CN111062557A - A method for evaluating the total frequency of power failures at load points - Google Patents
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Abstract
Description
技术领域technical field
本发明涉及电网的技术领域,尤其涉及到一种负荷点停电故障总频率评估方法。The invention relates to the technical field of power grids, in particular to a method for evaluating the total frequency of power failure at a load point.
背景技术Background technique
随着社会的发展,电力用户更加关注电力系统的供电可靠性。相关统计表明,负荷点的供电不可用度约80%–95%是由配电系统故障引起的。因此,配电系统的负荷点停电故障总频率评估是电力部门规划和运行的一个重要任务。With the development of society, power users pay more attention to the reliability of power supply of the power system. Relevant statistics show that about 80%-95% of the unavailability of power supply at the load point is caused by the failure of the power distribution system. Therefore, the assessment of the total frequency of outage faults at the load point of the distribution system is an important task for the planning and operation of the power sector.
发明内容SUMMARY OF THE INVENTION
本发明的目的在于克服现有技术的不足,提供一种准确率高的负荷点停电故障总频率评估方法。The purpose of the present invention is to overcome the deficiencies of the prior art, and to provide a method for evaluating the total frequency of power failure at a load point with high accuracy.
为实现上述目的,本发明所提供的技术方案为:For achieving the above object, the technical scheme provided by the present invention is:
一种负荷点停电故障总频率评估方法,包括以下步骤:A method for evaluating the total frequency of power outage faults at a load point, comprising the following steps:
S1.从所评估地区相关数据库获取工作系统和备用系统电源均采用双母线接线时三分段三联络城市配电网电源系统、配电线路、负荷母线接地、短路、雷击因素造成的故障数据;S1. Obtain the fault data caused by the three-section and three-connection urban distribution network power supply system, distribution lines, load busbar grounding, short circuit, and lightning strike factors when both the working system and the backup system power supply are connected by double busbars from the relevant database in the assessed area;
S2.计算电源系统Am1a、Am1b、Cm1a、Cm1b的故障率λSAm1a、λSAm1b、λSCm1a、λSCm1b;第一工作系统和第二工作系统配电线路故障率λSALi,i=1,2,3,NA为工作系统A配电线路数量NA=3;第一备用系统和第二备用系统的配电线路故障率λSCLi,i=1,2,3,NC为系统C的电源系统Cm1至联络开关2的配电线路数量NC=2;联络电线路故障率λSL2;工作系统A负荷母线故障率λSAi,i=1,2,3,第一备用系统和第二备用系统负荷母线故障率λSCi,i=1,2,3;S2. Calculate the failure rates λ SAm1a , λ SAm1b , λ SCm1a , λ SCm1b of the power systems Am1a, Am1b, Cm1a, Cm1b ; the first working system and the second working system distribution line failure rate λ SALi , i=1,2, 3, NA is the number of distribution lines in the working system A , NA = 3; the distribution line failure rate λ SCLi of the first backup system and the second backup system, i=1, 2, 3, NC is the power supply of the system C Number of distribution lines from system Cm1 to tie switch 2 N C =2; tie power line failure rate λ SL2 ; working system A load bus failure rate λ SAi , i=1, 2, 3, the first standby system and the second standby system System load bus failure rate λ SCi , i=1,2,3;
S3.从相关数据库获取工作系统和联络系统电源均采用双母线接线时三分段三联络城市配电网电源系统、配电线路、负荷母线等接地、短路、雷击因素造成的维修数据;S3. Obtain the maintenance data caused by grounding, short-circuit, and lightning strike factors such as the power supply system, distribution line, load bus, etc. of the three-section and three-contact urban power distribution network when the power supply of the working system and the contact system adopts double-bus connection from the relevant database;
S4.计算电源系统Am1a、Am1b、Cm1a、Cm1b的的维修率μSAm1a、μSAm1b、μSCm1a、μSCm1b;第一工作系统和第二工作系统的配电线路维修率μSALi,i=1,2,3;第一备用系统和第二备用系统配电线路维修率μSCLi,i=1,2,3;联络电线路维修率μSL1;第一工作系统和第二工作系统负荷母线维修率μSAi,i=1,2,3;第一备用系统和第二备用系统负荷母线维修率μSCi,i=1,2,3;S4. Calculate the maintenance rates μ SAm1a , μ SAm1b , μ SCm1a , μ SCm1b of the power systems Am1a, Am1b, Cm1a, Cm1b ; the distribution line maintenance rates μ SALi of the first working system and the second working system, i=1, 2,3; distribution line maintenance rate μ SCLi of the first standby system and the second standby system, i=1,2,3; tie line maintenance rate μ SL1 ; load bus maintenance rate of the first working system and the second working system μ SAi , i=1,2,3; load bus maintenance rate μ SCi of the first backup system and the second backup system, i=1,2,3;
