CN101697290B - Compact lead twisting method - Google Patents

Abstract

The invention discloses a compact lead and a twisting method thereof. The lead comprises a plurality of conductors which are divided into three layers from the inside to the outside, wherein a first layer of conductor is positioned in the middle part of the lead, a second layer of conductor encircles the first layer of conductor, a third layer of conductor encircles the second layer of conductor, the three layers of conductors are twisted together and then extruded and coated by an insulating layer on the outer part so as to form the lead, and the radius of the first layer of conductor is same as that of the second layer of conductor; and the third layer of conductor comprises first conductors and second conductors, the numbers of the first conductors and the second conductors are same, the radius of the first conductors is greater than that of the second conductors and the first conductors and the second conductors are arranged at intervals. The twisting method is mainly used for determining the radiuses of the first conductors and the second conductors in the third layer of conductor through the relationship between the radius of the conductors and the twisting outside diameter of the lead and the relationship among the summation of cross section areas of various conductors and the nominal cross section area and the actual cross section area. The invention can reduce the twisting outside diameter of the lead and save the laying space.

Description

The compact lead stranding method

Technical field

The present invention relates to the electric power transfer lead, relating in particular to nominal cross is 95mm ²Lead.

Background technology

According to the requirement of standard GB/T 3956-1997 " conductor of cable " and IEC IEC60228-1978 " conductor of insulated cable ", be 95mm for nominal cross ²Lead at least by 19 stranded forming of conductor.Referring to Fig. 1, the conductor 1 that is 2.52mm with 19 diameters is an example, and these 19 conductors 1 are divided into three layers from inside to outside; Carry out strandedly with the stranded mode of 1+6+12, promptly ground floor is a conductor 1, and ground floor conductor 2 is positioned at the lead middle part; The second layer is a six roots of sensation conductor 1, and second layer conductor 3 is centered around ground floor conductor 2 peripheries, and the 3rd layer is 12 conductors 1; The 3rd layer of conductor 4 is centered around second layer conductor 3 peripheries; Three layers of conductor 1 twist together the outside, back and are extruded with insulating barrier 5, form a lead, and every conductor 1 diameter are identical.The stranded external diameter of above-mentioned lead is 12.60mm, and actual cross-section is 94.72mm ²

Summary of the invention

The object of the present invention is to provide a kind of compact lead stranding method, this lead can dwindle stranded external diameter, practices thrift and lays the space.

The present invention is achieved in that

A kind of compact lead comprises some conductors, and some conductors are divided into three layers from inside to outside; The ground floor conductor is positioned at the lead middle part; Second layer conductor is centered around the periphery of ground floor conductor, and the 3rd layer of conductor is centered around the periphery of second layer conductor, and three layers of conductor twist together the outside, back and are extruded with insulating barrier; Form a lead, and the conductor radius of first, second layer is identical; The 3rd layer of conductor in the said lead comprises first conductor and second conductor, and first conductor is identical with second number of conductors, and the radius of first conductor is greater than the radius of second conductor, and first, second conductor separation is arranged.

The said first conductor radius is greater than first, second layer conductor radius, and the second conductor radius is less than first, second layer conductor radius, and two adjacent conductors in first conductor and the second layer conductor are tangent.

Said lead comprises 19 conductors, and ground floor is a conductor, and the second layer is a six roots of sensation conductor, and the 3rd layer is 12 conductors.

