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a(n) = Sum_{k=0..n} |Stirling1(n,k)|*k^2. - Peter Luschny, Jan 14 2020
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# Alternatively after Reshetnikov:
a := n -> n!*(add(1/k, k=1..n)^2 + add(1/k-1/k^2, k=1..n)):
seq(a(n), n=1..19); # Peter Luschny, Oct 21 2015
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N. J. A. Sloane and Alois P. Heinz, <a href="/A151881/b151881_1.txt">Table of n, a(n) for n = 1..450</a> (first 30 terms from N. J. A. Sloane)
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N. J. A. Sloane, and Alois P. Heinz, <a href="/A151881/b151881_1.txt">Table of n, a(n) for n = 1..450</a> (first 30</a> terms from N. J. A. Sloane)
a(n) = (-1)^(n+1)*(Stirling1(n+1,2)-2*Stirling1(n+1,3)). [_- _Vladeta Jovovic_, Jul 22 2009]
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