Revision History for A231409
(Underlined text is an addition;
strikethrough text is a deletion.)
Showing entries 1-10
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#11 by Bruno Berselli at Mon Dec 02 10:33:36 EST 2013
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#10 by Jonathan Sondow at Sun Dec 01 11:56:19 EST 2013
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#9 by Jonathan Sondow at Sun Dec 01 11:56:15 EST 2013
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| LINKS
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Jose María J. M. Grau, A. M. Oller-Marcen, and J. Sondow, <a href="http://arxiv.org/abs/1309.7941">On the congruence 1^m + 2^m + ... + m^m == n (mod m) with n|m</a>, arXiv:1309.7941 [math.NT].
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| FORMULA
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a(2) = A229303(1), a(3) = A229302(1), a(4) = A229301(1), a(5) = A229300, a(6) = A229312(1).
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| EXAMPLE
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1^m + 2^m + ... + m^m == 1 (mod m) for the first 5 terms m = 1, 2, 6, 42, 1806 of A230311, so a(n) = 1 for n <= 5.
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| CROSSREFS
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Cf. A031971, A229300, A229301, A229302, A229303, A230311.
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| STATUS
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approved
editing
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#8 by Bruno Berselli at Sun Dec 01 09:18:04 EST 2013
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#7 by Joerg Arndt at Sun Dec 01 09:09:39 EST 2013
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#6 by Joerg Arndt at Sun Dec 01 09:09:35 EST 2013
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| LINKS
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Jose María Grau, A. M. Oller-Marcen, and J. Sondow, <a href="http://arxiv.org/abs/1309.7941">On the congruence 1^m + 2^m + ... + m^m == n (mod m) with n|m</a>, arXiv 2013:1309.7941 [math.NT].
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proposed
editing
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#5 by Michel Marcus at Sat Nov 30 16:03:55 EST 2013
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#4 by Michel Marcus at Sat Nov 30 16:03:45 EST 2013
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| NAME
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Least k with 1^(k*m) + 2^(k*m) + ... + (k*m)^(k*m) == k (mod k*m) for m in A230311.
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proposed
editing
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#3 by Jonathan Sondow at Sat Nov 30 14:37:31 EST 2013
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#2 by Jonathan Sondow at Sat Nov 30 14:37:27 EST 2013
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| NAME
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allocatedLeast k with 1^(k*m) + 2^(k*m) + ... + (k*m)^(k*m) == k (mod k*m) for Jonathanm Sondowin A230311.
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| DATA
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1, 1, 1, 1, 1, 5, 5, 39607528021345872635
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| OFFSET
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1,6
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| COMMENTS
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Least k with A031971(k*m) == k (mod k*m) for m in A230311.
See A031971 and A230311 for more comments and crossrefs.
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| LINKS
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Jose María Grau, A. M. Oller-Marcen, and J. Sondow, <a href="http://arxiv.org/abs/1309.7941">On the congruence 1^m + 2^m + ... + m^m == n (mod m) with n|m</a>, arXiv 2013.
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| EXAMPLE
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1^m + 2^m + ... + m^m == 1 (mod m) for the first 5 terms 1, 2, 6, 42, 1806 of A230311, so a(n) = 1 for n <= 5.
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| CROSSREFS
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Cf. A031971, A230311.
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| KEYWORD
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allocated
nonn,more,hard
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| AUTHOR
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Jonathan Sondow, Nov 30 2013
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| STATUS
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approved
editing
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