S5.根据第一工作系统与大系统电源的连接关系以及配电线路和负荷母线的故障率和维修率特征,针对不同负系统A第2条荷母线在电源母线Am1a之间的相对关系,考虑系统A上大系统电源Am1a、Am1b、负荷侧电源母线Am1、配电线路AL1、AL2和负荷母线A1、A2七种元件,以及系统C上大系统电源Cm1a、Cm1b、负荷侧电源母线Cm1、配电线路CL1、CL2和负荷母线C1、C2及联络线L2八种元件,计算时间内只发生单一或m元件重复故障的概率;S5. According to the connection relationship between the first working system and the power supply of the large system, as well as the fault rate and maintenance rate characteristics of the distribution line and the load bus, for the relative relationship between the second load bus of different negative system A and the power bus Am1a, consider Seven components of large system power supply Am1a, Am1b, load side power supply busbar Am1, distribution lines AL1, AL2 and load busbars A1 and A2 on system A, as well as large system power supply Cm1a, Cm1b, load side power supply busbar Cm1, distribution line on system C Eight elements of electrical lines CL1, CL2, load bus bars C1, C2 and tie line L2, calculation time The probability that only a single or m element repeats failure occurs within;
S6.构建电源均采用双母线接线时三分段三联络城市配电网系统A第2条负荷母线LA2供电可靠性评估的五状态空间;S6. Construct the five-state space for the reliability assessment of the power supply of the second load bus LA2 of the urban distribution network system A with three sections and three connections when the power supplies are connected by double bus bars;
S7.计算出系统电源均采用双母线接线时三分段三联络城市配电网系统A第1条负荷母线停电不可用率U,即PC5;S7. Calculate the unavailability rate U of power failure of the first load bus of the three-section three-connection urban distribution network system A when the system power supply adopts double-bus connection, that is, P C5 ;
S8.计算工作系统A第2条负荷母线A2总维修率以及其停电故障总频率。S8. Calculate the total maintenance rate of the second load bus A2 of the working system A and the total frequency of power failures.
进一步地,所述步骤S5中计算时间内只发生单一或m元件重复故障的概率的具体过程如下:Further, the calculation time in the step S5 The specific process of the probability of repeated failure of only a single or m element occurs as follows:
S5.1.大系统电源母线Am1a故障,同时由相应备用断路器闭合将负荷转由电源系统母线Am1b供电,第一工作系统转移到第二工作系统,即系统由状态1转移到状态2;其转移概率为:S5.1. The power bus Am1a of the large system fails, and at the same time, the corresponding standby circuit breaker is closed to transfer the load to the power system bus Am1b, and the first working system is transferred to the second working system, that is, the system is transferred from state 1 to state 2; its The transition probability is:
p12=λSAm1a;p 12 =λ SAm1a ;
对于可修复大系统电源母线Am1a,在研究时间内由故障状态维修到正常工作状态,同时由相应备用断路器闭合将负荷恢复由电源系统母线Am1a供电,第二工作系统转移到第一工作系统,即系统由状态2转移到状态1;其转移概率为:For repairable large system power bus Am1a, at research time It is repaired from the fault state to the normal working state, and the corresponding standby circuit breaker is closed to restore the load to the power supply system bus Am1a, and the second working system is transferred to the first working system, that is, the system is transferred from state 2 to state 1; its transfer The probability is:
p21=μSAm1a;p 21 = μ SAm1a ;
S5.2.大系统电源母线Am1b故障,第一工作系统依旧正常工作,即大系统电源母线Am1b是否故障对第一工作系统不影响其可靠性;S5.2. If the power bus Am1b of the large system fails, the first working system still works normally, that is, whether the power bus Am1b of the large system fails does not affect the reliability of the first working system;
S5.3.负荷侧电源母线Am1、配电线路AL1、AL2、负荷母线A1任一故障,第一工作系统和第二工作系统均故障;同时由相应备用联络断路器闭合将负荷转由电源系统母线Cm1a供电,第一工作系统直接转移到第一备用系统,即系统由状态1转移到状态3;其转移概率为:S5.3. If any one of the load side power bus Am1, distribution lines AL1, AL2, and load bus A1 fails, both the first working system and the second working system fail; at the same time, the corresponding standby tie breaker is closed to transfer the load to the power system The bus Cm1a supplies power, and the first working system is directly transferred to the first standby system, that is, the system transfers from state 1 to state 3; the transition probability is:
其中,NA=2; Wherein, N A =2;
对于可修复负荷侧电源母线Am1、配电线路AL1、AL2、负荷母线A1,时间内对应元件由故障状态维修到正常工作状态,同时由相应断路器操作闭合将负荷恢复由电源系统母线Am1a供电,第一备用系统转移到第一工作系统,即系统由状态3转移到状态1;其转移概率为:For the repairable load-side power bus Am1, distribution lines AL1, AL2, and load bus A1, the time The internal corresponding components are repaired from the fault state to the normal working state, and at the same time, the corresponding circuit breaker is operated and closed to restore the load to the power supply system bus Am1a, and the first standby system is transferred to the first working system, that is, the system is transferred from state 3 to state 1; Its transition probability is:
其中, in,
S5.4.负荷母线A2故障,其上面负荷停电;即系统由状态1转移到状态5;其转移概率为:S5.4. The load bus A2 fails, and the load on it is powered off; that is, the system transfers from state 1 to state 5; its transition probability is:
p15=λSA2;p 15 =λ SA2 ;
对于可修复负荷母线A2,由故障状态维修到正常工作状态,同时由相应断路器操作将负荷恢复由电源系统母线Am1a供电,即系统由状态5转移到状态1;其转移概率为:For the repairable load bus A2, it is repaired from the fault state to the normal working state, and at the same time, the corresponding circuit breaker is operated to restore the load to the power supply system bus Am1a, that is, the system transfers from state 5 to state 1; the transition probability is:
S5.5.系统处于状态2,在研究时间内它可以返回状态1,也可以过渡到状态3,即大系统电源母线Am1b、负荷侧电源母线Am1、配电线路AL1再发生任一故障,同时由相应备用联络断路器闭合将负荷转由电源系统母线Cm1a供电,第二工作系统转移到第一备用系统,即系统由状态2转移到状态3;其转移概率为:S5.5. The system is in state 2, at study time It can return to state 1 or transition to state 3, that is, if any fault occurs on the large system power bus Am1b, the load side power bus Am1, and the distribution line AL1, the corresponding standby tie breaker is closed to transfer the load to the power source. The system bus Cm1a supplies power, and the second working system transfers to the first standby system, that is, the system transfers from state 2 to state 3; the transition probability is:
p23=λSAm1b;p 23 =λ SAm1b ;
对于可修复大系统电源母线Am1b,由故障状态维修到正常工作状态,同时由相应断路器操作将负荷由电源系统母线Cm1a转移到电源系统母线Am1b供电,第一备用系统转移到第二工作系统,即系统由状态3转移到状态2;其转移概率为:For the repairable large system power bus Am1b, it is repaired from the fault state to the normal working state. At the same time, the corresponding circuit breaker operates to transfer the load from the power system bus Cm1a to the power system bus Am1b for power supply, and the first standby system is transferred to the second working system. That is, the system transitions from state 3 to state 2; its transition probability is:
S5.6.系统处于状态3,在研究时间内对应元件的故障修复它可以返回状态1和状态2,也可以过渡到状态4和状态5;S5.6. The system is in state 3, at study time It can return to state 1 and state 2, and can also transition to state 4 and state 5;
当Cm1a故障时,第一备用系统故障,由相应断路器操作将负荷转移由电源系;When Cm1a fails, the first backup system fails, and the corresponding circuit breaker operates to transfer the load to the power system;
统母线Cm1b供电,即系统由状态3转移到状态4;其转移概率为:The system bus Cm1b supplies power, that is, the system transitions from state 3 to state 4; the transition probability is:
p34=λSCm1a;p 34 =λ SCm1a ;
对于可修复大系统电源母线Cm1a,在研究时间内由故障状态维修到正常工作状态,同时由相应断路器操作将负荷由电源系统母线Cm1b转移到电源系统母线Am1a供电,第一备用系统1转移到第二工作系统,即系统由状态4转移到状态3;For the repairable large system power bus Cm1a, at the research time It is repaired from the fault state to the normal working state, and at the same time, the corresponding circuit breaker operates to transfer the load from the power system bus Cm1b to the power system bus Am1a for power supply, and the first standby system 1 is transferred to the second working system, that is, the system is transferred from state 4 to state 3;
而系统由状态4转移到状态3,其转移概率为:And the system transitions from state 4 to state 3, and its transition probability is:
p43=μSCm1a;p 43 = μ SCm1a ;
当备用系统上的负荷侧电源母线Cm1、配电线路CL1、CL2、负荷母线C1、C2以及联络线L2任一故障,第一备用系统和第二备用系统均故障,负荷母线A2停电;即系统由状态3转移到状态5,其转移概率为:When any of the load-side power busbar Cm1, distribution lines CL1, CL2, load busbars C1, C2 and tie line L2 on the backup system fails, both the first backup system and the second backup system fail, and the load bus A2 is powered off; that is, the system From state 3 to state 5, the transition probability is:
其中,NC=2; Wherein, N C =2;
对于可修复负荷侧电源母线Cm1、配电线路CL1、CL2、负荷母线C1、C2以及联络线L2,对应对应元件的故障修复系统可以由状态5返回状态3;其转移概率为:For the repairable load-side power bus Cm1, distribution lines CL1, CL2, load bus C1, C2 and tie line L2, the fault repair system of the corresponding component can return from state 5 to state 3; the transition probability is:
其中,NC=2, where N C =2,
NC=2,为从联络断路器或联络开关至负荷电源母线Cm1之间的系统C配电线路,同时也是为从联络断路器或联络开关至负荷侧电源母线Cm1之间的系统C负荷母线总数;N C = 2, it is the system C distribution line from the tie breaker or tie switch to the load power busbar Cm1, and it is also the system C load bus from the tie breaker or tie switch to the load side power busbar Cm1 total;
S5.7.系统处于状态4,对应元件Cm1a的故障修复系统可以返回状态3,也可以过渡到状态5;即当大系统电源母线Cm1b,第二备用系统故障,负荷母线A1停电,其转移概率为:S5.7. The system is in state 4, the fault repair system of the corresponding component Cm1a can return to state 3, or it can transition to state 5; that is, when the large system power bus Cm1b, the second backup system fails, and the load bus A1 is powered off, its transition probability for:
p45=λSCm1b;p 45 =λ SCm1b ;
对于对应可修复大系统电源母线Cm1b、负荷侧电源母线Cm1、配电线路CL1、CL2、负荷母线C1、C2以及联络线L2故障修复,系统可以由状态5返回状态4,其转移概率为:For the corresponding repairable large system power busbar Cm1b, load side power busbar Cm1, distribution lines CL1, CL2, load busbars C1, C2 and tie line L2 fault repair, the system can return from state 5 to state 4, and its transition probability is:
S5.8.系统处于状态5,对应元件的故障修复系统可以返回状态4,可以返回状态3,可以返回状态1。S5.8. The system is in state 5, the fault repair system of the corresponding component can return to state 4, can return to state 3, and can return to state 1.