A kind of stranding method of compact lead may further comprise the steps:

Step 1 is 95mm from existing nominal cross ², number of conductors is to choose seven conductors arbitrarily and be divided into two layers in 19 the lead; Wherein a conductor is arranged on the lead middle part as the ground floor conductor; Six roots of sensation conductor is centered around the periphery of ground floor conductor as second layer conductor; And these seven conductor radiuses are identical, and promptly these seven conductor radiuses are r;

Step 2; The 3rd layer of conductor is made up of 12 conductors; And the 3rd layer of conductor is centered around the periphery of second layer conductor, and the 3rd layer of conductor comprises first conductor and second conductor, and the first conductor radius is greater than first, second layer conductor radius; The second conductor radius is less than first, second layer conductor radius, and two adjacent conductors in first conductor and the second layer conductor are tangent;

Step 3, confirm the span of the first conductor radius a in the 3rd layer of conductor:

A) in second layer conductor, appoint and get two adjacent conductors, the center of circle of ground floor cross-sectional area of conductor and the center of circle in above-mentioned two adjacent conductor cross sections are linked to each other, the formation length of side is the equilateral triangle of 2r, and obtains the high h of this equilateral triangle ₁

B) with the center of circle in above-mentioned two adjacent conductor cross sections with link to each other with the first tangent cross-sectional area of conductor center of circle of these two adjacent conductors, the formation base is 2r, waist is long to be the isosceles triangle of r+a, and obtains in this isoceles triangle shape and the corresponding high h in base ₂

C) set up functional relation H (a)=2h ₁+ 2h ₂+ 2a, wherein H (a) is the stranded external diameter of lead, stranded external diameter H (a) is by 2h ₁, 2h ₂Addition obtains with 2a;

D) according to the stranded external diameter of compact lead stranded external diameter, obtain functional relation H (a)=2h less than existing lead ₁+ 2h ₂+ 2a＜12.60mm, wherein 12.60mm is the stranded external diameter of existing lead;

E) through above-mentioned functional relation H (a)=2h ₁+ 2h ₂+ 2a＜12.60mm obtains the maximum a of the first conductor radius a _Max

F) according to the first conductor radius greater than first, second layer conductor radius, obtain the minimum value a of the first conductor radius a _Min, i.e. a _Min＞r;

G) comprehensive above-mentioned E) and F) obtain the span of the first conductor radius a: r＜a＜a _Max

Step 4, confirm the span of the second conductor radius b in the 3rd layer of conductor:

A) this lead is that nominal cross is 95mm ²Lead, and the actual cross-section area of existing lead is 94.72mm ²,, set up following functional relation: 94.72mm according to the relation between each cross-sectional area of conductor area sum and nominal cross area, the actual cross-section area ²≤S=S ₁+ 6S ₂+ 6S _a+ 6S _b≤95mm ², wherein S is 19 cross-sectional area of conductor area sums, S ₁Be the area of section of single conductor in the ground floor conductor, S ₂Be the area of section of single conductor in the second layer conductor, and S ₂With S ₁Equate S _aBe the area of section of single first conductor in the 3rd layer of conductor, S _bIt is the area of section of single second conductor in the 3rd layer of conductor;

B) be r according to first, second layer conductor radius, the first conductor radius is a in the 3rd layer of conductor, and the second conductor radius is b in the 3rd layer of conductor, and through above-mentioned functional relation: 94.72mm ²≤S=S ₁+ 6S ₂+ 6S _a+ 6S _b≤95mm ², obtain the relational expression of a and b: 1/6 (94.72/ π-7r ²)≤a ²+ b ²≤1/6 (95/ π-7r ²);

C) in the span of above-mentioned steps three a, a is carried out value, when a gets maximum, obtain the span of b minimum value: b _Min1＜b _Min＜b _Min2When a minimalization, obtain the peaked span of b: b _Max1＜b _Max＜b _Max2Promptly obtain the span of the second conductor radius b: b _Min1＜b＜b _Max2

Step 5 is confirmed a value a in the span of above-mentioned steps three a ₁, and to select section radius for use be a ₁Conductor as first conductor in the 3rd layer of conductor;

Step 6 is according to a in the step 5 ₁Numerical value, and the functional relation through a in the step 4 and b: 1/6 (94.72/ π-7r ²)≤a ²+ b ²≤1/6 (95/ π-7r ²), calculate at a=a ₁Situation under, the span of b: b ₁'≤b≤b ₁", in the span of above-mentioned b, confirm a value b ₁, and to select section radius for use be b ₁Conductor as second conductor in the 3rd layer of conductor;

Step 7, after above-mentioned three layers of conductor were twisted together, the outside was extruded with insulating barrier, forms a lead.

