CN108365900A - User access method based on energy consumption and pairing in super-intensive heterogeneous network system - Google Patents
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Abstract
本发明提供了一种超密集异构网系统中基于能耗与配对的用户接入方法。该方法包括:根据用户与每个基站之间的SINR值计算出在用户侧每个基站对该用户的效用函数值,用户向对自己效用函数值最高的基站发送接入申请,基站将从接入申请中提取出来的SINR值作为基站侧发送该接入请求的用户的效用函数值,基站根据基站侧效用函数值最高的用户的速率请求和干扰情况判断该效用函数值最高的用户是否能够接入该基站,如果是,则反馈接入成功的信息给所述效用函数值最高的用户;否则,反馈接入失败的信息给所述效用函数值最高的用户。本发明提出了一种用于超密集部署场景下的用户接入算法,解决了给定目标速率条件下基于能效优化的用户接入问题。
The invention provides a user access method based on energy consumption and pairing in an ultra-dense heterogeneous network system. The method includes: calculating the utility function value of each base station on the user side for the user according to the SINR value between the user and each base station, and the user sends an access application to the base station with the highest utility function value to the user, and the base station will receive from the base station The SINR value extracted from the access application is used as the utility function value of the user who sends the access request on the base station side. The base station judges whether the user with the highest utility function value can access the network according to the rate request and interference situation of the user with the highest utility function value on the base station side. If so, feed back the information of successful access to the user with the highest utility function value; otherwise, feed back the information of access failure to the user with the highest utility function value. The present invention proposes a user access algorithm used in an ultra-dense deployment scenario, and solves the problem of user access based on energy efficiency optimization under a given target rate condition.
Description
技术领域technical field
本发明涉及无线网络通信技术领域,尤其涉及一种超密集异构网系统中基于能耗与配对的用户接入方法。The invention relates to the technical field of wireless network communication, in particular to a user access method based on energy consumption and pairing in an ultra-dense heterogeneous network system.
背景技术Background technique
随着移动通信技术的进步,智能手机的广泛使用,移动互联网、物联网以及各种新型业务的快速发展,UE(User Equipment,用户终端)数量和移动数据流量经历了爆炸式的增长态势,超密集部署异构网络将成为未来移动通信发展的必然趋势。小小区的超密集部署势必会带来网络能耗的增加和基站负载的不均衡。基站的能耗与基站所关联的负载数量密切相关,所以一个合适的用户接入算法对于基站能耗的降低和用户接入公平度的提高具有重要作用。With the advancement of mobile communication technology, the widespread use of smart phones, the rapid development of mobile Internet, Internet of Things and various new services, the number of UEs (User Equipment, user terminals) and mobile data traffic have experienced explosive growth. Dense deployment of heterogeneous networks will become an inevitable trend in the future development of mobile communications. The ultra-dense deployment of small cells will inevitably lead to increased network energy consumption and unbalanced base station loads. The energy consumption of the base station is closely related to the number of loads associated with the base station, so a suitable user access algorithm plays an important role in reducing the energy consumption of the base station and improving the fairness of user access.
目前,现有技术中的用户接入算法更加关注负载均衡和系统能耗。现有技术中的一种用户接入算法包括:在满足用户数据速率需求的条件下,以优化基站发射功率为目标提出了一种联合功率和资源分配的算法。该用户接入算法的缺点是,并未有效的表示和优化基站的总发射功率。Currently, user access algorithms in the prior art pay more attention to load balancing and system energy consumption. A user access algorithm in the prior art includes: under the condition of meeting user data rate requirements, an algorithm for joint power and resource allocation is proposed with the goal of optimizing base station transmit power. The disadvantage of this user access algorithm is that it does not effectively represent and optimize the total transmission power of the base station.
发明内容Contents of the invention
本发明的实施例提供了一种超密集异构网系统中基于能耗与配对的用户接入方法,以克服现有技术的缺点。Embodiments of the present invention provide a user access method based on energy consumption and pairing in an ultra-dense heterogeneous network system, so as to overcome the shortcomings of the prior art.
为了实现上述目的,本发明采取了如下技术方案。In order to achieve the above object, the present invention adopts the following technical solutions.