进一步地,所述步骤S6的具体过程如下:Further, the specific process of the step S6 is as follows:
构建电源均采用双母线接线时三分段三联络城市配电网系统A第2条负荷母线LA2供电可靠性评估的五状态空间:The five-state space for the reliability assessment of the power supply of the second load bus LA2 of the three-segment and three-connection urban distribution network system A when the power sources are all connected by double busbars:
式中,p21=μSAm1a,p12=λSAm1a,In the formula, p 21 =μ SAm1a , p 12 =λ SAm1a ,
p23=λSAm1b,p15=λSA2,p 23 =λ SAm1b , p 15 =λ SA2 ,
p43=μSCm1a,p34=λSCm1a, p 43 =μ SCm1a , p 34 =λ SCm1a ,
p45=λSCm1b, p 45 =λ SCm1b ,
其中,NC=2,NA=2,并且矩阵Pc每行元素之和为1。Wherein, N C =2, N A =2, and the sum of the elements of each row of the matrix Pc is 1.
进一步地,所述步骤S7的具体过程如下:Further, the specific process of the step S7 is as follows:
利用[PC1 PC2 PC3 PC4 PC5]·Pc=[PC1 PC2 PC3 PC4 PC5]及PC1+PC2+PC3+PC4+PC5=1,上式联立形成新的等价矩阵形式:Using [P C1 P C2 P C3 P C4 P C5 ]·Pc=[P C1 P C2 P C3 P C4 P C5 ] and P C1 +P C2 +P C3 +P C4 +P C5 =1, the above equations are combined Form the new equivalent matrix form:
解方程组可得系统停留在对应状态的稳态概率,利用MATLAB编程计算出系统电源均采用双母线接线时三分段三联络城市配电网系统A第1条负荷母线停电不可用率U,即PC5。The steady-state probability of the system staying in the corresponding state can be obtained by solving the equation set, and the unavailability rate U of the first load bus of the three-section and three-connection urban distribution network system A when the power supply of the system is all connected by double busbars is calculated by MATLAB programming, Namely PC5 .
进一步地,所述步骤S8的具体为:Further, the details of the step S8 are:
系统A第2条负荷母线A2总维修率:The total maintenance rate of the second load bus A2 of system A:
μ2=p51+p53+p54 μ 2 =p 51 +p 53 +p 54
系统A第2条负荷母线A2停电故障总频率:The total frequency of power failure of the second load bus A2 of system A:
f2=PC5×(p51+p53+p54)。f 2 =P C5 ×(p 51 +p 53 +p 54 ).
与现有技术相比,本方案原理及优点如下:Compared with the prior art, the principle and advantages of this scheme are as follows:
本方案先进行电源系统及各线路的故障率和维修率计算,然后再针对元件重复故障的概率进行计算,接着构建状态空间,计算负荷母线停电不可用率,最后计算得出停电故障总频率。本方案计算得出的结果精准度较高。This scheme first calculates the failure rate and maintenance rate of the power system and each line, and then calculates the probability of repeated failure of the components, then constructs the state space, calculates the unavailability rate of power failure of the load bus, and finally calculates the total frequency of power failures. The results calculated by this scheme have high accuracy.
附图说明Description of drawings
为了更清楚地说明本发明实施例或现有技术中的技术方案,下面将对实施例或现有技术描述中所需要使用的服务作简单地介绍,显而易见地,下面描述中的附图仅仅是本发明的一些实施例,对于本领域普通技术人员来讲,在不付出创造性劳动的前提下,还可以根据这些附图获得其他的附图。In order to illustrate the embodiments of the present invention or the technical solutions in the prior art more clearly, the following briefly introduces the services required in the description of the embodiments or the prior art. Obviously, the drawings in the following description are only For some embodiments of the present invention, for those of ordinary skill in the art, other drawings can also be obtained according to these drawings without creative efforts.
