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(Python)
from sympy import primefactors, prime, primepi, integer_nthroot
def A085818(n): return 1 if n==1 else (f[0] if len(f:=primefactors(n))==1 and f[0]<n else prime(n-1-sum(primepi(integer_nthroot(n, k)[0]) for k in range(2, n.bit_length())))) # Chai Wah Wu, Aug 20 2024
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Michel Marcus, <a href="/A085818/b085818.txt">Table of n, a(n) for n = 1..10000</a>
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For n > 1: a(n) = p if (n = p^e with p prime and e > 1, otherwise a(n) then p else = (n-m)-th prime, where m = number of nonprime prime powers <= n; a(1)=1.
a(n) = A025473(n) if (n = p^e with p prime and e > 1) then A025473, otherwise a(n) else = A008578(n-A085501(n));
n divides A085819(n) =Prod(a(k): Product_{k<=n} a(k), as by construction: a(1)=1; if n divides A085819(n-1) then a(n) = smallest prime not occurring earlier; if n does not divide A085819(n-1) then a(n) = greatest prime factor of n (A006530);
a(A085971(n))=A000040(n) and for all k > 1: a(A000040(n)^k)=A000040(n); A085985(n)=A049084(a(n)). - Reinhard Zumkeller, Jul 06 2003
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