一种超密集异构网系统中基于能耗与配对的用户接入方法,包括:A user access method based on energy consumption and pairing in an ultra-dense heterogeneous network system, comprising:
用户测量并计算该用户与每个基站之间的信干噪比SINR值;The user measures and calculates the SINR value between the user and each base station;
根据用户与每个基站之间的SINR值计算出在用户侧每个基站对该用户的效用函数值,用户向对自己效用函数值最高的基站发送接入申请,该接入申请中携带与用户和该基站之间的SINR值相关的信道质量信息;According to the SINR value between the user and each base station, the utility function value of each base station on the user side is calculated for the user, and the user sends an access application to the base station with the highest utility function value for the user. Channel quality information related to the SINR value between the base stations;
基站接收到多个用户发送的接入申请后,对每个用户提供的信道质量信息进行处理,并将从接入申请中提取出来的SINR值作为基站侧发送该接入请求的用户的效用函数值,根据基站侧用户的效用函数值对多个用户进行排序,基站根据基站侧效用函数值最高的用户的速率请求和干扰情况判断该效用函数值最高的用户是否能够接入该基站,如果是,则反馈接入成功的信息给所述效用函数值最高的用户;否则,反馈接入失败的信息给所述效用函数值最高的用户。After the base station receives the access application sent by multiple users, it processes the channel quality information provided by each user, and uses the SINR value extracted from the access application as the utility function of the user who sent the access request on the base station side value, according to the utility function value of the user on the base station side, sort multiple users, and the base station judges whether the user with the highest utility function value can access the base station according to the rate request and interference situation of the user with the highest utility function value on the base station side, if it is , feed back information about successful access to the user with the highest value of the utility function; otherwise, feed back information about failed access to the user with the highest value of the utility function.
进一步地,所述的基站根据用户与基站之间的信干噪比SINR计算基站为每个用户提供的发射功率,包括:Further, the base station calculates the transmit power provided by the base station for each user according to the SINR between the user and the base station, including:
用户i与基站j之间的SINR与基站j为用户i提供的发射功率之间的关系由下式给出:The relationship between the SINR between user i and base station j and the transmit power provided by base station j to user i is given by:
Pij为用户i占用全部资源块传输时基站j的总发射功率,gij为基站j对用户i的信道衰落系数,gik为基站k对用户i的信道衰落系数,σ2为高斯白噪声功率,为基站j的最大发射功率。P ij is the total transmit power of base station j when user i occupies all resource blocks for transmission, g ij is the channel fading coefficient of base station j to user i, g ik is the channel fading coefficient of base station k to user i, and σ 2 is Gaussian white noise power, is the maximum transmit power of base station j.
进一步地,所述的根据用户与每个基站之间的SINR值计算出用户侧的每个基站对该用户的效用函数值,包括:Further, the calculation of the utility function value of each base station on the user side to the user according to the SINR value between the user and each base station includes:
用户侧的基站j对用户i的效用函数值的计算公式如下:The calculation formula of the utility function value of base station j on the user side to user i is as follows:
βt为不同类型的基站对应的偏置值,SINRij为基站j对用户i的信干噪比,t=1,2,3分别代表宏基站、微微基站和家庭基站,α为权重因子,Lj为当前第j个基站的负载, β t is the offset value corresponding to different types of base stations, SINR ij is the signal-to-interference and noise ratio of base station j to user i, t=1, 2, and 3 represent macro base stations, pico base stations and home base stations respectively, α is a weighting factor, L j is the load of the jth base station at present,
进一步地,所述的基站根据基站侧效用函数值最高的用户的速率请求和干扰情况判断该效用函数值最高的用户是否能够接入该基站,如果是,则反馈接入成功的信息给所述效用函数值最高的用户,包括:Further, the base station judges whether the user with the highest utility function value can access the base station according to the rate request and interference situation of the user with the highest utility function value on the base station side, and if so, feeds back information about successful access to the Users with the highest utility function values, including:
基站将基站侧效用函数值最高的用户作为待接入用户,采用拉格朗日对偶法和折半搜索迭代法重新计算该待接入用户和原有已接入用户的带宽分配比例,若满足用户速率以及基站总消耗功率优化的要求,则判断允许所述待接入用户接入基站,并反馈接入成功的信息给所述待接入用户,同时所述基站更新自身的当前负载。The base station takes the user with the highest utility function value on the base station side as the user to be accessed, and uses the Lagrangian dual method and the half search iteration method to recalculate the bandwidth allocation ratio between the user to be accessed and the original accessed user. rate and base station total power consumption optimization requirements, then judge to allow the user to be accessed to access the base station, and feed back successful access information to the user to be accessed, and at the same time, the base station updates its current load.