The present invention is to be 95mm to existing nominal cross ²The improvement of lead under the constant situation of lead inner wire quantity, keeps first, second layer conductor radius r constant, and the radius of the 3rd layer of conductor is improved.

The 3rd layer of conductor comprises first conductor and second conductor, and first, second conductor separation is arranged, and two adjacent conductors in first conductor and the second layer conductor are tangent.The first conductor radius a is greater than first, second layer conductor radius r, so obtain the first conductor radius a minimum value greater than first, second layer conductor radius r.The first conductor radius a maximum can be according to the stranded external diameter function of lead: H (a)＜12.60mm obtains, and wherein H (a) is the stranded external diameter of conductor, and 12.60mm is 95mm for existing nominal cross ²The stranded external diameter of lead.

The span of the second conductor radius b is according to the functional relation between each cross-sectional area of conductor area sum and nominal cross area, the actual cross-section area: 94.72mm ²≤S=S ₁+ 6S ₂+ 6S _a+ 6S _b≤95mm ²Obtain, wherein S is 19 cross-sectional area of conductor area sums, S ₁Be the area of section of single conductor in the ground floor conductor, S ₂Be the area of section of single conductor in the second layer conductor, S _aBe the area of section of single first conductor in the 3rd layer of conductor, S _bBe the area of section of single second conductor in the 3rd layer of conductor, 95mm ²Be the nominal cross area of lead, 94.72mm ²Actual cross-section area for existing lead.

First, second conductor separation is arranged in the 3rd layer of conductor of the present invention, has dwindled the stranded external diameter of lead, lays the space thereby practiced thrift.Simultaneously,, therefore can reduce the material that is extruded in the conductor external insulation, reduce production cost because the stranded external diameter of lead diminishes.

Description of drawings

Fig. 1 is 95mm for existing nominal cross ²The conductor structure sketch map;

Fig. 2 is the structural representation of compact lead of the present invention.

Among the figure: 1 conductor, 2 ground floor conductors, 3 second layer conductors, 4 the 3rd layers of conductor, 41 first conductors, 42 second conductors, 5 insulating barriers.

Embodiment

Below in conjunction with accompanying drawing and specific embodiment the present invention is described further.

Referring to Fig. 2, a kind of compact lead comprises that 1, ten nine conductor 1 of 19 conductors is divided into three layers from inside to outside.Ground floor is a conductor 1, and ground floor conductor 2 is positioned at the lead middle part.The second layer is a six roots of sensation conductor 1, and second layer conductor 3 is centered around the periphery of ground floor conductor 2, and first, second layer conductor 2,3 radiuses are identical.The 3rd layer is the periphery that 1, the three layer of conductor 4 of 12 conductors is centered around second layer conductor 3.The 3rd layer of conductor 4 comprises that first conductor 41 is identical with second conductor, 42 quantity with second conductor, 42, the first conductors 41, is the six roots of sensation, and the radius of first conductor 41 is greater than the radius of second conductor 42, and first, second conductor 41,42 is spaced.In the present invention, first conductor, 41 radiuses are greater than the radius of first, second layer conductor 2,3, and second conductor, 42 radiuses are less than the radius of first, second layer conductor 2,3, and first conductor 41 is tangent with two adjacent conductors 1 in the second layer conductor 3.Three layers of conductor 1 twist together the outside, back and are extruded with insulating barrier 5, form a lead.

