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A146968
Brocard's problem: positive integers n such that n!+1 = m^2.
11
OFFSET
1,1
COMMENTS
No other terms below 10^9.
See A085692 for more comments and references. - M. F. Hasler, Nov 20 2018
EXAMPLE
7! + 1 = 5041 = 71^2, hence 7 is in the sequence. - Klaus Brockhaus, Nov 05 2008
MATHEMATICA
Select[Range[10], IntegerQ[Sqrt[#!+1]]&] (* Harvey P. Dale, Jan 31 2015 *)
PROG
(Shell) #!/bin/sh n=0 while(true) do n=`echo $n + 1 | bc` calc "($n! + 1)" ^ "(1 / 2)" | grep -v \. done
(Magma) [ <n, p>: n in [1..8047] | t where t, p:=IsSquare(Factorial(n)+1) ]; // Klaus Brockhaus, Nov 05 2008
(PARI) { for (n=1, 60100, if(issquare(n!+1) == 1, print(n) ) ) } \\ Marco Bellaccini (marcomurk(AT)tele2.it), Nov 08 2008
CROSSREFS
A085692, A146968, A216071 are all essentially the same sequence. - N. J. A. Sloane, Sep 01 2012
Sequence in context: A166042 A321772 A333435 * A298982 A112247 A319260
KEYWORD
bref,nonn,hard
AUTHOR
Marco Bellaccini (marcomurk(AT)tele2.it), Nov 03 2008
EXTENSIONS
Edited by Max Alekseyev, Feb 06 2010
STATUS
approved