arXiv:math/0311384v1 [math.FA] 21 Nov 2003
Contemporary Mathematics
Frames of subspaces
Peter G. Casazza and Gitta Kutyniok
Abstract. One approach to ease the construction of frames is to first construct local components and then build a global frame from these. In this
paper we will show that the study of the relation between a frame and its local
components leads to the definition of a frame of subspaces. We introduce this
new notion and prove that it provides us with the link we need. It will also
turn out that frames of subspaces behave as a generalization of frames. In particular, we can define an analysis, a synthesis and a frame operator for a frame
of subspaces, which even yield a reconstruction formula. Also concepts such as
completeness, minimality, and exactness are introduced and investigated. We
further study several constructions of frames of subspaces, and also of frames
and Riesz frames using the theory of frames of subspaces. An important special case are harmonic frames of subspaces which generalize harmonic frames.
We show that wavelet subspaces coming from multiresolution analysis belong
to this class.
1. Introduction
During the last 20 years the theory of frames has been growing rapidly, since
several new applications have been developed. For example, besides traditional applications as signal processing, image processing, data compression, and sampling
theory, frames are now used to mitigate the effect of losses in packet-based communication systems and hence to improve the robustness of data transmission [7, 15],
and to design high-rate constellations with full diversity in multiple-antenna code
design [17].
To handle these emerging applications of frames new methods have to be developed. One starting point is to first build frames “locally” and then piece them
together to obtain frames for the whole space. One advantage of this idea is that
it would facilitate the construction of frames for special applications, since we can
first construct frames or choose already known frames for smaller spaces. And in a
second step one would construct a frame for the whole space from them. Therefore
1991 Mathematics Subject Classification. Primary 42C15; Secondary 46C99.
Key words and phrases. Abstract frame theory, frame, harmonic frame, Hilbert space, resolution of the identity, Riesz basis, Riesz frame.
The first author was supported by NSF DMS 0102686.
The second author was supported by Forschungspreis 2003 der Universität Paderborn.
c 0000 (copyright holder)
1
2
PETER G. CASAZZA AND GITTA KUTYNIOK
it is necessary to derive conditions for these components, so that there exists a construction, which yields a frame for the whole space with special properties. Various
approaches to piecing together familes of vectors to get a frame for the whole space
have been done over the years going back to Duffin and Schaeffer’s original work
[12]. One approach used in the wavelet as well as in the Gabor case [10, 1] is to start
with non-frame sequences and piece them together to build frames for the whole
space. Another is to build frames locally and piece them together orthogonally
to get frames. We refer to Heil and Walnut [18] for an excellent introduction to
these methods and Gabor frames in general. Recently, another approach was introduced by Fornasier [13, 14]. Fornasier uses subspaces which are quasi-orthogonal
to construct local frames and piece them together to get global frames.
In this paper we will formulate a general method for piecing together local
frames to get global frames. The importance of this approach is that it is both
necessary and sufficient for the the construction of global frames from local frames.
Some of these results are generalizations of Fornasier’s work [13, 14] although they
were done before his papers became available to us.
Another motivation comes from the theory of C*-algebras. Just recently Casazza, Christensen, Lindner, and Vershynin [5] proved that the so-called ”Feichtinger conjecture” is equivalent to the weak Bourgain-Tzafriri conjecture. The
Feichtinger conjecture states that each bounded frame is a finite union of Riesz
basic sequences. Then, Casazza and Vershynin [8] showed that the Kadison-Singer
problem is equivalent to the strong Bourgain-Tzafriri conjecture and that these
two problems have a positive solution if and only if both the Feichtinger conjecture
and the Fǫ -conjecture have positive solutions. The Fǫ -conjecture states: For every
ǫ > 0, every unit norm Riesz basis is a finite union of (1 + ǫ)-unconditional basic
sequences. A unit norm sequence {fi }i∈I is a (1 + ǫ)-basic sequence if for every
sequence of scalars {ai }i∈I we have
(1 − ǫ)
X
i∈I
2
|ai | ≤
X
i∈I
2
ai f i
≤ (1 + ǫ)
X
i∈I
|ai |2 .
To attack these problems it is important to know into which components we can
divide a frame. As we will see in this paper, the necessary divisions will form a
frame of subspaces for the space. At this time, it is not even known how to divide
a frame into two infinite frame sequences.
In this paper we want to answer the following two questions, which relate to
the two different motivations:
• Let {Wi }i∈I be a collection of closed subspaces in a Hilbert space H in
which we want to decompose our function, where each subspace Wi is
equipped with a weight vi , which indicate its importance. When can we
find frames for Wi for each i ∈ I so that the collection of all of them is a
frame with special properties for the whole space H?
S
• Let {fi }i∈I be a frame for a Hilbert space H, and let I = j∈Z Ij be a
partition of I so that {fi }i∈Ij is a frame sequence for each j ∈ Z. Which
relations exist between the closed linear spans of {fi }i∈Ij , j ∈ Z ?
We start our consideration by giving a brief review of the definitions and basic
properties of frames and bases and stating some notation in Section 2.
FRAMES OF SUBSPACES
3
In Section 3 it will turn out that both questions above lead to the definition of
a frame of subspaces. In the first subsection we will state the definition of a frame
of subspaces for a given family of closed subspaces {Wi }i∈I in a Hilbert space and
a family of weights {vi }i∈I . Then it is shown that this definition leads to some
answers to the above questions (see Theorem 3.2), since it shows that frames of
subspaces behave as a link between local components of a frame and the global
structure. This will also enlighten the advantage of our approach, since now we can
choose the frames for the single subspaces Wi arbitrarily and always get a frame
for the whole Hilbert space by just collecting them together. Thus it differs from
previous approaches and is a generalization of the approach of Fornasier [13, 14].
It will turn out that frames of subspaces behave as a generalization of frames. We
first give a definition of completeness of a family of subspaces and show that the
relation between this property and the notion of a frame of subspaces is similar
to the relation between the definition of completeness of a sequence and a frame.
Further in Subsection 3.2 we introduce an analysis and a synthesis operator, a frame
operator, and a dual frame of subspaces for a given frame of subspaces and prove
that they behave in an analogous way as the corresponding objects in abstract
frame theory. We even obtain a reconstruction formula using these ingredients
(Proposition 3.16). The next subsection deals with Parseval frames of subspaces,
which share several properties with Parseval frames. Finally in Subsection 3.4 we
show that using the theory of frames of subspaces we can construct several useful
resolutions of the identity.
Section 4 deals with Riesz decompositions, which are a generalization of the
notion of Riesz bases to our general setting. We further define minimality for a
family of subspaces and show that it behaves as expected. Also exactness is defined
in a canonical way. However, it will turn out that this property is much weaker
than exactness of a frame (compare Theorem 4.6).
Some constructions are given in Section 5. Here we first state some results
which help constructing frames of subspaces. An extended example concerning
the situation of Gabor frames is added. In Subsection 5.2 we then show how to
construct frames and Riesz frames using a frame of subspaces.
Finally, Section 6 deals with harmonic frames of subspaces. These are a generalization of harmonic frames, which distinguish themselves by having an easy
construction formula. In both the finite and the infinite dimensional cases we give
the definition of a harmonic frame of subspaces, state some results, and give examples, e.g., subspaces coming from Gabor systems and subspaces coming from
multiresolution analysis, for their occurance.
2. Review of frames and some notation
First we will briefly recall the definitions and basic properties of frames and
bases. For more information we refer to the survey articles by Casazza [3, 4], the
books by Christensen [9], Gröchenig [16], and Young [22] and the research-tutorial
by Heil and Walnut [18].
Let H be a separable Hilbert space and let I be an indexing set. A family
{fi }i∈I is a frame for H, if there exist 0 < A ≤ B < ∞ such that for all h ∈ H,
X
2
2
2
(2.1)
A khk ≤
|hh, fi i| ≤ B khk .
i∈I
4
PETER G. CASAZZA AND GITTA KUTYNIOK
The constants A and B are called a lower and upper frame bound for the frame.
Those sequences which satisfy only the upper inequality in (2.1) are called Bessel
sequences. A frame is tight, if A = B. If A = B = 1, it is called a Parseval frame.
We call a frame {fi }i∈I uniform (or equal norm), if we have kfi k = kfj k for all
i, j ∈ I. A frame is exact, if it ceases to be a frame whenever any single element is
deleted from the sequence {fi }i∈I . We say that two frames {fi }i∈I , {gi }i∈I for H
are equivalent, if there exists an invertible operator U : H → H satisfying U fi = gi
for all i ∈ I. If U is a unitary operator, {fi }i∈I and {gi }i∈I are called unitarily
2
equivalent. The
P synthesis operator Tf : l (I) → H of a frame f = 2{fi }i∈I is defined
by Tf (c) = i∈I ci fi for each sequence of scalars c = {ci }i∈I ∈ l (I). The adjoint
operator Tf∗ : H → l2 (I), the so-called analysis operator of f = {fi }i∈I , is given by
P
Tf∗ (g) = {hfi , gi}i∈I . Then the frame operator Sf (h) = Tf Tf∗ (h) = i∈I hh, fi i fi
associated with {fi }i∈I is a bounded, invertible, and positive operator mapping H
onto itself. This provides the reconstruction formula
X
X
h = Sf−1 Sf (h) =
hh, fi i f˜i =
hh, f˜i ifi ,
i∈I
i∈I
where f˜i = Sf−1 fi . The family {f˜i }i∈I is also a frame for H, called the canonical
dual frame of {fi }i∈I . A sequence is called a frame sequence, if it is a frame only
for its closed linear span. Moreover, we say that a frame {fi }i∈I is a Riesz frame,
if every subfamily of the sequence {fi }i∈I is a frame sequence with uniform frame
bounds A and B.