图1为三分段三联络城市配电网系统A第2条负荷母线扩大到联络系统图;Figure 1 is a diagram of the expansion of the second load bus of the three-section three-connection urban distribution network system A to the connection system;
图2为本发明一种负荷点停电故障总频率评估方法的原理流程图。FIG. 2 is a principle flow chart of a method for evaluating the total frequency of power failure at a load point according to the present invention.
具体实施方式Detailed ways
下面结合具体实施例对本发明作进一步说明:Below in conjunction with specific embodiment, the present invention will be further described:
本实施例基于三分段三联络城市配电网系统而进行,三分段三联络城市配电网系统中系统A上的第2条负荷母线联络线和联络断路器与系统C的第2条负荷母线联络,对于系统A上的第2条负荷母线来说,系统A处于工作状态,系统C处于备用状态,系统A称为工作系统,系统C称为备用系统。考虑系统A、系统C的电源均采用双母线接线时,系统A相应分为工作系统1和工作系统2,工作系统1通过断路器与变电站低压电源母线Am1a连接,并由负荷侧电源母线Am1、分段断路器、以及三条配电线路和三条负荷母线A1、A2、A3所组成。工作系统2通过断路器与变电站低压电源母线Am1b连接,并由负荷侧电源母线Am1、分段断路器、以及三条配电线路和三条负荷母线A1、A2、A3所组成。系统C相应分为备用系统1和备用系统2,备用系统1与变电站低压电源母线Cm1a连接,并由负荷侧电源母线Cm1、分段断路器、联络断路器,联络线以及2条配电线CL1、CL2和2条负荷母线C1、C2所组成;备用系统2与变电站低压电源母线Cm1b连接,并由负荷侧电源母线Cm1、分段断路器、联络断路器,联络线以及2条配电线CL1、CL2和2条负荷母线C1、C2所组成。具体如图1所示。This embodiment is based on a three-section three-connect urban distribution network system. In the three-section and three-connect urban distribution network system, the second load bus tie line and the circuit breaker on the system A in the three-section and three-connect urban distribution network system are connected with the second line of system C. Load bus connection, for the second load bus on system A, system A is in working state, system C is in standby state, system A is called the working system, and system C is called the standby system. Considering that the power supply of system A and system C are connected by double busbars, system A is correspondingly divided into working system 1 and working system 2. Working system 1 is connected to the low-voltage power busbar Am1a of the substation through a circuit breaker, and is connected by the load-side power busbar Am1, It consists of sectional circuit breakers, three distribution lines and three load buses A1, A2 and A3. The working system 2 is connected to the low-voltage power busbar Am1b of the substation through the circuit breaker, and is composed of the power busbar Am1 on the load side, the sectional circuit breaker, three distribution lines and three load busbars A1, A2, and A3. System C is correspondingly divided into standby system 1 and standby system 2. Standby system 1 is connected to the substation low-voltage power busbar Cm1a, and consists of the load-side power busbar Cm1, sectional circuit breaker, tie breaker, tie line and two distribution lines CL1 , CL2 and 2 load busbars C1, C2; the backup system 2 is connected to the substation low-voltage power busbar Cm1b, and consists of the load side power busbar Cm1, segment circuit breaker, tie circuit breaker, tie line and 2 distribution lines CL1 , CL2 and 2 load busbars C1, C2. Specifically as shown in Figure 1.
如图2所示,本实施例所述的一种负荷点停电故障总频率评估方法,包括以下步骤:As shown in FIG. 2 , the method for evaluating the total frequency of power failure at a load point described in this embodiment includes the following steps:
S1.从所评估地区相关数据库获取工作系统和备用系统电源均采用双母线接线时三分段三联络城市配电网电源系统、配电线路、负荷母线接地、短路、雷击因素造成的故障数据;S1. Obtain the fault data caused by the three-section and three-connection urban distribution network power supply system, distribution lines, load busbar grounding, short circuit, and lightning strike factors when both the working system and the backup system power supply are connected by double busbars from the relevant database in the assessed area;
S2.计算电源系统Am1a、Am1b、Cm1a、Cm1b的故障率λSAm1a、λSAm1b、λSCm1a、λSCm1b;第一工作系统和第二工作系统配电线路故障率λSALi,i=1,2,3,NA为工作系统A配电线路数量NA=3;第一备用系统和第二备用系统的配电线路故障率λSCLi,i=1,2,3,NC为系统C的电源系统Cm1至联络开关2的配电线路数量NC=2;联络电线路故障率λSL2;工作系统A负荷母线故障率λSAi,i=1,2,3,第一备用系统和第二备用系统负荷母线故障率λSCi,i=1,2,3;S2. Calculate the failure rates λ SAm1a , λ SAm1b , λ SCm1a , λ SCm1b of the power systems Am1a, Am1b, Cm1a, Cm1b ; the first working system and the second working system distribution line failure rate λ SALi , i=1,2, 3, NA is the number of distribution lines in the working system A , NA = 3; the distribution line failure rate λ SCLi of the first backup system and the second backup system, i=1, 2, 3, NC is the power supply of the system C Number of distribution lines from system Cm1 to tie switch 2 N C =2; tie power line failure rate λ SL2 ; working system A load bus failure rate λ SAi , i=1, 2, 3, the first standby system and the second standby system System load bus failure rate λ SCi , i=1,2,3;