进一步地,所述的否则,反馈接入失败的信息给所述效用函数值最高的用户,包括:Further, the said otherwise, feeding back the access failure information to the user with the highest utility function value includes:
若不满足用户速率以及基站总消耗功率优化的要求,则基站判断所述待接入用户不能够接入该基站,反馈接入失败的信息给所述待接入用户,所述待接入用户接收到接入失败的信息后,将用户侧原申请基站的效用函数值置为0,该用户再次选择剩余基站中效用函数值最大的一个基站递交接入申请;If the user rate and the optimization requirements of the total power consumption of the base station are not satisfied, the base station judges that the user to be accessed cannot access the base station, and feeds back information about the access failure to the user to be accessed, and the user to be accessed After receiving the access failure information, set the utility function value of the base station originally applied by the user side to 0, and the user selects the base station with the largest utility function value among the remaining base stations to submit the access application;
重复上述过程,直到所有用户都能接入基站后,用户接入算法停止。The above process is repeated until all users can access the base station, and the user access algorithm stops.
进一步地,所述的采用拉格朗日对偶法和折半搜索迭代法重新计算该待接入用户和原有已接入用户的带宽分配比例,包括:Further, the recalculation of the bandwidth allocation ratio between the user to be accessed and the original accessed user by using the Lagrangian dual method and the half search iteration method includes:
设超密集异构网系统中用户集合为Z,数量为Z,所有基站的集合为M,数量为M,下标i表示用户索引,下标j表示基站索引,用户为用户设备;Suppose the set of users in the ultra-dense heterogeneous network system is Z, the number is Z, the set of all base stations is M, the number is M, the subscript i represents the user index, the subscript j represents the base station index, and the user is a user equipment;
定义二元接入指示变量为:Define the binary access indicator variable as:
假设超密集异构网系统的资源复用因子为1,bij为第i个用户占用第j个基站总带宽的比例系数,设第j个基站的总资源块个数为50,第j个基站资源的最小划分比例为1/50=0.02,满足:Assuming that the resource multiplexing factor of the ultra-dense heterogeneous network system is 1, b ij is the proportional coefficient of the i-th user occupying the total bandwidth of the j-th base station, and the total number of resource blocks of the j-th base station is 50, and the j-th user The minimum division ratio of base station resources is 1/50=0.02, which satisfies:
0<bij≤1,bij=0.02k,k∈N+ (5)0<b ij ≤1, b ij =0.02k, k∈N + (5)
设定系统中所有用户通信时的速率需求固定为Ri,求得基站j为用户i提供的发射功率为:Set the rate requirement of all users in the system to be fixed as R i , and obtain the transmit power provided by base station j for user i as:
当给定接入方案时,基站j的总发射功率为:When the access scheme is given, the total transmit power of base station j is:
采用拉格朗日对偶法和折半搜索迭代法求解下面的式(9)所示的功耗优化算式,计算出比例系数bij和二元接入指示变量xij:The Lagrangian dual method and the half-search iterative method are used to solve the power consumption optimization formula shown in the following formula (9), and the proportional coefficient b ij and the binary access indicator variable x ij are calculated:
求解上面的式(9)同时需要满足(1)、(3)、(5)式的约束条件。Solving the above formula (9) needs to meet the constraints of formulas (1), (3) and (5) at the same time.