With the nominal cross is 95mm ², conductor 1 quantity is that 19 lead is an example.The stranding method of this lead may further comprise the steps:

Step 1 is 95mm from existing nominal cross ², conductor 1 quantity is to choose seven conductors 1 arbitrarily and be divided into two layers in 19 the lead; Wherein a conductor 1 is arranged on the lead middle part as ground floor conductor 2; Six roots of sensation conductor 1 is centered around the periphery of ground floor conductor 2 as second layer conductor 3; And these seven conductor 1 radiuses are identical, i.e. these seven conductor 1 radius r=1.26mm;

Step 2; The 3rd layer of conductor 4 is made up of 12 conductors 1; And the 3rd layer of conductor 4 is centered around the periphery of second layer conductor 3, and the 3rd layer of conductor 4 comprises that first conductor 41 and second conductor, 42, the first conductors, 41 radiuses are greater than first, second layer conductor 2,3 radiuses; Second conductor, 42 radiuses are less than first, second layer conductor 2,3 radiuses, and first conductor 41 is tangent with two adjacent conductors 1 in the second layer conductor 3;

Step 3, confirm the span of first conductor, 41 radius a in the 3rd layer of conductor 4:

A) in second layer conductor 3, appoint and get two adjacent conductors 1, the center of circle in ground floor conductor 2 cross sections and the center of circle in above-mentioned two adjacent conductor 1 cross sections are linked to each other, the formation length of side is the equilateral triangle of 2r=2.52mm, and obtains the height of equilateral triangle $h_{}$ ${}_1=\sqrt{3}\mathrm{Rmm};$

B) with the center of circle in above-mentioned two adjacent conductor 1 cross sections with link to each other with this two adjacent conductors, 1 tangent center of circle, first conductor, 41 cross section; The formation base is 2r=2.52mm; Waist is long to be the isosceles triangle of r+a (mm), and obtains in this isoceles triangle shape and the corresponding height in base $h_{}$ ${}_2=\sqrt{a^2+2\mathrm{Ar}}\left(\mathrm{Mm}\right);$

C) set up functional relation H (a)=2h ₁+ 2h ₂+ 2a, wherein H (a) is the stranded external diameter of lead, stranded external diameter H (a) is by 2h ₁, 2h ₂Addition obtains with 2a;

D) according to the stranded external diameter of compact lead stranded external diameter, obtain functional relation H (a)=2h less than existing lead ₁+ 2h ₂+ 2a＜12.60mm, wherein 12.60mm is the stranded external diameter of existing lead;

E) through above-mentioned functional relation H (a)=2h ₁+ 2h ₂+ 2a＜12.60mm, promptly $H_{\left(a\right)}=2\sqrt{3}r+2\sqrt{a^2+2\mathrm{Ar}}+2a<12.60\mathrm{Mm},$ Obtain the maximum a of first conductor, 41 radius a _Max＜1.58mm;

F) according to first conductor, 41 radiuses greater than first, second layer conductor 2,3 radiuses, obtain the minimum value a of first conductor, 41 radius a _Min, i.e. a _Min＞1.26mm;

G) comprehensive above-mentioned E) and F) obtain the span of first conductor, 41 radius a: 1.26mm＜a＜1.58mm;

Step 4, confirm the span of second conductor, 42 radius b in the 3rd layer of conductor 4:

A) this lead is that nominal cross is 95mm ²Lead, and the actual cross-section area of existing lead is 94.72mm ²,, set up following functional relation: 94.72mm according to the relation between each conductor 1 area of section sum and nominal cross area, the actual cross-section area ²≤S=S ₁+ 6S ₂+ 6S _a+ 6S _b≤95mm ², wherein S is 19 conductors, 1 area of section sums, S ₁Be the area of section of single conductor 1 in the ground floor conductor 2, S ₂Be the area of section of single conductor 1 in the second layer conductor 3, and S ₂With S ₁Equate S _aBe the area of section of single first conductor 41 in the 3rd layer of conductor 4, S _bIt is the area of section of single second conductor 42 in the 3rd layer of conductor 4;