S3.从相关数据库获取工作系统和联络系统电源均采用双母线接线时三分段三联络城市配电网电源系统、配电线路、负荷母线等接地、短路、雷击因素造成的维修数据;S3. Obtain the maintenance data caused by grounding, short-circuit, and lightning strike factors such as the power supply system, distribution line, load bus, etc. of the three-section and three-contact urban power distribution network when the power supply of the working system and the contact system adopts double-bus connection from the relevant database;
S4.计算电源系统Am1a、Am1b、Cm1a、Cm1b的的维修率μSAm1a、μSAm1b、μSCm1a、μSCm1b;第一工作系统和第二工作系统的配电线路维修率μSALi,i=1,2,3;第一备用系统和第二备用系统配电线路维修率μSCLi,i=1,2,3;联络电线路维修率μSL1;第一工作系统和第二工作系统负荷母线维修率μSAi,i=1,2,3;第一备用系统和第二备用系统负荷母线维修率μSCi,i=1,2,3;S4. Calculate the maintenance rates μ SAm1a , μ SAm1b , μ SCm1a , μ SCm1b of the power systems Am1a, Am1b, Cm1a, Cm1b ; the distribution line maintenance rates μ SALi of the first working system and the second working system, i=1, 2,3; distribution line maintenance rate μ SCLi of the first standby system and the second standby system, i=1,2,3; tie line maintenance rate μ SL1 ; load bus maintenance rate of the first working system and the second working system μ SAi , i=1,2,3; load bus maintenance rate μ SCi of the first backup system and the second backup system, i=1,2,3;
S5.根据第一工作系统与大系统电源的连接关系以及配电线路和负荷母线的故障率和维修率特征,针对不同负系统A第2条荷母线在电源母线Am1a之间的相对关系,考虑系统A上大系统电源Am1a、Am1b、负荷侧电源母线Am1、配电线路AL1、AL2和负荷母线A1、A2七种元件,以及系统C上大系统电源Cm1a、Cm1b、负荷侧电源母线Cm1、配电线路CL1、CL2和负荷母线C1、C2及联络线L2八种元件,计算时间内只发生单一或m元件重复故障的概率;具体过程如下:S5. According to the connection relationship between the first working system and the power supply of the large system, as well as the fault rate and maintenance rate characteristics of the distribution line and the load bus, for the relative relationship between the second load bus of different negative system A and the power bus Am1a, consider Seven components of large system power supply Am1a, Am1b, load side power supply busbar Am1, distribution lines AL1, AL2 and load busbars A1 and A2 on system A, as well as large system power supply Cm1a, Cm1b, load side power supply busbar Cm1, distribution line on system C Eight elements of electrical lines CL1, CL2, load bus bars C1, C2 and tie line L2, calculation time The probability that only a single or m element repeats failure occurs within; the specific process is as follows:
S5.1.大系统电源母线Am1a故障,同时由相应备用断路器闭合将负荷转由电源系统母线Am1b供电,第一工作系统转移到第二工作系统,即系统由状态1转移到状态2;其转移概率为:S5.1. The power bus Am1a of the large system fails, and at the same time, the corresponding standby circuit breaker is closed to transfer the load to the power system bus Am1b, and the first working system is transferred to the second working system, that is, the system is transferred from state 1 to state 2; its The transition probability is:
p12=λSAm1a;p 12 =λ SAm1a ;
对于可修复大系统电源母线Am1a,在研究时间内由故障状态维修到正常工作状态,同时由相应备用断路器闭合将负荷恢复由电源系统母线Am1a供电,第二工作系统转移到第一工作系统,即系统由状态2转移到状态1;其转移概率为:For repairable large system power bus Am1a, at research time It is repaired from the fault state to the normal working state, and the corresponding standby circuit breaker is closed to restore the load to the power supply system bus Am1a, and the second working system is transferred to the first working system, that is, the system is transferred from state 2 to state 1; its transfer The probability is:
p21=μSAm1a;p 21 = μ SAm1a ;
S5.2.大系统电源母线Am1b故障,第一工作系统依旧正常工作,即大系统电源母线Am1b是否故障对第一工作系统不影响其可靠性;S5.2. If the power bus Am1b of the large system fails, the first working system still works normally, that is, whether the power bus Am1b of the large system fails does not affect the reliability of the first working system;