As important example of frames are the so-called harmonic frames, which are
uniform Parseval frames of the form {U i ϕ}i∈I , where U is a unitary operator on H
and I = {0, . . . , N − 1}, N ∈ N or I = Z. Concerning a classification of harmonic
frames we refer to the paper by Casazza and Kovaĉević [7].
Riesz bases are special cases of frames, and can be characterized as those frames
which are biorthogonal to their dual frames. An equivalent definition is the following. A family {fi }i∈I is a Riesz basis for H, if there exist 0 < A ≤ B < ∞ such
that for all sequences of scalars c = {ci }i∈I ,
A kck2 ≤
X
i∈I
ci fi ≤ B kck2 .
We define the Riesz basis constants for {fi }i∈I to be the largest number A and the
smallest number B such that this inequality holds for all sequences of scalars c.
If {fi }i∈I is a Riesz basis only for its closed linear span, we call it a Riesz basic
sequence.
An arbitrary sequence {fi }i∈I in H is minimal, if fi 6∈ spanj∈I,j6=i {fj } for all
i ∈ I, or equivalently if there exists a sequence {f˜i }i∈I , which is biorthogonal to
{fi }i∈I . It is complete, if the span of {fi }i∈I is dense in H.
We conclude this section by giving some notation and remarks. Throughout this
paper H shall always denote an arbitrary separable Hilbert space. Furthermore all
subspaces are assumed to be closed although this is not stated explicitely. Moreover,
for the remainder a sequence {vi }i∈I always denotes a family of weights, i.e., vi > 0
for all i ∈ I.
In addition we use the following notation. Dependent on the context I denotes
an indexing set or the identity operator. If W is a subspace of a Hilbert space H, we
FRAMES OF SUBSPACES
5
let πW denote the orthogonal projection of H onto W . If {ei }i∈I is an orthonormal
basis for H and J ⊂ I, πJ is the orthogonal projection of H onto spani∈J {ei }.
3. Frames of subspaces
3.1. Definition and basic properties. We start with the definition of a
frame of subspaces. It will turn out that frames of subspaces share many of the
properties of frames, and thus can be viewed as a generalization of frames.
Definition 3.1. Let I be some index set, and let {vi }i∈I be a family of weights,
i.e., vi > 0 for all i ∈ I. A family of closed subspaces {Wi }i∈I of a Hilbert space
H is a frame of subspaces with respect to {vi }i∈I for H, if there exist constants
0 < C ≤ D < ∞ such that
X
(3.1)
Ckf k2 ≤
vi2 kπWi (f )k2 ≤ Dkf k2 for all f ∈ H.
i∈I
We call C and D the frame bounds for the frame of subspaces. The family {Wi }i∈I
is called a C-tight frame of subspaces with respect to {vi }i∈I , if in (3.1) the constants
C and D can be chosen so that C = D, a Parseval frame of subspaces with respect
to {viL
}i∈I provided that C = D = 1 and an orthonormal basis of subspaces if
H =
i∈I Wi . Moreover, we call a frame of subspaces with respect to {vi }i∈I
v-uniform, if v := vi = vj for all i, j ∈ I. If we only have the upper bound, we call
{Wi }i∈I a Bessel sequence of subspaces with respect to {vi }i∈I with Bessel bound
D.
Condition (3.1) states the necessary (and also sufficient) interaction between
the subspaces so that taking frames from them and putting them together yields a
frame for the whole space.
The importance of this definition is that it is both necessary and sufficient for us
to be able to string together frames for each of the subspaces Wi (with uniformly
bounded frame constants) to get a frame for H. This is contained in the next
theorem. The implication (3) ⇒ (1) of the following result is [7, Proposition 4.5].
Fornasier [13, 14] obtains a similar result for quasi-orthogonal decompositions.
Theorem 3.2. For each i ∈ I let vi > 0 and let {fij }j∈Ji be a frame sequence
in H with frame bounds Ai and Bi . Define Wi = spanj∈Ji {fij } for all i ∈ I
and choose an orthonormal basis {eij }j∈Ji for each subspace Wi . Suppose that
0 < A = inf i∈I Ai ≤ B = supi∈I Bi < ∞. The following conditions are equivalent.
(1) {vi fij }i∈I,j∈Ji is a frame for H.
(2) {vi eij }i∈I,j∈Ji is a frame for H.
(3) {Wi }i∈I is a frame of subspaces with respect to {vi }i∈I for H.
Proof. Since for each i ∈ I, {fij }j∈Ji is a frame for Wi with frame bounds
Ai and Bi , we obtain
X
X
XX
2
2
2
A
vi2 kπWi (f )k ≤
Ai vi2 kπWi (f )k ≤
|hπWi (f ), vi fij i|
i∈I
≤
X
i∈I
Now we observe that
XX
i∈I j∈Ji
i∈I
Bi vi2
2
kπWi (f )k ≤ B
2
|hπWi (f ), vi fij i| =
X
i∈I
i∈I j∈Ji
vi2
2
kπWi (f )k .
XX
i∈I j∈Ji
2
|hf, vi fij i| .
6
PETER G. CASAZZA AND GITTA KUTYNIOK
This shows that provided {vi fij }i∈I,j∈Ji is a frame for H with frame bounds C and
D, the sets {Wi }i∈I form a frame of subspaces with respect to {vi }i∈I for H with
C
and D
frame bounds B
A . Moreover, if {Wi }i∈I is a frame of subspaces with respect
to {vi }i∈I for H with frame bounds C and D, the calculation above implies that
{vi fij }i∈I,j∈Ji is a frame for H with frame bounds AC and BD. Thus (1) ⇔ (3).
To prove the equivalence of (2) and (3), note that we can now actually calculate
the orthogonal projections in the following way
vi2
2
kπWi (f )k =
vi2
X
j∈Ji
2
hf, eij i eij
=
X
j∈Ji
2
|hf, vi eij i| .
From this the claim follows immediately.
The definition of completeness of a sequence gives rise to a definition of completeness for a sequence of subspaces.
Definition 3.3. A family of subspaces {Wi }i∈I of H is called complete, if
spani∈I {Wi } = H.
The next lemma possesses a well-known analog in the frame situation.
Lemma 3.4. Let {Wi }i∈I be a family of subspaces in H, and let {vi }i∈I be a
family of weights. If {Wi }i∈I is a frame of subspaces with respect to {vi }i∈I for H,
then it is complete.
Proof. Assume that {Wi }i∈I is not complete.
Then there exists some f ∈ H,
P
f 6= 0 with f ⊥ spani∈I {Wi }. It follows that i∈I vi2 kπWi (f )k2 = 0, hence {Wi }i∈I
is not a frame of subspaces.
To check completeness of a frame of subspaces, we derive the following useful
characterization.
Lemma 3.5. Let {Wi }i∈I be a family of subspaces in H, and for each i ∈ I
let {eij }j∈Ji be an orthonormal basis for Wi . Then the following conditions are
equivalent.
(1) {Wi }i∈I is complete.
(2) {eij }i∈I,j∈Ji is complete.
Proof. The equivalence of (1) and (2) follows immediately from the definitions.
If we remove an element from a frame, we obtain either another frame or an
incomplete set [9, Theorem 5.4.7]. A similar result holds in our situation.
Proposition 3.6. The removal of a subspace from a frame of subspaces with
respect to some family of weights leaves either a frame of subspaces with respect to
the same family of weights or an incomplete family of subspaces.
Proof. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I for H,
and for each i ∈ I let {eij }j∈Ji be an orthonormal basis for Wi . By Theorem 3.2, {vi eij }i∈I,j∈Ji is a frame for H. Let i0 ∈ I. By [9, Theorem 5.4.7],
{vi eij }i∈I\{i0 },j∈Ji is either a frame or an incomplete set. If it is a frame, again by
Theorem 3.2, also {Wi }i∈I\{i0 } is a frame of subspaces with respect to {vi }i∈I for H.
FRAMES OF SUBSPACES
7
Now suppose that {vi eij }i∈I\{i0 },j∈Ji and hence {eij }i∈I\{i0 },j∈Ji is an incomplete
set. By Lemma 3.5, also {Wi }i∈I\{i0 } is incomplete.
We further observe that the intersection of the elements of a frame of subspaces
with a subspace still leaves a frame of subspaces for a smaller space.