进一步地,所述的采用拉格朗日对偶法和折半搜索迭代法求解上面的式(9)所示的功耗优化算法,计算出比例系数bij和二元接入指示变量xij,包括:Further, the above-mentioned power consumption optimization algorithm shown in the above formula (9) is solved by using the Lagrangian dual method and the binary search iteration method, and the proportional coefficient b ij and the binary access indicator variable x ij are calculated, including :
当给定接入方案,二元接入指示变量xij已知时,式(9)转化为式(10)所示的比例系数bij的优化算式:When the access scheme is given and the binary access indicator variable x ij is known, formula (9) is transformed into the optimization formula of proportional coefficient b ij shown in formula (10):
代入(6)式求得的发射功率Pij,则上式转为求解:Substituting the transmitted power P ij obtained from formula (6), the above formula is transformed into the solution:
其中,Zj为第j个基站接入的用户集合,上式(11)、(12)需满足(1)、(3)、(5)式的约束条件;Among them, Z j is the set of users accessed by the jth base station, and the above formulas (11) and (12) need to meet the constraints of (1), (3), and (5);
利用拉格朗日对偶函数对式(11)、(12)进行求解,第j个基站的拉格朗日函数如下:Using the Lagrangian dual function to solve equations (11) and (12), the Lagrangian function of the jth base station is as follows:
利用KKT条件,对拉格朗日函数求偏导数,并令其为0,则求得:Using the KKT condition, calculate the partial derivative of the Lagrangian function and set it to 0, then obtain:
对式(15)的拉格朗日乘数求一阶导数,f(bij)=λ在定义域范围内是关于自变量的单调递减函数,采用折半搜索迭代法来求解最优的λ取值,λ的最大取值和最小取值分别用λmax和λmin表示,满足:Calculate the first-order derivative of the Lagrangian multiplier of formula (15), f(b ij )=λ is a monotonously decreasing function of the independent variable within the domain, and use the half-search iterative method to find the optimal λ value, the maximum and minimum values of λ are denoted by λ max and λ min respectively, Satisfy:
将同时满足(16)式和(17)式的自变量取值代入(15)式中,求得一系列λ取值,即:The value of the independent variable that will satisfy both (16) and (17) Substitute into formula (15) to obtain a series of λ values, namely:
则得到 then get
将上式(19)求得的自变量取值代入(15)式中,同样求得一系列λ取值,则:The value of the independent variable obtained by the above formula (19) Substituting into formula (15), a series of λ values are also obtained, then:
其中,为接入第j个基站中第i个用户对应其自己计算的最小λ取值。由计算得到的λ的最大值和最小值所划分的区间,即可作为折半搜索迭代法中λ的初始计算范围;in, It is the minimum value of λ calculated by itself for the i-th user accessing the j-th base station. The interval divided by the calculated maximum value and minimum value of λ can be used as the initial calculation range of λ in the half search iteration method;
采用折半搜索迭代法来求解最优的λ取值的过程如下:将接入第j个基站的所有用户依照计算得到的带宽分配比例进行如下的验证过程:The process of using the half-search iterative method to find the optimal value of λ is as follows: All users accessing the j-th base station will perform the following verification process according to the calculated bandwidth allocation ratio:
如果接入第j个基站的所有用户的bij相加之和小于1,说明在该轮迭代过程中,λ取值过大,后续迭代需要令λmax=λ(n);If the sum of the b ij of all users accessing the j-th base station is less than 1, it means that in this round of iteration process, the value of λ is too large, and subsequent iterations need to make λ max = λ (n) ;
如果接入第j个基站的所有用户的bij相加之和大于1,说明在该轮迭代过程中,λ取值过小,后续迭代需要令λmin=λ(n);If the sum of the b ij of all users accessing the j-th base station is greater than 1, it means that the value of λ is too small in the iterative process of this round, and the subsequent iteration needs to set λ min = λ (n) ;
不断重复上述迭代过程,即令λ(n+1)=(λmax+λmin)/2,继续计算各用户相应的带宽分配比例,直到最终相加之和恰好为1时,算法停止迭代过程,此时的带宽分配比例bij即为满足各用户最低速率要求下的最优解。Repeat the iterative process above, that is, let λ (n+1) = (λ max + λ min )/2, continue to calculate the corresponding bandwidth allocation ratio of each user, until the final sum is exactly 1, the algorithm stops the iterative process, The bandwidth allocation ratio b ij at this time is the optimal solution that meets the minimum rate requirements of each user.
