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Absolute value of coefficient of X^2 in the characteristic polynomial of the n-th power of the matrix M = {{1,1,1,1,1}, {1,0,0,0,0}, {0,1,0,0,0}, {0,0,1,0,0}, {0,0,0,1,0}}.
(history; published version)
#23 by Charles R Greathouse IV at Thu Sep 08 08:45:28 EDT 2022
PROG

(MAGMAMagma) R<x>:=PowerSeriesRing(Integers(), 40); Coefficients(R!( x*(1 +3*x^2 -4*x^3 +30*x^4 -18*x^5 -21*x^6 -16*x^7 -9*x^8 -10*x^9)/(1 -x -x^3 +x^4 -6*x^5 +3*x^6 +3*x^7 +2*x^8 +x^9 +x^10) )); // G. C. Greubel, Aug 03 2021

Discussion
Thu Sep 08
08:45
OEIS Server: https://oeis.org/edit/global/2944
#22 by Michel Marcus at Tue Aug 03 02:26:41 EDT 2021
STATUS

reviewed

approved

#21 by Joerg Arndt at Tue Aug 03 02:03:02 EDT 2021
STATUS

proposed

reviewed

#20 by Joerg Arndt at Tue Aug 03 02:02:48 EDT 2021
STATUS

editing

proposed

#19 by Joerg Arndt at Tue Aug 03 02:02:40 EDT 2021
COMMENTS

Let P(x) = X^5 - X^4 - X^3 - X^2 - X - 1 and X1, X2, X3, X4, X5 its roots. Then a(n) = (X1*X2*X3)^n + (X1* X2*X4)^n + (X1*X2*X5)^n + ... + (X3*X4*X5)^n.

EXAMPLE

a(5) = 31 because the characteristic polynomial of M^5 is X^5 - 31*X^4 + 49*X^3 - 31*X^2 + 9*X - 1.

#18 by Joerg Arndt at Tue Aug 03 02:01:47 EDT 2021
COMMENTS

Sum of successive powers of all combinations of products of three different roots of the quintic pentanacci polynomial: Let P(x) = X^5 - X^4 - X^3 - X^2 - X - 1. Let the roots of the pentanacci polynomial be and X1, X2, X3, X4, X5 then its roots. Then a(n) = (X1*X2*X3)^n + (X1* X2*X4)^n + (X1*X2*X5)^n + ... + (X3*X4*X5)^n.

EXAMPLE

a(5) = 31 because characteristic polynomial fifth power of pentanacci matrix M^5 is X^5 - 31*X^4 + 49*X^3 - 31*X^2 + 9*X - 1.

STATUS

proposed

editing

#17 by G. C. Greubel at Tue Aug 03 00:27:44 EDT 2021
STATUS

editing

proposed

Discussion
Tue Aug 03
00:31
Michel Marcus: please see A176153
#16 by G. C. Greubel at Tue Aug 03 00:27:40 EDT 2021
FORMULA

x*(1 +3*x^2 -4*x^3 +30*x^4 -18*x^5 -21*x^6 -16*x^7 -9*x^8 -10*x^9)/(1 -x -x^3 +x^4 -6*x^5 +3*x^6 +3*x^7 +2*x^8 +x^9 +x^10)

#15 by G. C. Greubel at Tue Aug 03 00:26:40 EDT 2021
NAME

Absolute value of coefficient of X^2 in the characteristic polynomial of the n-th power of the matrix M = {{1,1,1,1,1}, {1,0,0,0,0}, {0,1,0,0,0}, {0,0,1,0,0}, {0,0,0,1,0}}.

COMMENTS

Also sum Sum of successive powers of all combinations of product products of three different roots of the quintic pentanacci polynomial : X^5 - X^4 - X^3 - X^2 - X - 1 . Let the roots are of the pentanacci polynomial be X1, X2, X3, X4, X5 then a(n) = (X1 *X2 *X3)^n + (X1 * X2 *X4)^n + (X1 *X2 *X5)^n + ... + (X3 X4 X5)^n A074048 are opposite coefficients by X^4 of characteristic polynomials successive powers of pentanacci matrix or successive powers of sums all roots (X1)^n+(X2)^n+(X3)^n+(*X4)^n+(*X5)^n.

LINKS

G. C. Greubel, <a href="/A123126/b123126.txt">Table of n, a(n) for n = 1..1000</a>

FORMULA

G.f.: -x*(10*x^9 1 +93*x^8 +162 -4*x^7 3 +2130*x^6 +4 -18*x^5 -3021*x^4 +46 -16*x^3 7 -39*x^2 8 -1) / (x^10 +*x^9 +2*)/(1 -x -x^8 +3 +x^4 -6*x^7 5 +3*x^6 -6+3*x^5 7 +2*x^4 -8 +x^3 -9 +x +1^10). - Colin Barker, May 16 2013

x*(1 +3*x^2 -4*x^3 +30*x^4 -18*x^5 -21*x^6 -16*x^7 -9*x^8 -10*x^9)/(1 -x -x^3 +x^4 -6*x^5 +3*x^6 +3*x^7 +2*x^8 +x^9 +x^10)

EXAMPLE

a(5) = 31 because characteristic polynomial fifth power of pentanacci matrix M^5 is X^5 - 31X31*X^4 + 49X49*X^3 - 31X31*X^2 + 9X 9*X - 1.

MATHEMATICA

f[n_] := CoefficientList[ CharacteristicPolynomial[ MatrixPower[{{1, 1, 1, 1, 1}, {1, 0, 0, 0, 0}, {0, 1, 0, 0, 0}, {0, 0, 1, 0, 0}, {0, 0, 0, 1, 0}}, n], x], x][[3]]; Array[f, 40] (* Robert G. Wilson v *)

PROG

(MAGMA) R<x>:=PowerSeriesRing(Integers(), 40); Coefficients(R!( x*(1 +3*x^2 -4*x^3 +30*x^4 -18*x^5 -21*x^6 -16*x^7 -9*x^8 -10*x^9)/(1 -x -x^3 +x^4 -6*x^5 +3*x^6 +3*x^7 +2*x^8 +x^9 +x^10) )); // G. C. Greubel, Aug 03 2021

(Sage)

def A123126_list(prec):

P.<x> = PowerSeriesRing(ZZ, prec)

return P( x*(1 +3*x^2 -4*x^3 +30*x^4 -18*x^5 -21*x^6 -16*x^7 -9*x^8 -10*x^9)/(1 -x -x^3 +x^4 -6*x^5 +3*x^6 +3*x^7 +2*x^8 +x^9 +x^10) ).list()

a=A123126_list(40); a[1:] # G. C. Greubel, Aug 03 2021

STATUS

approved

editing

#14 by Jon E. Schoenfield at Fri Mar 20 18:25:26 EDT 2015
STATUS

editing

approved