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a(n) = 2^n * Sum_{ k=0..n } binomial(2*k,k)^3 / 2^k.
a(n) = 2^n * Sum[ Binomial[_{k=0..n} binomial(2*k,k])^3 / 2^k, {k,0,n} ].
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Table[2^n Sum[Binomial[2k, k]^3/2^k, {k, 0, n}], {n, 0, 30}] (* _Vincenzo Librandi, _, Mar 26 2012 *)
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Recurrence: n^3*a(n) = 2*(33*n^3 - 48*n^2 + 24*n - 4)*a(n-1) - 16*(2*n-1)^3*a(n-2). - Vaclav Kotesovec, Aug 13 2013
a(n) ~ 2^(6*n+5)/(31*(Pi*n)^(3/2)). - Vaclav Kotesovec, Aug 13 2013
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_Alexander Adamchuk (alex(AT)kolmogorov.com), _, Nov 14 2009
More terms from _Sean A. Irvine (sairvin(AT)xtra.co.nz), _, Apr 27 2010