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a(n) = hypergeom([-n/3, (1 - n)/3, (2 - n)/3], [], -9/2). - Peter Luschny, Jun 04 2021
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Column k=3 of A275422.
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Alois P. Heinz, <a href="/A190865/b190865.txt">Table of n, a(n) for n = 0..666</a>
a:= proc(n) option remember; `if`(n=0, 1, add(
`if`(j>n, 0, a(n-j)*binomial(n-1, j-1)), j=[1, 3]))
end:
seq(a(n), n=0..30); # Alois P. Heinz, Jul 27 2016
1, 1, 1, 2, 5, 11, 31, 106, 337, 1205, 5021, 20186, 86461, 417847, 1992355, 9860306, 53734241, 292816841, 1633818457, 9855157330, 59926837141, 370352343971, 2439935383271, 16283034762842, 109982177787505, 783404343570301, 5668314772422901, 41412522553362026
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