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A348507 revision #37

A348507
a(n) = A003959(n) - n, where A003959 is multiplicative with a(p^e) = (p+1)^e.
14
0, 1, 1, 5, 1, 6, 1, 19, 7, 8, 1, 24, 1, 10, 9, 65, 1, 30, 1, 34, 11, 14, 1, 84, 11, 16, 37, 44, 1, 42, 1, 211, 15, 20, 13, 108, 1, 22, 17, 122, 1, 54, 1, 64, 51, 26, 1, 276, 15, 58, 21, 74, 1, 138, 17, 160, 23, 32, 1, 156, 1, 34, 65, 665, 19, 78, 1, 94, 27, 74, 1, 360, 1, 40, 69, 104, 19, 90, 1, 406, 175, 44, 1, 204
OFFSET
1,4
COMMENTS
a(p*(n/p)) - (n/p) = (p+1)*a(n/p) holds for all prime divisors p of n, which can be seen by expanding the left hand side as (A003959(p*(n/p)) - (p*(n/p))) - (n/p) = (p+1)*A003959(n/p)-((p+1)*(n/p)) = (p+1)*(A003959(n/p)-(n/p)) = (p+1)*a(n/p). This implies that a(n) >= A003415(n) for all n. (See comments in A348970). - Antti Karttunen, Nov 06 2021
FORMULA
a(n) = A003959(n) - n.
a(n) = A348508(n) + n.
a(n) = A001065(n) + A348029(n).
From Antti Karttunen, Nov 06 2021: (Start)
a(n) = Sum_{d|n} A348971(d).
a(n) = A003415(n) + A348970(n).
For all n>= 1, A322582(n) <= A003415(n) <= a(n).
For n > 1, a(n) = a(A032742(n))*(1+A020639(n)) + A032742(n). [See comments above, and compare this with Reinhard Zumkeller's May 09 2011 recursive formula for A003415 !]
(End)
MATHEMATICA
f[p_, e_] := (p + 1)^e; a[1] = 0; a[n_] := Times @@ f @@@ FactorInteger[n] - n; Array[a, 100] (* Amiram Eldar, Oct 30 2021 *)
PROG
(PARI)
A003959(n) = { my(f = factor(n)); for(i=1, #f~, f[i, 1]++); factorback(f); };
A348507(n) = (A003959(n) - n);
(PARI)
A020639(n) = if(1==n, n, (factor(n)[1, 1]));
A348507(n) = { my(s=0, m=1, spf); while(n>1, spf = A020639(n); n /= spf; s += m*n; m *= (1+spf)); (s); }; \\ (Compare this with my similar program for A003415 and for A322582) - Antti Karttunen, Nov 06 2021
CROSSREFS
Cf. A348971 (Möbius transform), A349139, A349140, A349141, A349142, A349143 (other Dirichlet convolutions).
Cf. also A168066 (the arithmetic mean of this and A322582).
Sequence in context: A028284 A359169 A096462 * A066948 A064265 A180595
KEYWORD
nonn
AUTHOR
Antti Karttunen, Oct 30 2021
STATUS
editing