CN109684777B - Electric formula car frame design method - Google Patents
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Abstract
本发明具体涉及一种电动方程式赛车车架的设计方法,在设计初期搭建人机试验台,获取人机参数,依据整车总布置确定整车参数;通过悬架运动学和动力学仿真计算出悬架硬点位置,估算车架硬点位置;利用车架参数与硬点位置,搭建车架初始模型;对车架模型进行优化并进行有限元扭转刚度分析,获得理想车架模型;对确定的车架模型进行工况分析,验证在不同工况下的结构强度与安全性能;在工况分析后对模型进行约束模态分析,获取车架的模态参数,验证是否会出现共振现象,并依据分析结果对模型进行优化,获得最终车架模型;设计车架焊接夹具,完成实物焊接。本发明大大减少了车架设计周期,提高了设计的合理性,使设计出的车架更好的满足整车性能。
The invention specifically relates to a design method for the frame of an electric formula racing car. In the early stage of design, a human-machine test bench is built to obtain human-machine parameters, and the vehicle parameters are determined based on the overall layout of the vehicle. The system is calculated through suspension kinematics and dynamics simulation. Suspension hard point position, estimate the frame hard point position; use the frame parameters and hard point positions to build an initial frame model; optimize the frame model and perform finite element torsional stiffness analysis to obtain the ideal frame model; determine Carry out working condition analysis on the frame model to verify the structural strength and safety performance under different working conditions; after the working condition analysis, conduct constrained modal analysis on the model to obtain the modal parameters of the frame and verify whether resonance phenomena will occur. And based on the analysis results, the model was optimized to obtain the final frame model; the frame welding fixture was designed to complete the physical welding. The invention greatly reduces the frame design cycle, improves the rationality of the design, and enables the designed frame to better meet the performance of the entire vehicle.
Description
技术领域Technical field
本发明属于结构设计与计算机辅助工程技术领域,具体涉及一种电动方程式赛车车架的设计方法。The invention belongs to the technical fields of structural design and computer-aided engineering, and specifically relates to a design method of an electric formula racing car frame.
背景技术Background technique
中国方程式电动汽车大赛起步于2013年,是中国方程式汽车大赛的拓展与补充。根据大赛组委会颁发的技术规则,在一年的时间里设计制造调教出一辆单人竞速小型赛车,其最大特征就在于赛车各项设计与制造必须符合技术规则,包括车架主体结构,电池箱设计、模组电量、电机功率等重要参数,以此来保证赛车的安全与赛事的公平。The China Formula Electric Car Competition started in 2013 and is an expansion and supplement of the China Formula Car Competition. According to the technical rules issued by the competition organizing committee, a single-person racing small car was designed, manufactured and tuned within one year. Its biggest feature is that the design and manufacturing of the car must comply with the technical rules, including the main structure of the frame. , battery box design, module power, motor power and other important parameters to ensure the safety of the car and the fairness of the event.
方程式赛车车架作为电动方程式赛车自主设计制造的最大结构部件,是整车各总成的载体,具有布置总体、连接总成的重要作用。车架的设计以高强度、高刚度、舒适性、轻量化作为设计目标。目前方程式赛车车架多采用钢管桁架式车架结构,加工通过钢管焊接而成,也有少数学校采用碳纤维单体壳设计。在设计过程中,存在设计流程不规范,理论应用不合理的问题,没有从全局进行设计考量,多是主观临时起意,导致设计与加工周期长、问题多,最重要的是车架设计不能满足整车性能要求。As the largest structural component independently designed and manufactured by the Formula E racing car, the frame of the formula racing car is the carrier of each assembly of the vehicle and plays an important role in arranging the overall layout and connecting the assemblies. The design of the frame takes high strength, high stiffness, comfort and lightweight as the design goals. At present, formula racing car frames mostly adopt a steel tube truss frame structure, which is processed and welded by steel tubes. There are also a few schools that use carbon fiber monocoque designs. During the design process, there are problems such as non-standard design process and unreasonable theoretical application. There is no overall design consideration and most of them are subjective and improvised, resulting in a long design and processing cycle and many problems. The most important thing is that the frame design cannot meet the requirements. Vehicle performance requirements.
发明内容Contents of the invention
针对上述存在的问题,本发明提出一种电动方程式赛车车架设计方法,以解决电动方程式赛车车架设计不规范不合理的问题。In view of the above-mentioned existing problems, the present invention proposes a frame design method for a formula electric racing car to solve the problem of irregular and unreasonable frame design of a formula electric racing car.
为实现上述目的,本发明具体技术方案如下:一种电动方程式赛车车架设计方法,包括以下步骤:In order to achieve the above objects, the specific technical solutions of the present invention are as follows: a design method for a formula electric racing car frame, including the following steps:
1)确定车架参数以及车架硬点位置;1) Determine the frame parameters and the position of the frame’s hard points;
2)利用人机参数、整车参数、车架硬点位置,搭建初始车架模型T;2) Build the initial frame model T using human-machine parameters, vehicle parameters, and frame hard point positions;
3)在初始车架模型T基础上增加辅助杆件,调整杆件尺寸,得到调整后的车架模型T’,其中,杆件尺寸包括管径尺寸、壁厚尺寸;3) Add auxiliary rods to the initial frame model T, adjust the rod dimensions, and obtain the adjusted frame model T’, where the rod dimensions include pipe diameter and wall thickness;
4)利用有限元分析车架模型T’扭转刚度,得到理想车架模型T1;4) Use finite element analysis to analyze the torsional stiffness of the frame model T’ and obtain the ideal frame model T1;
5)对理想车架模型T1进行工况分析,得到理想安全车架模型T2;5) Perform working condition analysis on the ideal frame model T1 to obtain the ideal safe frame model T2;
6)对理想安全车架模型T2进行有限元模态分析,得到最终车架模型T3;6) Conduct finite element modal analysis on the ideal safety frame model T2 to obtain the final frame model T3;
7)对最终车架模型T3进行焊接夹具设计。7) Design the welding fixture for the final frame model T3.
进一步的,上述步骤1)中确定车架参数及车架硬点位置的具体方法如下:Further, the specific method for determining the frame parameters and frame hard point positions in step 1) above is as follows:
1.1)在设计初期进行人机实验,搭建人机实验台,以模拟器操作成绩与驾驶员主观感受为评价标准,以驾驶员人机数据库为客观参考,获得人机参数,其中人机参数包括:主环前环之间的距离d1、主环高度h1、前环高度h2、制动油门踏板距主环的距离d2、制动油门踏板倾斜角度γ、方向盘中心点高度h3及距主环距离d2、座舱宽度l1;1.1) Carry out human-machine experiments in the early stage of design, build a human-machine experiment platform, use the simulator operation performance and the driver's subjective feelings as the evaluation criteria, and use the driver's human-machine database as an objective reference to obtain human-machine parameters, in which the human-machine parameters include : Distance d 1 between the main ring and the front ring, height h 1 of the main ring, height h 2 of the front ring, distance d 2 between the brake accelerator pedal and the main ring, inclination angle γ of the brake accelerator pedal, height h 3 of the steering wheel center point And the distance d 2 from the main ring, the cockpit width l 1 ;
1.2)确定前后载荷比k;1.2) Determine the front and rear load ratio k;
1.3)计算整车轴距L;1.3) Calculate the vehicle wheelbase L;
1.4)确定轮距Ls;1.4) Determine the wheelbase L s ;
1.5)确定悬架硬点位置,利用悬架定位参数,进行运动学、动力学仿真确定悬架硬点位置,定位参数包括外倾角α1、内倾角α2、后倾角α3、前束α4;1.5) Determine the position of the suspension hard point, and use the suspension positioning parameters to perform kinematics and dynamics simulations to determine the position of the suspension hard point. The positioning parameters include camber angle α 1 , inclination angle α 2 , caster angle α 3 , and toe-in α 4 ;
1.6)确定车架硬点位置,根据悬架硬点位置以及车架硬点与悬架硬点位置相对量得到车架硬点位置,其中相对量由悬架与车架连接的吊耳尺寸确定。1.6) Determine the position of the hard point of the frame. The position of the hard point of the frame is obtained based on the position of the hard point of the suspension and the relative position of the hard point of the frame and the hard point of the suspension. The relative amount is determined by the size of the lifting lugs connecting the suspension and the frame. .