由上述本发明的实施例提供的技术方案可以看出,本发明实施例研究了给定目标速率条件下的用户接入及能效优化问题,在改进基站总发射功率模型的基础上,利用拉格朗日对偶和二分法对接入过程中的用户资源分配比例和基站为每个接入用户提供的发射功率进行了优化和调节,使功耗优化模型能更准确反映基站的实际发射功率和功耗。本发明提出了一种用于超密集部署场景下的用户接入算法,解决了给定目标速率条件下基于能效优化的用户接入问题。It can be seen from the technical solutions provided by the above embodiments of the present invention that the embodiments of the present invention study the problem of user access and energy efficiency optimization under the condition of a given target rate. On the basis of improving the total transmission power model of the base station, the Lager The Langerian duality and dichotomy method optimize and adjust the user resource allocation ratio in the access process and the transmit power provided by the base station for each access user, so that the power consumption optimization model can more accurately reflect the actual transmit power and power of the base station. consumption. The present invention proposes a user access algorithm used in an ultra-dense deployment scenario, and solves the problem of user access based on energy efficiency optimization under a given target rate condition.
本发明附加的方面和优点将在下面的描述中部分给出,这些将从下面的描述中变得明显,或通过本发明的实践了解到。Additional aspects and advantages of the invention will be set forth in part in the description which follows, and will become apparent from the description, or may be learned by practice of the invention.
附图说明Description of drawings
为了更清楚地说明本发明实施例的技术方案,下面将对实施例描述中所需要使用的附图作简单地介绍,显而易见地,下面描述中的附图仅仅是本发明的一些实施例,对于本领域普通技术人员来讲,在不付出创造性劳动的前提下,还可以根据这些附图获得其他的附图。In order to more clearly illustrate the technical solutions of the embodiments of the present invention, the following will briefly introduce the accompanying drawings used in the description of the embodiments. Obviously, the accompanying drawings in the following description are only some embodiments of the present invention. For Those of ordinary skill in the art can also obtain other drawings based on these drawings without making creative efforts.
图1为本发明实施例提供的一种超密集异构蜂窝通信系统示意图;FIG. 1 is a schematic diagram of an ultra-dense heterogeneous cellular communication system provided by an embodiment of the present invention;
图2为本发明实施例提供的一种系统吞吐量与总功耗比值随用户个数变化情况示意图;FIG. 2 is a schematic diagram of a system throughput-to-total power consumption ratio changing with the number of users provided by an embodiment of the present invention;
图3为本发明实施例提供的一种系统基站各自吞吐量Jain公平性因子随系统用户数量变化而变化的示意图;FIG. 3 is a schematic diagram showing how the throughput Jain fairness factor of each system base station varies with the number of system users according to an embodiment of the present invention;
图4为本发明实施例提供的一种系统各个基站最终接入用户数量Jain公平性因子随系统用户数量变化而变化示意图。FIG. 4 is a schematic diagram of Jain fairness factors of the number of final access users in each base station of the system as the number of system users changes according to an embodiment of the present invention.
具体实施方式Detailed ways
下面详细描述本发明的实施方式,所述实施方式的示例在附图中示出,其中自始至终相同或类似的标号表示相同或类似的元件或具有相同或类似功能的元件。下面通过参考附图描述的实施方式是示例性的,仅用于解释本发明,而不能解释为对本发明的限制。Embodiments of the present invention are described in detail below, examples of which are shown in the drawings, wherein the same or similar reference numerals denote the same or similar elements or elements having the same or similar functions throughout. The embodiments described below by referring to the figures are exemplary only for explaining the present invention and should not be construed as limiting the present invention.