Lemma 3.7. Let V be a subspace of H and let {Wi }i∈I be a frame of subspaces
with respect to {vi }i∈I for H with frame bounds C and D. Then {Wi ∩ V }i∈I is a
frame of subspaces with respect to {vi }i∈I for V with frame bounds C and D.
Proof. For all f ∈ V we have
X
X
vi2 kπWi ∩V (f )k2 .
vi2 kπWi (f )k2 =
i∈I
i∈I
From this the result follows at once.
3.2. Frame properties. In this subsection we will show that a frame of subspaces behaves as a generalization of a frame, thus providing an associated analysis
and synthesis operator, a frame operator and a dual object.
For the definition of an analysis and a synthesis operator for a frame of subspaces, we will need the following notation.
3.8. For each family of subspaces {Wi }i∈I of H, we define the space
P Notation
⊕W
i ℓ2 by
i∈I
!
X
X
= {{fi }i∈I |fi ∈ Wi and
⊕Wi
kfi k2 < ∞}
i∈I
i∈I
ℓ2
with inner product given by
h{fi }i∈I , {gi }i∈I i =
X
i∈I
hfi , gi i.
We start with the definition of a synthesis operator for a frame of subspaces.
To show that the series appearing in this formula converges unconditionally, we
need the next lemma.
Lemma 3.9. Let {Wi }i∈I be a Bessel sequence of subspaces with respect to
{vi }i∈IPfor H. Then, for each sequence {fi }i∈I with fi ∈ Wi for each i ∈ I, the
series i∈I vi fi converges unconditionally.
P
⊕Wi ℓ . Fix J ⊂ I with |J| < ∞ and let
Proof. Let f = {fi }i∈I ∈
i∈I
2
P
g = i∈J vi fi . Then we compute
!2
!2
!2
X
X
X
X
4
k
vi fi k = hg,
vi fi i
=
vi hπWi (g), fi i
≤
vi kπWi (g)kkfi k
i∈J
≤
Hence,
X
i∈J
i∈J
vi2 kπWi (g)k2
X
i∈J
i∈J
2
kfi k ≤ Dkgk
k
X
2
X
i∈J
i∈J
2
kfi k ≤ Dk
vi fi k2 ≤ Dkf k2 .
X
i∈J
vi fi k2 kf k2.
i∈J
P
It follows that i∈I vi fi is weakly unconditionally Cauchy and hence unconditionally convergent in H (see [11], page 44, Theorems 6 and 8).
8
PETER G. CASAZZA AND GITTA KUTYNIOK
Definition 3.10. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I
for H. Then the synthesis operator for {Wi }i∈I and {vi }i∈I is the operator
!
X
TW,v :
−→ H
⊕Wi
i∈I
ℓ2
defined by
TW,v (f ) =
X
vi fi
i∈I
X
for all f = {fi }i∈I ∈ (
⊕Wi )ℓ2 .
i∈I
∗
We call the adjoint TW,v
of the synthesis operator the analysis operator.
The following proposition will provide us with a concrete formula for the analysis operator.
Proposition 3.11. Let {Wi }i∈I be a frame P
of subspaces with respect to {vi }i∈I
∗
for H. Then the analysis operator TW,v
: H → ( i∈I ⊕Wi )ℓ2 is given by
∗
TW,v
(f ) = {vi πWi (f )}i∈I .
P
Proof. Let f ∈ H and g = {gi }i∈I ∈ ( i∈I ⊕Wi )ℓ2 . Using the definition of
TW,v we compute that
X
X
∗
hTW,v
(f ), gi = hf, TW,v (g)i = hf,
vi gi i =
vi hf, gi i.
i∈I
i∈I
Since gi ∈ Wi for each i ∈ I, we can continue in the following way:
X
X
vi hπWi (f ), gi i = h{vi πWi (f )}i∈I , {gi }i∈I i.
vi hf, gi i =
i∈I
i∈I
The well-known relations between a frame and the associated analysis and
synthesis operator also holds in our more general situation.
Theorem 3.12. Let {Wi }i∈I be a family of subspaces in H, and let {vi }i∈I be
a family of weights. Then the following conditions are equivalent.
(1) {Wi }i∈I is a frame of subspaces with respect to {vi }i∈I for H.
(2) The synthesis operator TW,v is bounded, linear and onto.
∗
(3) The analysis operator TW,v
is a (possibly into) isomorphism.
Proof. First we prove (1) ⇔ (3). This claim follows immediately from the
fact that for each f ∈ H we have
X
∗
kTW,v
(f )k2 = k{vi πWi (f )}i∈I k2 =
vi2 kπWi (f )k2 .
i∈I
Further recall that (2) ⇔ (3) holds in general for each operator on a Hilbert space.
In an analogous way as in frame theory we can define equivalence classes of
frames of subspaces. Using the synthesis operator we can also characterize exactly
the elements belonging to the same equivalence class.
FRAMES OF SUBSPACES
9
fi }i∈I be frames of subspaces with reDefinition 3.13. Let {Wi }i∈I and {W
spect to the same family of weights. We say that they are (unitarily) equivalent, if
fi ) for all
there exists an (unitary) invertible operator U on H such that Wi = U (W
i ∈ I.
fi }i∈I be frames of subspaces with respect to
Lemma 3.14. Let {Wi }i∈I and {W
the same family of weights {vi }i∈I . The following conditions are equivalent.
fi }i∈I are (unitarily) equivalent.
(1) {Wi }i∈I and {W
(2) There exists an (unitary) invertible operator U on H such that TW,v =
U −1 TW
f ,v U , where U is applied to each component.
Proof. This follows immediately from the definition of the synthesis operator.
As in the well-known frame situation, there also exists an associated frame
operator for each frame of subspaces which satisfies similar properties as we will
see in the next proposition. For instance we even obtain a reconstruction formula.
Definition 3.15. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I
for H. Then the frame operator SW,v for {Wi }i∈I and {vi }i∈I is defined by
X
∗
SW,v (f ) = TW,v TW,v
(f ) = TW,v ({vi πWi (f )}i∈I ) =
vi2 πWi (f ).
i∈I
The next proposition generalizes a result of Fornasier [13, 14].
Proposition 3.16. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I
with frame bounds C and D. Then the frame operator SW,v for {Wi }i∈I and {vi }i∈I
is a positive, self-adjoint, invertible operator on H with CI ≤ SW,v ≤ DI. Further,
we have the reconstruction formula
X
−1
∗
f = TS −1 W,v TW,v
(f ) =
vi2 SW,v
πWi (f ) for all f ∈ H.
W,v
i∈I
Proof. For any f ∈ H, we have
X
X
X
hSW,v (f ), f i = h
vi2 πWi (f ), f i =
vi2 hπWi (f ), f i =
vi2 kπWi (f )k2 ,
i∈I
i∈I
i∈I
which implies that SW,v is a positive operator. We further compute
X
hCf, f i = Ckf k2 ≤
vi2 kπWi (f )k2 = hSW,v (f ), f i ≤ hDf, f i.
i∈I
This shows that CI ≤ SW,v ≤ DI and hence SW,v is an invertible operator on H.
Furthermore, for any f, g ∈ H we have
X
X
hSW,v (f ), gi =
vi2 hπWi (f ), gi =
vi2 hf, πWi (g)i.
i∈I
i∈I
Thus SW,v is self-adjoint. At last the reconstruction formula follows immediately
from
X
−1
−1
f = SW,v
SW,v (f ) =
vi2 SW,v
πWi (f ).
i∈I
10
PETER G. CASAZZA AND GITTA KUTYNIOK
The following result will show the connection between the frame operator for a
frame of subspaces and the frame operator for the frame generated by orthonormal
bases of the subspaces. Also the connection between the reconstruction formulas is
exposed.
Proposition 3.17. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I
for H and {vi fij }j∈Ji be a Parseval frame for Wi for each i ∈ I. Then the frame
operator SW,v equals the frame operator Svf for the frame {vi fij }i∈I,j∈Ji , and for
all g ∈ H we have
X
X
−1
−1
vi2 SW,v
πWi (g) =
hg, vi fij i Svf
vi fij .
i∈I
i∈I,j∈Ji
Proof. Since {fij }j∈Ji is a Parseval frame for Wi for all i ∈ I, if g ∈ H then
X
X
πWi (g) =
hπWi (g), fij ifij =
hg, fij ifij .
j∈Ji
Thus
SW,v (g) =
X
j∈Ji
vi2 πWi (g) =
i∈I
X
i∈I,j∈Ji
hg, vi fij ivi fij = Svf (g).
Moreover, we obtain
X
X
X
−1
−1
vi2 SW,v
πWi (g) =
Svf
hg, vi fij i vi fij =
i∈I
i∈I
j∈Ji
X
i∈I,j∈Ji
−1
hg, vi fij i Svf
vi fij .
Using the frame operator for a frame of subspaces for a special subspace yields
an easy way to compute the orthogonal projection onto this subspace.
Proposition 3.18. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I
for a subspace V of H. Then, the orthogonal projection πV onto V is given by
X
−1
πV (f ) =
vi2 SW,v
πWi (f ) for all f ∈ H.
i∈I
Proof. The fact that SW,v : V → V implies that πV (f ) = 0 for all f ∈ V ⊥ .