进一步的,上述步骤4)中得到理想车架模型T1的具体方法如下:Further, the specific method for obtaining the ideal frame model T1 in step 4) above is as follows:
4.1)利用有限元计算车架模型T’扭转刚度值Kn,计算公式如下:4.1) Use finite element to calculate the torsional stiffness value K n of the frame model T'. The calculation formula is as follows:
式中Kn为每次模型计算的扭转刚度值,F为支反力,d为悬架两硬点之间的距离,ΔA、ΔB为两硬点的强制位移;In the formula, K n is the torsional stiffness value calculated by each model, F is the support reaction force, d is the distance between the two hard points of the suspension, ΔA and ΔB are the forced displacements of the two hard points;
4.2)计算车架模型T’的综合车架扭转刚度K,计算公式如下:4.2) Calculate the comprehensive frame torsional stiffness K of the frame model T’. The calculation formula is as follows:
式中Kf为前悬扭转下的扭转刚度,Kr为后悬扭转下的扭转刚度,a为前轴距,,b为后轴距,L为轴距;In the formula, K f is the torsional stiffness of the front suspension under torsion, K r is the torsional stiffness of the rear suspension under torsion, a is the front wheelbase, b is the rear wheelbase, and L is the wheelbase;
4.3)判断是否满足K>K0且m<m0,如果满足转步骤4.4),否则转步骤3);4.3) Determine whether K>K 0 and m<m 0 are satisfied. If satisfied, go to step 4.4), otherwise go to step 3);
4.4)判断是否满足如果满足则得到理想车架模型T1,否则转步骤3)。4.4) Determine whether it is satisfied If satisfied, the ideal frame model T1 is obtained, otherwise go to step 3).
进一步的,上述步骤5)中对理想车架模型T1进行工况分析包括如下步骤:Further, the working condition analysis of the ideal frame model T1 in step 5) above includes the following steps:
5.1)直线工况分析;5.1) Straight-line working condition analysis;
5.2)匀速过弯工况分析;5.2) Analysis of uniform speed cornering conditions;
5.3)加速工况分析;5.3) Accelerate working condition analysis;
5.4)制动工况分析。5.4) Analysis of braking conditions.
进一步的,上述步骤中6)对理想安全车架模型T2进行有限元模态分析,得到最终车架模型T3的具体方法如下:Further, in step 6) above, finite element modal analysis is performed on the ideal safety frame model T2, and the specific method to obtain the final frame model T3 is as follows:
6.1)固定约束车架前后悬8个硬点;6.1) Fixed and constrained 8 hard points on the front and rear suspension of the frame;
6.2)对车架施加惯性力载荷;6.2) Apply inertial force load to the frame;
6.3)进行仿真分析,得到前8阶模态频率与振型;6.3) Carry out simulation analysis to obtain the first 8 mode frequencies and vibration shapes;
6.4)将所得8阶模态频率与电机等部件的外部激励频率进行比较,观察是否频率重合发生共振,若发生共振现象,则返回步骤3)进行尺寸杆件变化;否则得到最终车架模型T3。6.4) Compare the obtained 8th-order modal frequency with the external excitation frequency of the motor and other components, and observe whether the frequencies coincide with resonance. If resonance occurs, return to step 3) to change the size of the members; otherwise, the final frame model T3 is obtained. .
进一步的,上述步骤1.3)中计算整车轴距L的具体方法如下:Further, the specific method for calculating the vehicle wheelbase L in step 1.3) above is as follows:
1.3.1)计算整车前轴载荷Mtf,公式如下:1.3.1) Calculate the vehicle front axle load M tf , the formula is as follows:
式中,Mi为各主要部件的质量,Xi为各主要部件相对于质心的x轴距离,L则为轴距,N表示部件个数;In the formula, M i is the mass of each main component, Xi is the x-axis distance of each main component relative to the center of mass, L is the wheelbase, and N represents the number of components;
1.3.2)计算整车后轴载荷Mtr,公式方法如下:1.3.2) Calculate the vehicle rear axle load M tr , the formula method is as follows:
Mtr=M0-Mtf M tr =M 0 -M tf
式中,M0为整车质量(驾驶员满载的情况下);In the formula, M 0 is the mass of the vehicle (when the driver is fully loaded);
1.3.3)计算整车轴距L,公式如下:1.3.3) Calculate the vehicle wheelbase L, the formula is as follows:
进一步的,上述步骤5.1)中直线工况分析包括如下步骤:Further, the straight-line working condition analysis in step 5.1) above includes the following steps:
5.1.1)固定约束后悬4个硬点,前悬左侧硬点y,z方向约束,释放x方向的自由度,右侧硬点y,z方向约束,释放x方向自由度;5.1.1) Four hard points of the rear suspension are fixed and constrained. The left hard point y of the front suspension is constrained in the z direction and releases the degree of freedom in the x direction. The right hard point y is constrained in the z direction and releases the degree of freedom in the x direction;
5.1.2)对车架施加载荷,其中载荷位置为车架、驾驶员、电机、电池箱、减速机各自与车架接触的位置,载荷大小为各自重量乘动载因数;5.1.2) Apply a load to the frame, where the load position is the position where the frame, driver, motor, battery box, and reducer are in contact with the frame, and the load size is the respective weight multiplied by the dynamic load factor;
5.1.3)进行仿真计算,计算得到直线工况下的总变形云图、应力云图和安全系数图;5.1.3) Carry out simulation calculations and calculate the total deformation cloud diagram, stress cloud diagram and safety factor diagram under linear working conditions;
5.1.4)将仿真结果与材料屈服强度σs等力学属性进行对比,由安全系数图得出最小安全系数ξ,若最小安全系数ξ小于ξ0,增加不安全位置杆件壁厚和管径,转步骤3),否则说明直线工况下满足安全要求,转步骤5.2)。5.1.4) Compare the simulation results with mechanical properties such as material yield strength σ s , and obtain the minimum safety factor ξ from the safety factor diagram. If the minimum safety factor ξ is less than ξ 0 , increase the wall thickness and pipe diameter of the rod in the unsafe position , go to step 3), otherwise it means that the safety requirements are met under straight-line operating conditions, go to step 5.2).
进一步的,上述步骤5.2)中匀速过弯工况分析包括如下步骤:Further, the analysis of uniform speed cornering conditions in step 5.2) above includes the following steps:
5.2.1)固定约束内测全部硬点,对外侧z方向限制自由度,释放xy方向自由度;5.2.1) Fixed constraints test all hard points inside, restrict the degree of freedom in the z direction on the outside, and release the degree of freedom in the xy direction;
5.2.2)计算最大向心加速度armax,计算公式如下:5.2.2) Calculate the maximum centripetal acceleration a rmax . The calculation formula is as follows:
式中armax为最大向心加速度,r为转弯半径,tmin为最快单圈时间;In the formula, a rmax is the maximum centripetal acceleration, r is the turning radius, and t min is the fastest lap time;
5.2.3)对车架施加惯性力载荷,其中载荷位置为车架、驾驶员、电机、电池箱、减速机各自与车架接触的位置,载荷大小为部件惯性力与最大向心加速度的乘积,其中惯性力包括车架自重、驾驶员惯性力、电驱系统惯性力、电池箱惯性力;5.2.3) Apply an inertial force load to the frame. The load position is the position where the frame, driver, motor, battery box, and reducer are in contact with the frame. The load size is the product of the inertial force of the component and the maximum centripetal acceleration. , in which the inertial force includes the self-weight of the vehicle frame, the inertial force of the driver, the inertial force of the electric drive system, and the inertial force of the battery box;
5.2.4)对车架施加次要作用力,次要作用力分别来自后悬三角摇臂、后悬弹簧和前悬三角摇臂;5.2.4) Apply secondary forces to the frame, which come from the rear suspension triangular rocker arm, rear suspension spring and front suspension triangular rocker arm;
5.2.5)进行仿真计算,计算得到匀速过弯工况下的总变形云图、应力云图和安全系数图;5.2.5) Carry out simulation calculations and calculate the total deformation cloud diagram, stress cloud diagram and safety factor diagram under uniform speed cornering conditions;
5.2.6)将仿真结果与材料屈服强度σs等力学属性进行对比,由安全系数图得出最小安全系数ξ,若最小安全系数ξ小于ξ0,则增加不安全位置杆件壁厚和管径,转步骤3),否则匀速过弯工况下满足安全要求,转步骤5.3)。5.2.6) Compare the simulation results with mechanical properties such as material yield strength σ s , and obtain the minimum safety factor ξ from the safety factor diagram. If the minimum safety factor ξ is less than ξ 0 , increase the wall thickness of the rod and pipe at the unsafe position. diameter, go to step 3), otherwise the safety requirements are met under constant speed cornering conditions, go to step 5.3).
