CN111574334B - Novel phenolic compound and preparation method and application thereof - Google Patents
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Abstract
Description
技术领域technical field
本发明涉及酚类化合物的制备技术领域,尤其涉及一种新型酚类化合物及其制备方法与应用。The invention relates to the technical field of preparation of phenolic compounds, in particular to a novel phenolic compound and its preparation method and application.
背景技术Background technique
细菌感染日益成为危害公共健康的隐患,而抗生素的滥用又导致了大量的细菌出现耐药性。在革兰氏阳性菌中,最重要的耐药菌是耐甲氧西林的金黄色葡萄球菌,这严重的影响了人类的身体健康。抗菌剂是抗菌材料的核心成分,它具有杀灭或抑制微生物的功能。专利申请CN106667994A公开了低聚多酚类化合物在制备抗革兰氏阳性耐药菌产品的应用,且所述的低聚多酚类化合物为反式结构的二聚体和三聚体低聚多酚类化合物,所述的二聚体和三聚体白藜芦醇低聚多酚类化合物为化合物1:反式-D-葡萄素和化合物II:龙胆H,所述的二聚体抗耐药菌性较三聚体的抗耐药菌性更强,二聚体反式-D-葡萄素的抗耐药菌MIC值为8μg/mL,三聚体龙胆H的抗耐药菌MIC值为16μg/mL。但是这两种低聚多酚类化合物的MIC仍然较高。Bacterial infection has increasingly become a hidden danger to public health, and the abuse of antibiotics has led to the emergence of drug resistance in a large number of bacteria. Among Gram-positive bacteria, the most important drug-resistant bacteria is methicillin-resistant Staphylococcus aureus, which seriously affects human health. Antibacterial agents are the core components of antibacterial materials, which have the function of killing or inhibiting microorganisms. Patent application CN106667994A discloses the application of oligomeric polyphenolic compounds in the preparation of products against Gram-positive drug-resistant bacteria, and the oligomeric polyphenolic compounds are trans-structure dimers and trimers of oligomeric polyphenols Phenolic compounds, the dimer and trimer resveratrol oligomeric polyphenolic compounds are compound 1: trans-D-glucoside and compound II: gentian H, the dimer anti The resistance to drug-resistant bacteria is stronger than that of the trimer. The MIC value of the anti-drug-resistant bacteria of the dimer trans-D-glucose is 8 μg/mL, and the anti-drug-resistant bacteria of the trimeric gentian H The MIC value was 16 μg/mL. But the MICs of these two oligomeric polyphenolic compounds were still high.
因此,如何制备一种抗菌效果更好的抗革兰氏阳性耐药菌产品,成为亟待解决的技术问题。Therefore, how to prepare a product with better antibacterial effect against Gram-positive drug-resistant bacteria has become an urgent technical problem to be solved.
发明内容Contents of the invention
本发明的目的是提供一种新型酚类化合物及其制备方法与应用,所述新型酚类化合物够显著抑制革兰氏阳性菌的生长,对金黄色葡萄球菌、枯草芽孢杆菌、耐甲氧西林金黄色葡萄球菌的最小抑菌浓度为1~4μg/mL。The object of the present invention is to provide a kind of novel phenolic compound and its preparation method and application, described novel phenolic compound can significantly inhibit the growth of Gram-positive bacteria, and is resistant to Staphylococcus aureus, Bacillus subtilis, methicillin The minimum inhibitory concentration of Staphylococcus aureus is 1-4 μg/mL.
为了实现上述目的,本发明的目的之一在于提供一种新型酚类化合物,所述新型酚类化合物的化学通式为:In order to achieve the above object, one of the objects of the present invention is to provide a novel phenolic compound, the general chemical formula of the novel phenolic compound is:
其中,R=Br、Cl或F。where R=Br, Cl or F.
本发明的目的之二在于提供一种新型酚类化合物的制备方法,所述式(1)的新型酚类化合物中R=Br或者Cl时,所述制备方法包括:The second object of the present invention is to provide a kind of preparation method of novel phenolic compound, when R=Br or Cl in the novel phenolic compound of described formula (1), described preparation method comprises:
将4-羟基二苯甲烷与含卤素的化合物反应,得到化合物II,所述卤素包括溴或氯;4-hydroxydiphenylmethane is reacted with a halogen-containing compound to obtain compound II, and the halogen includes bromine or chlorine;
将所述化合物II与乙酰氯反应,得到化合物III;Reaction of the compound II with acetyl chloride to obtain the compound III;
将所述化合物III与苯酚溶液反应,得到所述新型酚类化合物;reacting the compound III with a phenol solution to obtain the novel phenolic compound;
其中所述化合物II的化学通式为以下式(2);所述化合物III的化学通式为式(3);Wherein the general chemical formula of the compound II is the following formula (2); the general chemical formula of the compound III is the formula (3);
所述式(2)和式(3)中,R1=Br或Cl。In the formula (2) and formula (3), R1=Br or Cl.
进一步地,所述将4-羟基二苯甲烷与含卤素的化合物反应,包括:Further, the reaction of 4-hydroxydiphenylmethane with halogen-containing compounds includes:
将4-羟基二苯甲烷与含卤素的化合物溶于醋酸或甲醇溶剂中,并在5~25℃温度条件下进行反应。Dissolving 4-hydroxydiphenylmethane and halogen-containing compounds in acetic acid or methanol solvent, and reacting at a temperature of 5-25°C.
进一步地,所述将所述化合物II与乙酰氯反应,包括:Further, the reaction of the compound II with acetyl chloride includes:
将所述化合物II与乙酰氯溶于二氯甲烷溶剂中,并在催化剂AlCl3和5~25℃温度条件下进行反应。The compound II and acetyl chloride were dissolved in dichloromethane solvent, and reacted under the conditions of catalyst AlCl 3 and temperature of 5-25°C.
进一步地,所述将所述化合物III与苯酚溶液反应,包括:Further, the reaction of the compound III with a phenol solution includes:
将所述化合物III溶于苯酚溶液中,并在25~65℃温度条件下加入甲苯磺酸并搅拌反应。The compound III is dissolved in a phenol solution, and toluenesulfonic acid is added under the temperature condition of 25-65° C. and stirred for reaction.
本发明的目的之三在于提供一种新型酚类化合物的制备方法,所述式(1)的新型酚类化合物中R=F时,所述制备方法包括:The third object of the present invention is to provide a kind of preparation method of novel phenolic compound, when R=F in the novel phenolic compound of described formula (1), described preparation method comprises:
将4-Br-2,6-二氟苯酚与溴甲苯反应,得到5-Br-1,3-二氟-2-苯基-甲氧基苯;4-Br-2,6-difluorophenol was reacted with bromotoluene to obtain 5-Br-1,3-difluoro-2-phenyl-methoxybenzene;
将所述5-Br-1,3-二氟-2-苯基-甲氧基苯与苄基氯化镁反应,得到4-苄基-2,6-二氯基-甲氧基苯;reacting the 5-Br-1,3-difluoro-2-phenyl-methoxybenzene with benzylmagnesium chloride to obtain 4-benzyl-2,6-dichloro-methoxybenzene;
将所述4-苄基-2,6-二氯基-甲氧基苯进行还原反应,得到4-苄基-2,6-二氟苯酚;Reducing the 4-benzyl-2,6-dichloro-methoxybenzene to obtain 4-benzyl-2,6-difluorophenol;
将所述4-苄基-2,6-二氟苯酚与乙酰氯反应,得到4-(4-乙酰苄基)-2,6-双氟苯基乙酸;reacting the 4-benzyl-2,6-difluorophenol with acetyl chloride to obtain 4-(4-acetylbenzyl)-2,6-difluorophenylacetic acid;
将所述4-(4-乙酰苄基)-2,6-双氟苯基乙酸与苯酚溶液反应得到所述新型酚类化合物。The 4-(4-acetylbenzyl)-2,6-difluorophenylacetic acid is reacted with a phenol solution to obtain the novel phenolic compound.
