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#27 by Bruno Berselli at Thu Mar 23 10:08:17 EDT 2017
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#26 by Giovanni Resta at Thu Mar 23 09:25:42 EDT 2017
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#25 by Robert Israel at Wed Mar 22 12:08:43 EDT 2017
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#24 by Robert Israel at Wed Mar 22 12:08:35 EDT 2017
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| MAPLE
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N:= 1000: # to get a(1) to a(N)
B[1]:= 1:
B[2]:= 1:
for n from 3 to N do
B[n]:= B[n-B[n-1]] + B[n-B[n-2]];
od:
seq(add(B[k+1-B[k]], k=1..n) mod n, n=1..N); # Robert Israel, Mar 22 2017
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proposed
editing
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#23 by Altug Alkan at Wed Mar 22 09:32:04 EDT 2017
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#22 by Altug Alkan at Wed Mar 22 09:28:50 EDT 2017
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| COMMENTS
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Sequence represents d(n, 1, 1) where d(n, i, j) = (Sum_{k=1..n} q(k+1j-q(k))) mod (n*i) where q(k) = A005185(k).
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#21 by Altug Alkan at Wed Mar 22 09:22:36 EDT 2017
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| COMMENTS
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Sequence represents d(n, 1) where d(n, i) = (Sum_{k=1..n} q(k+1-q(k))) mod (n*i) where q(k) = A005185(k).
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| STATUS
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proposed
editing
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#20 by Altug Alkan at Wed Mar 22 06:25:55 EDT 2017
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#19 by Altug Alkan at Wed Mar 22 06:16:49 EDT 2017
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| LINKS
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Robert Israel, <a href="/A284173/a284173_1.png">Illustration Of Residue Classes Modulo 8</a>
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proposed
editing
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Discussion
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| Wed Mar 22
| 06:25
| Altug Alkan: For your question, you understand correct, these are the form of indices. Thank you very much for your additions, best regards.
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#18 by Antti Karttunen at Wed Mar 22 05:17:12 EDT 2017
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Discussion
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| Wed Mar 22
| 06:11
| Altug Alkan: No, there was no something wrong. I was in the lecture and I took it editing mode in order to write message to you and add a Maple version. Thanks, best regards.
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