进一步的,上述步骤5.3)中加速工况分析包括如下步骤:Further, the acceleration working condition analysis in step 5.3) above includes the following steps:
5.3.1)固定约束后悬4个硬点,限制前悬四个硬点yz方向约束,释放x方向自由度;5.3.1) Fixed and constrained the four hard points of the rear suspension, restricted the four hard points of the front suspension in the yz direction, and released the degree of freedom in the x direction;
5.3.2)计算加速工况所需最大加速度amax,计算公式如下:5.3.2) Calculate the maximum acceleration a max required for acceleration conditions. The calculation formula is as follows:
式中S为直线加速行驶走过的路程,t为加速时间,q为经典系数,简化模型等于amax;In the formula, S is the distance covered by straight-line acceleration, t is the acceleration time, q is the classical coefficient, and the simplified model is equal to a max ;
5.3.3)对车架施加惯性力载荷,其中载荷位置为车架、驾驶员、电机、电池箱、减速机各自与车架接触的位置,载荷大小为部件惯性力与最大加速度的乘积,其中惯性力包括车架自重、驾驶员惯性力、电驱系统惯性力、电池箱惯性力;5.3.3) Apply an inertial force load to the frame, where the load position is the position where the frame, driver, motor, battery box, and reducer are in contact with the frame. The load size is the product of the inertial force of the component and the maximum acceleration, where The inertial force includes the self-weight of the vehicle frame, the inertial force of the driver, the inertial force of the electric drive system, and the inertial force of the battery box;
5.3.4)对车架施加次要作用力,次要作用力分别来自后悬三角摇臂、后悬弹簧和传动支架;5.3.4) Apply secondary forces to the frame, which come from the rear suspension triangular rocker arm, rear suspension spring and transmission bracket;
5.3.5)进行仿真计算,计算得到加速工况下的总变形云图、应力云图和安全系数图;5.3.5) Carry out simulation calculations and calculate the total deformation cloud diagram, stress cloud diagram and safety factor diagram under accelerated conditions;
5.3.6)将仿真结果与材料屈服强度σs等力学属性进行对比,由安全系数图得出最小安全系数ξ,若最小安全系数ξ小于ξ0,则增加不安全位置杆件壁厚和管径,转步骤3),否则加速工况下满足安全要求,转步骤5.4)。5.3.6) Compare the simulation results with mechanical properties such as material yield strength σ s , and obtain the minimum safety factor ξ from the safety factor diagram. If the minimum safety factor ξ is less than ξ 0 , increase the wall thickness of the rod and pipe at the unsafe position. diameter, go to step 3), otherwise the safety requirements are met under accelerated conditions, go to step 5.4).
进一步的,上述步骤5.4)中制动工况分析包括如下步骤:Further, the braking condition analysis in step 5.4) above includes the following steps:
5.4.1)固定约束所有硬点,即四轮抱死状态;5.4.1) Fixed constraints on all hard points, that is, four-wheel lock state;
5.4.2)计算制动工况所需要的制动减速度az,计算公式如下:5.4.2) Calculate the braking deceleration a z required for braking conditions. The calculation formula is as follows:
式中v0 2为开始制动速度,Z为制动距离;In the formula, v 0 2 is the starting braking speed, and Z is the braking distance;
5.4.3)对车架施加惯性力载荷,其中载荷位置为车架、驾驶员、电机、电池箱、减速机各自与车架接触的位置,载荷大小为部件惯性力与制动减速度的乘积,其中惯性力包括车架自重、驾驶员惯性力、电驱系统惯性力、电池箱惯性力;5.4.3) Apply an inertial force load to the frame. The load position is the position where the frame, driver, motor, battery box, and reducer are in contact with the frame. The load size is the product of the inertial force of the component and the braking deceleration. , in which the inertial force includes the self-weight of the vehicle frame, the inertial force of the driver, the inertial force of the electric drive system, and the inertial force of the battery box;
5.4.4)对车架施加次要作用力,次要作用力分别来自后悬三角摇臂、后悬弹簧和前悬三角摇臂;5.4.4) Apply secondary forces to the frame, which come from the rear suspension triangular rocker arm, rear suspension spring and front suspension triangular rocker arm;
5.4.5)进行仿真计算,计算得到制动工况下的总变形云图、应力云图和安全系数图;5.4.5) Carry out simulation calculations and calculate the total deformation cloud diagram, stress cloud diagram and safety factor diagram under braking conditions;
5.4.6)将仿真结果与材料屈服强度σs等力学属性进行对比,由安全系数图得出最小安全系数ξ,若最小安全系数ξ小于ξ0,增加不安全位置杆件壁厚和管径,转步骤3),否则加速工况下满足安全要求,得到理想安全车架模型T2。5.4.6) Compare the simulation results with mechanical properties such as material yield strength σ s , and obtain the minimum safety factor ξ from the safety factor diagram. If the minimum safety factor ξ is less than ξ 0 , increase the wall thickness and pipe diameter of the rod in the unsafe position , go to step 3), otherwise the safety requirements are met under acceleration conditions, and the ideal safety frame model T2 is obtained.
与现有技术相比,本发明从前期人机工程学实验出发,到车架夹具模型设计为止,为电动方程式赛车车架设计提供一套严谨合理的流程与理论方法,大大减少了车架设计周期,提高了车架性能,为当前FSEC车架的理论研究做了补充与完善,具有实用性。Compared with the existing technology, this invention provides a set of rigorous and reasonable processes and theoretical methods for the design of the electric formula racing car frame starting from the early ergonomic experiments and ending with the design of the frame fixture model, which greatly reduces the time required for frame design. cycle, improves the performance of the frame, supplements and improves the current theoretical research on FSEC frames, and is practical.
附图说明Description of the drawings
图1电动方程式赛车车架设计方法流程图。Figure 1 Flowchart of the design method of the electric formula racing car frame.
图2车架模型与硬点位置示意图。Figure 2 Schematic diagram of the frame model and hard point locations.
具体实施方式Detailed ways
下面结合附图以及具体实施例对本发明作进一步的说明,需要指出的是,下面仅以一种最优化的技术方案对本发明的技术方案以及设计原理进行详细阐述,但本发明的保护范围并不限于此。The present invention will be further described below in conjunction with the accompanying drawings and specific embodiments. It should be pointed out that the technical solution and design principles of the present invention are described in detail below only with an optimized technical solution, but the protection scope of the present invention does not Limited to this.
所述实施例为本发明的优选的实施方式,但本发明并不限于上述实施方式,在不背离本发明的实质内容的情况下,本领域技术人员能够做出的任何显而易见的改进、替换或变型均属于本发明的保护范围。The above-described embodiments are preferred implementations of the present invention, but the present invention is not limited to the above-described implementations. Without departing from the essence of the present invention, any obvious improvements, substitutions or modifications that can be made by those skilled in the art can be made without departing from the essence of the present invention. All modifications belong to the protection scope of the present invention.
