The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A294070 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
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A294070

a(n) = (1/4)*(n^2 - 2*n)^2 + (9/4)*(n^2 - 2*n) + 6.
(history; published version)

#86 by Charles R Greathouse IV at Thu Sep 08 08:46:20 EDT 2022

PROG

(MAGMAMagma) [(n^2-3*n+6)*(n^2-n+4)/4: n in [1..40]]; // Vincenzo Librandi, Aug 30 2018

Discussion

Thu Sep 08

08:46

OEIS Server: https://oeis.org/edit/global/2944

#85 by Joerg Arndt at Sun Feb 17 08:42:33 EST 2019

STATUS

reviewed

approved

#84 by Michel Marcus at Sun Feb 17 06:14:50 EST 2019

STATUS

proposed

reviewed

#83 by Colin Barker at Sun Feb 17 06:13:10 EST 2019

STATUS

editing

proposed

#82 by Colin Barker at Sun Feb 17 06:12:50 EST 2019

LINKS

Colin Barker, <a href="/A294070/b294070.txt">Table of n, a(n) for n = 1..1000</a>

STATUS

approved

editing

#81 by Peter Luschny at Fri Feb 15 09:08:24 EST 2019

STATUS

editing

approved

#80 by Peter Luschny at Fri Feb 15 09:06:11 EST 2019

NAME

a(n) = A152948(1/4)*(n^2 - 2*n) ^2 + (9/4)* A152948(n+1^2 - 2*n) + 6.

FORMULA

a(n) = A152948(n) * A152948(n+1).

MAPLE

ab:=n->(n^2-3*n+6)/2: seq(ab(n)*ab(n+1), n=1..40); # Muniru A Asiru, Aug 16 2018

STATUS

reviewed

editing

Discussion

Fri Feb 15

09:08

Peter Luschny: Jan, I hope you like the new name which addresses Maximilians concern.  Muniru, 'a' is a reserved name.

#79 by Andrey Zabolotskiy at Fri Feb 15 07:30:32 EST 2019

STATUS

proposed

reviewed

#78 by Andrey Zabolotskiy at Fri Feb 15 07:29:48 EST 2019

STATUS

editing

proposed

Discussion

Fri Feb 15

07:30

Andrey Zabolotskiy: kvant.mccme.ru now works. The question about the name is not seen by me as a blocking issue; i.e., it can be fixed later, if needed. After some thought I agree that the given source justifies this sequence. Hence reviewing.

#77 by Andrey Zabolotskiy at Fri Feb 15 07:29:43 EST 2019

LINKS

SESC NSU Correspondence School, <a href="http://kvant.mccme.ru/pdf/2018/2018-07.pdf#page=44">First assignments for 2018/2019</a> (in Russian), Kvant, 2018, No. 7, p. 42, Mathematics section, 6th grade, exercise no. 2. "Calculate and show in a reduced fraction form the following fractionssum: 1/(2*3) + 2/(3*5) + 3/(5*8) + 4/(8*12) + 5/(12*17)."

STATUS

proposed

editing