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Revision History for A233316 (Underlined text is an addition; strikethrough text is a deletion.)

Showing entries 1-10 | older changes
A233316 a(n) = Numerator(binomial(n+2, 2)*Bernoulli(n, 1)) for n >= 0 and 0 for n < 0.
(history; published version)
#38 by Peter Luschny at Sat Aug 24 03:20:30 EDT 2019
STATUS

editing

approved

#37 by Peter Luschny at Sat Aug 24 03:20:24 EDT 2019
KEYWORD

sign,frac,tabl,changed,uned

STATUS

proposed

editing

#36 by Peter Luschny at Mon Aug 19 09:23:02 EDT 2019
STATUS

editing

proposed

Discussion
Mon Aug 19 09:28
Joerg Arndt: I'd remove all the comments, nothing makes sense in there.  But leaving this edit, this is making me dizzy...
Sat Aug 24 03:20
Peter Luschny: I can't do it either. I give it the keyword uned and let it disappear into the depths of the ocean again.
#35 by Peter Luschny at Mon Aug 19 09:19:48 EDT 2019
NAME

a(n) = Numerator(binomial(n+2, 2)*Bernoulli(n, 1) )) for n >= 0 and 0 for n < 0.

Discussion
Mon Aug 19 09:22
Peter Luschny: I suggest you cut that interleaved moonshine...
#34 by Peter Luschny at Mon Aug 19 09:19:26 EDT 2019
NAME

Numerators of 0, 0, followed by A000217(n)*A164555(n)/A027642(n).

a(n) = Numerator(binomial(n+2, 2)*Bernoulli(n, 1) for n >= 0 and 0 for n < 0.

COMMENTS

TheNumerators Offsetof could0, 0, followed beby 0.A000217(n)*A164555(n)/A027642(n).

STATUS

proposed

editing

#33 by Michel Marcus at Mon Aug 19 02:17:07 EDT 2019
STATUS

editing

proposed

#32 by Michel Marcus at Mon Aug 19 02:16:21 EDT 2019
COMMENTS

Br2(n) = 0, 0, 1, 3/2, 1, 0, -1/2, 0, 2/3, 0, -3/2, 0, 5, 0, -691/30, ...,, ..., second complementary Bernoulli numbers.

second complementary Bernoulli numbers.

STATUS

proposed

editing

Discussion
Mon Aug 19 02:17
Michel Marcus: bof
#31 by Jon E. Schoenfield at Sun Aug 18 15:26:51 EDT 2019
STATUS

editing

proposed

#30 by Jon E. Schoenfield at Sun Aug 18 15:22:09 EDT 2019
COMMENTS

Third fractional autosequence after (1) (Br0(n)=) ) = ) A164555/A027642 and (2) Br(n)=) = A229979/(c(n)=) = 1,1,1,2,1,6,...=,... = 1 interleaved with A006955 or 1 followed by A050932.Thanks; thanks to _Jean-François Alcover). _). Hence

Br2(n)=) = 0, 0, 1, 3/2, 1, 0, -1/2, 0, 2/3, 0, -3/2, 0, 5, 0, -691/30,...,, ...,

0, , 0, , 1, , 3/2, 1, , 0, -, -1/2,..., ...

0, , 1, , 1/2, -, -1/2, -1, -, -1/2, , 1/2,..., ...

1, -, -1/2, -1, -, -1/2, , 1/2, 1, , 1/6,..., ...

- -3/2, -, -1/2, , 1/2, 1, , 1/2, -, -5/6, -, -3/2,..., ...

1, , 1, , 1/2, -, -1/2, -, -4/3, -, -2/3, 2,..., ...

0, -, -1/2, -1, -, -5/6, , 2/3, , 8/3, , 4/3,..., ...

- -1/2, -, -1/2, , 1/6, , 3/2, 2, -, -4/3, -8,... ., ... .

First Bernoulli polynomials, i.e., for B(1)=-) = -1/2,, A196838/A196839,, with 0's instead of the spaces:

1, , 0, 0, 0, 0, , 0, , 0, , 0, 0,..., ...

- -1/2, , 1, 0, 0, 0, , 0, , 0, , 0, 0,..., ...

1/6, -, -1, 1, 0, 0, , 0, , 0, , 0, 0,..., ...

0, , 1/2, -3/2, , 1, 0, , 0, , 0, , 0, 0,..., ...

- -1/30, , 0, 1, -2, 1, , 0, , 0, , 0, 0,..., ...

0, -, -1/6, , 0, , 5/3, -5/2, 1, , 0, , 0, 0,..., ...

1/42, , 0, -, -1/2, , 0, , 5/2, -3, , 1, , 0, 0,..., ...

0, , 1/6, , 0, -, -7/6, , 0, , 0, -7/2, 1, 0,..., ...

- -1/30, , 0, , 2/3, , 0. -, -7/3, 0, 14/3, -4, 10,... ., ... .

Second column: A229979/c(n) with -1 instead of 1, first column in A229979.

Third column: Br2(n) with -3/2 instead of 3/2, first column of the first array ..

1, 1, 1, 1, 1, 1, 1, 1, 1, 1,..., ...

0, 1, 2, 3, 4, 5, 6, 7, 8, 9,... =, ... = A001477,

0, 0, 1, 3, 6, 10, 15, 21, 28, 36,..., ...

0, 0, 0, 1, 4, 10, 20, 35, 56, 84,... . , ... . See A052553.

(Br0(n),), Br(n),), Br2(n),), Br3(n),... ), ... lead to A193815)..)

EXAMPLE

a(2)=1*1=1, a(3)=3*1/2, a(4)=6/6=1, a(5)=10*0=0, a(6)=-15/30=-1/2.

a(2) = 1*1 = 1,

a(3) = 3*1/2 = 3/2,

a(4) = 6/6 = 1,

a(5) = 10*0 = 0,

a(6) = -15/30 = -1/2.

STATUS

approved

editing

Discussion
Sun Aug 18 15:26
Jon E. Schoenfield: I tried to improve the readability.

The parenthesization (I don't think I messed it up, but I could've misunderstood something) of the following sentence seems strange to me:

Third fractional autosequence after (1) (Br0(n) = ) A164555/A027642 and (2) Br(n) = A229979/(c(n) = 1,1,1,2,1,6,... = 1 interleaved with A006955 or 1 followed by A050932; thanks to _Jean-François Alcover_). 

-- specifically, the part

Br(n) = A229979/(c(n) = 1,1,1,2,1,6,... = 1 interleaved with A006955 or 1 followed by A050932; thanks to _Jean-François Alcover_) 

... might it be better to rearrange that part as something like the following?

Br(n) = A229979/c(n), where {c(n)} = 1,1,1,2,1,6,... = 1 interleaved with A006955 or 1 followed by A050932; thanks to _Jean-François Alcover_
#29 by Alois P. Heinz at Tue Jul 15 20:55:15 EDT 2014
STATUS

editing

approved

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Last modified August 30 09:19 EDT 2024. Contains 375532 sequences. (Running on oeis4.)