图1所示为电动方程式赛车车架设计方法流程图;包括如下步骤:Figure 1 shows the flow chart of the frame design method for an electric formula racing car; it includes the following steps:
1)确定车架参数以及车架硬点位置,车架参数包括人机参数和整车参数,其中,人机参数包括:主环前环之间的距离d1、主环高度h1、前环高度h2、制动油门踏板距主环的距离d2、制动油门踏板倾斜角度γ、方向盘中心点高度h3及距主环距离d2、座舱宽度l1,整车参数包括整车轴距L、轮距Ls和前后载荷比,具体方法如下:1) Determine the frame parameters and the position of the frame hard points. The frame parameters include human-machine parameters and vehicle parameters. Among them, the human-machine parameters include: the distance d 1 between the main rings and the front rings, the height h 1 of the main rings, the front Ring height h 2 , distance d 2 between the brake accelerator pedal and the main ring, brake accelerator pedal inclination angle γ, steering wheel center point height h 3 and distance d 2 from the main ring, cockpit width l 1 , the vehicle parameters include the vehicle Wheelbase L, wheelbase L s and front-to-rear load ratio, the specific method is as follows:
1.1)在设计初期进行人机实验,搭建人机实验台,以模拟器操作成绩与驾驶员主观感受为评价标准,以驾驶员人机数据库为客观参考,获取人机参数,其中人机参数包括:主环前环之间的距离d1、主环高度h1、前环高度h2、制动油门踏板距主环的距离d2、制动油门踏板倾斜角度γ、方向盘中心点高度h3及距主环距离d2、座舱宽度l1;1.1) Carry out human-machine experiments in the early stage of design, build a human-machine experiment platform, use the simulator operation performance and the driver's subjective feelings as the evaluation criteria, and use the driver's human-machine database as an objective reference to obtain human-machine parameters. The human-machine parameters include : Distance d 1 between the main ring and the front ring, height h 1 of the main ring, height h 2 of the front ring, distance d 2 between the brake accelerator pedal and the main ring, inclination angle γ of the brake accelerator pedal, height h 3 of the steering wheel center point And the distance d 2 from the main ring, the cockpit width l 1 ;
1.2)确定前后载荷比k,本实施例中,载荷比k取值为48:52,当整车前后载荷比保持在48:52会使整车拥有良好的操纵稳定性。1.2) Determine the front and rear load ratio k. In this embodiment, the load ratio k is 48:52. When the front and rear load ratio of the vehicle is maintained at 48:52, the vehicle will have good handling stability.
1.3)计算整车轴距L,轴距根据整车载荷而定,以座椅最下点为人机H点,也就是整车质心所在x方向位置,具体计算方法如下:1.3) Calculate the wheelbase L of the vehicle. The wheelbase is determined according to the load of the vehicle. The lowest point of the seat is the human-machine H point, which is the x-direction position of the center of mass of the vehicle. The specific calculation method is as follows:
1.3.1)计算整车前轴载荷Mtf,方法如下:1.3.1) Calculate the vehicle front axle load M tf as follows:
式中,Mi为各主要部件的质量,Xi为各主要部件相对于质心的x轴距离,L则为轴距,N表示部件个数;In the formula, M i is the mass of each main component, Xi is the x-axis distance of each main component relative to the center of mass, L is the wheelbase, and N represents the number of components;
1.3.2)计算整车后轴载荷Mtr,方法如下:1.3.2) Calculate the vehicle rear axle load M tr as follows:
Mtr=M0-Mtf M tr =M 0 -M tf
式中,M0为整车质量(驾驶员满载的情况下);In the formula, M 0 is the mass of the vehicle (when the driver is fully loaded);
1.3.3)计算整车轴距L,方法如下:1.3.3) Calculate the wheelbase L of the vehicle as follows:
在本实施例中,考虑到FSEC大赛规则要求,赛车至少1525mm的轴距,赛车的轴距大,车架质量也势必增加,在轻量化的思想下,将整车布置尽量紧凑,初定轴距1570mm;In this embodiment, taking into account the requirements of FSEC competition rules, the wheelbase of the racing car is at least 1525mm. The wheelbase of the racing car is large, and the mass of the frame is bound to increase. Under the idea of lightweighting, the whole vehicle is arranged as compactly as possible, and the axle is initially determined. distance 1570mm;
1.4)确定轮距Ls;轮距根据规则要求,较小的轮距不少于较大轮距的75%,轮距对赛车的总质量、总尺寸、操纵稳定性都有较大影响,轮距增加,悬架侧倾角刚度越大,悬架力学与运动学性能越好,对于后舱布置也越有利,但不宜过大,否则会导致空间冗余,质量无故增加。在本实施例中选定前轮距1210mm,后轮距1180mm;1.4) Determine the wheelbase L s ; the wheelbase is determined according to the rules. The smaller wheelbase is not less than 75% of the larger wheelbase. The wheelbase has a great impact on the total mass, total size, and handling stability of the car. As the wheelbase increases, the stiffness of the suspension roll angle increases, and the mechanical and kinematic performance of the suspension becomes better, which is also more beneficial to the layout of the rear cabin. However, it should not be too large, otherwise it will lead to redundant space and unreasonable increase in mass. In this embodiment, the front wheelbase is selected to be 1210mm and the rear wheelbase is 1180mm;
1.5)确定悬架硬点位置,利用悬架定位参数,进行运动学、动力学仿真确定悬架硬点位置,定位参数主要包括外倾角α1、内倾角α2、后倾角α3、前束α4等;1.5) Determine the position of the suspension hard point. Use the suspension positioning parameters to perform kinematics and dynamics simulations to determine the position of the suspension hard point. The positioning parameters mainly include camber angle α 1 , inclination angle α 2 , caster angle α 3 , and toe-in. α 4 etc.;
1.6)确定车架硬点位置,根据悬架硬点位置以及车架硬点与悬架硬点位置相对量得到车架硬点位置;本实施例中,车架硬点与悬架硬点位置相对量范围为:x方向(-10,20),y方向(30,40),z方向(-5,5),硬点位置如图2所示;1.6) Determine the position of the hard point of the frame, and obtain the position of the hard point of the frame according to the position of the hard point of the suspension and the relative position of the hard point of the frame and the hard point of the suspension; in this embodiment, the position of the hard point of the frame and the position of the hard point of the suspension The relative quantity range is: x direction (-10, 20), y direction (30, 40), z direction (-5, 5), and the hard point position is shown in Figure 2;
2)利用人机参数、整车参数、车架硬点位置,搭建初始车架模型T;2) Build the initial frame model T using human-machine parameters, vehicle parameters, and frame hard point positions;
根据主环前环之间的距离d1、主环高度h1、前环高度h2、制动、油门踏板距主环的距离d2、制动油门踏板倾斜角度γ、方向盘中心点高度h3及距主环距离d2、座舱宽度l1、轴距L、轮距Ls以及车架硬点位置进行模型搭建,硬点之间用杆件相连,并连接到主环前环以及前隔板位置处;车架模型包括腿舱、坐舱和后舱;其中腿舱结构是前环之前的车架部分,为驾驶员腿脚提供操作空间。具体有前隔板、前隔板支撑杆、前环、前环支撑杆以及其他附属杆件,腿舱中集成了制动系统、转向系统和前悬架系统,腿舱底部设置杆件承载转向总成,在前隔板上焊吊耳固定制动油缸,在满足规则中915的规则基础上,进一步节省空间,在底部两x方向平行钢管上搭焊钢管作制动底板支撑。为了使在减震器处车架受力更好,在腿舱上部增加横杆作为支撑。至于前环,为了照顾车手驾驶视野,尽量降低前环高度,但需要保障高度满足腿舱规则板和方向盘打死时不超过前环高度;坐舱指主环前环之间的车架部分,坐舱设计中侧边防撞结构按照规则中所要求的经典三角结构设计,增加上侧边杆上部杆件,作为与车身贴合杆件,使车手逃生时可以按着驾驶员两侧车身出舱,要求车身侧箱与上侧边防撞杆上部杆件之间距离不超过10mm;后舱是主环之后的车架部分,为电池箱、电机传动总成以及电控系统提供安装环境。后舱设计时需要有适中的y方向距离,满足电池箱的安装与操作空间,后舱底部加焊两根4mm厚钢条,作为电池箱支撑,通过10个角码,将电池箱机械连接到车架上。尾部布置相关杆件结构,用来为差速器支架与电机提供焊接位置;According to the distance d 1 between the main ring and the front ring, the height h 1 of the main ring, the height h 2 of the front ring, the distance d 2 between the brake and accelerator pedals and the main ring, the inclination angle γ of the brake accelerator pedal, and the height h of the steering wheel center point 3 and the distance d 2 from the main ring, the cockpit width l 1 , the wheelbase L, the wheelbase L s and the position of the hard points of the frame are used to build the model. The hard points are connected with rods and connected to the front ring of the main ring and the front ring. At the partition position; the frame model includes leg compartments, seat compartments and rear compartments; the leg compartment structure is the frame part before the front ring, providing operating space for the driver's legs and feet. Specifically, there are front bulkheads, front bulkhead support rods, front rings, front ring support rods and other auxiliary rods. The braking system, steering system and front suspension system are integrated in the leg compartment. Rods are set at the bottom of the leg compartment to carry the steering. Assembling, the lifting lugs are welded on the front bulkhead to fix the brake cylinder. On the basis of meeting the