By Proposition 3.16, we have
X
−1
f=
vi2 SW,v
πWi (f ) for all f ∈ V.
i∈I
Thus
πV2
= πV , which finishes the proof.
In the same manner as in frame theory we define a dual frame of subspaces
associated with a frame of subspaces.
Definition 3.19. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I
−1
Wi }i∈I is called the dual frame of
and with frame operator SW,v . Then {SW,v
subspaces with respect to {vi }i∈I .
The dual frame of subspaces is a frame of subspaces with the same weights. In
fact, more is true.
Proposition 3.20. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I ,
and let T : H → H be an invertible operator on H. Then {T Wi }i∈I is a frame of
subspaces with respect to {vi }i∈I .
FRAMES OF SUBSPACES
11
Proof. Since T is an invertible operator on H, we have that πT Wi = T πWi T −1 .
Let C, D > 0 be the frame bounds for the frame of subspaces {Wi }i∈I . Then for
all f ∈ H we have
X
X
X
vi2 kπT Wi (f )k2 =
vi2 kT πWi T −1 (f )k2 ≤ kT k2
vi2 kπWi T −1 (f )k2
i∈I
i∈I
2
i∈I
−1
2
2
−1 2
≤ kT k DkT (f )k ≤ kT k kT k Dkf k2.
Similarly, we obtain a lower frame of subspaces bound for {T Wi }i∈I .
3.3. Parseval frames of subspaces. Parseval frames play an important role
in abstract frame theory, since they are extremely useful for applications. Therefore
in this subsection we study characterizations of Parseval frames of subspaces and
special cases of them.
The first result extends [7, Corollary 4.1].
Corollary 3.21. For each i ∈ I let vi > 0 and let {fij }j∈Ji be a Parseval
frame sequence in H. Define Wi = spanj∈Ji {fij } for all i ∈ I, and choose for
each subspace Wi an orthonormal basis {eij }j∈Ji . Then the following conditions
are equivalent.
(1) {vi fij }i∈I,j∈Ji is a Parseval frame for H.
(2) {vi eij }i∈I,j∈Ji is a Parseval frame for H.
(3) {Wi }i∈I is a Parseval frame of subspaces with respect to {vi }i∈I for H.
Proof. This follows immediately from Theorem 3.2.
We can also characterize Parseval frames of subspaces in terms of their frame
operators in a similar manner as in frame theory.
Proposition 3.22. Let {Wi }i∈I be a family of subspaces in H, and let {vi }i∈I
be a family of weights. Then the following conditions are equivalent.
(1) {Wi }i∈I is a Parseval frame of subspaces with respect to {vi }i∈I for H.
(2) SW,v = I.
Proof. For each i ∈ I, let {eij }j∈Ji be an orthonormal basis for Wi .
By Proposition 3.16, (1) implies (2). To prove the converse implication suppose
that SW,v = I. Then for all f ∈ H we have
X
X X
f = SW,v (f ) =
vi2 πWi (f ) =
hf, eij i eij .
vi2
i∈I
This yields
2
kf k =
*
X
i∈I
vi2
X
j∈Ji
i∈I
hf, eij i eij , f
+
=
j∈Ji
X
i∈I
vi2 kπWi (f )k2 .
We also have the following characterization of orthonormal bases of subspaces,
which reflects exactly the situation in frame theory.
Proposition 3.23. Let {Wi }i∈I be a family of subspaces in H, and let {vi }i∈I
be a family of weights. Then the following conditions are equivalent.
(1) {Wi }i∈I is an orthonormal basis of subspaces for H.
(2) {Wi }i∈I is a 1-uniform Parseval frame of subspaces for H.
12
PETER G. CASAZZA AND GITTA KUTYNIOK
Proof. For each i ∈ I, let {eij }j∈Ji be an orthonormal basis for Wi .
If (1) is satisfied, then {eij }i∈I,j∈Ji is an orthonormal basis for H. This implies
X
XX
|heij , f i|2 =
kπWi (f )k2
kf k2 =
i∈I
i∈I j∈Ji
for all f ∈ H. Thus also (2) holds.
On the other hand suppose that (2) holds. Then for all f ∈ H we have
XX
X
2
kπWi (f )k2 =
kf k2 =
|heij , f i|
i∈I j∈Ji
i∈I
and keij k = 1 for all i ∈ I, j ∈ Ji , which shows
L that {eij }i∈I,j∈Ji is an orthonormal
basis for H. This immediately implies H = i∈I Wi , hence (1) follows.
3.4. Resolution of the identity. Let {Wi }i∈I be a frame of subspaces with
respect to {vi }i∈I for H and let its frame operator be denoted by SW,v . By Proposition 3.16, we have
X
−1
f=
πWi (f ) for all f ∈ H.
vi2 SW,v
i∈I
−1
This shows that the family of operators {vi2 SW,v
πWi }i∈I is a resolution of the identity. But a frame of subspaces for H provides us with many more resolutions of the
identity than only this one.
We start our consideration with the general definition of a resolution of the
identity.
Definition 3.24. Let I be an indexing set. A family of bounded operators
{Ti }i∈I on H is called a (unconditional) resolution of the identity on H, if for all
f ∈ H we have
X
f=
Ti (f )
i∈I
(and the series converges unconditionally for all f ∈ H).
Note that it follows from the definition and the uniform boundedness principle
that supi∈I kTi k < ∞.
The following result shows another way to obtain a resolution of the identity
from a frame of subspaces, which even satisfies an analog of (3.1).
Proposition 3.25. Let {vi }i∈I be a family of weights, and for each i ∈ I let
{vi fij }j∈Ji be a frame sequence in H with frame bounds Ai and Bi . Suppose that
{Wi }i∈I is a frame of subspaces with respect to {vi }i∈I for H with frame bounds C
and D, where Wi = spanj∈Ji {fij } for all i ∈ I. Then {vi fij }i∈I,j∈Ji is a frame for
H with frame operator denoted by Svf . Further, for each i ∈ I, let Ti : H → Wi be
given by
X
−1
Ti (f ) =
hf, Svf
vi fij ivi fij .
j∈Ji
If 0 < A = inf i∈I Ai ≤ B = supi∈I Bi < ∞, then {Ti }i∈I is an unconditional
resolution of the identity on H satisfying
X
B 2 D3
AC
2
2
2
kf
k
≤
kf k2 for all f ∈ H.
v
kT
(f
)k
≤
i
i
B 2 D2
A2 C 2
i∈I
FRAMES OF SUBSPACES
13
Proof. Recall that {vi fij }i∈I,j∈Ji is a frame for H by Theorem 3.2 with frame
bounds AC and BD. For any f ∈ H we have
XX
X
−1
f=
hf, Svf
vi fij ivi fij =
Ti (f ).
i∈I j∈Ji
i∈I
Since this is convergence relative to a frame, the convergence is unconditional.
For each i ∈ I, let Svf,i be the frame operator for {vi fij }j∈Ji . Let i ∈ I be
fixed. Then we obtain
X
−1
hSvf
f, vi fij ivi fij k2
kTi (f )k2 = k
j∈Ji
=
≤
−1
(f )k2
kSvf,i πWi Svf
−1
(f )k2 .
kSvf,i k2 kπWi Svf
To prove the upper bound, we compute
X
X
B 2 D3
−1
−1
vi2 kTi (f )k2 ≤ B 2 D2
(f )k2 ≤ B 2 D3 kSvf
(f )k2 ≤ 2 2 kf k2 .
vi2 kπWi Svf
A C
i∈I
i∈I
The lower bound follows from
X
X
X
−1
vi2 kTi (f )k2 =
vi2 kSvf,i πWi S −1 (f )k2 ≥
(f )k2
Ai vi2 kπWi Svf
i∈I
i∈I
i∈I
−1
≥ ACkSvf
(f )k2 ≥
AC
kf k2 .
B 2 D2
We now give another method for obtaining an unconditional resolution of the
identity from a frame of subspaces. A special case of this can be found in Fornasier
[13, 14].
Proposition 3.26. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I
for H with frame bounds C and D, and let SW,v denote its frame operator. Then
−1
, i ∈ I satisfies that {vi2 Ti }i∈I is an unconditional
{Ti }i∈I defined by Ti = πWi SW,v
resolution of the identity, and for all f ∈ H we have
X
C
D
kf k2 ≤
vi2 kTi (f )k2 ≤ 2 kf k2 .
