CN114186400B - Equivalent modeling method of power electronic transformer based on H-bridge constant admittance unit - Google Patents
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Abstract
Description
技术领域Technical Field
本发明涉及一种基于H桥型定导纳单元的电力电子变压器等效建模方法,属于电力系统仿真技术领域。The invention relates to an equivalent modeling method for a power electronic transformer based on an H-bridge type constant admittance unit, and belongs to the technical field of power system simulation.
背景技术Background Art
电力电子变压器(power electronic transformer(PET))电磁暂态仿真面临“矩阵阶数高,仿真步长小,仿真效率低”的巨大挑战。现有已建立的PET串行等效模型,利用嵌套快速同时求解法降低系统节点数,有明显提速效果,但存在导纳不定,消去过程中每步长需进行矩阵求逆更新导纳值,模块数较多时会影响仿真效率的问题。The electromagnetic transient simulation of power electronic transformer (PET) faces the huge challenge of "high matrix order, small simulation step size, and low simulation efficiency". The existing PET serial equivalent model uses the nested fast simultaneous solution method to reduce the number of system nodes, which has a significant speed-up effect, but there is an uncertainty in admittance. During the elimination process, the matrix inversion needs to be performed at each step to update the admittance value, which will affect the simulation efficiency when the number of modules is large.
本发明针对电力电子变压器电磁暂态仿真效率较低的问题,提出一种基于H桥型定导纳单元的电力电子变压器等效建模方法。以PET中常见的4节点H桥型电路为单元,利用短路收缩推导其定导纳等效电路,按连接方式组合生成PET串行等效模型。模型建立过程规避矩阵求逆运算,节省了计算资源,提高了模型仿真速率。Aiming at the problem of low efficiency of electromagnetic transient simulation of power electronic transformer, the present invention proposes a power electronic transformer equivalent modeling method based on H-bridge type constant admittance unit. Taking the 4-node H-bridge circuit commonly seen in PET as a unit, the constant admittance equivalent circuit is derived by using short-circuit contraction, and the PET serial equivalent model is generated by combining according to the connection mode. The model establishment process avoids matrix inversion operation, saves computing resources, and improves the model simulation rate.
发明内容Summary of the invention
本发明提供一种基于H桥型定导纳单元的CHB-PET电磁暂态等效模型的建立方法,该建模方法包括以下步骤:The present invention provides a method for establishing a CHB-PET electromagnetic transient equivalent model based on an H-bridge type constant admittance unit, and the modeling method comprises the following steps:
步骤1:将开关组等效为二值电阻,将变压器、储能元件离散化处理,利用端口电压单步长近似对变压器原副边解耦,获取功率模块伴随电路。Step 1: Equivalently treat the switch group as a binary resistor, discretize the transformer and energy storage element, use the port voltage single-step approximation to decouple the primary and secondary sides of the transformer, and obtain the accompanying circuit of the power module.
步骤2:将功率模块划分为双有源桥(dual active bridge(DAB))单元1、2及输入侧H桥的单元H,利用短路收缩分别推导其定导纳等效电路,形成功率模块等效模型。Step 2: Divide the power module into dual active bridge (DAB) units 1 and 2 and unit H of the input side H bridge, and use short-circuit contraction to derive their fixed admittance equivalent circuits to form an equivalent model of the power module.
步骤3:考虑将功率模块高压侧戴维南电路串联、低压侧诺顿电路并联的连接方式,形成CHB-PET双端口解耦等效模型。Step 3: Consider connecting the Thevenin circuit on the high-voltage side of the power module in series and the Norton circuit on the low-voltage side in parallel to form a CHB-PET two-port decoupling equivalent model.
步骤4:将形成的等效模型代入外电路求解得端口电压电流量,利用端口电气量对功率模块端子电位、定导纳单元内部节点电压反解。Step 4: Substitute the formed equivalent model into the external circuit to solve the port voltage and current, and use the port electrical quantities to inversely solve the power module terminal potential and the internal node voltage of the constant admittance unit.