rules of 915 in the regulations, to further save space, two parallel steel pipes in the x direction at the bottom are lap-welded to support the brake floor. In order to better support the frame at the shock absorber, a crossbar is added to the upper part of the leg well as a support. As for the front ring, in order to take care of the driver's driving vision, the height of the front ring should be reduced as much as possible, but the height must be ensured to meet the height of the leg compartment rule plate and the steering wheel does not exceed the height of the front ring when the steering wheel is turned down; the cockpit refers to the frame part between the main ring and the front ring. In the cabin design, the side anti-collision structure is designed according to the classic triangular structure required by the rules. The upper part of the side bar is added as a rod that fits the car body, so that the driver can press the car body on both sides of the driver to exit when escaping. The cabin requires that the distance between the body side box and the upper part of the upper side anti-collision bar should not exceed 10mm; the rear cabin is the part of the frame behind the main ring, which provides an installation environment for the battery box, motor transmission assembly and electronic control system. The design of the rear cabin requires a moderate distance in the y direction to meet the installation and operation space of the battery box. Two 4mm thick steel bars are welded to the bottom of the rear cabin as a support for the battery box. The battery box is mechanically connected to the battery box through 10 corner codes. On the frame. The relevant rod structure is arranged at the rear to provide welding positions for the differential bracket and the motor;
3)在初始车架模型T基础上增加辅助杆件,调整杆件的尺寸,包括管径、壁厚,得到调整后的车架模型T’;3) Add auxiliary rods to the initial frame model T, adjust the dimensions of the rods, including pipe diameter and wall thickness, and obtain the adjusted frame model T’;
4)利用有限元分析车架模型扭转刚度,得到理想车架模型T1;车架扭转刚度是车架评价指标中重要的一项,车架的扭转刚度指的是车架在承受垂直载荷时,扭转变形的程度,可将车架模型简化为一个简支梁,支点为前后悬车架硬点。车架与悬架进行匹配,在运动过程中,如果车架刚度低于悬架侧倾角刚度,会发生车架受扭的情况,对车架结构造成安全风险,整车操纵稳定性下降,所以要求车架实际扭转刚度高于悬架侧倾角刚度,还要有足够的富余。具体方法为:4) Use finite element analysis to analyze the torsional stiffness of the frame model to obtain the ideal frame model T1; the torsional stiffness of the frame is an important item in the frame evaluation index. The torsional stiffness of the frame refers to the torsional stiffness of the frame when it is subjected to vertical loads. Depending on the degree of torsional deformation, the frame model can be simplified into a simply supported beam, with the fulcrums being the hard points of the front and rear suspension frame. The frame and suspension are matched. During the movement, if the frame stiffness is lower than the suspension roll angle stiffness, the frame will be torsion, causing safety risks to the frame structure and reducing the vehicle's handling stability. Therefore The actual torsional stiffness of the frame is required to be higher than the roll angle stiffness of the suspension, and there must be enough margin. The specific methods are:
4.1)利用有限元计算调整后的车架模型T’扭转刚度值Kn;分析方法为在有限元分析软件中,约束前后悬其中一方的硬点,对另一方施加上下各1mm的强制位移,得出支反力F,并由此计算车架扭转刚度,每次模型计算的扭转刚度值计算公式如下:4.1) Use finite element to calculate the torsional stiffness value K n of the adjusted frame model T'; the analysis method is to constrain the hard points of one of the front and rear suspensions in the finite element analysis software, and impose a forced displacement of 1mm up and down on the other side. The support reaction force F is obtained, and the torsional stiffness of the frame is calculated from this. The torsional stiffness value calculated by each model is calculated as follows:
式中Kn为每次模型计算的扭转刚度值,F为支反力,d为悬架两硬点之间的距离,ΔA、ΔB为两硬点的强制位移。In the formula, K n is the torsional stiffness value calculated by each model, F is the support reaction force, d is the distance between the two hard points of the suspension, and ΔA and ΔB are the forced displacements of the two hard points.
4.2)计算调整后的车架模型T’的综合车架扭转刚度K,K是由前后悬约束下的扭转刚度联合得出的,具体公式如下:4.2) Calculate the comprehensive frame torsional stiffness K of the adjusted frame model T’. K is jointly derived from the torsional stiffness under the front and rear suspension constraints. The specific formula is as follows:
式中Kf为前悬扭转下的扭转刚度,Kr为后悬扭转下的扭转刚度,a为前轴距,,b为后轴距,L为轴距。In the formula, K f is the torsional stiffness under torsion of the front suspension, K r is the torsional stiffness of the rear suspension under torsion, a is the front wheelbase, b is the rear wheelbase, and L is the wheelbase.
具体实施中在有限元软件中定义好材料,导入模型,进行管件赋予,施加约束条件,首先计算前悬扭转下的扭转刚度值,将后悬靠后的上下左右四个硬点进行固定约束,限制自由度,对前悬靠前的上方两个硬点施加上下各1mm的强制位移,计算出支反力,带入公式进行计算得到Kf,本实施例中,d1=404mm,通过仿真得到最大支反力F=1632.55N,计算可得Kf=2325.306N·m/deg;再计算后悬扭转下的扭转刚度值,将前悬靠前的上下左右四个硬点进行固定约束,限制其自由度,对后悬靠后的上下两个硬点施加上下各1mm的强制位移,计算出支反力,带入公式进行计算得到Kr,本实施例中d2=506mm,通过仿真得到最大支反力F=1269.5N,Kr=2836.5N·m/deg,带入公式(4)得到总刚度K,本实施例中a=753.6mm,b=816.4mm,In the specific implementation, the material is defined in the finite element software, the model is imported, the pipe fittings are assigned, and the constraint conditions are applied. First, the torsional stiffness value under torsion of the front suspension is calculated, and the four hard points of the upper, lower, left and right rear suspension are fixed and constrained. To limit the degree of freedom, impose a forced displacement of 1 mm on each of the upper and lower hard points of the front suspension, calculate the support reaction force, and enter it into the formula to calculate K f . In this embodiment, d 1 =404 mm, through simulation The maximum support reaction force F = 1632.55N is obtained, and the calculated K f = 2325.306N·m/deg; then the torsional stiffness value under torsion of the rear suspension is calculated, and the four hard points on the upper, lower, left and right front of the front suspension are fixed and restrained. Limit its degree of freedom, apply a forced displacement of 1 mm each to the upper and lower hard points behind the rear suspension, calculate the support reaction force, and enter it into the formula to calculate K r . In this embodiment, d 2 = 506 mm, through simulation The maximum support reaction force F = 1269.5N, K r = 2836.5N·m/deg, is entered into formula (4) to obtain the total stiffness K. In this embodiment, a = 753.6mm, b = 816.4mm,
4.3)判断是否满足K>K0且m<m0,如果满足转步骤4.4),否则转步骤3),本实施例中,K0=2000N·m/deg,m0=28kg;4.3) Determine whether K>K 0 and m<m 0 are satisfied. If satisfied, go to step 4.4), otherwise go to step 3). In this embodiment, K 0 =2000N·m/deg, m 0 =28kg;
4.4)计算单位质量扭转刚度 4.4) Calculate torsional stiffness per unit mass
4.5)判断是否满足如果满足得出理想车架模型T1,否则转步骤3),本实施例中,p0=81N·m/(kg·deg);4.5) Determine whether it is satisfied If the ideal frame model T1 is satisfied, otherwise go to step 3). In this embodiment, p 0 =81N·m/(kg·deg);
5)对理想车架模型T1进行工况分析,得到理想安全车架模型T2;校核车架在各个典型工况下的强度,对车架受力薄弱的部位进行优化加强,以保证满足赛车在行驶过程中的要求;其中,工况包括直线工况、匀速过弯工况、加速工况和制动工况。5) Conduct working condition analysis on the ideal frame model T1 to obtain the ideal safe frame model T2; check the strength of the frame under various typical working conditions, and optimize and strengthen the weak parts of the frame to ensure that it meets the requirements of racing Requirements during driving; among them, working conditions include straight-line working conditions, uniform speed cornering conditions, acceleration working conditions and braking conditions.