2
D
C
i∈I
Proof. First, for any f ∈ H we have
X
−1
−1
(f ) = SW,v SW,v
(f ) = f.
vi2 πWi SW,v
i∈I
To prove the second claim we compute
X
C
D
−1
−1
−1
kf k2 ≤ CkSW,v
(f )k2 ≤
(f )k2 ≤ DkSW,v
(f )k2 ≤ 2 kf k2 .
vi2 kπWi SW,v
2
D
C
i∈I
next result will turn out to be useful for proving a lower bound for
P The
2
2
2
v
kT
i (f )k if {vi Ti }i∈I is a resolution of the identity.
i∈I i
14
PETER G. CASAZZA AND GITTA KUTYNIOK
Lemma 3.27. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I with
frame bounds C and D for H, and let Ti : H → Wi be such that {vi2 Ti }i∈I is a
resolution of the identity on H (Note that a resolution of the identity need not be
unconditional so the index set must have an ordering on it. In our case, the result
will hold for any ordering so we do not specify the ordering here). For any J ⊂ I
we have
X
1 X 2
k
vi Tj (f )k2 ≤
vj2 kTj (f )k2 for all f ∈ H.
D
j∈J
j∈J
Proof. We may assume that |J| < ∞, since if our inequalityPholds for all
finite subsets then it holds for all subsets. Let f ∈ H and set g = j∈J vj2 Tj (f ).
Then, using the fact that {Wi }i∈I is a frame of subspaces with respect to {vi }i∈I
for H, we compute
2
X
kgk4 = hg,
vj2 Tj (f )i
j∈J
=
=
≤
≤
≤
X
j∈J
X
j∈J
X
j∈J
X
j∈J
2
vj hg, vj Tj (f )i
vj hπWj (g), vj Tj (f )i
2
vj kπWj (g)kkvj Tj (f )k
X
vj2 kπWj (g)k2
Dkgk
2
2
X
j∈J
j∈J
kvj Tj (f )k2
kvj Tj (f )k2 .
Dividing both sides of this inequality by Dkgk2 completes the proof.
Using this lemma, we obtain bounds for
of the identity {vi2 Ti }i∈I .
P
i∈I
vi2 kTi (f )k2 for many resolutions
Proposition 3.28. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I
for H with frame bounds C and D, let Ti : H → Wi be such that {vi2 Ti }i∈I is a
resolution of the identity on H, and assume that Ti πWi = Ti . Then for all f ∈ H
X
1
kf k2 ≤
vi2 kTi (f )k2 ≤ DEkf k2 ,
D
i∈I
where E = supi kTi k < ∞.
Proof. By Lemma 3.27, for all f ∈ H, we have
X
X
1
1 X 2
kf k2 = k
vi Ti (f )k2 ≤
vi2 kTi (f )k2 =
vi2 kTi πWi (f )k2
D
D
i∈I
i∈I
i∈I
FRAMES OF SUBSPACES
≤
X
i∈I
vi2 kTi k2 kπWi (f )k2 ≤ E
X
i∈I
15
vi2 kπWi (f )k2 ≤ DEkf k2.
Obviously the condition Ti πWi = Ti for all i ∈ I is satisfied by the example
−1
{vi2 SW,v
πWi }i∈I from the beginning of this subsection. This shows that this family
of operators is not only a resolution of the identity but even satisfies an analog of
(3.1).
The following definition provides us with a condition, which implies that a
resolution of the identity Ti : H → Wi , where {Wi }i∈I is a frame of subspaces with
respect to {vi }i∈I for H, automatically satisfies an analog of (3.1).
Definition 3.29. A family of bounded operators {Ti }i∈I on H is called an
ℓ2 -resolution of the identity with respect to a family of weights {vi }i∈I on H, if it
is a resolution of the identity on H and there exists a constant B > 0 so that for
all f ∈ H we have
X
vi−2 kTi (f )k2 ≤ Bkf k2 .
i∈I
Theorem 3.30. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I for
H, and let Ti : H → Wi be such that {vi2 Ti }i∈I is an ℓ2 -resolution of the identity
with respect to {vi }i∈I on H. Then there exist constants A, B > 0 so that for all
f ∈ H we have
X
Akf k2 ≤
vi2 kTi (f )k2 ≤ Bkf k2 .
i∈I
Proof. This follows immediately from the definition of an ℓ2 -resolution of the
identity on H and Lemma 3.27.
4. Riesz decompositions
In this section we first study minimal frames of subspaces, which share similar
properties with minimal frames.
Definition 4.1. A family of subspaces {Wi }i∈I of H is called minimal, if for
each i ∈ I
Wi ∩ spanj∈I,j6=i {Wj } = {0}.
Using orthonormal bases for the subspaces we obtain a useful characterization
of minimal families of subspaces.
Lemma 4.2. Let {Wi }i∈I be a family of subspaces in H, and for each i ∈ I
let {eij }j∈Ji be an orthonormal basis for Wi . Then the following conditions are
equivalent.
(1) {Wi }i∈I is minimal.
(2) {eij }i∈I,j∈Ji is minimal.
Proof. The implication (2) ⇒ (1) is obvious. P
To prove (1) ⇒ (2) suppose that
{cij }j∈Ji ∈ ℓ2 (Ji ) for all i ∈ I and we have fi = j∈Ji cij eij and f = {fi }i∈I ∈
P
P
i∈I ⊕Wi ℓ2 . If
i∈I fi = 0, then by minimality of {Wi }i∈I we have that fi = 0
for all i ∈ I and so cij = 0 for all i ∈ I, j ∈ Ji . It follows that {eij }i∈I,j∈Ji is a
minimal frame for H.
16
PETER G. CASAZZA AND GITTA KUTYNIOK
The following two propositions show that for families of subspaces we can also
give a definition of biorthogonal families of subspaces, which possess similar properties compared to minimal frames of subspaces as in the situation of minimal frames
(compare [9, Lemma 3.3.1]).
Proposition 4.3. Let {Wi }i∈I be a family of subspaces in H. Then the following conditions are equivalent.
(1) {Wi }i∈I is minimal.
(2) There exists a unique maximal (up to containment) biorthogonal family
of subspaces for {Wi }i∈I , i.e., there exists a family of subspaces {Vi }i∈I
with Wi ⊥ Vj for all i, j ∈ I, j 6= i and f 6⊥ Vi for all f ∈ Wi , i ∈ I.
Moreover, if {Wi }i∈I is a minimal frame of subspaces with respect to {vi }i∈I for
−1/2
H, then {SW,v Wi }i∈I is an orthogonal family of subspaces in H.
Proof. Suppose thatP(2) holds and towards a contradiction assume that there
exists i ∈ I and 0 6= f = j∈I,j6=i gj ∈ Wi with gj ∈ Wj . By (2), we have gj ⊥ Vi
for all j 6= i, hence f ⊥ Vi , but this is a contradiction. Thus (1) follows.
To prove the opposite direction suppose that {Wi }i∈I is minimal. For each
i ∈ I, let Pi denote the orthogonal projection onto spanj∈I,j6=i {Wj }. Let i ∈ I and
let Vi be defined by Vi = (I − Pi )H for all i ∈ I. By the definition of Vi , we have
Wj ⊥ Vi for all j 6= i. Towards a contradiction assume that there exists f ∈ Wi
with hf, gi = 0 for all g ∈ Vi . Then f ∈ Pi H and so Wi ∩ Pi H =
6 {0}, which is a
contradiction.
For the moreover part, let {vi eij }j∈Ji be an orthonormal basis for Wi for each
i ∈ I. By Proposition 3.17, SW,v is the frame operator for {vi eij }i∈I,j∈Ji . Since
{Wi }i∈I is minimal, Lemma 4.2 implies that {vi eij }i∈I,j∈Ji is a minimal frame for
−1/2
H and hence is a Riesz basis for H. Thus {SW,v vi eij }i∈I,j∈Ji is an orthonormal
sequence in H. Since we have
−1/2
−1/2
−1/2
SW,v Wi = spanj∈Ji {SW,v vi eij },
it follows that {SW,v Wi }i∈I,j∈Ji is an orthogonal sequence in H.
The next definition transfers the definition of Riesz bases and exact sequences
to families of subspaces in a canonical way. The so-called Riesz decomposition will
share most properties with Riesz bases. However it will turn out that being an
exact frame of subspaces is strictly weaker than being a Riesz decomposition, a
fact which differs from the situation in abstract frame theory.
Definition 4.4. We call a frame of subspaces {Wi }i∈I with respect to some
family of weights for H a Riesz decomposition
of H, if for every f ∈ H there is a
P
unique choice of fi ∈ Wi so that f = i∈I fi . A frame of subspaces with respect
to some family of weights is exact, if it ceases to be a frame of subspaces once one
element is deleted.
Lemma 4.5. Let {Wi }i∈I be a family of subspaces in H, and for each i ∈ I let
{eij }j∈Ji be an orthonormal basis for Wi .
(1) The following conditions are equivalent.
(a) {Wi }i∈I is a Riesz decomposition of H.
(b) {eij }i∈I,j∈Ji is a Riesz basis for H.
(c) {eij }i∈I,j∈Ji is an unconditional basis for H.
FRAMES OF SUBSPACES
17
(2) Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I for H. If
{vi eij }i∈I,j∈Ji is an exact frame for H, then also {Wi }i∈I is an exact
frame of subspaces with respect to {vi }i∈I for H. The opposite implication
is not valid.
