传递到分频电路中,调节分频的比例。通过给出E1、T1在58.32M晶振下的基准值与11BIT寄存器输入数据的差值,并对此差值在一个复帧时间每隔E1/T1周期循环相加,根据进位值来调节输出时钟的频率。下面详细介绍各电路。E1T1 is a slow data stream. In order to ensure the uniformity of the output clock, a high-speed clock must be used for frequency division. The present invention uses a 58.32M crystal oscillator. However, there will always be a deviation between the input rate and the output rate. In order to ensure the correctness of the data flow, FIFO must be used to absorb the gap between the two sides. At the same time, the deviation between the input and output data streams can be known through the difference between the read and write pointers. And pass it to the frequency division circuit to adjust the ratio of frequency division. By giving the difference between the reference value of E1 and T1 under the 58.32M crystal oscillator and the input data of the 11BIT register, and adding the difference every E1/T1 cycle in a multi-frame time, the output clock is adjusted according to the carry value Frequency of. Each circuit is described in detail below.
如图1,输入的LEAKDATA LEAKCLK为有抖动的E1T1数据和时钟信号,输出的RCLK为分频后的时钟,RDNRZ在RCLK的上升沿被读出。此锁相环电路就是跟踪输入的数据流,得到输出抖动在规定范围内的E1T1数据流。As shown in Figure 1, the input LEAKDATA LEAKCLK is the jittered E1T1 data and clock signal, the output RCLK is the frequency-divided clock, and RDNRZ is read on the rising edge of RCLK. This phase-locked loop circuit is to track the input data stream and obtain the E1T1 data stream whose output jitter is within the specified range.
图1中的电路1包含FIFO,读写指针计数,读写指针相减。FIFO深度可设置为96BITS,复位时设置为48BITS(0110,0000),选择96BITS是为了不让FIFO溢出,原专利5297180中的64BITS会导致FIFO溢出。
当写时钟快于读时钟时,FIFO深度大于48BITS,当写时钟慢于读时钟时,FIFO深度小于48BITS,此电路通过读写指针的差值得到输入和输出数据流速率的差距,并将差值送到11BIT寄存器中。写指针随着输入数据流的变化而增加,因为输出数据流是高频时钟分频得到,为了保证FIFO深度计算的正确性,用高速时钟来同步输入数据。When the write clock is faster than the read clock, the FIFO depth is greater than 48BITS. When the write clock is slower than the read clock, the FIFO depth is less than 48BITS. This circuit obtains the difference between the input and output data stream rates through the difference between the read and write pointers, and uses the difference The value is sent to the 11BIT register. The write pointer increases with the change of the input data stream, because the output data stream is obtained by frequency division of a high-frequency clock. In order to ensure the correctness of the FIFO depth calculation, a high-speed clock is used to synchronize the input data.
11BIT REGISTER高七位存储读写指针差值,低四位存储复帧到达时分频电路所计算的值。11BIT寄存器变化频率为一个复帧周期,即采样一个复帧周期内输入输出数据流速度差。The upper seven bits of 11BIT REGISTER store the difference between read and write pointers, and the lower four bits store the value calculated by the frequency division circuit when the multiframe arrives. The change frequency of the 11BIT register is a multiframe period, that is, the speed difference between the input and output data streams within a multiframe period is sampled.
18BITS减法器,被减数为一个固定值。E1为0111101_0110000_0000,T1为11000110_011000_1100。此基准值为要得到标准的E1、T1信号,即将58.32M晶振,分别进行28/29、37/38分频的比例值与FIFO深度为半满状态,分频电路的余数为0时相组合的数值。18BITS subtractor, the minuend is a fixed value. E1 is 0111101_0110000_0000, and T1 is 11000110_011000_1100. This reference value is to obtain the standard E1, T1 signal, that is, the 58.32M crystal oscillator, respectively, the proportion value of 28/29, 37/38 frequency division and the FIFO depth is half full, and the remainder of the frequency division circuit is 0. Phase combination value.
对于E1来说,要得到均匀的E1时钟,必须对58.32M进行28/29分频,而58.32/2.048=28.4765625。必须除以29占47.65625%,除以28占52.34375%。计算如下:58.32/(28*0.5234375+29*0.4765625)=2.048。0.4765625转化为二进制为0111101,0111101作为基准参数,0110000对应FIFO深度为半满的状态,即读写指针速率相等。当读写指针相等时,11BITS输入的数据为0110000_0000,相应18BITS减法器的差值为0111101_0000000_0000,此时除以29占47.65625%,除以28占52.34375当写时钟快于读时钟时,FIFO深度大于48BITS,18BITS减法器的差值小于上面的差值,相应要求读时钟加快,除以28的次数增多。For E1, to obtain a uniform E1 clock, 58.32M must be divided by 28/29, and 58.32/2.048=28.4765625. It must be divided by 29 for 47.65625%, and divided by 28 for 52.34375%. The calculation is as follows: 58.32/(28*0.5234375+29*0.4765625)=2.048. 0.4765625 converted into binary is 0111101, 0111101 is used as the benchmark parameter, 0110000 corresponds to the half-full state of the FIFO depth, that is, the reading and writing pointer rates are equal. When the read and write pointers are equal, the data input by 11BITS is 0110000_0000, and the difference of the corresponding 18BITS subtractor is 0111101_0000000_0000. At this time, dividing by 29 accounts for 47.65625%, and dividing by 28 accounts for 52.34375. When the write clock is faster than the read clock, the FIFO depth is greater than The difference between the 48BITS and 18BITS subtractors is smaller than the above difference, correspondingly, the reading clock is required to be accelerated, and the times of dividing by 28 are increased.