附图说明BRIEF DESCRIPTION OF THE DRAWINGS
图1 CHB-PET功率模块拓扑Figure 1 CHB-PET power module topology
图2基于H桥型定导纳单元的功率模块伴随电路(摘要附图)Figure 2 Power module companion circuit based on H-bridge constant admittance unit (Abstract attached)
图3功率模块等效电路Figure 3 Power module equivalent circuit
图4功率模块最终等效电路Figure 4 Final equivalent circuit of power module
图5 ISOP型CHB-PET双端口解耦等效模型Figure 5 ISOP type CHB-PET dual-port decoupling equivalent model
具体实施方式DETAILED DESCRIPTION
本发明提供一种基于H桥型定导纳单元的电力电子变压器等效建模方法;下面将对本发明的建模步骤做进一步详细的说明。The present invention provides a method for equivalent modeling of a power electronic transformer based on an H-bridge type constant admittance unit; the modeling steps of the present invention will be further described in detail below.
步骤1:Step 1:
CHB-PET单模块拓扑如图1所示,其中12个IGBT与二极管并联形成的“开关组”电路可等效为二值电阻“RON/ROFF”,取值由开关组导通信号决定;DAB输入、输出侧电容C1、C2分别由梯形积分法离散化为诺顿等效电路形式。The CHB-PET single module topology is shown in Figure 1, where the "switch group" circuit formed by 12 IGBTs and diodes in parallel can be equivalent to a binary resistor "R ON /R OFF ", and the value is determined by the switch group conduction signal; the DAB input and output side capacitors C 1 and C 2 are discretized into Norton equivalent circuit forms by the trapezoidal integration method.
DAB中的高频隔离变压器采用梯形积分法离散化处理,利用端口电压单步长近似解除原副边电气耦合,整理为两个诺顿等效电路的形式,如式(1)所示。忽略变压器铜损、铁损,LA为变压器原副边之间的辅助电感,L1、L2分别为变压器原副边漏抗,Lm为变压器励磁电抗,Δt为系统仿真步长。The high-frequency isolation transformer in DAB is discretized by trapezoidal integration method, and the electrical coupling between the primary and secondary sides is approximately released by using the single step of port voltage, which is organized into two Norton equivalent circuits, as shown in equation (1). Ignoring the copper loss and iron loss of the transformer, LA is the auxiliary inductance between the primary and secondary sides of the transformer, L1 and L2 are the leakage reactance of the primary and secondary sides of the transformer, Lm is the transformer excitation reactance, and Δt is the system simulation step.
其中 in
此时变压器等效为两个独立的诺顿电路,其中GT1=Y11、GT2=Y22为等效导纳且均为定值,jT1-H(t)、jT2-H(t)为单步长更新的等效电流源。jT1-H(t)、jT2-H(t)仅与上一时刻的端口电压电流值有关,实现变压器原副边解耦。经过上述过程,功率模块可等效为图2的伴随电路形式。At this time, the transformer is equivalent to two independent Norton circuits, where G T1 = Y 11 and G T2 = Y 22 are equivalent admittances and are both constant values, and j T1-H (t) and j T2-H (t) are equivalent current sources updated in a single step. j T1-H (t) and j T2-H (t) are only related to the port voltage and current values at the previous moment, realizing the decoupling of the primary and secondary sides of the transformer. After the above process, the power module can be equivalent to the accompanying circuit form of Figure 2.
步骤2:Step 2:
将功率模块划分为DAB的单元1、2以及输入侧H桥的单元H。单元1与单元2有着相同的电路结构,均为4节点的H桥型电路单元。在非闭锁运行工况下,DAB的开关组状态满足同桥臂互补,其工作模式可用开关函数T11、T12表示,见式(2):The power module is divided into DAB units 1 and 2 and input side H-bridge unit H. Unit 1 and unit 2 have the same circuit structure, both of which are 4-node H-bridge circuit units. Under non-locking operation conditions, the switch group state of DAB satisfies the complementarity of the same bridge arm, and its working mode can be expressed by the switch function T 11 and T 12 , as shown in formula (2):
因此,单元1、2的工作模式仅有4种,其等效导纳也至多为4种。以单元1为例推导其定导纳形式,首先列写单元1节点导纳方程如式(3),记为式(4)的分块矩阵形式:Therefore, there are only 4 working modes for units 1 and 2, and their equivalent admittances are also at most 4. Taking unit 1 as an example to derive its definite admittance form, first write the node admittance equation of unit 1 as formula (3), which is recorded as the block matrix form of formula (4):
利用短路收缩消去单元1的内部节点,得到仅含外端子H1、H2的等效电路表达式如式(5)所示:By using the short-circuit contraction to eliminate the internal nodes of unit 1, the equivalent circuit expression containing only the external terminals H1 and H2 is obtained as shown in equation (5):
其中,Y1-EX为单元1对外等效导纳矩阵,J1-S为等效历史电流源。经过外电路EMT解算得到外端子电位后,可利用式(6)反解内部节点电压。Among them, Y 1-EX is the external equivalent admittance matrix of unit 1, and J 1-S is the equivalent historical current source. After the external terminal potential is obtained by EMT solution of the external circuit, the internal node voltage can be inversely solved using formula (6).