Proof. First we prove (1). The equivalence (b) ⇔ (c) follows immediately
from the fact that {vi eij }i∈I,j∈Ji is bounded and that a Schauder basis is a Riesz
basis if and only if it is a bounded unconditional basis. The implication (b) ⇒ (a) is
obvious. To prove (a) ⇒ (c) assume that {eij }i∈I,j∈Ji is not an unconditional basis.
Hence
there exist P
f ∈ H and sequences {cij }i∈I,j∈Ji and {dij }i∈I,j∈Ji with f =
P
i0 ∈ I, j0 ∈ Ji0 .
c
e
=
ij
ij
i∈I,j∈Ji dij eij such that ci0 j0 6= di0 j0 for someP
i∈I,j∈Ji
By construction {ei0 j }j∈Ji0 is an orthonormal basis for Wi0 , hence j∈Ji ci0 j ei0 j 6=
0
P
j∈Ji0 di0 j ei0 j , which implies that {Wi }i∈I is not a Riesz decomposition.
To prove (2) suppose that {Wi }i∈I is a frame of subspaces with respect to
{vi }i∈I for H. By Theorem 3.2, {vi eij }i∈I,j∈Ji is a frame for H. If this is exact,
then, by definition, deleting one element vi0 ei0 j0 does not leave a frame. Thus also
{vi eij }i∈I\{i0 },j∈Ji does not form a frame. Applying Theorem 3.2 once more yields
the first claim. The fact that the opposite implication is not valid is demonstrated
by Example 4.7.
The next theorem is the analog of a well-known result in abstract frame theory
(see [9, Theorem 6.1.1]), only the role of exact frames of subspaces differs from the
frame situation.
Theorem 4.6. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I for
H. Then the following conditions are equivalent.
(1) {Wi }i∈I is a Riesz decomposition of H.
(2) {Wi }i∈I is minimal.
(3) The synthesis operator TW,v is one-to-one.
∗
(4) The analysis operator TW,v
is onto.
Moreover, if {Wi }i∈I is a Riesz decomposition of H, then it is also an exact frame
of subspaces for H. The opposite implication is not valid.
Proof. First note that (3) ⇔ (4) is always true for operators on a Hilbert
space. Moreover, it is obvious that (1) implies (3).
∗
Next we prove (4) ⇒ (1). By Theorem 3.12, TW,v
is an isomorphism. Therefore
if it is onto, then it is invertible. Hence,
T
is
invertible.
This implies that for
P W,v
so
that
⊕W
every f ∈ H there exists a {fi }i∈I ∈
i l2
i∈I
X
f = TW,v ({fi }i∈I ) =
vi fi .
i∈I
P
If we have f = i∈I fi = i∈I gi with {fi }, {gi } ∈
i∈I ⊕Wi l2 , then it follows
that TW,v ({vi−1 fi }i∈I ) = TW,v ({vi−1 gi }i∈I ). Since TW,v is one-to-one, {vi−1 fi }i∈I =
{vi−1 gi }i∈I and so fi = gi for all i ∈ I. This shows the equivalence of (1), (3), and
(4).
It remains to prove that (1) is equivalent to (2). If {Wi }i∈I is not a Riesz
decomposition of H, there exists anPelement fP∈ H and fi , gi ∈ Wi , i ∈ I with
fi0 6= gi0 for some i0 ∈ I and f = i∈I fi = i∈I gi . It follows 0 6= gi0 − fi0 =
P
i∈I,i6=i0 (fi − gi ) and gi0 − fi0 ∈ Wi0 . This proves
P
P
gi0 − fi0 ∈ Wi0 ∩ spani∈I,i6=i0 {Wi },
18
PETER G. CASAZZA AND GITTA KUTYNIOK
which implies that {Wi }i∈I is not minimal.
To prove the converse implicationPassume that {Wi }i∈I is not minimal. Then,
for some i0 ∈ I, there exists 0 6= f = i∈I,i6=i0 fi ∈ Wi0 with fi ∈ Wi . Hence
X
X
(fi − f ) =
0.
0=
i∈I
i∈I,i6=i0
Thus {Wi }i∈I is not a Riesz decomposition of H.
To prove the moreover part, suppose {Wi }i∈I is a frame of subspaces with
respect to {vi }i∈I for H and a Riesz decomposition of H. We will prove that this
∗
implies that {Wi }i∈I is exact. For this, fix some i0 ∈ I. Since TW,v
is onto, there
exists an element f ∈ H such that πWi0 (f ) 6= 0, but πWi (f ) = 0 for all i 6= i0 . Thus
X
vi2 kπWi (f )k2 = vi20 kπWi0 (f )k2 .
i∈I
Therefore it is not possible to delete Wi0 from the frame of subspaces yet leave a
frame of subspaces. Since i0 was chosen arbitrarily, the claim follows.
The fact that the opposite implication is not valid is demonstrated by Example
4.7.
Note that we could have also proven the equivalence of (1) and (2) and the
moreover part of the previous result by using Lemma 4.2, Lemma 4.5, and [9,
Theorem 6.1.1]. We have chosen to add the extended proof here in order to enlighten
the use of frames of subspaces.
Next we give an example for the different role exactness plays in the situation
of families of subspaces.
Example 4.7. Let {ei }i∈Z be an orthonormal basis for some Hilbert space H
and define the subspaces W1 , W2 by
W1 = spani≥0 {ei }
and W2 = spani≤0 {ei }.
Then {W1 , W2 } is a frame of subspaces with respect to weights {v1 , v2 } with v1 =
v2 =: v > 0, since
X
2
2
2
v1 kπW1 (f )k2 + v2 kπW2 (f )k2 =
v |hf, ei i| + v |hf, e0 i| = vkf k2 + v |hf, e0 i|
i∈Z
and
2
vkf k2 ≤ vkf k2 + v |hf, e0 i| ≤ 2vkf k2 .
It is also exact, since when we delete one subspace the remaining one does not span
the space. But it is not a Riesz decomposition, because we can write the element
e0 as e0 = e0 + 0 and e0 = 0 + e0 . Thus the decomposition is not unique. Also
observe that the sequence {vei }i≥0 ∪ {vei }i≤0 is a frame, but is not exact.
We conclude this subsection by mentioning that orthonormal bases of subspaces
are special cases of Riesz decompositions.
Corollary 4.8. If {Wi }i∈I is an orthonormal basis of subspaces for H, then
it is also a Riesz decomposition of H.
Proof. This follows immediately from the definition of a Riesz decomposition
and Proposition 3.23.
FRAMES OF SUBSPACES
19
5. Several constructions
In this section we will discuss several constructions concerning frames of subspaces, frames, and Riesz frames. Recall that in addition to what follows we are
already equipped with some constructions by Theorem 3.2, Corollary 3.21, and
Lemma 4.5.
5.1. Constructions of frames of subspaces. Dealing with Bessel families
of subspaces is important, since there are easy ways to turn such a family into a
frame of subspaces. One way is to just add the subspace W0 = H to the family.
Another more careful method is the following one: Take any orthonormal basis for
H and partition its elements into the subspaces Wi , i ∈ I. Then add the subspaces
spanned by the remaining elements to the Bessel family. This yields a frame of
subspaces.
Using the synthesis operator TW,v , we obtain a characterization of Bessel sequences of subspaces.
Proposition 5.1. Let {Wi }i∈I be a family of subspaces of H, and let {vi }i∈I
be a family of weights. Then the following conditions are equivalent.
(1) {Wi }i∈I is a Bessel sequence of subspaces with respect to {vi }i∈I for H.
(2) The synthesis operator TW,v is bounded and linear.
Proof. First suppose that (1) holds. Then Lemma 3.9 shows that the series in
the definition of the synthesis operator TW,v converges unconditionally. Moreover,
we have
X
vi2 kπWi (f )k2 ≤ Bkf k2 .
i∈I
∗
By definition of the analysis operator TW,v
,
X
∗
(5.1)
kTW,v
(f )k2 =
vi2 kπWi (f )k2 .
i∈I
Since {Wi }i∈I is a Bessel sequence of subspaces with respect to {vi }i∈I , this implies
∗
that TW,v
is bounded. Hence also TW,v is bounded, which shows (2).
∗
If (2) holds, then also TW,v
is a bounded operator. This fact together with (5.1)
yields (1).
One possible application for frames of subspaces is to the problem of classifying
those g ∈ L2 (R) and 0 < a, b ≤ 1 so that (g, a, b) yields a Gabor frame (see Example
5.4 below). This is an exceptionally deep problem even in the case of characteristic
functions [6, 20]. But we have simple classifications of when {e2πimbt g(t)}m∈Z is a
frame sequence in L2 (R) and when {e2πimbt g(t−na)}m,n∈Z has dense span in L2 (R).
By our results, this family will be a Gabor frame for L2 (R) if and only if {Wn }n∈Z
is a frame of subspaces where Wn is the closed linear span of {e2πimbt g(t− na)}m∈Z.
For some applications, we would like to take a frame for H and divide it into
subsets so that the closed linear span of these subsets is a frame of subspaces for H.
This is not always possible. But the next proposition shows that one of the needed
inequalities will always hold.
