Conjecture: a(n) = Sum_{k=1..n} A010051(2*k/gcd(n, k)). - Velin Yanev, Jun 20 2024
easy,core,nonn,nice,mult,hear,changed
proposed
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Conjecture: a(n) = Sum_{k=1..n} A010051(2*k/gcd(n, k)). - Velin Yanev, Jun 20 2024
easy,core,nonn,nice,mult,hear,changed
proposed
approved
editing
proposed
Conjecture: a(n) = Sum_{k=1..n} A010051(2*k/gcd(n, k)). - Velin Yanev, Jun 20 2024
approved
editing
proposed
approved
editing
proposed
T. Terence Tao, Poincaré's Legacies, Part I, Amer. Math. Soc., 2009, see pp. 31ff for upper bounds on d(n).
Terence Tao, <a href="https://terrytao.wordpress.com/wp-content/uploads/2009/01/whatsnew.pdf">Poincaré's Legacies: pages from year two of a mathematical blog</a>, see page 59.
approved
editing
editing
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a(n) = Sum_{d divides n} mu(core(d))^2 = Sum_{d divides n} core(mu(core(d)), where core(n) = A007913(n). - Peter Bala, Jan 24 2024
easy,core,nonn,nice,mult,hear,changed
editing
approved
a(n) = Sum_{d divides n} mu(core(d))^2, = Sum_{d divides n} core(mu(core(d)), where core(n) = A007913(n). - Peter Bala, Jan 24 2024