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CN111277526A - Modulation identification method of constellation diagram identical signals based on compressed sensing - Google Patents

Modulation identification method of constellation diagram identical signals based on compressed sensing Download PDF

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CN111277526A
CN111277526A CN202010133208.6A CN202010133208A CN111277526A CN 111277526 A CN111277526 A CN 111277526A CN 202010133208 A CN202010133208 A CN 202010133208A CN 111277526 A CN111277526 A CN 111277526A
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CN111277526B (en
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王伶
段正祥
张捷
汪跃先
杨欣
张兆林
谢坚
陶明亮
粟嘉
韩闯
宫延云
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Northwestern Polytechnical University
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Abstract

本发明提供了一种基于压缩感知的星座图相同信号的调制识别方法,通过对信号进行非均匀采样与粗重构,再利用信号高次方谱的谱线数量特征,实现了信号的次奈奎斯特频率采样,同时实现了信号集{QPSK,OQPSK,π/4‑DQPSK,8PSK}内的信号识别。本发明由于采用了对信号四次方谱进行压缩感知的技术手段,不仅解决了QPSK信号和OQPSK信号之间识别,8PSK信号和π/4‑DQPSK信号之间识别的技术难题,而且能够有效降低采样速率及采样点数。

Figure 202010133208

The invention provides a modulation identification method for the same signal in a constellation diagram based on compressed sensing. By performing non-uniform sampling and rough reconstruction on the signal, and then using the spectral line quantity feature of the high-power spectrum of the signal, the second order of the signal is realized. quist frequency sampling, while realizing the signal identification in the signal set {QPSK, OQPSK, π/4‑DQPSK, 8PSK}. Due to the adoption of the technical means of compressing the signal quadratic spectrum, the present invention not only solves the technical problems of identifying between QPSK signals and OQPSK signals, and identifying between 8PSK signals and π/4-DQPSK signals, but also can effectively reduce the Sampling rate and number of sampling points.

Figure 202010133208

Description

一种基于压缩感知的星座图相同信号的调制识别方法A Modulation Identification Method of Constellation Identical Signals Based on Compressed Sensing

技术领域technical field

本发明涉及信号处理领域,尤其是涉及星座图的调制识别方法,适用于信号集{QPSK,OQPSK,π/4-DQPSK,8PSK}内的信号识别。The invention relates to the field of signal processing, in particular to a modulation identification method of a constellation diagram, which is suitable for signal identification in a signal set {QPSK, OQPSK, π/4-DQPSK, 8PSK}.

背景技术Background technique

随着现在通信设备的增多,通信种类的增多,为了实现多体制信号的互通,信号的调制方式必不可少。调制识别是一项介于信号检测与信号解调之间的一项关键技术,为了在拥挤的电磁频谱环境中实现可靠、高效、智能的通信,在软件无线电与认知无线电系统中,接收端需要对接收信号的调制方式、调制参数等信息进行估计,从而实现多种调制信号的智能接收解调。With the increase of communication equipment and the increase of communication types, in order to realize the intercommunication of multi-system signals, the modulation mode of the signal is indispensable. Modulation identification is a key technology between signal detection and signal demodulation. In order to achieve reliable, efficient and intelligent communication in the crowded electromagnetic spectrum environment, in software radio and cognitive radio systems, the receiving end It is necessary to estimate the modulation mode, modulation parameters and other information of the received signal, so as to realize the intelligent reception and demodulation of various modulated signals.

当前的调制识别方式主要是基于提取特征进行识别的方法,提取特征主要有以下几种:包含幅度、频率和相位的瞬时特征,统计量特征及变换域特征等。目前比较有效的识别特征方法数字调制信号识别算法(DMRAs),采用的就是瞬时包络、相位和频率等关键特征参数作为调制识别的特征,该算法计算速度快,分类效果明显,工程上较易实现,但在某些星座图相同的信号之间没有相应的特征提取算法,如QPSK信号和OQPSK信号之间的识别,8PSK信号和π/4-DQPSK信号之间的识别。同时,这种方法依赖于大量的数据,在高速信号下,给数字模拟转换器的采样频率与系统的存储容量也带来了巨大的压力。The current modulation identification methods are mainly based on extraction features. The extraction features mainly include the following: instantaneous features including amplitude, frequency and phase, statistical features and transform domain features. Digital Modulated Signal Recognition Algorithms (DMRAs), the most effective feature identification method at present, adopts key feature parameters such as instantaneous envelope, phase and frequency as the features of modulation identification. The algorithm has fast calculation speed, obvious classification effect, and is easy in engineering. However, there is no corresponding feature extraction algorithm between signals with the same constellation diagram, such as the identification between QPSK signals and OQPSK signals, and the identification between 8PSK signals and π/4-DQPSK signals. At the same time, this method relies on a large amount of data. Under the high-speed signal, it also brings huge pressure on the sampling frequency of the digital-to-analog converter and the storage capacity of the system.

