OFFSET
1,3
COMMENTS
This is the zeta-function Sum_{j>=1} A000005(j)/j^s evaluated at s=4. At s=2, we find A098198; at s=3, A183030.
Since tau(n)/n^4 is a multiplicative function, one finds an Euler product for the sum, which is expanded with an Euler transformation to a product of Riemann zeta functions as in A175639 for numerical evaluation.
FORMULA
Equals the Euler product Product_{p prime} (1 + (2*p^s - 1)/(p^s - 1)^2) at s=4, which is the square of A013662.
EXAMPLE
1.1714235822309350626084... = 1 + 2/2^4 + 2/3^4 + 3/4^4 + 2/5^4 + 4/6^4 + 2/7^4 + ...
MAPLE
evalf(Pi^8/8100) ;
MATHEMATICA
RealDigits[Zeta[4]^2, 10, 120][[1]] (* Amiram Eldar, May 22 2023 *)
PROG
(PARI) zeta(4)^2 \\ Charles R Greathouse IV, Mar 04 2015
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
R. J. Mathar, Dec 18 2010
STATUS
approved