S5.3.负荷侧电源母线Am1、配电线路AL1、AL2、负荷母线A1任一故障,第一工作系统和第二工作系统均故障;同时由相应备用联络断路器闭合将负荷转由电源系统母线Cm1a供电,第一工作系统直接转移到第一备用系统,即系统由状态1转移到状态3;其转移概率为:S5.3. If any one of the load side power bus Am1, distribution lines AL1, AL2, and load bus A1 fails, both the first working system and the second working system fail; at the same time, the corresponding standby tie breaker is closed to transfer the load to the power system The bus Cm1a supplies power, and the first working system is directly transferred to the first standby system, that is, the system transfers from state 1 to state 3; the transition probability is:
其中,NA=2; Wherein, N A =2;
对于可修复负荷侧电源母线Am1、配电线路AL1、AL2、负荷母线A1,时间内对应元件由故障状态维修到正常工作状态,同时由相应断路器操作闭合将负荷恢复由电源系统母线Am1a供电,第一备用系统转移到第一工作系统,即系统由状态3转移到状态1;其转移概率为:For the repairable load-side power bus Am1, distribution lines AL1, AL2, and load bus A1, the time The internal corresponding components are repaired from the fault state to the normal working state, and at the same time, the corresponding circuit breaker is operated and closed to restore the load to the power supply system bus Am1a, and the first standby system is transferred to the first working system, that is, the system is transferred from state 3 to state 1; Its transition probability is:
其中, in,
S5.4.负荷母线A2故障,其上面负荷停电;即系统由状态1转移到状态5;其转移概率为:S5.4. The load bus A2 fails, and the load on it is powered off; that is, the system transfers from state 1 to state 5; its transition probability is:
p15=λSA2;p 15 =λ SA2 ;
对于可修复负荷母线A2,由故障状态维修到正常工作状态,同时由相应断路器操作将负荷恢复由电源系统母线Am1a供电,即系统由状态5转移到状态1;其转移概率为:For the repairable load bus A2, it is repaired from the fault state to the normal working state, and at the same time, the corresponding circuit breaker is operated to restore the load to the power supply system bus Am1a, that is, the system transfers from state 5 to state 1; the transition probability is:
S5.5.系统处于状态2,在研究时间内它可以返回状态1,也可以过渡到状态3,即大系统电源母线Am1b、负荷侧电源母线Am1、配电线路AL1再发生任一故障,同时由相应备用联络断路器闭合将负荷转由电源系统母线Cm1a供电,第二工作系统转移到第一备用系统,即系统由状态2转移到状态3;其转移概率为:S5.5. The system is in state 2, at study time It can return to state 1 or transition to state 3, that is, if any fault occurs on the large system power bus Am1b, the load side power bus Am1, and the distribution line AL1, the corresponding standby tie breaker is closed to transfer the load to the power source. The system bus Cm1a supplies power, and the second working system transfers to the first standby system, that is, the system transfers from state 2 to state 3; the transition probability is:
p23=λSAm1b;p 23 =λ SAm1b ;
对于可修复大系统电源母线Am1b,由故障状态维修到正常工作状态,同时由相应断路器操作将负荷由电源系统母线Cm1a转移到电源系统母线Am1b供电,第一备用系统转移到第二工作系统,即系统由状态3转移到状态2;其转移概率为:For the repairable large system power bus Am1b, it is repaired from the fault state to the normal working state. At the same time, the corresponding circuit breaker operates to transfer the load from the power system bus Cm1a to the power system bus Am1b for power supply, and the first standby system is transferred to the second working system. That is, the system transitions from state 3 to state 2; its transition probability is:
S5.6.系统处于状态3,在研究时间内对应元件的故障修复它可以返回状态1和状态2,也可以过渡到状态4和状态5;S5.6. The system is in state 3, at study time It can return to state 1 and state 2, and can also transition to state 4 and state 5;
当Cm1a故障时,第一备用系统故障,由相应断路器操作将负荷转移由电源系;When Cm1a fails, the first backup system fails, and the corresponding circuit breaker operates to transfer the load to the power system;
统母线Cm1b供电,即系统由状态3转移到状态4;其转移概率为:The system bus Cm1b supplies power, that is, the system transitions from state 3 to state 4; the transition probability is:
p34=λSCm1a;p 34 =λ SCm1a ;
对于可修复大系统电源母线Cm1a,在研究时间内由故障状态维修到正常工作状态,同时由相应断路器操作将负荷由电源系统母线Cm1b转移到电源系统母线Am1a供电,第一备用系统1转移到第二工作系统,即系统由状态4转移到状态3;For the repairable large system power bus Cm1a, at the research time It is repaired from the fault state to the normal working state, and at the same time, the corresponding circuit breaker operates to transfer the load from the power system bus Cm1b to the power system bus Am1a for power supply, and the first standby system 1 is transferred to the second working system, that is, the system is transferred from state 4 to state 3;
而系统由状态4转移到状态3,其转移概率为:And the system transitions from state 4 to state 3, and its transition probability is:
p43=μSCm1a;p 43 = μ SCm1a ;