为了简化计算结果,记:In order to simplify the calculation results, remember:
式(6)中Y1-22为2阶对称矩阵,其逆矩阵可直接求得,如式(8)所示:In formula (6), Y 1-22 is a 2nd-order symmetric matrix, and its inverse matrix is It can be directly obtained as shown in formula (8):
其中 in
d11、d12均为常数,将式(7)、式(8)代入式(5)中可求得Y1-EX与J1-S。此时单元1短路收缩为2节点诺顿等效电路,其中Geq1=Y1-EX(1,1),Jeq1=J1-S(2)。结合桥臂开关状态,可推导出单元1的等效电路参数:d 11 and d 12 are both constants. Substituting equations (7) and (8) into equation (5), we can obtain Y 1-EX and J 1-S . At this time, unit 1 is short-circuited and shrinks to a 2-node Norton equivalent circuit, where G eq1 = Y 1-EX (1,1) and J eq1 = J 1-S (2). Combined with the switch state of the bridge arm, the equivalent circuit parameters of unit 1 can be derived:
由式(10),考虑所有工作模式,单元1的等效电导取值仅含三种确定的情况,为定导纳单元。单元2的推导过程与单元1相同,由此功率模块等效为图3所示。According to formula (10), considering all working modes, the equivalent conductance value of unit 1 only contains three certain cases, which is a fixed admittance unit. The derivation process of unit 2 is the same as that of unit 1, so the power module is equivalent to that shown in Figure 3.
此时单元H仍为4节点电路,在非闭锁状态下,CHB的H桥运行模式包括投入与旁路两种模式,且均满足同桥臂开关信号互补,也可推导为定导纳单元。推导过程如下,列写单元H的节点导纳方程,并求取逆矩阵 At this time, unit H is still a 4-node circuit. In the non-locked state, the H-bridge operation mode of CHB includes two modes: input and bypass, and both satisfy the complementary signal of the same bridge arm switch. It can also be derived as a fixed admittance unit. The derivation process is as follows: write the node admittance equation of unit H and obtain the inverse matrix
其中 in
当H桥投入时,满足TH1≠TH2,此时单元H的等效电导与单元1的第一种情况形式相同:When the H bridge is put into operation, TH1 ≠ TH2 is satisfied. At this time, the equivalent conductance of unit H is the same as that of the first case of unit 1:
GeqH=GS-GRdZ1-2GXdZ2 (13)G eqH =G S -G R d Z1 -2G X d Z2 (13)
JeqH=KHGB(dZ2-dZ1)Jeq1 J eqH =K H G B (d Z2 -d Z1 )J eq1
其中 in
当H桥旁路时,满足TH1=TH2,此时有:When the H bridge is bypassed, T H1 = T H2 , then:
GeqH=GS-dP (17)G eqH =G S -d P (17)
JeqH=0 (18)J eqH = 0 (18)
功率模块最终等效为图4所示的双端口解耦等效电路。其中等效电导均为定值,仿真时根据控制信号选取;等效历史电流源由储能元件历史电流源单步长更新,与控制信号有关。The power module is ultimately equivalent to the two-port decoupling equivalent circuit shown in Figure 4. The equivalent conductances are all constant values, which are selected according to the control signal during simulation; the equivalent historical current source is updated by the energy storage element historical current source in a single step, which is related to the control signal.