B) be r=1.26mm according to first, second layer conductor 2,3 radiuses, first conductor, 41 radiuses are a in the 3rd layer of conductor 4, and second conductor, 42 radiuses are b in the 3rd layer of conductor 4, and through above-mentioned functional relation: 94.72mm ²≤S=S ₁+ 6S ₂+ 6S _a+ 6S _b≤95mm ², obtain the relational expression of a and b: 1/6 (94.72/ π-7r ²)≤a ²+ b ²≤1/6 (95/ π-7r ²);

C) in the span of above-mentioned steps three a, a is carried out value, when a gets maximum, obtain the span of b minimum value: b _Min1＜b _Min＜b _Min2, promptly when a=1.58mm, the span of b: 0.82mm＜b＜0.83mm; When a minimalization, obtain the peaked span of b: b _Max1＜b _Max＜b _Max2, promptly during a=1.26mm, the span of b: 1.259mm＜b＜1.260mm; Promptly obtain the span of second conductor, 42 radius b: 0.82mm＜b＜1.26mm;

Step 5 is confirmed a value a in the span of above-mentioned steps three a ₁=1.445mm, and to select section radius for use be that the conductor 1 of 1.445mm is as first conductor 41 in the 3rd layer of conductor 4;

Step 6 is according to a in the step 5 ₁=1.445mm, and the functional relation through a in the step 4 and b: 1/6 (94.72/ π-7r ²)≤a ²+ b ²≤1/6 (95/ π-7r ²), calculating under the situation of a=1.445mm, a value b is confirmed in the span of b: 1.04≤b≤1.050 in the span of above-mentioned b ₁=1.045mm, and to select section radius for use be that the conductor 1 of 1.045mm is as second conductor 42 in the 3rd layer of conductor 4;

Step 7, after above-mentioned three layers of conductor 1 were twisted together, the outside was extruded with insulating barrier 5, forms a lead.

The stranded external diameter of above-mentioned compact lead: $H_{\left(a\right)}=2\sqrt{3}r+2\sqrt{a^2+2\mathrm{Ar}}+2a=12.04\mathrm{Mm},$ Its actual cross-section: S=S ₁+ 6S ₂+ 6S _a+ 6S _b=94.81mm ²

The present invention is under the constant situation of lead inner wire 1 quantity, keeps first, second layer conductor 2,3 radiuses constant, and the radius of the 3rd layer of conductor 4 is improved.The present invention is mainly through the relation between conductor 1 radius and the stranded external diameter of lead; Relation between each conductor 1 area of section sum and nominal cross area, the actual cross-section area; Confirm the radius of first, second conductor 41,42 in the 3rd layer of conductor 4; Promptly first conductor, 41 diameters are 2.89mm, and second conductor, 42 diameters are 2.09mm.First, second conductor 41,42 is spaced, and the stranded external diameter that obtains lead is 12.04mm, and the actual cross-section area of lead is 94.81mm ², this stranded external diameter 12.04mm is less than the stranded external diameter 12.60mm of existing lead, this actual cross-section area 94.81mm ²Actual cross-section area 94.72mm greater than existing lead ²Thereby lead of the present invention has been practiced thrift and has been laid the space.Simultaneously,, therefore can reduce the material that is extruded in conductor 1 external insulation, reduce production cost because the stranded external diameter of lead diminishes.

Claims (1)

1. compact lead stranding method, it is characterized in that: said stranding method may further comprise the steps:

Step 1 is 95mm from existing nominal cross ², number of conductors is to choose seven conductors arbitrarily and be divided into two layers in 19 the lead; Wherein a conductor is arranged on the lead middle part as the ground floor conductor; Six roots of sensation conductor is centered around the periphery of ground floor conductor as second layer conductor; And these seven conductor radiuses are identical, and promptly these seven conductor radiuses are r;

Step 2; The 3rd layer of conductor is made up of 12 conductors; And the 3rd layer of conductor is centered around the periphery of second layer conductor, and the 3rd layer of conductor comprises first conductor and second conductor, and the first conductor radius is greater than first, second layer conductor radius; The second conductor radius is less than first, second layer conductor radius, and two adjacent conductors in first conductor and the second layer conductor are tangent;

