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k=1: (1/3, 2/3);
k=2: (1/9, 2/9), (7/9, 8/9);
k=1: (1/3, 2/3); k=2: (1/9, 2/9), (7/9, 8/9); k=3: (1/27, 2/27), (7/27, 8/27), (19/27, 20/27), (25/27, 26/27); ...
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Let g(n) = Sum_{i=0..n} (i*binomial(n+i,i)^3*binomial(n,i)^2) = A112035(n). Let b = {m>0 : g(m) != 0 (mod 3)}. Then b(n) = a(n). - Mohammed Bouayoun (bouyao(AT)wanadoo.fr), Mar 08 2004
R. Ralf Stephan, <a href="/somedcgf.html">Some divide-and-conquer sequences ...</a>
R. Ralf Stephan, <a href="/A079944/a079944.ps">Table of generating functions</a>