发明内容SUMMARY OF THE INVENTION

为了克服现有技术的不足,本发明提供一种基于压缩感知的星座图相同信号的调制识别方法。为了解决部分信号间无法识别与ADC采样频率高的问题,本发明通过对信号进行非均匀采样与粗重构,再利用信号高次方谱的谱线数量特征,实现了信号的次奈奎斯特频率采样,同时实现了信号集{QPSK,OQPSK,π/4-DQPSK,8PSK}内的信号识别。In order to overcome the deficiencies of the prior art, the present invention provides a modulation identification method for the same signal in a constellation diagram based on compressed sensing. In order to solve the problem that some signals cannot be identified and the sampling frequency of ADC is high, the present invention realizes the sub-Nyquis of the signal by performing non-uniform sampling and rough reconstruction on the signal, and then using the number of spectral lines of the high-power spectrum of the signal. At the same time, it realizes the signal identification in the signal set {QPSK, OQPSK, π/4-DQPSK, 8PSK}.

本发明解决其技术问题所采用的技术方案包括以下步骤:The technical scheme adopted by the present invention to solve its technical problem comprises the following steps:

步骤1:对信号进行非均匀采样;Step 1: Non-uniform sampling of the signal;

假设信号所需奈奎斯特采样频率为fnyq,数字模拟转换器的采样频率为fADC,得到采样的压缩比为

Figure BDA0002396384750000021
非均匀采样信号与奈奎斯特采样信号的关系表示为y=Ψr,其中y为M×1维压缩采样信号,r为N×1维奈奎斯特采样信号,Ψ为M×N维观测矩阵,Ψ表示为
Figure BDA0002396384750000022
其中kj∈[1,ω],ψij∈Ψ,得到y[j]=r[ω(j-1)+kj];Assuming that the required Nyquist sampling frequency of the signal is f nyq , and the sampling frequency of the digital-to-analog converter is f ADC , the sampling compression ratio obtained is
Figure BDA0002396384750000021
The relationship between the non-uniform sampling signal and the Nyquist sampling signal is expressed as y=Ψr, where y is the M×1-dimensional compressed sampling signal, r is the N×1-dimensional Nyquist sampling signal, and Ψ is the M×N-dimensional observation matrix, Ψ is expressed as
Figure BDA0002396384750000022
where k j ∈[1,ω], ψ ij ∈Ψ, get y[j]=r[ω(j-1)+k j ];

步骤2:由于QPSK信号、OQPSK信号和π/4-DQPSK为四相移调制,故对非均匀采样信号进行四阶非线性变换,得到y4,y4[j]=(y[j])4,j=0,1,...,M-1;Step 2: Since the QPSK signal, OQPSK signal and π/4-DQPSK are four-phase shift modulation, the non-uniform sampling signal is subjected to fourth-order nonlinear transformation to obtain y 4 , y 4 [j]=(y[j]) 4 , j=0,1,...,M-1;

步骤3:对非均匀采样信号的四阶非线性变换进行粗重构得到四次方谱u,粗重构方法为u=ΦΨHy4,其中u为N×1维重构的四次方谱,Φ为N×N维傅里叶变换基,即对ΨHy4做傅里叶变换;信号的四次方谱由四阶非线性变换后的信号进行傅里叶变换得到,即

Figure BDA0002396384750000023
其中
Figure BDA0002396384750000024
表示傅Step 3: Perform coarse reconstruction on the fourth-order nonlinear transformation of the non-uniform sampling signal to obtain the quartic spectrum u, and the coarse reconstruction method is u=ΦΨ H y 4 , where u is the fourth power of N×1-dimensional reconstruction spectrum, Φ is the N×N-dimensional Fourier transform basis, that is, the Fourier transform is performed on Ψ H y 4 ; the fourth power spectrum of the signal is obtained by the Fourier transform of the fourth-order nonlinear transformed signal, that
Figure BDA0002396384750000023
in
Figure BDA0002396384750000024
means Fu

表示傅里叶变换;represents the Fourier transform;

步骤4:找出信号四次方谱u最大的3个谱峰所在位置,记作Fmax={fm1,fm2,fm3},其中|u(fm1)|≥|u(fm2)|≥|u(fm3)|;Step 4: Find the positions of the 3 peaks with the largest 4th power spectrum u of the signal, denoted as F max ={f m1 , f m2 , f m3 }, where |u(f m1 )|≥|u(f m2 )|≥|u(f m3 )|;