Step 3, confirm the span of the first conductor radius a in the 3rd layer of conductor:

A) in second layer conductor, appoint and get two adjacent conductors, the center of circle of ground floor cross-sectional area of conductor and the center of circle in above-mentioned two adjacent conductor cross sections are linked to each other, the formation length of side is the equilateral triangle of 2r, and obtains the high h of this equilateral triangle ₁

B) with the center of circle in above-mentioned two adjacent conductor cross sections with link to each other with the first tangent cross-sectional area of conductor center of circle of these two adjacent conductors, the formation base is 2r, waist is long to be the isosceles triangle of r+a, and obtains in this isoceles triangle shape and the corresponding high h in base ₂

C) set up functional relation H (a)=2h ₁+ 2h ₂+ 2a, wherein H (a) is the stranded external diameter of lead, stranded external diameter H (a) is by 2h ₁, 2h ₂Addition obtains with 2a;

D) according to the stranded external diameter of compact lead stranded external diameter, obtain functional relation H (a)=2h less than existing lead ₁+ 2h ₂+ 2a＜12.60mm, wherein 12.60mm is the stranded external diameter of existing lead;

E) through above-mentioned functional relation H (a)=2h ₁+ 2h ₂+ 2a＜12.60mm obtains the maximum a of the first conductor radius a _Max

F) according to the first conductor radius greater than first, second layer conductor radius, obtain the minimum value a of the first conductor radius a _Min, i.e. a _Min＞r;

G) comprehensive above-mentioned E) and F) obtain the span of the first conductor radius a: r＜a＜a _Max

Step 4, confirm the span of the second conductor radius b in the 3rd layer of conductor:

A) this lead is that nominal cross is 95mm ²Lead, and the actual cross-section area of existing lead is 94.72mm ²,, set up following functional relation: 94.72mm according to the relation between each cross-sectional area of conductor area sum and nominal cross area, the actual cross-section area ²≤S=S ₁+ 6S ₂+ 6S _a+ 6S _b≤95mm ², wherein S is 19 cross-sectional area of conductor area sums, S ₁Be the area of section of single conductor in the ground floor conductor, S ₂Be the area of section of single conductor in the second layer conductor, and S ₂With S ₁Equate S _aBe the area of section of single first conductor in the 3rd layer of conductor, S _bIt is the area of section of single second conductor in the 3rd layer of conductor;

B) be r according to first, second layer conductor radius, the first conductor radius is a in the 3rd layer of conductor, and the second conductor radius is b in the 3rd layer of conductor, and through above-mentioned functional relation: 94.72mm ²≤S=S ₁+ 6S ₂+ 6S _a+ 6S _b≤95mm ², obtain the relational expression of a and b: 1/6 (94.72/ π-7r ²)≤a ²+ b ²≤1/6 (95/ π-7r ²);

C) in the span of above-mentioned steps three a, a is carried out value, when a gets maximum, obtain the span of b minimum value: b _Min1＜b _Min＜b _Min2When a minimalization, obtain the peaked span of b: b _Max1＜b _Max＜b _Max2Promptly obtain the span of the second conductor radius b: b _Min1＜b＜b _Max2

Step 5 is confirmed a value a in the span of above-mentioned steps three a ₁, and to select section radius for use be a ₁Conductor as first conductor in the 3rd layer of conductor;

Step 6 is according to a in the step 5 ₁Numerical value, and the functional relation through a in the step 4 and b: 1/6 (94.72/ π-7r ²)≤a ²+ b ²≤1/6 (95/ π-7r ²), calculate at a=a ₁Situation under, the span of b: b ₁'≤b≤b ₁", in the span of above-mentioned b, confirm a value b ₁, and to select section radius for use be b ₁Conductor as second conductor in the 3rd layer of conductor;

Step 7, after above-mentioned three layers of conductor were twisted together, the outside was extruded with insulating barrier, forms a lead.

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