5.1)直线工况主要考虑的是赛车在满载的工况下的强度和受弯情况。这种情况下,车架除了承受自身的重力外,还要承受电池箱、电机传动系统、转向系统等装置和车手的重力,因此要求车架具有高的强度和刚度。在此假设,其他小部件的质量对此工况没有太大影响,可以忽略,直线工况仿真分析方法如下:5.1) The main consideration for straight-line conditions is the strength and bending conditions of the car under full load conditions. In this case, in addition to bearing its own gravity, the frame also has to bear the gravity of the battery box, motor transmission system, steering system and other devices as well as the rider, so the frame is required to have high strength and stiffness. It is assumed here that the quality of other small parts does not have much impact on this working condition and can be ignored. The simulation analysis method of the straight line working condition is as follows:
5.1.1)固定约束后悬4个硬点,硬点位置如图2所示,考虑赛车的近似直线运动,前悬左侧硬点y,z方向约束,释放x方向的自由度,右侧硬点y,z方向约束,释放x方向自由度。5.1.1) Fix and constrain 4 hard points on the rear suspension. The hard point locations are shown in Figure 2. Considering the approximate linear motion of the racing car, the hard point on the left side of the front suspension is y, constrained in the z direction, and the degree of freedom in the x direction is released. On the right side Hard point y, z direction constraint, release x direction freedom.
5.1.2)对车架施加载荷,载荷位置为车架、驾驶员、电机、电池箱、减速机各自与车架接触的位置,载荷大小为各自重量乘动载因数,具体实施中动载因数2,除此之外还有其余主要部件重力和电机扭矩;本实施例中,电池箱箱里布置5个模组,每个模组选用18650三元锂电池,7并20串,再加上各种电器元件,保守估计电池箱总重55Kg,其作用力作用在电池箱底部的两根4mm厚钢条上。电机选用228电机,加上行星齿轮减速机构、链轮和差速器,电驱总成重34Kg,作用力施加在相关吊耳焊接的钢管上,驾驶员重70Kg,乘上动载因子,作用在座椅吊耳焊接的钢管上,其余还有车架自重,与电机扭矩,电机扭矩取240N·m,作用在电机支架上;5.1.2) Apply a load to the frame. The load position is the position where the frame, driver, motor, battery box, and reducer are in contact with the frame. The load size is the weight of each multiplied by the dynamic load factor. The dynamic load factor in the specific implementation 2. In addition, there are other main components such as gravity and motor torque; in this embodiment, 5 modules are arranged in the battery box, and each module uses 18650 ternary lithium batteries, 7 in parallel and 20 in series, plus Various electrical components, the total weight of the battery box is conservatively estimated to be 55Kg, and its force acts on the two 4mm thick steel bars at the bottom of the battery box. The motor is a 228 motor, plus the planetary gear reduction mechanism, sprocket and differential. The electric drive assembly weighs 34Kg. The force is exerted on the steel pipe welded by the relevant lifting lugs. The driver weighs 70Kg. Multiplied by the dynamic load factor, the effect On the steel pipe welded to the seat lifting lugs, the rest is the weight of the frame and the motor torque. The motor torque is 240N·m, which acts on the motor bracket;
5.1.3)进行仿真计算,计算得到直线工况下的总变形云图、应力云图和安全系数图;5.1.3) Carry out simulation calculations and calculate the total deformation cloud diagram, stress cloud diagram and safety factor diagram under linear working conditions;
5.1.4)将仿真结果与材料屈服强度σs等力学属性进行对比,由安全系数图得出最小安全系数ξ,若最小安全系数ξ小于1.8,转步骤3),增加不安全位置杆件壁厚和管径;否则说明直线工况下满足要求,转步骤5.2);5.1.4) Compare the simulation results with mechanical properties such as material yield strength σ s , and obtain the minimum safety factor ξ from the safety factor diagram. If the minimum safety factor ξ is less than 1.8, go to step 3) and add the member wall at the unsafe position. Thickness and pipe diameter; otherwise, it means that the requirements are met under straight-line conditions, and go to step 5.2);
5.2)匀速过弯工况主要考虑的是车架桁架结构在最大向心加速度过弯工况下,受到的其横向方向主要作用,有车架的离心加速度惯性力、各主要大质量部件的惯性力,与直线工况相同,惯性力是通过乘以动载因子的方式实现的。假定该工况为向左转弯,其他小部件影响忽略不计。最大离心加速度的作用力主要通过悬架横臂作用于车架,横向作用力为主要作用力,横向位移为主约束。在分析仿真计算时,具体操作如下:5.2) The main considerations in the uniform speed cornering condition are the main effects on the frame truss structure in the lateral direction under the maximum centripetal acceleration cornering condition, including the centrifugal acceleration inertia force of the frame and the inertia of each major large-mass component. Force, the same as the straight line condition, the inertial force is realized by multiplying the dynamic load factor. It is assumed that the working condition is a left turn, and the influence of other small components is ignored. The force of the maximum centrifugal acceleration mainly acts on the frame through the suspension wishbone, the lateral force is the main force, and the lateral displacement is the main constraint. When analyzing simulation calculations, the specific operations are as follows:
5.2.1)固定约束内测全部硬点,对外侧也就是右侧z方向限制自由度,释放xy方向自由度。5.2.1) The fixed constraint tests all hard points inside, restricts the degree of freedom in the z direction on the outside, that is, the right side, and releases the degree of freedom in the xy direction.