步骤5:将y4平均分为两段M/2×1维向量y4,1和y4,2,构造一个新的N/2×N/2维离散傅里叶基ΦN/2,同时将M×N维的观测矩阵Ψ分为如下4个M/2×N/2维的4部分:Step 5: Divide y 4 into two segments of M/2×1-dimensional vectors y 4,1 and y 4,2 equally, and construct a new N/2×N/2-dimensional discrete Fourier basis Φ N/2 , At the same time, the M×N-dimensional observation matrix Ψ is divided into four parts of M/2×N/2 dimensions as follows:

Figure BDA0002396384750000025
Figure BDA0002396384750000025

步骤6:得到两个切片u1和u2的四次方谱为:u1=ΦN/2Ψ1 Hy4,1,u2=ΦN/2Ψ4 Hy4,2Step 6: Obtain the quadratic spectrum of the two slices u 1 and u 2 as: u 1N/2 Ψ 1 H y 4,1 , u 2N/2 Ψ 4 H y 4,2 ;

步骤7:分别寻找u1和u2最大的3个谱峰所在的位置Fmax,1={fm1,1,fm2,1,fm3,1}和Fmax,2={fm1,2,fm2,2,fm3,2},其中u1(fm1,1)≥u1(fm2,1)≥u1(fm3,1),u2(fm1,2)≥u2(fm2,2)≥u2(fm3,2);Step 7: Find the positions F max,1 ={f m1,1 ,f m2,1 ,f m3,1 } and F max,2 = {f m1, 2 ,f m2,2 ,f m3,2 }, where u 1 (f m1,1 )≥u 1 (f m2,1 )≥u 1 (f m3,1 ), u 2 (f m1,2 )≥ u 2 (f m2,2 )≥u 2 (f m3,2 );

步骤8:求并集Fmax,o=Fmax,1∪Fmax,2Step 8: Find the union F max,o =F max,1 ∪F max,2 ;

步骤9:求交集Fmax,a=Fmax∩Fmax,oStep 9: Find the intersection F max,a =F max ∩F max,o ;

步骤10:得到Fmax,a中元素个数NrStep 10: Obtain the number of elements N r in F max,a ;

若Nr为0,输出识别结果调制方式为8PSK;若Nr为1,输出识别结果调制方式为OQPSK;若Nr为3,输出识别结果调制方式为QPSK;若Nr为2进入步骤11;If N r is 0, the modulation mode of the output identification result is 8PSK; if N r is 1, the modulation mode of the output identification result is OQPSK; if N r is 3, the modulation mode of the output identification result is QPSK; if N r is 2, go to step 11 ;

步骤11:若Nr为2,判断

Figure BDA0002396384750000031
是否大于门限η,若大于η,输出识别结果调制方式为QPSK;若小于等于η,输出识别结果调制方式为π/4-DQPSK。Step 11: If N r is 2, judge
Figure BDA0002396384750000031
Whether it is greater than the threshold η, if it is greater than η, the modulation mode of the output identification result is QPSK; if it is less than or equal to η, the modulation mode of the output identification result is π/4-DQPSK.

本发明的有益效果在于由于采用了对信号四次方谱进行压缩感知的技术手段,不仅解决了QPSK信号和OQPSK信号之间识别,8PSK信号和π/4-DQPSK信号之间识别的技术难题,而且能够有效降低采样速率及采样点数。The beneficial effect of the present invention is that because the technical means of compressing the quartet spectrum of the signal is adopted, not only the identification between the QPSK signal and the OQPSK signal, but also the identification between the 8PSK signal and the π/4-DQPSK signal is solved. Moreover, the sampling rate and the number of sampling points can be effectively reduced.

附图说明Description of drawings

图1为本发明压缩框架下的谱峰检测算法流程图。Fig. 1 is the flow chart of the spectral peak detection algorithm under the compression framework of the present invention.

图2为本发明非均匀采样原理框图。FIG. 2 is a block diagram of the principle of non-uniform sampling according to the present invention.

图3为本发明采样保持模块时序图。FIG. 3 is a timing diagram of the sample and hold module of the present invention.

图4为本发明非均匀采样系统时序图。FIG. 4 is a timing diagram of the non-uniform sampling system of the present invention.

图5为本发明不同信号的粗重构四次方谱图。FIG. 5 is a rough reconstruction quartogram of different signals of the present invention.

图6为本发明压缩比4时不同信号的识别概率图。FIG. 6 is the identification probability diagram of different signals when the compression ratio is 4 according to the present invention.