步骤3:Step 3:
考虑到功率模块ISOP型的连接方式,可将高压侧的诺顿电路转变为戴维南形式,最后按高压侧串联,低压侧并联的方式将N个等效电路连接,形成CHB-PET双端口解耦等效模型如图4所示,等效参数计算式如式(19)所示。其中S表示串联侧,P表示并联侧,N表示模块个数,i为模块编号。Considering the connection mode of the ISOP type power module, the Norton circuit on the high voltage side can be transformed into the Thevenin form, and finally the N equivalent circuits are connected in series on the high voltage side and in parallel on the low voltage side to form the CHB-PET two-port decoupling equivalent model as shown in Figure 4. The equivalent parameter calculation formula is shown in formula (19). Where S represents the series side, P represents the parallel side, N represents the number of modules, and i is the module number.
步骤4:Step 4:
将形成的等效模型代入外电路求得端口电压电流量VS、IS、VP、IP,强制定义模块的2、4端子为虚拟地节点,此时1、3端子电位分别为两侧端口的电位差。以图4中功率模块i为例,其端子电位分别为vi1、vi2、vi3、vi4,其计算式如下:Substitute the formed equivalent model into the external circuit to obtain the port voltage and current V S , I S , V P , and I P , and define the 2nd and 4th terminals of the module as virtual ground nodes. At this time, the potentials of the 1st and 3rd terminals are the potential differences of the ports on both sides. Taking the power module i in Figure 4 as an example, its terminal potentials are vi1 , vi2 , vi3 , and vi4 , respectively, and the calculation formula is as follows:
求得端子电位后,对于高压侧,由vi1、vi2反解单元H内部节点电压,得到单元1端口电压后继续反解单元1;对于低压侧,由vi3、vi4直接反解单元2节点电压。After obtaining the terminal potential, for the high-voltage side, the internal node voltage of unit H is inverted from vi1 and vi2 , and after obtaining the port voltage of unit 1, the inverted unit 1 is continued; for the low-voltage side, the node voltage of unit 2 is directly inverted from vi3 and vi4 .
对于定导纳单元内部节点电压反解,以单元1为例,结合控制方式与定导纳单元推导过程,可将式(6)推导为如下形式:For the inverse solution of the internal node voltage of the constant admittance unit, taking unit 1 as an example, combined with the control method and the derivation process of the constant admittance unit, equation (6) can be derived as follows:
其中 in
此时内部电压的反解过程仅由一个系数矩阵体现,矩阵各元素取值如下:At this time, the inverse solution process of the internal voltage is only reflected by a coefficient matrix, and the values of each element of the matrix are as follows:
结合单元1的工作状态,该系数矩阵仅含四种情况,可预计算存储,其取值如下::Combined with the working state of unit 1, the coefficient matrix contains only four cases, which can be pre-calculated and stored, and its values are as follows:
其中 in
其中c1~c5均为定值,取值如表1所示:Among them, c 1 ~ c 5 are all fixed values, and their values are shown in Table 1:
表1单元1系数矩阵取值表Table 1 Unit 1 coefficient matrix value table
类似得,可得到单元H、单元2的反解表达式,如下表2,系数矩阵A2×3、B2×3也都为随开关函数变化的常数阵。Similarly, the inverse expressions of unit H and unit 2 can be obtained, as shown in Table 2. The coefficient matrices A 2×3 and B 2×3 are also constant matrices that vary with the switching function.
表2定导纳单元反解表达式Table 2 Inverse solution expression of constant admittance unit
反解得到各节点电压之后,储能历史电流源更新,准备进入下一步长模型解算。After the voltage of each node is obtained by inverse solution, the energy storage historical current source is updated and ready to enter the next step of long model solution.
最后应当说明的是:所描述的实施例仅是本申请一部分实施例,而不是全部的实施例。基于本申请中的实施例,本领域普通技术人员在没有做出创造性劳动前提下所获得的所有其他实施例,都属于本申请保护的范围。Finally, it should be noted that the described embodiments are only part of the embodiments of this application, not all of the embodiments. Based on the embodiments in this application, all other embodiments obtained by ordinary technicians in this field without creative work are within the scope of protection of this application.
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