Proposition 5.2. Let {fj }j∈J be a frame for H with frame bounds A and B.
Let {Ji }i∈I be a partition of the indexing set J, and for all i ∈ I let Wi denote the
20
PETER G. CASAZZA AND GITTA KUTYNIOK
closed linear span of {fj }j∈Ji . Then for all f ∈ H we have
X
A
kf k2 ≤
kπWi (f )k2 .
B
i∈I
Hence, if |I| < ∞, then {Wi }i∈I is a 1-uniform frame of subspaces for H.
Proof. We compute
XX
X
XX
|hπWi (f ), fj i|2 .
|hf, fj i|2 =
Akf k2 ≤
|hf, fj i|2 =
j∈J
i∈I j∈Ji
i∈I j∈Ji
Recall that if a family of vectors is a B-Bessel family then every subfamily is also
B-Bessel. Thus
XX
X
|hπWi (f ), fj i|2 ≤
BkπWi (f )k2 .
i∈I j∈Ji
i∈I
This proves the first claim.
If |I| < ∞, then we have
X
i∈I
kπWi (f )k2 ≤ |I| · kf k2.
Hence in this case {Wi }i∈I is always a frame of subspaces for H, in particular a
1-uniform frame of subspaces.
An easy way to obtain a frame of subspaces is provided by the next result.
Proposition 5.3. Let {fj }j∈J be a frame for H, let J = J1 ∪ . . . ∪ Jn be a
finite partition of J, and let {vi }ni=1 be a family of weights. Then {Wi }ni=1 is a
frame of subspaces with respect to {vi }ni=1 for H, where Wi = spanj∈Ji {fj }.
Proof. Let f ∈ H. Obviously, kπWi (f )k2 ≤ kf k2 for all 1 ≤ i ≤ n, which
implies that
n
X
vi2 kπWi (f )k2 ≤ max {vi2 } · kf k2.
i=1
i=1,...,n
Thus {Wi }ni=1 is a Bessel sequence of subspaces with respect to {vi }ni=1 . The lower
bound follows from an application of Proposition 5.2. That is, for any f ∈ H we
have
X
X
A
1
kf k2 ≤
kπWi (f )k2 ≤
vi2 kπWi (f )k2 .
2
B
maxi=1,...,n {vi }
i∈I
i∈I
This partition of the frame elements is not always a partition into frame sequences. Let us consider the case of Gabor systems. In the following example we
will show that a large class of Gabor systems can be written as a frame of subspaces. Moreover, we can characterize those Gabor atoms, for which this partition
is a partition into frame sequences.
Example 5.4. For each a ∈ R, let the unitary operators Ea , Ta on L2 (R) be
defined by
Ea f (x) = e2πiax f (x) and Ta f (x) = f (x − a).
Given a function g ∈ L2 (R) and a, b > 0, the Gabor system determined by g and
a, b is defined by
G(g, a, b) = {Ema Tnb g : m, n ∈ Z}.
FRAMES OF SUBSPACES
Let
Z : L2 (R) → L2 ([0, 1)2 ),
Zf (x, y) =
X
21
f (x + k)e2πiky .
k∈Z
2
denote the Zak transform on L (R) (compare [19]).
Let h ∈ L2 (R) and q ∈ N. In the following we will consider some Gabor system
G(h, a, b) with a, b > 0, ab = q1 . Using a metaplectic transform it can be shown that
this system is unitarily equivalent to G(g, q1 , 1) for some g ∈ L2 (R) [16, Proposition
9.4.4], hence it suffices to consider this system. Now the Gabor system G(g, 1q , 1)
in turn can be decomposed using the partition
G(g, q1 , 1) =
(5.2)
q−1
[
j=0
{E 1q (mq+j) Tn g}m,n∈Z.
By Proposition 5.3, the set of the subspaces Wj := spanm,n∈Z {E 1q (mq+j) Tn g}, j =
0, . . . , q − 1 is indeed a frame of subspaces.
In a second step we will investigate, whether the sequences {E q1 (mq+j) Tn g}m,n∈Z
are frame sequences. It will turn out that this will not happen unless the Zak transform is discontinuous.
We first observe that the following conditions are equivalent.
(1) The sequence {E q1 (mq+j) Tn g}m,n∈Z is a frame sequence for each 0 ≤ j ≤
q − 1.
(2) There exist 0 < A ≤ B < ∞ such that
A ≤ |Zg(x, y)|2 ≤ B
for almost all (x, y) ∈ [0, 1)2 \V,
where V = {(x, y) ∈ [0, 1)2 : Zg(x, y) = 0}.
This can be proven as follows. First notice that since
E q1 ({E 1q (mq+j) Tn g}m,n∈Z ) = {E q1 (mq+j+1) Tn g}m,n∈Z
for all 0 ≤ j < q − 1
and
E 1q ({E q1 (mq+q−1) Tn g}m,n∈Z ) = {E q1 (mq) Tn g}m,n∈Z = {Em Tn g}m,n∈Z,
the fact that E 1q is a unitary operator implies that condition (1) holds if and
only if {Em Tn g}m,n∈Z is a frame sequence. Since Z : L2 (R) → L2 ([0, 1)2 ) is
an isomorphism [19] and it is an easy calculation to show that Z(Em Tn g)(x, y) =
Em (x)En (y)Zg(x, y), condition (1) holds if and only if {Em (x)En (y)Zg(x, y)}m,n∈Z
is a frame sequence. Since {Em En }m,n∈Z is an orthonormal basis for L2 ([0, 1)2 ),
for each f ∈ L2 ([0, 1)2 ) we obtain
X
2
2
|hf, Em En Zgi| = f · Zg .
m,n∈Z
This implies that (1) is equivalent to
2
A kf k ≤ f · Zg
2
2
for all f ∈ spanm,n∈Z {Em (x)En (y)Zg(x, y)},
≤ B kf k
which holds if and only if
A kf · Zgk2 ≤ f · |Zg|2
2
≤ B kf · Zgk2
for all f ∈ L2 ([0, 1)2 ).
It is easy to check that this is equivalent to (2), which proves the claim.
22
PETER G. CASAZZA AND GITTA KUTYNIOK
Finally, we consider g ∈ L2 (R) with Zg being continuous. By [19], this implies
that Zg has a zero. Hence condition (2) can never be fulfilled. This shows that the
sequences {E q1 (mq+j) Tn g}m,n∈Z can only be frame sequences, if the Zak transform
Zg is discontinuous.
5.2. Constructions of frames and Riesz frames. If we have a frame for
H, using a frame of subspaces for H we can construct new frames for H from these
components.
Proposition 5.5. Let {Wi }i∈I be a frame of subspaces with respect to {vi }i∈I
for H and let {fj }j∈J be a frame for H. Then there exist A, B > 0 so that
−1
(fj )}j∈J is a frame for Wi with frame bounds A and B for each i ∈ I.
{πWi SW,v
−1
(fj )}i∈I,j∈J is also a frame for H.
Hence {πWi SW,v
−1
Proof. Since SW,v
is an invertible operator on H and {fj }j∈J is a frame for H,
−1
we have that {SW,v fj }j∈J is a frame for H with frame bounds A and B. Therefore
−1
(fj )}j∈J is a frame for Wj with frame bounds A and B for every i ∈ I.
{πWi SW,v
−1
(fj )}i∈I,j∈J is
Since {Wi }i∈I is a frame of subspaces for H, we have that {πWi SW,v
a frame for H by Theorem 3.2.
To construct Riesz frames for H we first need to give an analog definition for
families of subspaces.
Definition 5.6. We call a frame of subspaces {Wi }i∈I a Riesz frame of subspaces with respect to {vi }i∈I , if there exist constants C, D > 0 so that every
subfamily {Wi }i∈J with J ⊂ I is a frame of subspaces with respect to {vi }i∈J for
its closed linear span with frame bounds C and D.
First we may ask whether subfamilies of a frame of subspaces are automatically
frames of subspaces for their closed linear spans. The following example shows that
this is not always the case.
Example 5.7. In general, if {Wi }i∈I is a 1-uniform frame of subspaces and
J ⊂ I, then {Wi }i∈J need not be a frame of subspaces for its closed linear span.
For example, let {ei }∞
i=1 be an orthonormal basis for H and for each i ∈ I define
the subspaces Wi1 , Wi2 , and Wi3 by
Wi1 = span{e2i + 1i e2i+1 },
Wi2 = span{e2i },
and Wi3 = span{e2i+1 }.
Then it is easily checked that {Wi1 , Wi2 , Wi3 }∞
i=1 is a frame of subspaces for H. Also
observe that spani=1,...,∞ {Wi1 , Wi2 } = H. Since for all positive integers i we have
1
πWi1 (e2i+1 ) = q
i 1+
1
i2
(e2i + 1i e2i+1 ) and πWi2 (e2i+1 ) = 0,
it follows that {Wi1 , Wi2 }∞
i=1 is not a frame of subspaces for its closed linear span.
Using a Riesz frame of subspaces and Riesz frames for the single subspaces, we
can construct a Riesz frame for H by just taking all elements of the Riesz frames.