具体实施方式Detailed ways

下面结合附图和实施例对本发明进一步说明,本发明包括但不仅限于下述实施例,具体包括以下步骤:The present invention is further described below in conjunction with the accompanying drawings and embodiments, the present invention includes but is not limited to the following embodiments, and specifically includes the following steps:

步骤1:对信号进行非均匀采样;Step 1: Non-uniform sampling of the signal;

假设信号所需奈奎斯特采样频率为fnyq,数字模拟转换器的采样频率为fADC,得到采样的压缩比为

Figure BDA0002396384750000032
非均匀采样信号与奈奎斯特采样信号的关系表示为y=Ψr,其中y为M×1维压缩采样信号,r为N×1维奈奎斯特采样信号,Ψ为M×N维观测矩阵,Ψ表示为
Figure BDA0002396384750000033
其中kj∈[1,ω],ψij∈Ψ,得到y[j]=r[ω(j-1)+kj];Assuming that the required Nyquist sampling frequency of the signal is f nyq , and the sampling frequency of the digital-to-analog converter is f ADC , the sampling compression ratio obtained is
Figure BDA0002396384750000032
The relationship between the non-uniform sampling signal and the Nyquist sampling signal is expressed as y=Ψr, where y is the M×1-dimensional compressed sampling signal, r is the N×1-dimensional Nyquist sampling signal, and Ψ is the M×N-dimensional observation matrix, Ψ is expressed as
Figure BDA0002396384750000033
where k j ∈[1,ω], ψ ij ∈Ψ, get y[j]=r[ω(j-1)+k j ];

步骤2:由于QPSK信号、OQPSK信号和π/4-DQPSK为四相移调制,故对非均匀采样信号进行四阶非线性变换,得到y4,y4[j]=(y[j])4,j=0,1,...,M-1;Step 2: Since the QPSK signal, OQPSK signal and π/4-DQPSK are four-phase shift modulation, the non-uniform sampling signal is subjected to fourth-order nonlinear transformation to obtain y 4 , y 4 [j]=(y[j]) 4 , j=0,1,...,M-1;

步骤3:对非均匀采样信号的四阶非线性变换进行粗重构得到四次方谱u,粗重构方法为u=ΦΨHy4,其中u为N×1维重构的四次方谱,Φ为N×N维傅里叶变换基,即对ΨHy4做傅里叶变换;信号的四次方谱由四阶非线性变换后的信号进行傅里叶变换得到,即

Figure BDA0002396384750000041
其中
Figure BDA0002396384750000042
表示傅里叶变换;Step 3: Perform coarse reconstruction on the fourth-order nonlinear transformation of the non-uniform sampling signal to obtain the quartic spectrum u, and the coarse reconstruction method is u=ΦΨ H y 4 , where u is the fourth power of N×1-dimensional reconstruction spectrum, Φ is the N×N-dimensional Fourier transform basis, that is, the Fourier transform is performed on Ψ H y 4 ; the fourth power spectrum of the signal is obtained by the Fourier transform of the fourth-order nonlinear transformed signal, that
Figure BDA0002396384750000041
in
Figure BDA0002396384750000042
represents the Fourier transform;

步骤4:找出信号四次方谱u最大的3个谱峰所在位置,记作Fmax={fm1,fm2,fm3},其中|u(fm1)|≥u|(fm2)|≥|u(fm3)|;Step 4: Find the positions of the three peaks with the largest 4th power spectrum u of the signal, denoted as F max ={f m1 ,f m2 ,f m3 }, where |u(f m1 )|≥u|(f m2 )|≥|u(f m3 )|;

步骤5:将y4平均分为两段M/2×1维向量y4,1和y4,2,构造一个新的N/2×N/2维离散傅里叶基ΦN/2,同时将M×N维的观测矩阵Ψ分为如下4个M/2×N/2维的4部分:Step 5: Divide y 4 into two segments of M/2×1-dimensional vectors y 4,1 and y 4,2 equally, and construct a new N/2×N/2-dimensional discrete Fourier basis Φ N/2 , At the same time, the M×N-dimensional observation matrix Ψ is divided into four parts of M/2×N/2 dimensions as follows:

Figure BDA0002396384750000043
Figure BDA0002396384750000043

步骤6:得到两个切片u1和u2的四次方谱为:u1=ΦN/2Ψ1 Hy4,1,u2=ΦN/2Ψ4 Hy4,2Step 6: Obtain the quadratic spectrum of the two slices u 1 and u 2 as: u 1N/2 Ψ 1 H y 4,1 , u 2N/2 Ψ 4 H y 4,2 ;