本技术领域技术人员可以理解,除非特意声明,这里使用的单数形式“一”、“一个”、“所述”和“该”也可包括复数形式。应该进一步理解的是,本发明的说明书中使用的措辞“包括”是指存在所述特征、整数、步骤、操作、元件和/或组件,但是并不排除存在或添加一个或多个其他特征、整数、步骤、操作、元件、组件和/或它们的组。应该理解,当我们称元件被“连接”或“耦接”到另一元件时,它可以直接连接或耦接到其他元件,或者也可以存在中间元件。此外,这里使用的“连接”或“耦接”可以包括无线连接或耦接。这里使用的措辞“和/或”包括一个或更多个相关联的列出项的任一单元和全部组合。Those skilled in the art will understand that unless otherwise stated, the singular forms "a", "an", "said" and "the" used herein may also include plural forms. It should be further understood that the word "comprising" used in the description of the present invention refers to the presence of said features, integers, steps, operations, elements and/or components, but does not exclude the presence or addition of one or more other features, Integers, steps, operations, elements, components, and/or groups thereof. It will be understood that when an element is referred to as being "connected" or "coupled" to another element, it can be directly connected or coupled to the other element or intervening elements may also be present. Additionally, "connected" or "coupled" as used herein may include wirelessly connected or coupled. As used herein, the term "and/or" includes any and all combinations of one or more of the associated listed items.
本技术领域技术人员可以理解,除非另外定义,这里使用的所有术语(包括技术术语和科学术语)具有与本发明所属领域中的普通技术人员的一般理解相同的意义。还应该理解的是,诸如通用字典中定义的那些术语应该被理解为具有与现有技术的上下文中的意义一致的意义,并且除非像这里一样定义,不会用理想化或过于正式的含义来解释。Those skilled in the art can understand that, unless otherwise defined, all terms (including technical and scientific terms) used herein have the same meaning as commonly understood by one of ordinary skill in the art to which this invention belongs. It should also be understood that terms such as those defined in commonly used dictionaries should be understood to have a meaning consistent with the meaning in the context of the prior art, and will not be interpreted in an idealized or overly formal sense unless defined as herein explain.
为便于对本发明实施例的理解,下面将结合附图以几个具体实施例为例做进一步的解释说明,且各个实施例并不构成对本发明实施例的限定。In order to facilitate the understanding of the embodiments of the present invention, several specific embodiments will be taken as examples for further explanation below in conjunction with the accompanying drawings, and each embodiment does not constitute a limitation to the embodiments of the present invention.
实施例一Embodiment one
本发明实施例在现有文献的基础上进行改进,使功耗优化模型能更准确反映基站的实际发射功率和功耗,在此基础上提出一种改进的基于最大信干噪比和配对理论的接入策略。其中,用配对理论解决接入过程中负载数量变化带来的负载均衡问题,用拉格朗日对偶和二分法优化和调整接入过程中分配给每个用户的资源比例以及基站为每个用户提供的发射功率。The embodiment of the present invention improves on the basis of the existing literature, so that the power consumption optimization model can more accurately reflect the actual transmission power and power consumption of the base station, and on this basis, an improved SINR-based and pairing theory is proposed access strategy. Among them, the pairing theory is used to solve the load balancing problem caused by the change of the load quantity in the access process, and the Lagrangian dual and dichotomy method are used to optimize and adjust the resource ratio allocated to each user in the access process and the base station for each user. The transmit power provided.
系统模型与问题建模System Model and Problem Modeling
本发明实施例主要考虑超密集部署下行异构蜂窝通信系统,图1为本发明实施例提出的一张超密集异构蜂窝通信系统示意图,如图1所示。系统中存在下述类型的基站:宏基站、微微蜂窝基站(Picocells)和家庭基站(Femtocells)。在所研究范围内,记所有活动用户集合为Z,数量为Z,所有基站的集合为M,数量为M。下标i和j分别表示活动用户索引和密集部署的基站索引。在本发明实施例中,用户是指用户设备。The embodiment of the present invention mainly considers the ultra-dense deployment of the downlink heterogeneous cellular communication system. FIG. 1 is a schematic diagram of the ultra-dense heterogeneous cellular communication system proposed by the embodiment of the present invention, as shown in FIG. 1 . The following types of base stations exist in the system: macro base stations, picocell base stations (Picocells) and home base stations (Femtocells). In the research area, record the set of all active users as Z, the number is Z, the set of all base stations is M, and the number is M. Subscripts i and j denote active user index and densely deployed base station index, respectively. In this embodiment of the present invention, a user refers to a user equipment.
