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Revision History for A233833 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
a(n) = 3*binomial(7*n+3, n)/(7*n+3).
(history; published version)
#24 by Charles R Greathouse IV at Thu Sep 08 08:46:06 EDT 2022
PROG

(MAGMAMagma) [3*Binomial(7*n+3, n)/(7*n+3): n in [0..30]];

Discussion
Thu Sep 08
08:46
OEIS Server: https://oeis.org/edit/global/2944
#23 by Alois P. Heinz at Fri May 13 19:25:59 EDT 2022
STATUS

proposed

approved

#22 by Michael De Vlieger at Fri May 13 18:35:13 EDT 2022
STATUS

editing

proposed

#21 by Michael De Vlieger at Fri May 13 18:35:12 EDT 2022
LINKS

Clemens Heuberger, Sarah J. Selkirk, and Stephan Wagner, <a href="https://arxiv.org/abs/2204.14023">Enumeration of Generalized Dyck Paths Based on the Height of Down-Steps Modulo k</a>, arXiv:2204.14023 [math.CO], 2022.

STATUS

approved

editing

#20 by Peter Luschny at Sat Sep 15 05:27:17 EDT 2018
STATUS

reviewed

approved

#19 by Joerg Arndt at Sat Sep 15 02:10:42 EDT 2018
STATUS

proposed

reviewed

#18 by Ilya Gutkovskiy at Fri Sep 14 16:07:32 EDT 2018
STATUS

editing

proposed

#17 by Ilya Gutkovskiy at Fri Sep 14 16:00:58 EDT 2018
NAME

a(n) = 3*binomial(7*n+3, n)/(7*n+3).

FORMULA

From Ilya Gutkovskiy, Sep 14 2018: (Start)

E.g.f.: 6F6(3/7,4/7,5/7,6/7,8/7,9/7; 2/3,5/6,1,7/6,4/3,3/2; 823543*x/46656).

a(n) ~ 7^(7*n+5/2)/(sqrt(Pi)*3^(6*n+5/2)*4^(3*n+2)*n^(3/2)). (End)

STATUS

approved

editing

#16 by Bruno Berselli at Fri Jan 10 04:13:23 EST 2014
STATUS

editing

approved

#15 by Bruno Berselli at Fri Jan 10 04:13:19 EST 2014
FORMULA

G.f. satisfies: B(x) = {1 + x*B(x)^(p/r)}^r, here where p=7, r=3.

STATUS

proposed

editing