进一步地,所述将4-Br-2,6-二氟苯酚与溴甲苯反应,包括:Further, the reaction of 4-Br-2,6-difluorophenol with bromotoluene includes:
将4-Br-2,6-二氟苯酚溶于DMF溶液中,并在N2氛围下加入碱性物质搅拌,搅拌后加入溴甲苯进行反应。Dissolve 4-Br-2,6-difluorophenol in DMF solution, and add basic substance to stir under N 2 atmosphere, after stirring, add bromotoluene to react.
进一步地,所述将所述5-Br-1,3-二氟-2-苯基-甲氧基苯与苄基氯化镁反应,包括:Further, the reaction of the 5-Br-1,3-difluoro-2-phenyl-methoxybenzene with benzylmagnesium chloride includes:
将ZnBr2和THF混合,得到第一混合溶液;ZnBr 2 and THF are mixed to obtain the first mixed solution;
在N2氛围下,将所述苄基氯化镁和所述第一混合溶液混合并搅拌,搅拌后加入5-Br-1,3-二氟-2-苯基-甲氧基苯进行反应。Under N 2 atmosphere, the benzylmagnesium chloride and the first mixed solution were mixed and stirred, and after stirring, 5-Br-1,3-difluoro-2-phenyl-methoxybenzene was added for reaction.
本发明的目的之四在于提供了所述的新型酚类化合物在制备革兰氏阳性菌抗菌剂中的应用。The fourth object of the present invention is to provide the application of the novel phenolic compound in the preparation of antibacterial agents for Gram-positive bacteria.
进一步地,所述革兰氏阳性菌包括金黄色葡萄球菌、枯草芽孢杆菌、耐甲氧西林金黄色葡萄球菌。Further, the Gram-positive bacteria include Staphylococcus aureus, Bacillus subtilis, and methicillin-resistant Staphylococcus aureus.
本发明实施例中的一个或多个技术方案,至少具有如下技术效果或优点:One or more technical solutions in the embodiments of the present invention have at least the following technical effects or advantages:
本发明提供的一种新型酚类化合物,能够显著抑制革兰氏阳性菌的生长,对金黄色葡萄球菌、枯草芽孢杆菌、耐甲氧西林金黄色葡的最小抑菌浓度为1~4μg/mL,且在长时间低剂量暴露下不产生耐药性,可见该新型酚类化合物可作为革兰氏阳性菌抗菌剂,抗菌效果好,是良好的抗菌剂。A novel phenolic compound provided by the invention can significantly inhibit the growth of Gram-positive bacteria, and the minimum inhibitory concentration for Staphylococcus aureus, Bacillus subtilis, and methicillin-resistant Graupus aureus is 1-4 μg/mL , and does not produce drug resistance under long-term low-dose exposure, it can be seen that the new phenolic compound can be used as an antibacterial agent for Gram-positive bacteria, with good antibacterial effect, and is a good antibacterial agent.
附图说明Description of drawings
为了更清楚地说明本发明实施例中的技术方案,下面将对实施例描述中所需要使用的附图作一简单地介绍,显而易见地,下面描述中的附图是本发明的一些实施例,对于本领域普通技术人员来讲,在不付出创造性劳动的前提下,还可以根据这些附图得到其它的附图。In order to more clearly illustrate the technical solutions in the embodiments of the present invention, the following will briefly introduce the drawings that need to be used in the description of the embodiments. Obviously, the drawings in the following description are some embodiments of the present invention. For those skilled in the art, other drawings can also be obtained based on these drawings without any creative effort.
图1是本发明实施例1制备得到新型酚类化合物的质谱图;Fig. 1 is the mass spectrogram of the novel phenolic compound prepared in Example 1 of the present invention;
图2是本发明实施例2制备得到新型酚类化合物的质谱图;Fig. 2 is the mass spectrogram of the novel phenolic compound prepared by Example 2 of the present invention;
图3是本发明实施例3制备得到新型酚类化合物的质谱图。Fig. 3 is the mass spectrogram of the novel phenolic compound prepared in Example 3 of the present invention.
具体实施方式Detailed ways
下文将结合具体实施方式和实施例,具体阐述本发明,本发明的优点和各种效果将由此更加清楚地呈现。本领域技术人员应理解,这些具体实施方式和实施例是用于说明本发明,而非限制本发明。The present invention will be described in detail below in conjunction with specific embodiments and examples, and the advantages and various effects of the present invention will be presented more clearly. Those skilled in the art should understand that these specific implementations and examples are used to illustrate the present invention, not to limit the present invention.
在整个说明书中,除非另有特别说明,本文使用的术语应理解为如本领域中通常所使用的含义。因此,除非另有定义,本文使用的所有技术和科学术语具有与本发明所属领域技术人员的一般理解相同的含义。若存在矛盾,本说明书优先。Throughout the specification, unless otherwise specified, terms used herein should be understood as commonly used in the art. Therefore, unless otherwise defined, all technical and scientific terms used herein have the same meaning as commonly understood by one of ordinary skill in the art to which this invention belongs. In case of conflict, this specification shall take precedence.
除非另有特别说明,本发明中用到的各种原材料、试剂、仪器和设备等,均可通过市场购买得到或者可通过现有方法制备得到。Unless otherwise specified, various raw materials, reagents, instruments and equipment used in the present invention can be purchased from the market or prepared by existing methods.
本发明实施例提供的技术方案为解决上述技术问题,总体思路如下:The technical solutions provided by the embodiments of the present invention are to solve the above-mentioned technical problems, and the general idea is as follows:
为实现上述目的,本实施例提供一种新型酚类化合物,所述新型酚类化合物的化学通式为:In order to achieve the above purpose, this embodiment provides a novel phenolic compound, the general chemical formula of which is:
其中,R=Br、Cl或F。where R=Br, Cl or F.
