OFFSET
1,6
COMMENTS
LINKS
Jose MarĂa Grau, A. M. Oller-Marcen, and J. Sondow, On the congruence 1^m + 2^m + ... + m^m == n (mod m) with n|m, arXiv:1309.7941 [math.NT].
EXAMPLE
1^m + 2^m + ... + m^m == 1 (mod m) for the first 5 terms 1, 2, 6, 42, 1806 of A230311, so a(n) = 1 for n <= 5.
CROSSREFS
KEYWORD
nonn,more,hard
AUTHOR
Jonathan Sondow, Nov 30 2013
STATUS
editing