当备用系统上的负荷侧电源母线Cm1、配电线路CL1、CL2、负荷母线C1、C2以及联络线L2任一故障,第一备用系统和第二备用系统均故障,负荷母线A2停电;即系统由状态3转移到状态5,其转移概率为:When any of the load-side power busbar Cm1, distribution lines CL1, CL2, load busbars C1, C2 and tie line L2 on the backup system fails, both the first backup system and the second backup system fail, and the load bus A2 is powered off; that is, the system From state 3 to state 5, the transition probability is:
其中,NC=2; Wherein, N C =2;
对于可修复负荷侧电源母线Cm1、配电线路CL1、CL2、负荷母线C1、C2以及联络线L2,对应对应元件的故障修复系统可以由状态5返回状态3;其转移概率为:For the repairable load-side power bus Cm1, distribution lines CL1, CL2, load bus C1, C2 and tie line L2, the fault repair system of the corresponding component can return from state 5 to state 3; the transition probability is:
其中,NC=2, where N C =2,
NC=2,为从联络断路器或联络开关至负荷电源母线Cm1之间的系统C配电线路,同时也是为从联络断路器或联络开关至负荷侧电源母线Cm1之间的系统C负荷母线总数;N C = 2, it is the system C distribution line from the tie breaker or tie switch to the load power busbar Cm1, and it is also the system C load bus from the tie breaker or tie switch to the load side power busbar Cm1 total;
S5.7.系统处于状态4,对应元件Cm1a的故障修复系统可以返回状态3,也可以过渡到状态5;即当大系统电源母线Cm1b,第二备用系统故障,负荷母线A1停电,其转移概率为:S5.7. The system is in state 4, the fault repair system of the corresponding component Cm1a can return to state 3, or it can transition to state 5; that is, when the large system power bus Cm1b, the second backup system fails, and the load bus A1 is powered off, its transition probability for:
p45=λSCm1b;p 45 =λ SCm1b ;
对于对应可修复大系统电源母线Cm1b、负荷侧电源母线Cm1、配电线路CL1、CL2、负荷母线C1、C2以及联络线L2故障修复,系统可以由状态5返回状态4,其转移概率为:For the corresponding repairable large system power busbar Cm1b, load side power busbar Cm1, distribution lines CL1, CL2, load busbars C1, C2 and tie line L2 fault repair, the system can return from state 5 to state 4, and its transition probability is:
S5.8.系统处于状态5,对应元件的故障修复系统可以返回状态4,可以返回状态3,可以返回状态1。S5.8. The system is in state 5, the fault repair system of the corresponding component can return to state 4, can return to state 3, and can return to state 1.
S6.构建电源均采用双母线接线时三分段三联络城市配电网系统A第2条负荷母线LA2供电可靠性评估的五状态空间:S6. The five-state space for the reliability assessment of the power supply reliability of the second load bus LA2 of the three-segment and three-connected urban distribution network system A when the power sources are all connected by double busbars:
式中,p21=μSAm1a,p12=λSAm1a,In the formula, p 21 =μ SAm1a , p 12 =λ SAm1a ,
p23=λSAm1b,p15=λSA2,p 23 =λ SAm1b , p 15 =λ SA2 ,
p43=μSCm1a,p34=λSCm1a, p 43 =μ SCm1a , p 34 =λ SCm1a ,
p45=λSCm1b, p 45 =λ SCm1b ,
其中,NC=2,NA=2,并且矩阵Pc每行元素之和为1。Wherein, N C =2, N A =2, and the sum of the elements of each row of the matrix Pc is 1.
S7.利用[PC1 PC2 PC3 PC4 PC5]·Pc=[PC1 PC2 PC3 PC4 PC5]及PC1+PC2+PC3+PC4+PC5=1,上式联立形成新的等价矩阵形式:S7. Using [P C1 P C2 P C3 P C4 P C5 ]·Pc=[P C1 P C2 P C3 P C4 P C5 ] and P C1 + P C2 + P C3 + P C4 + P C5 =1, the above formula Simultaneously form a new equivalent matrix form:
解方程组可得系统停留在对应状态的稳态概率,利用MATLAB编程计算出系统电源均采用双母线接线时三分段三联络城市配电网系统A第1条负荷母线停电不可用率U,即PC5;The steady-state probability of the system staying in the corresponding state can be obtained by solving the equation set, and the unavailability rate U of the first load bus of the three-section and three-connection urban distribution network system A when the power supply of the system is all connected by double busbars is calculated by MATLAB programming, i.e. PC5 ;
S8.计算系统A第2条负荷母线A2总维修率:S8. Calculate the total maintenance rate of the second load bus A2 of system A:
μ2=p51+p53+p54;μ 2 =p 51 +p 53 +p 54 ;
计算系统A第2条负荷母线A2停电故障总频率:Calculate the total frequency of power failure of the second load bus A2 of system A:
f2=PC5×(p51+p53+p54)。f 2 =P C5 ×(p 51 +p 53 +p 54 ).
以上所述之实施例子只为本发明之较佳实施例,并非以此限制本发明的实施范围,故凡依本发明之形状、原理所作的变化,均应涵盖在本发明的保护范围内。The above-mentioned embodiments are only preferred embodiments of the present invention, and are not intended to limit the scope of implementation of the present invention. Therefore, any changes made according to the shape and principle of the present invention should be included within the protection scope of the present invention.
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