本发明实施例还提供了所述新型酚类化合物的制备方法:The embodiment of the present invention also provides the preparation method of described novel phenolic compound:
1、所述式(1)的新型酚类化合物中R=Br或者Cl时,所述制备方法包括:1. When R=Br or Cl in the novel phenolic compound of the formula (1), the preparation method comprises:
步骤1、将4-羟基二苯甲烷与含卤素的化合物反应,得到化合物II,所述卤素包括溴或氯;具体地,Step 1, reacting 4-hydroxydiphenylmethane with a halogen-containing compound to obtain compound II, and the halogen includes bromine or chlorine; specifically,
(1)当R=Br时,将4-羟基二苯甲烷溶解于醋酸溶液中后,可直接通入溴气反应,所述含卤素的化合物即为溴气,其中4-羟基二苯甲烷与溴气的摩尔比优选范围为15~17:32~34,在该摩尔比范围内能够充分反应;(1) when R=Br, after 4-hydroxyl diphenylmethane is dissolved in the acetic acid solution, can directly pass into bromine gas reaction, and described halogen-containing compound is bromine gas, and wherein 4-hydroxyl diphenylmethane and The molar ratio of bromine gas preferably ranges from 15 to 17:32 to 34, and can fully react within this molar ratio range;
优选地,所述反应还加入了有机溶剂,所述有机溶剂油氯仿、醋酸、甲醇等,本实施例优选醋酸AcOH,因为根据实验发现对该结构来说用醋酸收率最高。Preferably, the reaction has also added an organic solvent, such as chloroform, acetic acid, methanol, etc., the preferred AcOH acetate in the present embodiment, because according to experiments, it is found that the yield of acetic acid is the highest for this structure.
(2)当R=Cl时,由于通入氯气反应效率低,本申请将4-羟基二苯甲烷溶解于甲醇溶液后,加入NaOH、NaCl、NaClO的混合物作为所述含卤素的化合物,(2) When R=Cl, due to the low reaction efficiency of introducing chlorine gas, the applicant dissolves 4-hydroxydiphenylmethane in methanol solution, and then adds a mixture of NaOH, NaCl, and NaClO as the halogen-containing compound,
所述NaOH、NaCl、NaClO的摩尔比优选为2~3:4.5~5:4.5~5;NaOH、NaCl、NaClO的摩尔比这样选择的原因在于:本申请人首先选用摩尔比是1.5:3:3,发现有原料剩余,经过原因分析发现这可能是由于NaClO的有效含量不够的,所以我们进行了筛选,发现增加NaClO的当量可以使反应完全。所以本申请经过一系列实验的探索发现最终NaOH、NaCl、NaClO的摩尔比选在2~3:4.5~5:4.5~5的范围能够使得反应完全。The molar ratio of NaOH, NaCl, and NaClO is preferably 2 to 3:4.5 to 5:4.5 to 5; the reason why the molar ratio of NaOH, NaCl, and NaClO is selected in this way is that the applicant first chooses a molar ratio of 1.5:3: 3. It was found that there was a surplus of raw materials. After reason analysis, it was found that this may be due to insufficient effective content of NaClO, so we screened and found that increasing the equivalent of NaClO can make the reaction complete. Therefore, after a series of experiments, the present application finds that the final molar ratio of NaOH, NaCl, and NaClO in the range of 2-3:4.5-5:4.5-5 can make the reaction complete.
优选地,所述反应还加入了有机溶剂,所述有机溶剂油氯仿、醋酸、甲醇等,本实施例优选甲醇MeOH,因为根据实验发现对该结构来说用甲醇收率最高。Preferably, the reaction has also added an organic solvent, such as chloroform, acetic acid, methanol, etc., the preferred methanol MeOH in this embodiment, because according to the experiment, it is found that the yield of methanol is the highest for this structure.
步骤2、将所述化合物II与乙酰氯反应,得到化合物III;Step 2, reacting the compound II with acetyl chloride to obtain compound III;
优选地,所述反应在二氯甲烷溶剂中进行,并加入催化剂AlCl3,所述反应的温度为5~25℃;Preferably, the reaction is carried out in a dichloromethane solvent, and a catalyst AlCl 3 is added, and the reaction temperature is 5-25°C;
所述反应是很典型的傅克酰基化反应,对于这类反应:反应的溶剂最常用为二氯甲烷,还有二氯乙烷和二硫化碳等;反应的催化剂最常用为三氯化铝,还有无水氯化锌、三氯化铁、四氯化钛等;该反应选择二氯甲烷作溶剂,AlCl3作为催化剂,完全是因为这两样东西均廉价易得,而且收率还可以,适于放大;Described reaction is very typical Friedel-Crafts acylation reaction, for this type of reaction: the solvent of reaction is the most commonly used methylene dichloride, also has dichloroethane and carbon disulfide etc.; The catalyzer of reaction is most commonly used as aluminum trichloride, also There are anhydrous zinc chloride, iron trichloride, titanium tetrachloride etc.; This reaction selects dichloromethane as solvent, AlCl as catalyst, because these two things are all cheap and easy to get, and the yield is OK, suitable to enlarge;
先加入乙酰氯是为了将酚羟基保护起来;这一过程,温度在5~25℃之间几乎没什么影响,但是温度过高的话可能会导致保护酚羟基的乙酰基掉下来,这样在后面加入AlCl3进行傅克酰基化反应时,会由于酚羟基的强定位效应而发生副反应;加入AlCl3时,温度不宜过高(更为优选为5~15℃),这样一是为了防止反应过于剧烈,二是担心体系内局部温度过高导致副反应发生;加料完毕,自然升温至室温即可。The purpose of adding acetyl chloride first is to protect the phenolic hydroxyl group; in this process, the temperature has little effect between 5 and 25°C, but if the temperature is too high, the acetyl group protecting the phenolic hydroxyl group may fall off, so AlCl is added later 3. When carrying out Friedel-Crafts acylation reaction, side reactions will occur due to the strong positioning effect of phenolic hydroxyl groups; when adding AlCl 3 , the temperature should not be too high (more preferably 5-15°C), so as to prevent the reaction from being too violent , The second is to worry that the local temperature in the system is too high to cause side reactions;
优选地,所述化合物II与乙酰氯的摩尔比范围优选为1~3:4~6,能够使得反应完全。Preferably, the molar ratio range of the compound II to acetyl chloride is preferably 1-3:4-6, which can make the reaction complete.
步骤3、将所述化合物III与苯酚溶液反应得到所述新型酚类化合物;Step 3, reacting the compound III with a phenol solution to obtain the novel phenolic compound;
优选地,所述化合物III与所述苯酚的摩尔比为1~3:5~7,是为了使底物与苯酚混合的更均匀。Preferably, the molar ratio of the compound III to the phenol is 1-3:5-7, in order to make the substrate and phenol mix more uniformly.
(1)当R=Br时,将所述化合物III溶于苯酚溶液中,在25~65℃、N2保护作用下加入甲苯磺酸并搅拌反应。(1) When R=Br, dissolve the compound III in a phenol solution, add toluenesulfonic acid under the protection of N 2 at 25-65° C., and stir to react.
苯酚在低温时为固体,我们加入了苯酚,这样在温度升至25~65℃(更为优选为60~65℃)时,化合物III与苯酚混合的较为均匀,易于反应;而产品中酚羟基较多,加氮气保护是为了防止产品在加热时被氧化;对甲苯磺酸是这类反应(类似双酚A的合成)常用的催化剂,其他还有硫酸,盐酸,三氟甲磺酸等;前期我们对这些酸进行了筛选,发现甲苯磺酸TsOH对于这类底物反应最好。Phenol is solid at low temperature, and we added phenol, so that when the temperature rises to 25-65°C (more preferably 60-65°C), compound III and phenol are mixed evenly and are easy to react; and the phenolic hydroxyl group in the product More, adding nitrogen protection is to prevent the product from being oxidized when heated; p-toluenesulfonic acid is a commonly used catalyst for this type of reaction (similar to the synthesis of bisphenol A), and there are other sulfuric acid, hydrochloric acid, trifluoromethanesulfonic acid, etc.; In the early stage, we screened these acids and found that TsOH tosylate reacted best for this kind of substrate.