步骤7:分别寻找u1和u2最大的3个谱峰所在的位置Fmax,1={fm1,1,fm2,1,fm3,1}和Fmax,2={fm1,2,fm2,2,fm3,2},其中|u1(fm1,1)|≥|u1(fm2,1)|≥|u1(fm3,1)|,|u2(fm1,2)|≥|u2(fm2,2)|≥|u2(fm3,2)|;Step 7: Find the positions F max,1 ={f m1,1 ,f m2,1 ,f m3,1 } and F max,2 = {f m1, 2 ,f m2,2 ,f m3,2 }, where |u 1 (f m1,1 )|≥|u 1 (f m2,1 )|≥|u 1 (f m3,1 )|, |u 2 (f m1,2 )|≥|u 2 (f m2,2 )|≥|u 2 (f m3,2 )|;

步骤8:求并集Fmax,o=Fmax,1∪Fmax,2Step 8: Find the union F max,o =F max,1 ∪F max,2 ;

步骤9:求交集Fmax,a=Fmax∩Fmax,oStep 9: Find the intersection F max,a =F max ∩F max,o ;

步骤10:得到Fmax,a中元素个数NrStep 10: Obtain the number of elements N r in F max,a ;

若Nr为0,输出识别结果调制方式为8PSK;若Nr为1,输出识别结果调制方式为OQPSK;若Nr为3,输出识别结果调制方式为QPSK;若Nr为2进入步骤11;If N r is 0, the modulation mode of the output identification result is 8PSK; if N r is 1, the modulation mode of the output identification result is OQPSK; if N r is 3, the modulation mode of the output identification result is QPSK; if N r is 2, go to step 11 ;

步骤11:若Nr为2,判断

Figure BDA0002396384750000044
是否大于门限η,若大于η,输出识别结果调制方式为QPSK;若小于等于η,输出识别结果调制方式为π/4-DQPSK。Step 11: If N r is 2, judge
Figure BDA0002396384750000044
Whether it is greater than the threshold η, if it is greater than η, the modulation mode of the output identification result is QPSK; if it is less than or equal to η, the modulation mode of the output identification result is π/4-DQPSK.

本发明以一个经过滤波下变频还存在残留载波频率fc=0.5GHz,码元速率fb=1GHz未知调制信号为例。假定接收端等效奈奎斯特采样频率fnyq=4GHz,采样压缩比ω=4模拟数字转换器实际采样频率

Figure BDA0002396384750000045
采样符号数Nsymbol=4096,由图1所示,本发明提供了一种基于压缩感知的调制识别,具体实施例如下:The present invention takes an unknown modulated signal with residual carrier frequency f c =0.5GHz and symbol rate f b =1GHz after filtering and down-conversion as an example. Assuming that the equivalent Nyquist sampling frequency f nyq = 4GHz at the receiving end, the sampling compression ratio ω = 4 The actual sampling frequency of the analog-to-digital converter
Figure BDA0002396384750000045
The number of sampling symbols N symbol = 4096, as shown in FIG. 1 , the present invention provides a modulation recognition based on compressed sensing, and the specific embodiment is as follows:

步骤一:采用非均匀采样对信号进行采样,得到4096×1维采样值y,系统原理框图如图2。整个系统由时钟产生模块、采样保持模块和数据采集模块3部分组成。时钟产生模块,它负责产生两个时钟,一个是ADC采样时钟一个是非均匀时钟。非均匀时钟由一串满足奈奎斯特频率的伪随机二进制码产生,其中当伪随机码为1的时候输出时钟高电平,当伪随机码为0时输出时钟低电平,在一个ADC采样时钟周期内非均匀始终只存在一个下降沿,并且在下一次ADC采样时钟上升沿到来时伪随机码也置为1,即伪随机码为‘…11100…’的形式。采样保持模块的功能是在非均匀时钟下降沿到来时采集此时的信号并一直保持到下一个非均匀时钟的上升沿到来,而当时钟信号为高时模拟信号可以自由通过,如图3所示。数据采集模块则是按照ADC采样时钟对信号来自采样保持模块的信号进行采样。整个过程描述如图4所示,可以看出虽然ADC的采样时钟远低于奈奎斯特采样频率,但是通过采样保持模块,实际采集到的信号是按照奈奎斯特频率非均匀采样得到信号,等效观测矩阵为4096×16384维的Ψ,Ψ可以表示为