图1中的电路2完成上述工作。当写时钟慢于读时钟时,FIFO深度小于48BITS,18BITS减法器的差值大于上面的差值,相应要求读时钟减慢,除以29的次数增多。最低四位0000对应复帧到达时,分频电路刚好开始。这四位作为微调参数。The circuit 2 in Fig. 1 completes the above work. When the write clock is slower than the read clock, the FIFO depth is less than 48BITS, and the difference of the 18BITS subtractor is greater than the above difference, correspondingly requiring the read clock to slow down, and the number of times divided by 29 increases. When the lowest four
对于T1来说,要得到均匀的T1时钟,必须对58.32M进行37/38分频。而58.32/1.544=37.772020725388601036269430051813。可以看到尾数位比较多,但由于加法器最多只有18位(过多会增加容量)。可以计算一下采用18位后分频得到的数据流的速率。这18位二进制数为int(0.772020725388601036269430051813×218)=110001_01101000_1100。而这18位二进制数对应于0.7720184326171875。除以38为0.7720184326171875,除以37为0.2279815673828125。分频后的速率为58.32/(38*0.7720184326171875+37*0.2279815673828125)=1.5440000937212044。与1.544相差比较小。因此T1情况下的18位BITS数为110001_01101000_1100+0110000_0000=h’3198c。与E1一样,当读写指针相等时,11BITS输入的数据为0110000_0000,相应18BITS减法器的差值为110001_01101000_1100,此时除以38为0.7720184326171875,除以37为0.2279815673828125,当写时钟快于读时钟时,FIFO深度大于48BITS,18BITS减法器的差值小于上面的差值,相应要求读时钟加快,除以37的次数增多。图1中的电路2完成此工作。当写时钟慢于读时钟时,FIFO深度小于48BITS,18BITS减法器的差值大于上面的差值,相应要求读时钟减慢,除以38的次数增多。For T1, to get a uniform T1 clock, 58.32M must be divided by 37/38. And 58.32/1.544 = 37.772020725388601036269430051813. It can be seen that there are more mantissa bits, but since the adder only has 18 bits at most (too many will increase the capacity). You can calculate the rate of the data stream obtained by frequency division after 18 bits. The 18-bit binary number is int(0.772020725388601036269430051813×2 18 )=110001_01101000_1100. And this 18-bit binary number corresponds to 0.7720184326171875. Divided by 38 is 0.7720184326171875, divided by 37 is 0.2279815673828125. The rate after frequency division is 58.32/(38*0.7720184326171875+37*0.2279815673828125)=1.5440000937212044. The difference with 1.544 is relatively small. Therefore, the 18-bit BITS number in the case of T1 is 110001_01101000_1100+0110000_0000=h'3198c. Same as E1, when the read and write pointers are equal, the data input by 11BITS is 0110000_0000, and the difference of the corresponding 18BITS subtractor is 110001_01101000_1100. At this time, dividing by 38 is 0.7720184326171875, and dividing by 37 is 0.2279815673828125. When the write clock is faster than the read clock , the FIFO depth is greater than 48BITS, and the difference of the 18BITS subtractor is smaller than the above difference, correspondingly, the reading clock is required to be accelerated, and the number of times of dividing by 37 is increased. Circuit 2 in Figure 1 does this. When the write clock is slower than the read clock, the FIFO depth is less than 48BITS, and the difference of the 18BITS subtractor is greater than the above difference, correspondingly requiring the read clock to slow down, and the number of times divided by 38 increases.
图1中的电路2完成按比例的分频,由18BITS加法器和分频电路构成。18BITS加法器对送入的18BITS减法器的差按E1/T1的频率进行加法计算,和的值送入18BIT寄存器,进位值送到分频电路中,进位值为1时,对于E1来说,除以29,对于T1来说,除以38。当写时钟快于读时钟时,FIFO深度增加,11BITS寄存器值增加,18BITS减法器值减小,加法计算的进位为1的情况减少,对于E1来说,除以28的情况减少,除以27的情况增多,相应输出的写时钟速率加快。由于E1T1在18BITS加法器这部分功能一样,所以电路可共用。The circuit 2 in Fig. 1 completes the proportional frequency division, which is composed of 18BITS adder and frequency division circuit. The 18BITS adder adds and calculates the difference of the input 18BITS subtractor according to the frequency of E1/T1, and the value of the sum is sent to the 18BIT register, and the carry value is sent to the frequency division circuit. When the carry value is 1, for E1, Divide by 29, and for T1, divide by 38. When the write clock is faster than the read clock, the FIFO depth increases, the value of the 11BITS register increases, the value of the 18BITS subtractor decreases, and the case where the addition calculation is 1 is reduced. For E1, the case of dividing by 28 is reduced and divided by 27. As the number of cases increases, the write clock rate of the corresponding output increases. Since E1T1 has the same function in the 18BITS adder, the circuit can be shared.