(2)当R=Cl时,将所述化合物III溶于苯酚溶液中,在25~65℃下加入甲苯磺酸并搅拌反应。此时无需加入N2保护。(2) When R=Cl, dissolve the compound III in a phenol solution, add toluenesulfonic acid at 25-65° C. and stir for reaction. There is no need to add N2 protection at this time.
其中,所述化合物II的化学通式为以下式(2);所述化合物III的化学通式为式(3);Wherein, the general chemical formula of the compound II is the following formula (2); the general chemical formula of the compound III is the formula (3);
所述式(2)和式(3)中,R1=Br或Cl。In the formula (2) and formula (3), R1=Br or Cl.
2、所述式(1)的新型酚类化合物中R=F时,所述制备方法包括:2. When R=F in the novel phenolic compound of the formula (1), the preparation method comprises:
步骤1、将4-Br-2,6-二氟苯酚与溴甲苯反应,得到5-Br-1,3-二氟-2-苯基-甲氧基苯;具体地,将4-Br-2,6-二氟苯酚溶于DMF溶液中在N2下加入碱性物质搅拌,后加入溴甲苯。Step 1, react 4-Br-2,6-difluorophenol with bromotoluene to obtain 5-Br-1,3-difluoro-2-phenyl-methoxybenzene; specifically, 4-Br- Dissolve 2,6-difluorophenol in DMF solution, add basic substance under N 2 and stir, then add bromotoluene.
加氮气保护是为了防止产品在加热时被氧化;所述碱性物质包括NaOH、K2CO3等,本实施例选用K2CO3是考虑到K2CO3完全可以满足反应要求,而且廉价易得,后处理也方便。Nitrogen protection is used to prevent the product from being oxidized during heating; the alkaline substances include NaOH, K 2 CO 3 , etc. K 2 CO 3 is selected in this example because K 2 CO 3 can fully meet the reaction requirements and is cheap Easy to obtain and convenient for post-processing.
优选地,所述4-Br-2,6-二氟苯酚与溴甲苯的摩尔比为40-50:50-60。溴甲苯具有很强的刺激性,催泪,多加无益;这个比例范围足以使反应完全。Preferably, the molar ratio of 4-Br-2,6-difluorophenol to bromotoluene is 40-50:50-60. Toluene bromide is highly irritating and tear-jerking, and adding more is useless; this ratio range is sufficient to make the reaction complete.
步骤2、将所述5-Br-1,3-二氟-2-苯基-甲氧基苯与苄基氯化镁反应,得到4-苄基-2,6-二氯基-甲氧基苯;Step 2, reacting the 5-Br-1,3-difluoro-2-phenyl-methoxybenzene with benzylmagnesium chloride to obtain 4-benzyl-2,6-dichloro-methoxybenzene ;
具体地,向混合ZnBr2的THF中在N2下于10℃下加入所述苄基氯化镁,搅拌混匀后加入5-Br-1,3-二氟-2-苯基-甲氧基苯的THF溶液。在这种条件下加入苄基氯化镁是因为可以使苄基氯化镁快速转变为有机Zn试剂,同时也是为了确保生成的Zn试剂能够稳定存在,不至于因为调价过强而变坏。Specifically, add the benzylmagnesium chloride to THF mixed with ZnBr2 under N2 at 10°C, stir and mix well, then add 5-Br-1,3-difluoro-2-phenyl-methoxybenzene of THF solution. Adding benzylmagnesium chloride under this condition is because benzylmagnesium chloride can be quickly converted into organic Zn reagent, and also to ensure that the generated Zn reagent can exist stably, so as not to deteriorate due to excessive price adjustment.
优选地,所述苄基氯化镁与化合物7的摩尔比范围为1:1-2。这个比例范围足以使反应完全。Preferably, the molar ratio of the benzylmagnesium chloride to compound 7 is in the range of 1:1-2. This ratio range is sufficient to complete the reaction.
步骤3、将所述4-苄基-2,6-二氯基-甲氧基苯经还原反应,得到4-苄基-2,6-二氟苯酚;具体地,先将4-苄基-2,6-二氯基-甲氧基苯溶解于甲醇溶液中,在催化剂Pd/C下通入H2进行还原反应。Step 3. Reducing the 4-benzyl-2,6-dichloro-methoxybenzene to obtain 4-benzyl-2,6-difluorophenol; specifically, the 4-benzyl -2,6-dichloro-methoxybenzene was dissolved in methanol solution, and the reduction reaction was carried out by feeding H2 under the catalyst Pd/C.
步骤4、将所述4-苄基-2,6-二氟苯酚与乙酰氯反应,得到4-(4-乙酰苄基)-2,6-双氟苯基乙酸;具体地,先将所述4-苄基-2,6-二氟苯酚溶解于二氯甲烷中,后滴加乙酰氯,同时加入催化剂AlCl3。反应的溶剂最常用为二氯甲烷,还有二氯乙烷和二硫化碳等;反应的催化剂最常用为三氯化铝,还有无水氯化锌、三氯化铁、四氯化钛等;该反应选择二氯甲烷作溶剂,AlCl3作为催化剂,完全是因为这两样东西均廉价易得,而且收率还可以,适于放大。Step 4, reacting the 4-benzyl-2,6-difluorophenol with acetyl chloride to obtain 4-(4-acetylbenzyl)-2,6-difluorophenylacetic acid; specifically, the The 4-benzyl-2,6-difluorophenol was dissolved in dichloromethane, then acetyl chloride was added dropwise, and the catalyst AlCl 3 was added at the same time. The most commonly used solvent for the reaction is methylene chloride, as well as dichloroethane and carbon disulfide, etc.; the most commonly used catalyst for the reaction is aluminum trichloride, as well as anhydrous zinc chloride, ferric chloride, titanium tetrachloride, etc.; This reaction chooses dichloromethane as a solvent and AlCl3 as a catalyst, entirely because these two things are cheap and easy to get, and the yield is acceptable, which is suitable for scale-up.
优选地,所述4-苄基-2,6-二氟苯酚与乙酰氯的摩尔比范围优选为1~2:1.1~4,能够使得反应完全。Preferably, the molar ratio range of the 4-benzyl-2,6-difluorophenol to acetyl chloride is preferably 1-2:1.1-4, which can make the reaction complete.
步骤5、将所述4-(4-乙酰苄基)-2,6-双氟苯基乙酸与苯酚溶液反应得到所述新型酚类化合物。对甲苯磺酸是这类反应(类似双酚A的合成)常用的催化剂,其他还有硫酸,盐酸,三氟甲磺酸等,前期本申请人们对这些酸进行了筛选,发现TsOH对于这类底物反应最好。优选地,所述4-(4-乙酰苄基)-2,6-双氟苯基乙酸与所述苯酚的摩尔比为1~3:5~7,是为了使底物与苯酚混合的更均匀,反应完全。Step 5, reacting the 4-(4-acetylbenzyl)-2,6-difluorophenylacetic acid with a phenol solution to obtain the novel phenolic compound. P-toluenesulfonic acid is a catalyst commonly used for this type of reaction (similar to the synthesis of bisphenol A), and other also have sulfuric acid, hydrochloric acid, trifluoromethanesulfonic acid, etc., the applicants have screened these acids in the early stage, and found that TsOH is suitable for this type of reaction. The substrate reacts best. Preferably, the molar ratio of the 4-(4-acetylbenzyl)-2,6-difluorophenylacetic acid to the phenol is 1-3:5-7, in order to make the substrate and phenol mix more efficiently. Uniform, complete reaction.