Figure BDA0002396384750000051
其中kj∈[1,4],ψij∈Ψ。Step 1: The signal is sampled by non-uniform sampling, and the 4096×1-dimensional sampling value y is obtained. The schematic diagram of the system is shown in Figure 2. The whole system is composed of clock generation module, sample and hold module and data acquisition module. The clock generation module is responsible for generating two clocks, one is the ADC sampling clock and the other is a non-uniform clock. The non-uniform clock is generated by a series of pseudo-random binary codes that satisfy the Nyquist frequency. When the pseudo-random code is 1, the output clock is high, and when the pseudo-random code is 0, the output clock is low. In an ADC There is always only one falling edge for non-uniformity in the sampling clock period, and the pseudo-random code is also set to 1 when the next rising edge of the ADC sampling clock arrives, that is, the pseudo-random code is in the form of '...11100...'. The function of the sample and hold module is to collect the signal at this time when the falling edge of the non-uniform clock arrives and keep it until the rising edge of the next non-uniform clock, and when the clock signal is high, the analog signal can pass freely, as shown in Figure 3. Show. The data acquisition module samples the signal from the sample and hold module according to the ADC sampling clock. The description of the whole process is shown in Figure 4. It can be seen that although the sampling clock of the ADC is much lower than the Nyquist sampling frequency, the actual collected signal is obtained by non-uniform sampling according to the Nyquist frequency through the sampling and holding module. , the equivalent observation matrix is Ψ of 4096×16384 dimensions, and Ψ can be expressed as
Figure BDA0002396384750000051
where k j ∈ [1,4], ψ ij ∈ Ψ.

步骤二:求非均匀采样信号每个值的四次方,得到y4Step 2: Calculate the fourth power of each value of the non-uniformly sampled signal to obtain y 4 .

步骤三:通过式u=ΦΨHy4得到粗重构四次方谱,16384×16384维傅里叶变换基Φ可以通过对相应维数的单位矩阵求傅里叶变换得到,不同信号的粗重构谱如图5所示。Step 3: The rough reconstruction quartic spectrum is obtained by the formula u=ΦΨ H y 4. The 16384×16384-dimensional Fourier transform basis Φ can be obtained by taking the Fourier transform of the identity matrix of the corresponding dimension. The reconstructed spectrum is shown in Figure 5.

步骤四:找出信号四次方谱u最大的3个谱峰所在位置,记作Fmax={fm1,fm2,fm3},其中|u(fm1)|≥|u(fm2)|≥|u(fm3)|。Step 4: Find the positions of the 3 largest spectral peaks in the quartic spectrum of the signal, denoted as F max ={f m1 , f m2 , f m3 }, where |u(f m1 )|≥|u(f m2 )|≥|u(f m3 )|.

步骤五:将y4平均分为两段2048×1维向量y4,1和y4,2,构造一个新的8192×8192维离散傅里叶基ΦN/2,同时将4096×16384维的观测矩阵Ψ分为如下4个2048×8192维的4部分:

Figure BDA0002396384750000052
Step 5: Divide y 4 into two 2048×1-dimensional vectors y 4,1 and y 4,2 equally, construct a new 8192×8192-dimensional discrete Fourier basis Φ N/2 , and divide 4096×16384-dimensional The observation matrix Ψ is divided into 4 parts of 2048×8192 dimensions as follows:
Figure BDA0002396384750000052

步骤六:得到两个切片u1和u2的四次方谱为:u1=ΦN/2Ψ1 Hy4,1,u2=ΦN/2Ψ4 Hy4,2Step 6: The quadratic spectrum of the two slices u 1 and u 2 is obtained as: u 1N/2 Ψ 1 H y 4,1 , u 2N/2 Ψ 4 H y 4,2 .

步骤七:分别寻找u1和u2最大的3个谱峰所在的位置Fmax,1={fm1,1,fm2,1,fm3,1}和Fmax,2={fm1,2,fm2,2,fm3,2},其中|u1(fm1,1)|≥|u1(fm2,1)|≥|u1(fm3,1)|,|u2(fm1,2)|≥|u2(fm2,2)|≥|u2(fm3,2)|。Step 7: Find the positions F max,1 ={f m1,1 ,f m2,1 ,f m3,1 } and F max,2 = {f m1, 2 ,f m2,2 ,f m3,2 }, where |u 1 (f m1,1 )|≥|u 1 (f m2,1 )|≥|u 1 (f m3,1 )|, |u 2 (f m1,2 )|≥|u 2 (f m2,2 )|≥|u 2 (f m3,2 )|.

步骤八:求并集Fmax,o=Fmax,1∪Fmax,2Step 8: Find the union F max,o =F max,1 ∪F max,2 .

步骤九:求交集Fmax,a=Fmax∩Fmax,oStep 9: Find the intersection F max,a =F max ∩F max,o .

步骤十:得到Fmax,a中元素个数NrStep 10: Obtain the number N r of elements in F max,a .

