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#23 by Michael De Vlieger at Sun Nov 26 08:37:15 EST 2023
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#22 by Joerg Arndt at Sun Nov 26 06:35:32 EST 2023
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#21 by Jianing Song at Sun Nov 26 05:57:51 EST 2023
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#20 by Jianing Song at Sun Nov 26 05:57:42 EST 2023
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We have 1.66053906610*10^(-27) kg <= 1 u <= 1.66053906710*10^(-27) kg. Multiplying this by the Avogadro constant (A322578) we get 0.0009999999993533... kg/mol <= (1 u)*N_A <= 0.0009999999999555... kg/mol. In other words, 1 u is strictly less than (but very close to) (0.001 kg/mol)/N_A after the redefinition of SI units in 2019. (End)
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proposed
editing
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#19 by Jianing Song at Sun Nov 26 05:57:03 EST 2023
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#18 by Jianing Song at Sun Nov 26 05:57:00 EST 2023
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Cf. A081813 (atomic mass constant in MeV/c^2).
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proposed
editing
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#17 by Jianing Song at Sun Nov 26 05:51:19 EST 2023
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#16 by Jianing Song at Sun Nov 26 05:51:15 EST 2023
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We have 1.66053906610*10^(-27) kg <= 1 u <= 1.66053906710*10^(-27) kg. Multiplying this by the Avogadro constant (A322578) we get 0.0009999999993533... kg/mol <= (1 u)*N_A <= 0.0009999999999555... kg/mol. In other words, 1 u is strictly less than (0.001 kg/mol)/N_A after the redefinition of SI units in 2019. (End)
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#15 by Jianing Song at Sun Nov 26 05:50:45 EST 2023
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From Jianing Song, Nov 26 2023: (Start)
The atomic mass constant (with symbol Da or u) is defined as 1/12 of the mass of an unbound neutral atom of carbon-12 in its nuclear and electronic ground state and at rest.
We have 1.66053906610*10^(-27) kg <= 1 u <= 1.66053906710*10^(-27) kg. Multiplying this by the Avogadro constant we get 0.0009999999993533... kg/mol <= (1 u)*N_A <= 0.0009999999999555... kg/mol. In other words, 1 u is strictly less than (0.001 kg/mol)/N_A after the redefinition of SI units in 2019. (End)
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approved
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#14 by Peter Luschny at Thu Jan 21 05:44:14 EST 2021
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