所述的新型酚类化合物能够显著抑制革兰氏阳性菌的生长,对金黄色葡萄球菌、枯草芽孢杆菌、耐甲氧西林金黄色葡的最小抑菌浓度为1~4μg/mLThe novel phenolic compound can significantly inhibit the growth of Gram-positive bacteria, and the minimum inhibitory concentration for Staphylococcus aureus, Bacillus subtilis, and methicillin-resistant Staphylococcus aureus is 1-4 μg/mL
下面将结合实施例及实验数据对本申请的一种新型酚类化合物及其制备方法与应用进行详细说明。A new type of phenolic compound of the present application, its preparation method and application will be described in detail below in combination with examples and experimental data.
实施例1Example 1
当式(1)中R=Br时,本实施例中的新型酚类化合物的结构式为:When R=Br in formula (1), the structural formula of the novel phenolic compound in the present embodiment is:
具体制备方法的流程为:The flow process of concrete preparation method is:
步骤1、在AcOH(15.0mL)中加入化合物1(4-羟基二苯甲烷,3.00g,16.3mmol,1.00eq),在10℃下滴加Br2(5.23g,32.7mmol,1.69mL,2.01eq)。混合物在5-25℃下搅拌2小时。Step 1. Compound 1 (4-hydroxydiphenylmethane, 3.00g, 16.3mmol, 1.00eq) was added to AcOH (15.0mL), and Br 2 (5.23g, 32.7mmol, 1.69mL, 2.01 eq). The mixture was stirred at 5-25°C for 2 hours.
TLC(石油醚:乙酸乙酯=5:1,Rf=0.59)检测4-羟基二苯甲烷反应完全后,将反应混合物倒入两倍体积的冰水中,并用相同体积乙酸乙酯萃取两次,将得到的有机相用NaHCO3清洗两次,然后浓盐水清洗,无水Na2SO4干燥,减压过滤浓缩得到残留物,然后柱色谱纯化得到淡黄色油状溶液A,即得到化合物II并用核磁共振检测该化合物;TLC (petroleum ether: ethyl acetate = 5: 1, Rf = 0.59) detected that after the reaction of 4-hydroxydiphenylmethane was complete, the reaction mixture was poured into twice the volume of ice water, and extracted twice with the same volume of ethyl acetate, The obtained organic phase was washed twice with NaHCO 3 , then washed with concentrated brine, dried with anhydrous Na 2 SO 4 , filtered and concentrated under reduced pressure to obtain a residue, and then purified by column chromatography to obtain a light yellow oily solution A, that is, compound II was obtained and analyzed by NMR Resonance detection of the compound;
步骤2、在二氯甲烷DCM(30.0mL)中加入化合物2(3.00g,8.77mmol,1.00eq),在10℃下滴加乙酰氯(1.45g,18.4mmol,1.31mL,2.10eq),0-15℃下搅拌1小时后得到混合物,将AlCl3(1.87g,14.0mmol,767uL,1.60eq)按比例加入到所述混合物中,在0-15℃下搅拌12小时。Step 2. Compound 2 (3.00g, 8.77mmol, 1.00eq) was added to dichloromethane DCM (30.0mL), and acetyl chloride (1.45g, 18.4mmol, 1.31mL, 2.10eq) was added dropwise at 10°C, 0 After stirring at -15°C for 1 hour to obtain a mixture, AlCl 3 ( 1.87g, 14.0mmol, 767uL, 1.60eq) was added to the mixture in proportion and stirred at 0-15°C for 12 hours.
TLC(石油醚:乙酸乙酯=5:1,Rf=0.30)检测到化合物II被完全反应后,将该反应混合物倒入的冰水中,用二氯甲烷萃取,将得到的萃取有机相用浓盐水清洗,无水Na2SO4干燥,减压过滤浓缩得到残留物,然后硅胶柱层析色谱纯化得到白色固体B,即得到化合物3;After TLC (petroleum ether: ethyl acetate = 5: 1, Rf = 0.30) detected that compound II was completely reacted, the reaction mixture was poured into ice water, extracted with dichloromethane, and the obtained extracted organic phase was concentrated Washed with brine, dried over anhydrous Na2SO4, filtered and concentrated under reduced pressure to obtain a residue, and then purified by silica gel column chromatography to obtain a white solid B, namely compound 3;
步骤3、将TsOH(2.02g,11.7mmol,2.00eq)加入到化合物3(2.50g,5.87mmol,1.00eq)的混合物中,加入苯酚(2.76g,29.3mmol,2.58mL,5.00eq),在N2下,温度为5-25℃。混合物在65℃下搅拌12小时。HPLC(ET28324-9-P1A1)和TLC(石油醚:乙酸乙酯=5:1,Rf=0.51)显示化合物3被完全消耗。将反应混合物溶解在乙酸乙酯EtOAc(15.0mL)中,用相同体积NaHCO3溶液清洗,然后用二分之一体积的浓盐水清洗有机相,无水Na2SO4干燥,减压过滤浓缩得到残留物,然后柱色谱纯化得到黄色固体,用反向高效液相色谱进一步纯化得到淡黄色固体,即得到该新型酚类化合物。Step 3, TsOH (2.02g, 11.7mmol, 2.00eq) was added to the mixture of compound 3 (2.50g, 5.87mmol, 1.00eq), phenol (2.76g, 29.3mmol, 2.58mL, 5.00eq) was added, and Under N2 , the temperature is 5-25 °C. The mixture was stirred at 65°C for 12 hours. HPLC (ET28324-9-P1A1) and TLC (petroleum ether:ethyl acetate=5:1, Rf=0.51) showed that compound 3 was completely consumed. The reaction mixture was dissolved in ethyl acetate EtOAc (15.0 mL), washed with the same volume of NaHCO 3 solution, and then the organic phase was washed with one-half volume of concentrated brine, dried over anhydrous Na 2 SO 4 , filtered and concentrated under reduced pressure to obtain The residue was then purified by column chromatography to obtain a yellow solid, and further purified by reverse-phase high-performance liquid chromatography to obtain a light yellow solid, that is, the novel phenolic compound was obtained.
实施例2Example 2
当式(1)中R=Cl时,本实施例的新型酚类化合物的结构式为:When R=Cl in formula (1), the structural formula of the novel phenolic compound of the present embodiment is:
具体制备方法的流程为:The flow process of concrete preparation method is:
步骤1、在MeOH(50.0mL)中加入化合物1(3.00g,16.3mmol,1eq)的溶液中加入NaOH(977mg,24.4mmol,1.5eq)和NaCl(2.85g,48.9mmol,3eq),温度为5-15℃,得到混合物。将NaClO(45.5g,48.9mmol,37.6mL,8%纯度,3eq)滴加到所述混合物中,在5-15℃下搅拌13小时。Step 1, add NaOH (977mg, 24.4mmol, 1.5eq) and NaCl (2.85g, 48.9mmol, 3eq) to the solution of compound 1 (3.00g, 16.3mmol, 1eq) in MeOH (50.0mL), the temperature is 5-15°C, a mixture was obtained. NaClO (45.5 g, 48.9 mmol, 37.6 mL, 8% purity, 3 eq) was added dropwise to the mixture and stirred at 5-15°C for 13 hours.