Proposition 5.8. Let {Wi }i∈I be a Riesz frame of subspaces with respect to
{vi }i∈I for H, and let {fij }j∈Ii be a Riesz frame for Wi with Riesz frame bounds
A and B for all i ∈ I. Then {vi fij }i∈I,j∈Ii is a Riesz frame for H. Also, for any
J ⊂ I, {Wj }j∈J is a Riesz frame of subspaces with respect to {vi }i∈I for its closed
linear span.
FRAMES OF SUBSPACES
23
Proof. Let C and D be the Riesz frame of subspaces bounds for {Wi }i∈I . For
fi by
every i ∈ I choose Ji ⊂ Ii and define W
fi = span
W
j∈Ji {fij } ⊂ Wi .
Let f ∈ spani∈I,j∈Ji {fij }. Then we have
X
X X
X
2
2
2
|hf, vi fij i|2 =
vi2
|hπW
Bvi2 kπW
fi (f ), fij i| ≤
fi (f )k ≤ BDkf k .
i∈I,j∈Ji
i∈I
j∈Ji
i∈I
Concerning the lower bounds, we compute
X
X X
X
2
2
2
|hf, vi fij i|2 =
vi2
|hπW
Avi2 kπW
fi (f ), fij i| ≥
fi (f )k ≥ CAkf k .
i∈I,j∈Ji
i∈I
j∈Ji
i∈I
6. Harmonic frames of subspaces
Harmonic frames of subspaces are a special case of frames of subspaces, which
are equipped with a natural structure and which occur in several situations, e.g.,
in Gabor analysis or in wavelet analysis in the form of multiresolution analysis.
6.1. The finite case. We start by giving the definition of a harmonic frame
of subspaces for a finite family of subspaces.
Definition 6.1. A frame of subspaces {Wi }i∈I with respect to {vi }i∈I for H is
a finite harmonic frame of subspaces with respect to {vi }i∈I , if I = {0, . . . , N − 1},
N ∈ N and there exists a unitary operator U on H so that
U WN −1 = W0
and U Wi = Wi+1
for all 0 ≤ i ≤ N − 2.
If {Wi }i∈I is a uniform Parseval frame of subspaces, U WN −1 = W0 follows automatically as the following proposition shows. This result equals the corresponding
result in the frame situation [7, Theorem 4.1].
Theorem 6.2. Let {Wi }i∈I , |I| = N , be a uniform Parseval frame of subspaces
such that there exists a unitary operator U on H so that
U Wi = Wi+1
for all 0 ≤ i ≤ N − 2.
Then
U WN −1 = W0 .
Proof. Without loss of generality we can assume that vi = 1 for all i ∈ I.
Let {gj }j∈J be an orthonormal basis for W0 . By hypothesis, {U i gj }j∈J is an
orthonormal basis for Wi for all 0 ≤ i ≤ N − 1. Now let f ∈ H. By Proposition
3.23 and since {Wi }i∈I was assumed to be uniform, we have
(6.1)
f=
N
−1 X
X
i=0 j∈J
f, U i gj U i gj .
24
PETER G. CASAZZA AND GITTA KUTYNIOK
Applying U , this leads to
=
Uf
N
−1 X
X
U f, U i gj U i gj
i=0 j∈J
=
N
−1 X
X
f, U i−1 gj U i gj
i=0 j∈J
N
−1 X
X
= U
= U
i=0 j∈J
N
−2
X
X
f, U i−1 gj U i−1 gj
i=−1 j∈J
Since U is unitary and by (6.1), we obtain
f=
N
−2
X
X
f, U i gj U i gj .
f, U i gj U i gj =
i=−1 j∈J
N
−1 X
X
f, U i gj U i gj .
i=0 j∈J
This implies
X
f, U −1 gj U −1 gj =
j∈J
X
f, U N −1 gj U N −1 gj .
j∈J
Now we apply U , which yields
X
X
f, U −1 gj gj =
f, U N −1 gj U N gj .
j∈J
j∈J
Using U −1 f instead of f gives
X
X
hf, gj i gj =
f, U N gj U N gj ,
j∈J
j∈J
which shows that πW0 = πspanj∈J {U N gj } = πUWN −1 . This completes the proof.
The following result is [7, Theorem 4.2 and Theorem 4.3], which we add for
completeness in a reformulated version and with a proof using our results.
Proposition 6.3. Let ϕ ∈ H and let V be a unitary operator on H such
that {V j ϕ}M−1
j=0 is a uniform Parseval frame sequence. Define the subspace W0 by
W0 = spanj=0,...,M −1 {V j ϕ}. Further let U be a unitary operator on H. Then the
following conditions are equivalent.
M−1
(1) {U i V j ϕ}L−1,
i=0, j=0 is a uniform Parseval frame for H.
L−1
(2) {U i W0 }i=0 is a uniform Parseval frame of subspaces for H.
Proof. This follows immediately from Theorem 3.2 with setting Wi = U i W0
for all i = 1, . . . , L − 1.
We conclude this subsection by giving an example for this type of frames of
subspaces.
FRAMES OF SUBSPACES
25
Example 6.4. Let a ∈ R and g ∈ L2 (R) be such that {Eam Tn g}m,n∈Z is a
Parseval Gabor frame. Fix some N ∈ N and define Wi , 0 ≤ i ≤ N − 1, by
Wi = spanm,n∈Z {Ea(mN +i) Tn g}.
−1
Then {Wi }N
i=0 is a finite harmonic frame of subspaces. To see this let U := Ea .
Then
U WN −1 = W0 and U Wi = Wi+1 for all 0 ≤ i ≤ N − 2.
Also,
U i (EamN Tn g) = Ea(mN +i) Tn g.
Hence the sequences {Ea(mN +i) Tn g}m,n∈Z are even unitarily equivalent to each
other.
Notice that this construction generalizes the one in Example 5.4.
6.2. The infinite case. We can also define a harmonic frame of subspaces
for an infinite family of subspaces.
Definition 6.5. A frame of subspaces {Wi }i∈I with respect to {vi }i∈I for H is
an infinite harmonic frame of subspaces with respect to {vi }i∈I , if I = Z and there
exists a unitary operator U on H so that
U Wi = Wi+1
for all i ∈ I.
An interesting example for this type of frame of subspaces is the generalized
frame multiresolution analysis in the sense of Papadakis [21], which generalizes the
classical multiresolution analysis.
Example 6.6. Here we consider the generalized frame multiresolution analysis
in the sense of Papadakis [21], whose approach includes all classical multiresolution
analysis (MRAs) in one and higher dimensions as well as the FMRAs of Benedetto
and Li [2].
Let H be a Hilbert space, U : H → H be a unitary operator, and let G be
a unitary abelian group acting on H. A sequence {Vi }i∈Z of closed subspaces of
H is a generalized frame multiresolution analysis of H, if it satisfies the following
properties.
(1) Vi ⊆ Vi+1 for all i ∈ Z.
(2) Vi = U i (V0 ) for all i ∈ Z.
S
T
(3) i Vi = {0} and i Vi = H.
(4) There exists a countable subset B of V0 such that the set G(B) = {gφ :
g ∈ G, φ ∈ B} is a frame for V0 .
Now {Wi }i∈Z is defined by W0 := V1 ∩ V0⊥ and Wi := U i (W0 ) for every i ∈ Z.
Then we have
Wi = U i (V1 ∩ V0⊥ ) = U i (V1 ) ∩ U i (V0 )⊥ = Vi+1 ∩ Vi⊥ .
In the case H = L2 (R), G = {Tk : k ∈ Z}, B√containing only one element, and
U = D2 being the dilation operator D2 f (t) = 2f (2t) this definition reduces to
the well-known MRA.
In the general situation we have the following relations:
(i) If {Vi }i∈Z is a GFMRA of some Hilbert space H, then {Wi }i∈Z L
is an infinite 1-uniform harmonic Parseval frame of subspaces, since H = i∈Z Wi ,
with unitary operator U .
26
PETER G. CASAZZA AND GITTA KUTYNIOK
(ii) Let {Wi }i∈Z be an infinite 1-uniform harmonic Parseval frame of subspaces
with
L unitary operator denoted by U . By Proposition 3.23, we have H =
i∈Z Wi . Then we can define {Vi }i∈Z by
M
Vi =
Wm .
m≤i−1
Then (1)-(3) are obviously satisfied. Therefore {Wi }i∈Z is a GFMRA if
and only if (4) is satisfied.
Acknowledgments
The majority of the research for this paper was performed while the second
author was visiting the Departments of Mathematics at the University of Missouri
and Washington University in St. Louis. This author thanks these departments for
their hospitality and support during these visits.
The second author is indebted to Damir Bakić, Ilya Krishtal, Demetrio Labate,
Guido Weiss, and Ed Wilson for helpful discussions.
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Department of Mathematics, University of Missouri, Columbia, Missouri 65211 USA
E-mail address: pete@math.missouri.edu
Institute of Mathematics, University of Paderborn, 33095 Paderborn, Germany
E-mail address: gittak@uni-paderborn.de