5.2.2)计算最大向心加速度armax,计算计算公式如下;5.2.2) Calculate the maximum centripetal acceleration a rmax . The calculation formula is as follows;
式中armax为最大向心加速度,r为转弯半径,tmin为最快单圈时间,经过计算得armax=18m/s2;In the formula, a rmax is the maximum centripetal acceleration, r is the turning radius, t min is the fastest lap time, and after calculation, a rmax =18m/s 2 ;
5.2.3)对车架施加惯性力载荷,载荷计算方法为各个部件惯性力与最大侧向加速度的乘积,其惯性力有车架自重、驾驶员惯性力、电驱系统惯性力、电池箱惯性力,除此之外还有其余主要部件重力和电机扭矩;本实施例中,驾驶员惯性力载荷为70×2×1.8g=2520N,电驱系统惯性力载荷为34×2×1.8g=1224N,电池箱惯性力载荷为55×2×1.8g=1980N,除此之外还有主要部件重力3060N,电机扭矩240N·m;5.2.3) Apply an inertial force load to the frame. The load calculation method is the product of the inertial force of each component and the maximum lateral acceleration. The inertial forces include the self-weight of the frame, the driver's inertial force, the inertial force of the electric drive system, and the inertia of the battery box. force, in addition to other main components such as gravity and motor torque; in this embodiment, the driver's inertia force load is 70×2×1.8g=2520N, and the electric drive system's inertia force load is 34×2×1.8g= 1224N, the inertia force load of the battery box is 55×2×1.8g=1980N, in addition to the main component gravity of 3060N, and the motor torque of 240N·m;
5.2.4)对车架施加次要作用力,分别来自后悬三角摇臂、后悬弹簧和前悬三角摇臂;本实施例中,后悬三角摇臂受力情况为Fx=0,Fy=432.54N,Fz=-212.94N;后悬弹簧受力情况为Fx=366.26N,Fy=2168N,Fz=-935.25N;前悬三角摇臂受力情况为Fx=0,Fy=600.05N,Fz=1610.2N;5.2.4) Secondary forces are exerted on the frame, respectively from the rear suspension triangular rocker arm, the rear suspension spring and the front suspension triangular rocker arm; in this embodiment, the force situation of the rear suspension triangular rocker arm is F x =0, F y = 432.54N, F z = -212.94N; the force of the rear suspension spring is F x = 366.26N, F y = 2168N, F z = -935.25N; the force of the front suspension triangular rocker arm is F x = 0, F y =600.05N, F z =1610.2N;
5.2.5)进行仿真计算,计算得到匀速过弯工况下的总变形云图、应力云图和安全系数图;5.2.5) Carry out simulation calculations and calculate the total deformation cloud diagram, stress cloud diagram and safety factor diagram under uniform speed cornering conditions;
5.2.6)将仿真结果与材料屈服强度σs等力学属性进行对比,由安全系数图得出最小安全系数ξ,若最小安全系数ξ小于1.8,转步骤3),增加不安全位置杆件壁厚和管径;否则说明匀速过弯工况下满足要求,转步骤5.3);5.2.6) Compare the simulation results with mechanical properties such as material yield strength σ s , and obtain the minimum safety factor ξ from the safety factor diagram. If the minimum safety factor ξ is less than 1.8, go to step 3) and add the member wall at the unsafe position. Thickness and pipe diameter; otherwise, it means that the requirements are met under uniform speed cornering conditions, go to step 5.3);
5.3)上述加速工况主要考虑的是车架在赛车直线最大加速度行驶工况下的受力情况,其纵向方向上作用着车架的加速度惯性力和各主要大质量部件的惯性力,在最大加速度行驶时车架的惯性力与悬架系统作用在车架上的纵向力相平衡并以此作为校核的依据。假设其他小质量部件对整体影响不大。最大直线加速度的作用力主要通过悬架横臂作用于车架,纵向作用力为主要作用力,纵向位移为主约束。在分析仿真计算时,具体操作如下:5.3) The above-mentioned acceleration conditions mainly consider the stress of the frame under the maximum acceleration of the racing car in a straight line. The acceleration inertia force of the frame and the inertia force of each major large-mass component act in the longitudinal direction. At the maximum When accelerating, the inertial force of the frame is balanced with the longitudinal force of the suspension system acting on the frame, and this is used as the basis for calibration. It is assumed that other small mass components have little impact on the overall effect. The force of maximum linear acceleration mainly acts on the frame through the suspension wishbone, the longitudinal force is the main force, and the longitudinal displacement is the main constraint. When analyzing simulation calculations, the specific operations are as follows:
5.3.1)固定约束后悬4个硬点,限制前悬四个硬点yz方向约束,释放x方向自由度。5.3.1) Fixed and constrained the four hard points of the rear suspension, restricted the four hard points of the front suspension in the yz direction, and released the degree of freedom in the x direction.
5.3.2)计算加速工况所需最大加速度amax,计算公式如下:5.3.2) Calculate the maximum acceleration a max required for acceleration conditions. The calculation formula is as follows:
amax=qaavg amax = qaavg
式中S为直线加速行驶走过的路程,t为加速时间,aavg为加速过程中的平均加速度,q为经典系数,简化模型等于amax;本实施例中,q取1.5,直线加速时间取4.33s,S取75m,计算可得amax=1.2g;In the formula, S is the distance covered by straight-line acceleration, t is the acceleration time, a avg is the average acceleration during the acceleration process, q is the classic coefficient, and the simplified model is equal to a max ; in this embodiment, q is 1.5, and the straight-line acceleration time Taking 4.33s, S taking 75m, the calculation shows a max = 1.2g;
5.3.2)对车架施加惯性力载荷,载荷计算方法为各个部件惯性力与最大侧向加速度的乘积,惯性力有车架自重、驾驶员惯性力、电驱系统惯性力、电池箱惯性力,除此之外还有其余主要部件重力和电机扭矩;本实施例中,驾驶员惯性力载荷为70×2×1.2g=1680N,电驱系统惯性力载荷为34×2×1.2g=816N,电池箱惯性力载荷为55×2×1.2g=1320N,除此之外还有主要部件重力3060N,电机扭矩240N·m;5.3.2) Apply an inertial force load to the frame. The load calculation method is the product of the inertial force of each component and the maximum lateral acceleration. The inertial force includes the self-weight of the frame, the driver's inertial force, the inertial force of the electric drive system, and the battery box inertial force. , in addition to the other main components gravity and motor torque; in this embodiment, the driver's inertial force load is 70×2×1.2g=1680N, and the electric drive system's inertial force load is 34×2×1.2g=816N , the inertia force load of the battery box is 55×2×1.2g=1320N. In addition, the gravity of the main components is 3060N and the motor torque is 240N·m;
5.3.4)对车架施加次要作用力,分别来自后悬三角摇臂、后悬弹簧和传动支架;本实施例中,后悬三角摇臂受力情况为Fx=0,Fy=324.06N,Fz=-159.54N;后悬弹簧受力情况为Fx=274.4N,Fy=1624.2N,Fz=-700.68N;传动左上支架受力情况为Fx=2784.4N,Fy=0,Fz=-5071.34N;传动右上支架受力情况为Fx=-393.8N,Fy=0,Fz=717.23N;传动左下支架受力情况为Fx=-5188.8N,Fy=0,Fz=-6693.5N;传动右下支架受力情况为Fx=733.8N,Fy=0,Fz=946.6N;5.3.4) Secondary forces are exerted on the frame, respectively from the rear suspension triangular rocker arm, rear suspension spring and transmission bracket; in this embodiment, the force situation of the rear suspension triangular rocker arm is F x = 0, F y = 324.06N, F z =-159.54N; the force of the rear suspension spring is F x =274.4N, F y =1624.2N, F z =-700.68N; the force of the upper left bracket of the transmission is F x =2784.4N, F y = 0, F z = -5071.34N; the stress of the upper right bracket of the transmission is F x = -393.8N, F y = 0, F z = 717.23N; the stress of the lower left bracket of the transmission is F x = -5188.8N, F y =0, F z =-6693.5N; the stress of the lower right bracket of the transmission is F x =733.8N, F y =0, F z =946.6N;
5.3.5)进行仿真计算,计算得到加速工况下的总变形云图、应力云图和安全系数图;5.3.5) Carry out simulation calculations and calculate the total deformation cloud diagram, stress cloud diagram and safety factor diagram under accelerated conditions;
5.3.6)将仿真结果与材料屈服强度σs等力学属性进行对比,由安全系数图得出最小安全系数ξ,若最小安全系数ξ小于1.8,转步骤3),增加不安全位置杆件壁厚和管径;否则说明加速工况下满足要求,转步骤5.4);5.3.6) Compare the simulation results with the material yield strength σ s and other mechanical properties, and obtain the minimum safety factor ξ from the safety factor diagram. If the minimum safety factor ξ is less than 1.8, go to step 3) and add the member wall at the unsafe position. Thickness and pipe diameter; otherwise, it means that the requirements are met under accelerated working conditions, go to step 5.4);
5.4)上述制动工况下,车架桁架的惯性力与悬架系统作用于车架的作用力处于平衡状态,以此作为校核的理论依据,其纵向方向作用着车架的减速度惯性力和各主要大质量部件的惯性力,假定其他小质量部件的作用很小,小质量部件的惯性力影响不大。最大直线减速度的作用力主要通过悬架横臂作用于车架,纵向作用力为主要作用力,纵向位移为主约束。在分析仿真计算时,具体操作如下:5.4) Under the above braking conditions, the inertial force of the frame truss and the force of the suspension system acting on the frame are in a balanced state. This is used as a theoretical basis for calibration. The longitudinal direction acts on the deceleration inertia of the frame. force and the inertial force of each main large-mass component. It is assumed that the effect of other small-mass components is very small, and the inertial force of the small-mass component has little effect. The force of maximum linear deceleration mainly acts on the frame through the suspension wishbone, the longitudinal force is the main force, and the longitudinal displacement is the main constraint. When analyzing simulation calculations, the specific operations are as follows:
5.4.1)固定约束所有硬点,即四轮抱死状态;5.4.1) Fixed constraints on all hard points, that is, four-wheel lock state;
5.4.2)计算制动工况所需要的制动减速度az,计算公式如下:5.4.2) Calculate the braking deceleration a z required for braking conditions. The calculation formula is as follows:
式中v0 2为开始制动速度,Z为制动距离,通过计算可得az=1.6g。In the formula, v 0 2 is the starting braking speed, Z is the braking distance, and through calculation, a z =1.6g can be obtained.