TLC(石油醚:乙酸乙酯=5:1)表示反应物1已被完全消耗。混合物在减压的情况下浓缩,以除去大部分MeOH。用水稀释(15.0mL),EtOAc提取(20.0mL*2)。混合后的有机层用盐水(15.0mL)清洗,在无水Na2SO4上干燥,过滤,减压浓缩,得到残留物。用柱层析法(SiO2,石油醚/乙酸乙酯=100/1~10/1)对残渣进行纯化。化合物4(2.50g,9.88mmol,60.7%的收率)经HNMR(ET25545-13-P1A)鉴定为淡黄色固体。TLC (petroleum ether:ethyl acetate=5:1) indicated that reactant 1 had been completely consumed. The mixture was concentrated under reduced pressure to remove most of the MeOH. Dilute with water (15.0 mL), extract with EtOAc (20.0 mL*2). The combined organic layers were washed with brine (15.0 mL), dried over anhydrous Na2SO4 , filtered, and concentrated under reduced pressure to obtain a residue. The residue was purified by column chromatography (SiO2, petroleum ether/ethyl acetate=100/1-10/1). Compound 4 (2.50 g, 9.88 mmol, 60.7% yield) was identified as a pale yellow solid by HNMR (ET25545-13-P1A).
步骤2、在DCM(3mL)中加入化合物4(500mg,1.98mmol,1eq),在5℃下滴加乙酰氯(325mg,4.15mmol,296uL,2.1eq),0-15℃搅拌1小时后得到混合物,将AlCl3(579mg,4.35mmol,237uL,2.2eq)按比例加入到所述混合物中,并在0-15℃下搅拌2小时。Step 2. Add compound 4 (500mg, 1.98mmol, 1eq) to DCM (3mL), add acetyl chloride (325mg, 4.15mmol, 296uL, 2.1eq) dropwise at 5°C, and stir at 0-15°C for 1 hour to obtain mixture, AlCl 3 (579mg, 4.35mmol, 237uL, 2.2eq) was added in proportion to the mixture, and stirred at 0-15°C for 2 hours.
TLC(石油醚:乙酸乙酯=5:1)表示反应物4已完全消耗,将反应混合物倒入10℃的冰水(5ml)中,然后用二氯甲烷DCM(2ml*2)萃取。混合后的有机层用盐水(2ml)清洗,在无水Na2SO4上干燥,过滤,减压浓缩,得到残留物。用硅胶柱层析色谱纯化残渣得到化合物5(400g,1.19mmol,60.1%的收率)经HNMR(ET25545-16-P1B)鉴定为淡黄色固体。TLC (petroleum ether:ethyl acetate=5:1) indicated that reactant 4 was completely consumed, and the reaction mixture was poured into ice water (5ml) at 10°C, and then extracted with dichloromethane DCM (2ml*2). The combined organic layers were washed with brine (2ml) , dried over anhydrous Na2SO4 , filtered and concentrated under reduced pressure to give a residue. The residue was purified by silica gel column chromatography to obtain compound 5 (400 g, 1.19 mmol, 60.1% yield) as a pale yellow solid identified by HNMR (ET25545-16-P1B).
步骤3、将苯酚(558mg,5.93mmol,522uL,5eq)中的溶液化合物5(400mg,1.19mmol,1eq)加入到TsOH(409mg,2.37mmol,2eq)中。混合物在60℃下搅拌12小时。LCMS(ET25545-19-P1A1)和HPLC(ET25545-19-P1A)显示化合物5被完全消耗,并检测到一个主峰。将反应混合物溶解于乙酸乙酯EtOAc(5.00mL),用相同体积NaHCO3溶液清洗,然后用二分之一体积的浓盐水清洗有机相,无水Na2SO4干燥,过滤,减压浓缩,得到残留物。采用高效液相色谱法(柱:Welch xc18 250*50mm*10um;流动相:[水(10mm-NH4HCO3)-ACN];B%:55%-75%,10min)得到白色固体,即得到该新型酚类化合物。Step 3. A solution of compound 5 (400mg, 1.19mmol, 1eq) in phenol (558mg, 5.93mmol, 522uL, 5eq) was added to TsOH (409mg, 2.37mmol, 2eq). The mixture was stirred at 60°C for 12 hours. LCMS (ET25545-19-P1A1) and HPLC (ET25545-19-P1A) showed that compound 5 was completely consumed and one main peak was detected. The reaction mixture was dissolved in ethyl acetate EtOAc (5.00 mL), washed with the same volume of NaHCO 3 solution, and then the organic phase was washed with one-half volume of concentrated brine, dried over anhydrous Na 2 SO 4 , filtered, and concentrated under reduced pressure, get residue. Using high performance liquid chromatography (column: Welch xc18 250*50mm*10um; mobile phase: [water (10mm-NH 4 HCO 3 )-ACN]; B%: 55%-75%, 10min) to obtain a white solid, namely The novel phenolic compound was obtained.
实施例3Example 3
当式(1)中R=F时,本实施例的新型酚类化合物的结构式为:When R=F in formula (1), the structural formula of the novel phenolic compound of the present embodiment is:
具体制备方法的流程为:The flow process of concrete preparation method is:
步骤1、对溶解于DMF(100mL)中化合物6(10g,47.85mmol,1eq)在N2下于15℃下加入K2CO3(9.92g,71.77mmol,1.5eq),15℃搅拌0.5小时后,加入溴甲苯(9.82g,57.42mmol,6.82mL,1.2eq)并在15℃下搅拌12小时,得到混合物。Step 1. Add K 2 CO 3 (9.92g, 71.77mmol, 1.5eq) to compound 6 (10g, 47.85mmol, 1eq) dissolved in DMF (100mL) at 15°C under N 2 , and stir at 15°C for 0.5 hours Afterwards, toluene bromide (9.82 g, 57.42 mmol, 6.82 mL, 1.2 eq) was added and stirred at 15° C. for 12 hours to obtain a mixture.
TLC(石油醚:乙酸乙酯=3:1)表明反应物6已被完全消耗,将所述混合物倒入300毫升冰水中,用EtOAc(100毫升*2)萃取。混合后的有机层用盐水(50mL*3)清洗,在无水Na2SO4上干燥,过滤,减压浓缩,得到残留物。用柱层析法(SiO2,石油醚/乙酸乙酯=100/1~20/1)对残渣进行纯化。经HNMR(ET25545-5-P1A)测定,化合物7(10g,33.43mmol,收率69.87%)为淡黄色油。TLC (petroleum ether:ethyl acetate=3:1) showed that reactant 6 was completely consumed, and the mixture was poured into 300 mL of ice water and extracted with EtOAc (100 mL*2). The combined organic layers were washed with brine (50 mL*3), dried over anhydrous Na 2 SO 4 , filtered, and concentrated under reduced pressure to obtain a residue. The residue was purified by column chromatography (SiO 2 , petroleum ether/ethyl acetate=100/1 to 20/1). As determined by HNMR (ET25545-5-P1A), compound 7 (10 g, 33.43 mmol, yield 69.87%) was a pale yellow oil.