若Nr为0,输出识别结果调制方式为8PSK;若Nr为1,输出识别结果调制方式为OQPSK;若Nr为3,输出识别结果调制方式为QPSK。若Nr为2进行步骤十一。If N r is 0, the modulation mode of the output identification result is 8PSK; if N r is 1, the modulation mode of the output identification result is OQPSK; if N r is 3, the modulation mode of the output identification result is QPSK. If N r is 2, go to step eleven.

步骤十一:若Nr为2判断

Figure BDA0002396384750000061
是否大于门限η=1.8,若大于1.8,输出识别结果调制方式为QPSK;若小于等于1.8输出识别结果调制方式为π/4-DQPSK。从图5可以看出π/4-DQPSK信号高阶谱最大的2根谱线强度相近,而QPSK信号高阶谱最大的2根谱线强度相差较大,因此设置η=1.8。在QPSK有1根较弱谱线可能无法检测出的时候,通过从2个谱线的情况中分离出QPSK信号能够提升识别率。Step 11: Judge if N r is 2
Figure BDA0002396384750000061
Whether it is greater than the threshold η=1.8, if it is greater than 1.8, the modulation mode of the output identification result is QPSK; if it is less than or equal to 1.8, the modulation mode of the output identification result is π/4-DQPSK. It can be seen from Figure 5 that the intensity of the two largest spectral lines in the high-order spectrum of the π/4-DQPSK signal is similar, while the intensity of the two largest spectral lines in the high-order spectrum of the QPSK signal is quite different, so η=1.8 is set. When QPSK has a weak spectral line that may not be detected, the recognition rate can be improved by separating the QPSK signal from the case of two spectral lines.

图6显示了压缩比4时不同信号的识别概率图,从图6可以看出,在信噪比为5dB时,除了QPSK信号均实现了100%的识别率,在信噪比为10dB时,所有信号的识别概率均达到了100%,,这意味着只需要奈奎斯特采样频率四分之一的AD采样速率,便可以实现信号集{QPSK,OQPSK,π/4-DQPSK,8PSK}内信号100%的检测概率,采样数据量是均匀采样的四分之一,也减小了存储的压力。Figure 6 shows the recognition probability diagram of different signals when the compression ratio is 4. It can be seen from Figure 6 that when the signal-to-noise ratio is 5dB, except for the QPSK signal, the recognition rate of 100% is achieved. When the signal-to-noise ratio is 10dB, The identification probability of all signals reaches 100%, which means that the signal set {QPSK,OQPSK,π/4-DQPSK,8PSK} can be achieved with only one quarter of the AD sampling rate of the Nyquist sampling frequency. The detection probability of the internal signal is 100%, and the amount of sampled data is a quarter of that of uniform sampling, which also reduces the pressure of storage.

Claims (1)

