SU37350A1 - The device for dividing the segment straight - Google Patents

Description

The proposed instrument is intended to mechanize the computational work in the interpolation of tachometric point marks for the construction of tablets and maps in horizontal lines. At the same time, it can be used for all sorts of designs where division into equal parts or finding the fractional parts of straight line segments is required. The device is made in the form of an i-harnessed frame, fitted on the sides with divisions of a certain scale and with a net of hairs taut inside, located parallel to the sides of the frame, and intended to divide the segment straight into equal parts. To set the direction of the divisible straight on the device, sliders are used, carrying rulers installed with the possibility of rotation and longitudinal displacement.

The drawing shows a top view of the device.

The proposed device consists of a metal frame 1, connected at the ends by hinges 3 and fitted on the sides with divisions of a certain scale. Inside the frame 7 is tensioned with a net 2 of thin metallic hairs attached to the frame pivotally. The indicated grid is intended to divide the straight line into equal parts. To set the direction of the divisible direct

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The device uses sliders 4, carrier bars 5, mounted with the possibility of rotation and longitudinal displacement.

The device is also equipped with a retractable ruler 6 with divisions of the same scale divided by frame 7. The frame 7 with the hair moves along the ruler 6.

To divide a straight line, suppose 107 lengths into eleven equal parts, move the device along ruler 5 by 107 m (the ruler must divide the corresponding scale), combine the ends of this cut with the intersection points of the hairs with the inner edges of the upper half of the frame against figures 11. The distance between the intersections of the hairs gives the desired value.

If it is required to divide the line by a number that exceeds the number of hairs in the frame, suppose 22, you should mark the line into eleven parts and, moving the whole device along the divisible line by V2 division, repeat the marking.

Marking on paper is done by vertical pressing on the hairs with a wooden roller, which speeds up and refines the work. If necessary, apply odd digits of the second order, for example. 21, line 5 should be set in direction 21-21. The intersection of the hairs with a ruler divided the line into twenty one parts. Each direct particle between the intersections of the hairs can be again divided by the ruler 5 into the required number of divisions. Suppose the 11th part of the segment ae must be divided into eight equal parts. To do this, find on the right side of the bottom (half) of the frame of the eighth hair, set the ruler 5 on the diagonal of the parallelogram axd in the direction of sa and move the slider 4 up to the intersection of the ruler with the point O on the eleventh hair. The path passed by the ruler in the direction of its part or ss of the whole segment ae. When moving further the ruler to the intersection O on the segment cte, parts of it are deposited, etc. If it is required, say, to find the segment ae, you should find the fifth hair on the left side of the upper half of the frame and move ruler 5 to the intersection with the eleventh hair ,four); In the segment ae, the desired quantity is deposited, i.e. f. Thus, to divide the straight segment 107 meters into 88 equal parts, it is necessary to divide the eleventh part into eight divisions, moving the entire device along the line, marking the whole segment ne For beginners, it is recommended to pre-compile a table indicating the number of divisions in the grid and the number of divisions of each individual cell, with dividers from 1 to 100, in order to quickly find the elements of which it is more convenient to divide the number of divisions in the grid. in the following way. Suppose it is necessary to find on the horizontal plane between the marks: at the point, 5 and at the point e of 66.3 m., Located at a distance of 107 m. The height difference 66.3-57.5 is determined by the ruler on the lower half of the frame. , 6 m, i.e. 88 tenth meters, we see that to get the 58th horizontal line from the a point, it is necessary to postpone it from the a point to the e / as side and the last, 66th horizontal line, side a% 8 of segment ae. Do this using the method specified; above, the distance between the points obtained is divided by a grid of 65-58 8 equal-j parts. At the intersection points of the hairs with the line ae and are the desired horizontals. The subject of the invention ..:,. A device for dividing a straight segment, characterized in that it is made in the form of a hinged frame / equipped on the sides with divisions of a certain scale and with a tension inside; mesh 2, consisting of hairs, spaced ;; parallel to the sides of the frame. and Intended for dividing the straight segment into equal parts. 2. In the device according to claim 1, the use of sliders 4, bearing bars 5, installed with the possibility of rotation and longitudinal displacement and used to set the direction divisible straight on the device.