步骤2、向混合ZnBr2(902.60mg,4.01mmol,200.58uL,2.4eq)的THF(10mL)中在N2下于10℃下滴加苄基氯化镁(1M,3.34mL,2.0eq),在15℃下搅拌0.5小时得到混合物。将化合物7(0.5g,1.67mmol,1eq)和1,3-双(2,6-二异丙基苯基)-2h-咪唑、3-氯吡啶、二氯钯(113.81mg,167.00umol,0.1eq)溶解在THF(5mL)中,在N2下15℃滴加到所述混合物中,在15℃下搅拌12.5小时。Step 2. To THF (10 mL) mixed with ZnBr 2 (902.60 mg, 4.01 mmol, 200.58 uL, 2.4 eq), benzylmagnesium chloride (1M, 3.34 mL, 2.0 eq) was added dropwise at 10° C. under N 2 . Stirring at 15°C for 0.5 hours gave a mixture. Compound 7 (0.5g, 1.67mmol, 1eq) and 1,3-bis(2,6-diisopropylphenyl)-2h-imidazole, 3-chloropyridine, dichloropalladium (113.81mg, 167.00umol, 0.1 eq) was dissolved in THF (5 mL), added dropwise to the mixture at 15° C. under N 2 , and stirred at 15° C. for 12.5 hours.
LCMS(ET25545-10-P1A)显示化合物7被完全消耗,检测到一个理想的m/z峰。将混合物倒入冰水(20ml)中,用EtOAc(10ml*2)提取。混合后的有机萃取物用盐水(10ml)洗涤,在MgSO4上干燥,过滤后在真空中浓缩,得到残留物。用柱层析法(SiO2,石油醚/乙酸乙酯=50/1~5/1)对残渣进行纯化。化合物8(0.3g,原油)为黄色油状物。LCMS (ET25545-10-P1A) showed that compound 7 was completely consumed and an ideal m/z peak was detected. The mixture was poured into ice water (20ml), extracted with EtOAc (10ml*2). The combined organic extracts were washed with brine (10 mL), dried over MgSO4, filtered and concentrated in vacuo to give a residue. The residue was purified by column chromatography (SiO 2 , petroleum ether/ethyl acetate=50/1-5/1). Compound 8 (0.3 g, crude oil) was a yellow oil.
步骤3、在MeOH(3mL)中加入化合物8(0.3g,966.69umol,1eq),在15℃下加入Pd/C(0.3g,10%纯度),在H2(15Psi)条件下,在15℃下搅拌12小时。LCMS(ET25545-33-P1A)表明消耗了化合物8,并检测到一个理想的MS峰。反应混合物在较低的压力下被过滤和浓缩,产生残渣,得到的化合物9(0.2g,原油)为棕褐色油状物。Step 3, add compound 8 (0.3g, 966.69umol, 1eq) in MeOH (3mL), add Pd/C (0.3g, 10% purity) at 15°C, under the condition of H 2 (15Psi), at 15 Stir at °C for 12 hours. LCMS (ET25545-33-P1A) indicated that compound 8 was consumed and a desirable MS peak was detected. The reaction mixture was filtered and concentrated under lower pressure to yield a residue to give compound 9 (0.2 g, crude oil) as a tan oil.
步骤4、在DCM(3ml)中加入化合物9(0.2g,908.21umol,1eq),在5℃下滴加乙酰氯(149.71mg,1.91mmol,136.10uL,2.1eq),5℃搅拌1小时后,加入AlCl3(266.42mg,2.00mmol,109.19uL,2.2eq),在15℃下搅拌2小时得到反应混合物。TLC(石油醚:乙酸乙酯=5:1)和LCMS(ET25545-40-P1A)表示化合物9被完全消耗。将所述反应混合物倒入10℃的冰水(5ml)中,然后用DCM(2ml*2)萃取。混合后的有机层用盐水(2ml)清洗,在无水Na2SO4上干燥,过滤,减压浓缩,得到残留物。用预tlc(SiO2,石油醚/乙酸乙酯=5/1)纯化残渣,得到化合物10(0.3g,粗)为淡黄色固体。Step 4. Add compound 9 (0.2g, 908.21umol, 1eq) to DCM (3ml), add acetyl chloride (149.71mg, 1.91mmol, 136.10uL, 2.1eq) dropwise at 5°C, and stir at 5°C for 1 hour , AlCl 3 (266.42mg, 2.00mmol, 109.19uL, 2.2eq) was added, and stirred at 15°C for 2 hours to obtain a reaction mixture. TLC (petroleum ether:ethyl acetate=5:1) and LCMS (ET25545-40-P1A) indicated that compound 9 was completely consumed. The reaction mixture was poured into ice water (5ml) at 10°C, then extracted with DCM (2ml*2). The combined organic layers were washed with brine (2ml) , dried over anhydrous Na2SO4 , filtered and concentrated under reduced pressure to give a residue. The residue was purified by pre-tlc (SiO 2 , petroleum ether/ethyl acetate=5/1) to obtain compound 10 (0.3 g, crude) as a pale yellow solid.
步骤5、向溶解在苯酚(309.28mg,3.29mmol,289.05uL,5.0eq)中的化合物10(0.2g,657.27umol,1eq)的溶液中加入TsOH(226.36mg,1.31mmol,2.0eq),在60℃下搅拌12小时得到反应混合物。LCMS(ET25545-46-P1B)和HPLC(ET25545-46-P1A)显示化合物10被完全消耗,并检测到一个主峰。将所述反应混合物溶解于EtOAc(5ml),用用相同体积NaHCO3溶液清洗,然后用二分之一体积的浓盐水清洗有机相,无水Na2SO4干燥,过滤,减压浓缩,得到残留物。粗品经反相高效液相色谱(0.1%NH4HCO3)纯化,得到淡黄色固体,用LCMS(ET25545-46-P1B1)和HPLC(ET25545-46-P1B)检测。所得的固体经prep-HPLC(柱:Waters XbridgeBEH C18 100*30mm*10um;流动相:[水(10mM NH4HCO3)-ACN];B%:30%-80%,10min)给予白色固体。经HNMR测定,得(0.12g,274.68umol,产率41.79%,纯度98.99%)为白色固体,即为该新型酚类化合物。Step 5. Add TsOH (226.36mg, 1.31mmol, 2.0eq) to a solution of compound 10 (0.2g, 657.27umol, 1eq) dissolved in phenol (309.28mg, 3.29mmol, 289.05uL, 5.0eq), Stirring at 60°C for 12 hours gave a reaction mixture. LCMS (ET25545-46-P1B) and HPLC (ET25545-46-P1A) showed complete consumption of compound 10 and one main peak was detected. The reaction mixture was dissolved in EtOAc (5 ml), washed with the same volume of NaHCO 3 solution, then the organic phase was washed with one-half volume of concentrated brine, dried over anhydrous Na 2 SO 4 , filtered, and concentrated under reduced pressure to give the remains. The crude product was purified by reverse-phase high-performance liquid chromatography (0.1% NH 4 HCO 3 ) to obtain a light yellow solid, which was detected by LCMS (ET25545-46-P1B1) and HPLC (ET25545-46-P1B). The obtained solid was subjected to prep-HPLC (column: Waters Xbridge BEH C18 100*30mm*10um; mobile phase: [water (10mM NH 4 HCO 3 )-ACN]; B%: 30%-80%, 10min) to give a white solid. As determined by HNMR, (0.12g, 274.68umol, yield 41.79%, purity 98.99%) was obtained as a white solid, which was the novel phenolic compound.