1.一种基于压缩感知的星座图相同信号的调制识别方法,其特征在于包括下述步骤:1. a modulation identification method based on the same signal of the constellation diagram of compressed sensing, is characterized in that comprising the following steps: 步骤1:对信号进行非均匀采样;Step 1: Non-uniform sampling of the signal; 假设信号所需奈奎斯特采样频率为fnyq,数字模拟转换器的采样频率为fADC,得到采样的压缩比为
Figure FDA0002396384740000011
非均匀采样信号与奈奎斯特采样信号的关系表示为y=Ψr,其中y为M×1维压缩采样信号,r为N×1维奈奎斯特采样信号,Ψ为M×N维观测矩阵,Ψ表示为
Figure FDA0002396384740000012
其中kj∈[1,ω],ψij∈Ψ,得到y[j]=r[ω(j-1)+kj];
Assuming that the required Nyquist sampling frequency of the signal is f nyq , and the sampling frequency of the digital-to-analog converter is f ADC , the sampling compression ratio obtained is
Figure FDA0002396384740000011
The relationship between the non-uniform sampling signal and the Nyquist sampling signal is expressed as y=Ψr, where y is the M×1-dimensional compressed sampling signal, r is the N×1-dimensional Nyquist sampling signal, and Ψ is the M×N-dimensional observation matrix, Ψ is expressed as
Figure FDA0002396384740000012
where k j ∈[1,ω], ψ ij ∈Ψ, get y[j]=r[ω(j-1)+k j ];
步骤2:由于QPSK信号、OQPSK信号和π/4-DQPSK为四相移调制,故对非均匀采样信号进行四阶非线性变换,得到y4,y4[j]=(y[j])4,j=0,1,...,M-1;Step 2: Since the QPSK signal, OQPSK signal and π/4-DQPSK are four-phase shift modulation, the non-uniform sampling signal is subjected to fourth-order nonlinear transformation to obtain y 4 , y 4 [j]=(y[j]) 4 , j=0,1,...,M-1; 步骤3:对非均匀采样信号的四阶非线性变换进行粗重构得到四次方谱u,粗重构方法为u=ΦΨHy4,其中u为N×1维重构的四次方谱,Φ为N×N维傅里叶变换基,即对ΨHy4做傅里叶变换;信号的四次方谱由四阶非线性变换后的信号进行傅里叶变换得到,即
Figure FDA0002396384740000013
其中
Figure FDA0002396384740000014
表示傅里叶变换;
Step 3: Perform coarse reconstruction on the fourth-order nonlinear transformation of the non-uniform sampling signal to obtain the quartic spectrum u, and the coarse reconstruction method is u=ΦΨ H y 4 , where u is the fourth power of N×1-dimensional reconstruction spectrum, Φ is the N×N-dimensional Fourier transform basis, that is, the Fourier transform is performed on Ψ H y 4 ; the fourth power spectrum of the signal is obtained by the Fourier transform of the fourth-order nonlinear transformed signal, that
Figure FDA0002396384740000013
in
Figure FDA0002396384740000014
represents the Fourier transform;
步骤4:找出信号四次方谱u最大的3个谱峰所在位置,记作Fmax={fm1,fm2,fm3},其中|u(fm1)|≥|u(fm2)|≥|u(fm3)|;Step 4: Find the positions of the 3 peaks with the largest 4th power spectrum u of the signal, denoted as F max ={f m1 , f m2 , f m3 }, where |u(f m1 )|≥|u(f m2 )|≥|u(f m3 )|; 步骤5:将y4平均分为两段M/2×1维向量y4,1和y4,2,构造一个新的N/2×N/2维离散傅里叶基ΦN/2,同时将M×N维的观测矩阵Ψ分为如下4个M/2×N/2维的4部分:
Figure FDA0002396384740000015
Step 5: Divide y 4 into two segments of M/2×1-dimensional vectors y 4,1 and y 4,2 equally, and construct a new N/2×N/2-dimensional discrete Fourier basis Φ N/2 , At the same time, the M×N-dimensional observation matrix Ψ is divided into four parts of M/2×N/2 dimensions as follows:
Figure FDA0002396384740000015
步骤6:得到两个切片u1和u2的四次方谱为:u1=ΦN/2Ψ1 Hy4,1,u2=ΦN/2Ψ4 Hy4,2Step 6: Obtain the quadratic spectrum of the two slices u 1 and u 2 as: u 1N/2 Ψ 1 H y 4,1 , u 2N/2 Ψ 4 H y 4,2 ; 步骤7:分别寻找u1和u2最大的3个谱峰所在的位置Fmax,1={fm1,1,fm2,1,fm3,1}和Fmax,2={fm1,2,fm2,2,fm3,2},其中|u1(fm1,1)|≥|u1(fm2,1)|≥|u1(fm3,1)|,|u2(fm1,2)|≥|u2(fm2,2)|≥|u2(fm3,2)|;Step 7: Find the positions F max,1 ={f m1,1 ,f m2,1 ,f m3,1 } and F max,2 = {f m1, 2 ,f m2,2 ,f m3,2 }, where |u 1 (f m1,1 )|≥|u 1 (f m2,1 )|≥|u 1 (f m3,1 )|, |u 2 (f m1,2 )|≥|u 2 (f m2,2 )|≥|u 2 (f m3,2 )|; 步骤8:求并集Fmax,o=Fmax,1∪Fmax,2Step 8: Find the union F max,o =F max,1 ∪F max,2 ; 步骤9:求交集Fmax,a=Fmax∩Fmax,oStep 9: Find the intersection F max,a =F max ∩F max,o ; 步骤10:得到Fmax,a中元素个数NrStep 10: Obtain the number of elements N r in F max,a ; 若Nr为0,输出识别结果调制方式为8PSK;若Nr为1,输出识别结果调制方式为OQPSK;若Nr为3,输出识别结果调制方式为QPSK;若Nr为2进入步骤11;If N r is 0, the modulation mode of the output identification result is 8PSK; if N r is 1, the modulation mode of the output identification result is OQPSK; if N r is 3, the modulation mode of the output identification result is QPSK; if N r is 2, go to step 11 ; 步骤11:若Nr为2,判断
Figure FDA0002396384740000021
是否大于门限η,若大于η,输出识别结果调制方式为QPSK;若小于等于η,输出识别结果调制方式为π/4-DQPSK。
Step 11: If N r is 2, judge
Figure FDA0002396384740000021
Whether it is greater than the threshold η, if it is greater than η, the modulation mode of the output identification result is QPSK; if it is less than or equal to η, the modulation mode of the output identification result is π/4-DQPSK.
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