5.4.3)对车架施加惯性力载荷,载荷计算方法为各个部件惯性力与制动加速度的乘积,惯性力载荷有车架自重、驾驶员惯性力、电驱系统惯性力、电池箱惯性力,除此之外还有其余主要部件重力和电机扭矩;本实施例中,驾驶员惯性力载荷为70×2×1.6g=2240N,电驱系统惯性力载荷为34×2×1.6g=1088N,电池箱惯性力载荷为55×2×1.6g=1760N,除此之外还有主要部件重力3060N,电机扭矩240N·m。5.4.3) Apply an inertial force load to the frame. The load calculation method is the product of the inertial force of each component and the braking acceleration. The inertial force load includes the self-weight of the frame, the driver's inertial force, the inertial force of the electric drive system, and the battery box's inertial force. , in addition to the other main components gravity and motor torque; in this embodiment, the driver's inertia force load is 70×2×1.6g=2240N, and the electric drive system's inertia force load is 34×2×1.6g=1088N , the inertia force load of the battery box is 55×2×1.6g=1760N. In addition, the gravity of the main components is 3060N and the motor torque is 240N·m.
5.4.4)对车架施加次要作用力,分别来自后悬三角摇臂、后悬弹簧和前悬三角摇臂;本实施例中,后悬三角摇臂受力情况为Fx=0,Fy=102.84N,Fz=-50.63N;后悬弹簧受力情况为Fx=87.085N,Fy=-515.47N,Fz=-222.37N;前悬三角摇臂受力情况为Fx=0,Fy=527.9N,Fz=1416.6N。5.4.4) Secondary forces are exerted on the frame, respectively from the rear suspension triangular rocker arm, the rear suspension spring and the front suspension triangular rocker arm; in this embodiment, the force situation of the rear suspension triangular rocker arm is F x =0, F y = 102.84N, F z = -50.63N; the force of the rear suspension spring is F x = 87.085N, F y = -515.47N, F z = -222.37N; the force of the front suspension triangular rocker arm is F x =0, F y =527.9N, F z =1416.6N.
5.4.5)进行仿真计算,计算得到制动工况下的总变形云图、应力云图和安全系数图;5.4.5) Carry out simulation calculations and calculate the total deformation cloud diagram, stress cloud diagram and safety factor diagram under braking conditions;
5.4.6)将仿真结果与材料屈服强度σs等力学属性进行对比,由安全系数图得出最小安全系数ξ,若最小安全系数ξ小于1.8,转步骤3),增加不安全位置杆件壁厚和管径;否则说明加速工况下满足要求,得到理想安全车架模型T2;5.4.6) Compare the simulation results with mechanical properties such as material yield strength σ s , and obtain the minimum safety factor ξ from the safety factor diagram. If the minimum safety factor ξ is less than 1.8, go to step 3) and add the member wall at the unsafe position. thickness and pipe diameter; otherwise, it means that the requirements are met under accelerated conditions, and the ideal safety frame model T2 is obtained;
6)对理想安全车架模型T2进行有限元模态分析,得到最终车架模型;6) Conduct finite element modal analysis on the ideal safety frame model T2 to obtain the final frame model;
模态分析是车技动态特性分析的重要部分,通过分析可以获取结构的模态频率和模态振型。赛车在赛道上行驶,由于路面不平和发动机的振动会对车架产生激振,如果激振频率与车技的某一固有频率相同,就会产生共振现象,可能会影响赛车的机械性能甚至破坏车架结构。因此有必要分析车架的固有频率和振型,对车架的结构设计提供参考。模态分析有自由模态和约束模态两种,为了更好的贴合实际,采用约束模态分析方法,具体操作为:Modal analysis is an important part of the dynamic characteristics analysis of vehicle technology. Through analysis, the modal frequency and mode shape of the structure can be obtained. When a racing car drives on a track, uneven road surfaces and engine vibrations will excite the frame. If the excitation frequency is the same as a certain natural frequency of the car, resonance will occur, which may affect the mechanical performance of the racing car or even damage the car. frame structure. Therefore, it is necessary to analyze the natural frequency and vibration shape of the frame to provide reference for the structural design of the frame. There are two types of modal analysis: free mode and constrained mode. In order to better fit the reality, the constrained modal analysis method is used. The specific operations are:
6.1)固定约束车架前后悬8个硬点。6.1) Fixed and constrained 8 hard points on the front and rear suspension of the frame.
6.2)对车架施加惯性力载荷。考虑赛车的近似直线运动,除了车架的重量外,还有驾驶员的重量,发动机的重量,另外此工况模拟的是赛车在运动过程中的受力状态,故应乘上一个动载因数,本实施例中,取动载因数为2。主要受力有驾驶员、电池箱、电驱系统、车架自重、电机扭矩,载荷大小与施加位置与直线工况相同。6.2) Apply inertial force load to the frame. Considering the approximate linear motion of the racing car, in addition to the weight of the frame, there is also the weight of the driver and the weight of the engine. In addition, this working condition simulates the stress state of the racing car during movement, so it should be multiplied by a dynamic load factor. , in this embodiment, the dynamic load factor is taken to be 2. The main forces are the driver, battery box, electric drive system, frame weight, and motor torque. The load size and application position are the same as those under linear conditions.
6.3)进行仿真分析,得到前8阶模态频率与振型;6.3) Carry out simulation analysis to obtain the first 8 mode frequencies and vibration shapes;
6.4)将所得8阶模态频率与电机等部件的外部激励频率进行比较,观察是否频率重合发生共振,造成车架结构破坏,若发生共振现象,则返回步骤3)进行尺寸杆件变化;如果未发生共振现象,则说明车架满足模态分析要求,得到最终车架模型T3;6.4) Compare the obtained 8th-order modal frequency with the external excitation frequency of the motor and other components, and observe whether the frequencies overlap and cause resonance, causing damage to the frame structure. If resonance occurs, return to step 3) to change the size of the rod; if If no resonance phenomenon occurs, it means that the frame meets the requirements of modal analysis, and the final frame model T3 is obtained;
7)对最终车架模型T3进行焊接夹具设计;本实施例中,采用4040铝型材作为夹具材料,用角码进行杆材固联,设计过程中,以前隔板、前环、主环作为三个标准面,使用框架型结构,保证整体性,减少在焊接过程中焊接应力对钢管位置的影响。主要保证车架与悬架相关的16个硬点的位置与前后减震器吊耳的位置,利用铝型材以及辅助夹具对这些重要点进行自由度限制,以保证加工精度。车架模型与焊接夹具在三维软件中匹配观察,保证夹具设计的合理性。7) Design the welding fixture for the final frame model T3; in this example, 4040 aluminum profiles are used as the fixture material, and corner codes are used to fasten the rods. During the design process, the front partition, front ring, and main ring are used as the three A standard surface, using a frame structure to ensure integrity and reduce the impact of welding stress on the position of the steel pipe during the welding process. It mainly ensures the positions of the 16 hard points related to the frame and suspension and the positions of the front and rear shock absorber lifting lugs. Aluminum profiles and auxiliary fixtures are used to limit the degree of freedom of these important points to ensure processing accuracy. The frame model and the welding fixture are matched and observed in the 3D software to ensure the rationality of the fixture design.
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