对比例1Comparative example 1
该对比例为采用常规方法制备得到的无取代的酚类化合物,结构式如下:This comparative example is an unsubstituted phenolic compound prepared by a conventional method, and its structural formula is as follows:
试验例Test case
将实施例1-3的新型酚类化合物以及对比例1的无取代酚类化合物,分别进行最小抑制浓度(Minimum Inhibition Concentration,MIC)测试实验,MIC测定结果如表1所示。The novel phenolic compounds of Examples 1-3 and the unsubstituted phenolic compound of Comparative Example 1 were subjected to minimum inhibitory concentration (Minimum Inhibition Concentration, MIC) testing experiments, and the MIC measurement results are shown in Table 1.
具体实验步骤如下:The specific experimental steps are as follows:
从平板上接种少许菌于装有LB培养基(Luria-Bertani培养基)的锥形瓶中,37℃摇床培养8-10h;其中,菌包括:革兰氏阳性菌和革兰氏阴性菌;所述革兰氏阳性菌包括金黄色葡萄球菌、芽孢杆菌、耐甲氧西林金黄色葡萄球菌,所述枯草芽孢杆菌为Bacillussubtilis 168;所用的金黄色葡萄球菌为Staphylococcus aureus 25923;所述的耐甲氧西林金黄色葡萄球菌的简称为MRSA;所用的革兰氏阴性菌为大肠杆菌Escherichiacoli DH5α。Inoculate a little bacteria from the plate in an Erlenmeyer flask equipped with LB medium (Luria-Bertani medium), and culture on a shaker at 37°C for 8-10h; wherein, the bacteria include: Gram-positive bacteria and Gram-negative bacteria Described Gram-positive bacterium comprises Staphylococcus aureus, Bacillus, methicillin-resistant Staphylococcus aureus, and described Bacillus subtilis is Bacillussubtilis 168; Used Staphylococcus aureus is Staphylococcus aureus 25923; Described resistant Methicillin Staphylococcus aureus is abbreviated as MRSA; the Gram-negative bacteria used is Escherichia coli DH5α.
LB培养基的配方如下:胰蛋白陈(Tryptone)10g/L,酵母提取物(Yeast extract)5g/L,氧化纳(NaCl)10g/L。The formula of LB medium is as follows: tryptone (Tryptone) 10g/L, yeast extract (Yeast extract) 5g/L, sodium oxide (NaCl) 10g/L.
第2天上午从锥形瓶中吸取菌液以1%的体积比转接于装有20mL的LB培养基的锥形瓶中,继续于37℃摇床中培养5h-6h,至OD600(OD600表示该菌液在600nm波长处的吸光值)为0.6-0.8,并记录菌液的具体OD值(optical density,光密℃)。In the morning of the second day, the bacterial solution was drawn from the Erlenmeyer flask and transferred to the Erlenmeyer flask containing 20 mL of LB medium at a volume ratio of 1%, and continued to cultivate in a shaker at 37°C for 5h-6h until OD600 (OD600 Indicates that the absorbance value of the bacterial liquid at a wavelength of 600nm) is 0.6-0.8, and the specific OD value (optical density, optical density °C) of the bacterial liquid is recorded.
用LB培养基将培养后的菌液稀释1000倍,使菌液浓度为105CFU/ml,吸取稀释后的菌液,并加至96孔板中,每孔150μl。Dilute the cultured bacterial solution 1000 times with LB medium to make the concentration of the bacterial solution 105 CFU/ml, draw the diluted bacterial solution, and add it to a 96-well plate, 150 μl per well.
配制浓度为128μg/ml的该酚化合物溶液,吸取150μl该三酚化合物溶液加至96孔板中的第1孔中,然后吸出150μl至第2孔中,以此类推。滴加完毕后,将96孔板放入摇床中经37℃培养过夜。Prepare the phenolic compound solution with a concentration of 128 μg/ml, pipette 150 μl of the triphenolic compound solution into the first well of a 96-well plate, then pipette 150 μl into the second well, and so on. After the dropwise addition, the 96-well plate was placed in a shaker and incubated overnight at 37°C.
表1-MIC值结果Table 1 - MIC value results
由表1可知,相比于对比例1,本发明的新型酚类化合物对革兰氏阳性菌的抑制效果提高了1倍。本发明实施例1-3提供的新型酚类化合物能够显著抑制革兰氏阳性菌的生长,对金黄色葡萄球菌、枯草芽孢杆菌、耐甲氧西林金黄色葡萄球菌的最小抑制浓度为1-2μg/ml,可见该三酚化合物的抗菌效果良好,可作为良好的革兰氏阳性菌的抗菌剂。It can be seen from Table 1 that compared with Comparative Example 1, the inhibitory effect of the novel phenolic compound of the present invention on Gram-positive bacteria is doubled. The novel phenolic compounds provided by Examples 1-3 of the present invention can significantly inhibit the growth of Gram-positive bacteria, and the minimum inhibitory concentration for Staphylococcus aureus, Bacillus subtilis, and methicillin-resistant Staphylococcus aureus is 1-2 μg /ml, it can be seen that the antibacterial effect of the triphenol compound is good, and it can be used as a good antibacterial agent for Gram-positive bacteria.
最后,还需要说明的是,术语“包括”、“包含”或者其任何其他变体意在涵盖非排他性的包含,从而使得包括一系列要素的过程、方法、物品或者设备不仅包括那些要素,而且还包括没有明确列出的其他要素,或者是还包括为这种过程、方法、物品或者设备所固有的要素。Finally, it should also be noted that the term "comprises", "comprises" or any other variation thereof is intended to cover a non-exclusive inclusion such that a process, method, article or apparatus comprising a set of elements includes not only those elements, but also Other elements not expressly listed, or inherent to the process, method, article, or apparatus are also included.
尽管已描述了本发明的优选实施例,但本领域内的技术人员一旦得知了基本创造性概念,则可对这些实施例作出另外的变更和修改。所以,所附权利要求意欲解释为包括优选实施例以及落入本发明范围的所有变更和修改。显然,本领域的技术人员可以对本发明进行各种改动和变型而不脱离本发明的精神和范围。这样,倘若本发明的这些修改和变型属于本发明权利要求及其等同技术的范围之内,则本发明也意图包含这些改动和变型在内。While preferred embodiments of the invention have been described, additional changes and modifications to these embodiments can be made by those skilled in the art once the basic inventive concept is appreciated. Therefore, it is intended that the appended claims be construed to cover the preferred embodiment as well as all changes and modifications which fall within the scope of the invention. Obviously, those skilled in the art can make various changes and modifications to the present invention without departing from the spirit and scope of the present invention. Thus, if these modifications and variations of the present invention fall within the scope of the claims of the present invention and equivalent technologies thereof, the present invention also intends to include these modifications and variations.
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