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a(n) = A103762(n+1) - 1 = A136617(n+1) + n - 1 for n > 0. - Jinyuan Wang, Mar 06 2020
a(n) = floor( e*n + (e-1)/2 + (e - 1/e)/(24*(n + 1/2))), after a suggestion by David Cantrell.
a(n) = floor(e*n+(e-1)/2+(e-1/e)/(24*n+12)); \\ _Jinyuan Wang_, Mar 06 2020
a(n) = a(n) = floor(e*n+(e-1)/2+(e-1/e)/(24*n+12)); \\
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a(n) = largest m with H(m) - H(n) <= 1, where H(i) = sumSum_{j=1 to i} 1/j, the i-th harmonic number, H(0) = 0.
a(n) = A103762(n+1) - 1 = A136617(n+1) + n - 1 for n > 0. - Jinyuan Wang, Mar 06 2020
a(3) = 9 because H(9) - H(3) = 1/4 + ... + 1/9 < 1 < 1/4 + ... + 1/10 = H(10) - H(3).
(PARI) default(realprecision, 10^5); e=exp(1);
a(n) = a(n) = floor(e*n+(e-1)/2+(e-1/e)/(24*n+12)); \\
easy,nonn
nonn,easy
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