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a(p^k) = p^(k-1) * mu(p-1)^2 for k = 1 or 2, and 0 for k > 2.
If p is an odd prime, a(2*p) = p + mu(2*p-1)^2. - Robert Israel, Apr 28 2020
a(p^k) = p^(k-1) * mu(p-1)^2 for k = 1 or 2, and 0 for k > 2.
If p is an odd prime, a(2*p) = p + mu(2*p-1)^2. - Robert Israel, Apr 28 2020
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If p is an odd prime, a(2*p) = p + mu(2*p-1)^2. - Robert Israel, Apr 28 2020
nonn,easy,new,look
Robert Israel, <a href="/A332696/b332696.txt">Table of n, a(n) for n = 1..10000</a>
f:= proc(n) uses numtheory;
convert(select(t-> issqrfree(t) and issqrfree(n/t) and issqrfree(n-t), divisors(n) minus {n}), `+`)
end proc:
map(f, [$1..100]); # Robert Israel, Apr 28 2020
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