分频电路根据18BITS加法器送的进位值,有选择地进行分频。E1最大计至29,T1最大计至38,它们的计数器部分可共用。为了保证输出时钟的占空比为50%,可按照图2进行设计,E1初始值设置为2,T1初始值设置为13,计数器为6位,E1的输出时钟为计数器第5位的输出,T1的输出时钟为计数器第6位的输出。对于E1,初始值为000010,计至16(1_0000),第5位发生跳变,输出读时钟为高,当计至30并且进位值为1时,计数器初始化为2,第5位再发生跳变,输出读时钟为低,从而输出占空比为50%的E1读时钟。对于T1,初始值为001101,计至32(100000),第6位发生跳变,输出读时钟为高,当计至50并且进位值为1时,计数器初始化为13,第6位再发生跳变,输出读时钟为低,从而输出占空比为50%的T1读时钟。The frequency division circuit selectively divides the frequency according to the carry value sent by the 18BITS adder. E1 counts up to 29, T1 counts up to 38, and their counters can be shared. In order to ensure that the duty cycle of the output clock is 50%, it can be designed according to Figure 2. The initial value of E1 is set to 2, the initial value of T1 is set to 13, the counter is 6 bits, and the output clock of E1 is the output of the 5th bit of the counter. The output clock of T1 is the output of the 6th bit of the counter. For E1, the initial value is 000010, count to 16 (1_0000), the 5th bit jumps, the output read clock is high, when the count reaches 30 and the carry value is 1, the counter is initialized to 2, and the 5th bit jumps again change, the output read clock is low, thus outputting the E1 read clock with a duty cycle of 50%. For T1, the initial value is 001101, counting to 32 (100000), the 6th bit jumps, the output read clock is high, when the count reaches 50 and the carry value is 1, the counter is initialized to 13, and the 6th bit jumps again change, the output read clock is low, thus outputting the T1 read clock with a duty cycle of 50%.
从上述可以看出,本发明中除了加入E1/T1存储器、E1/T1选择器外,其余电路均可共用,根据E1T1选择信号来选择E1、T1基准值,大大减少了芯片的容量。Can find out from above, except adding E1/T1 memory, E1/T1 selector among the present invention, all the other circuits can be shared, select E1, T1 reference value according to E1T1 selection signal, greatly reduced the capacity of chip.
Claims (9)
Priority Applications (1)
Application Number | Priority Date | Filing Date | Title |
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CNB031582036A CN1330095C (en) | 2003-04-14 | 2003-09-08 | Single crystal vibrator digital phase-locked loop device realizing E1T1 debouncing |
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Cited By (4)
Publication number | Priority date | Publication date | Assignee | Title |
---|---|---|---|---|
CN101009483B (en) * | 2006-01-27 | 2011-08-03 | 上海奇码数字信息有限公司 | Digital phase lock loop and its clock adjusting method |
CN102149012A (en) * | 2010-11-30 | 2011-08-10 | 广东星海数字家庭产业技术研究院有限公司 | Data statistical method of multi-compatible hardware drive of digital television |
CN103490841A (en) * | 2013-09-25 | 2014-01-01 | 科大智能(合肥)科技有限公司 | Clock recovery method based on distributed frame header in multi-path E1 multiplexing system |
WO2014194719A1 (en) | 2013-06-03 | 2014-12-11 | 中兴通讯股份有限公司 | Clock data recovery method and device for branch signal in sdh |
Family Cites Families (3)
Publication number | Priority date | Publication date | Assignee | Title |
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US5033064A (en) * | 1988-12-09 | 1991-07-16 | Transwitch Corporation | Clock dejitter circuit for regenerating DS1 signal |
US5297180A (en) * | 1989-11-17 | 1994-03-22 | Transwitch Corporation | Digital clock dejitter circuits for regenerating clock signals with minimal jitter |
JP3241079B2 (en) * | 1992-02-24 | 2001-12-25 | 株式会社日立製作所 | Digital phase locked loop |
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2003
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Cited By (4)
Publication number | Priority date | Publication date | Assignee | Title |
---|---|---|---|---|
CN101009483B (en) * | 2006-01-27 | 2011-08-03 | 上海奇码数字信息有限公司 | Digital phase lock loop and its clock adjusting method |
CN102149012A (en) * | 2010-11-30 | 2011-08-10 | 广东星海数字家庭产业技术研究院有限公司 | Data statistical method of multi-compatible hardware drive of digital television |
WO2014194719A1 (en) | 2013-06-03 | 2014-12-11 | 中兴通讯股份有限公司 | Clock data recovery method and device for branch signal in sdh |
CN103490841A (en) * | 2013-09-25 | 2014-01-01 | 科大智能(合肥)科技有限公司 | Clock recovery method based on distributed frame header in multi-path E1 multiplexing system |
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