定义二元接入指示变量为:Define the binary access indicator variable as:
用户i与基站j之间的SINR(Signal to Interference plus Noise Ratio,信干噪比)由下式给出:The SINR (Signal to Interference plus Noise Ratio) between user i and base station j is given by the following formula:
Pij为用户i占用全部资源块传输时基站j的总发射功率,gij为基站j对用户i的信道衰落系数,gik为基站k对用户i的信道衰落系数,σ2为高斯白噪声功率,为基站j的最大发射功率。P ij is the total transmit power of base station j when user i occupies all resource blocks for transmission, g ij is the channel fading coefficient of base station j to user i, g ik is the channel fading coefficient of base station k to user i, and σ 2 is Gaussian white noise power, is the maximum transmit power of base station j.
本发明实施例采用用户所受干扰的最大值来简化干扰过程的计算,设为相应用户所受到的最大干扰功率之和。根据香农公式,该用户的实际可达通信速率为:In the embodiment of the present invention, the maximum value of the interference suffered by the user is used to simplify the calculation of the interference process. is the sum of the maximum interference power received by the corresponding users. According to Shannon's formula, the user's actual achievable communication rate is:
ri=Bbijlog2(1+SINRij) (4)r i =Bb ij log 2 (1+SINR ij ) (4)
其中,B为系统的总带宽。Among them, B is the total bandwidth of the system.
假设系统的资源复用因子为1。bij为第i个用户占用第j个基站总带宽的比例系数,设总资源块个数为50,因此其最小划分比例为1/50=0.02,即需要满足:Assume that the resource reuse factor of the system is 1. b ij is the ratio coefficient of the i-th user occupying the total bandwidth of the j-th base station, and the total number of resource blocks is set to 50, so the minimum division ratio is 1/50=0.02, that is, it needs to satisfy:
0<bij≤1,bij=0.02k,k∈N+ (5)0<b ij ≤1, b ij =0.02k, k∈N + (5)
设定系统中用户通信时的需求速率固定为Ri,为了计算方便,假设所有用户的需求速率都相同,求得基站j为用户i提供的发射功率为:Set the required rate of user communication in the system to be fixed as R i , for the convenience of calculation, assuming that the required rate of all users is the same, the transmission power provided by base station j for user i is obtained as:
当给定接入方案时,基站j的总发射功率为:When the access scheme is given, the total transmit power of base station j is:
同样的,Pj也应满足(3)式的约束限制。Similarly, P j should also satisfy the constraints of (3).
基站的发射功率并不是其消耗的总功率,基站的发射功率模型为线性消耗模型,其主要形式如下:The transmit power of the base station is not the total power consumed by it. The transmit power model of the base station is a linear consumption model, and its main form is as follows:
其中,为基站最终总体功耗值,为相应类型基站的固定功耗值,Δj相应类型基站在线性消耗模型中的斜率。in, is the final overall power consumption value of the base station, is the fixed power consumption value of the corresponding type of base station, and Δj is the slope of the corresponding type of base station in the linear consumption model.
由于基站的总功耗直接取决于基站最终的总发射功率,所以功耗的优化等效于以下优化问题:Since the total power consumption of the base station directly depends on the final total transmit power of the base station, the optimization of power consumption is equivalent to the following optimization problem:
上式同时需要满足(1)、(3)、(5)式的限制要求。由于优化变量有两类,代表了该优化问题中用户接入子问题和带宽分配子问题的强耦合性。其中,求解变量xij的问题为用户接入子问题,求解变量bij的问题为带宽分配子问题。本发明将对上述两个子问题分别进行建模求解,最终提出基于能耗与配对理论的用户接入算法。The above formula needs to meet the constraints of (1), (3), and (5) at the same time. Since there are two types of optimization variables, it represents the strong coupling between the user access sub-problem and the bandwidth allocation sub-problem in this optimization problem. Among them, the problem of solving the variable x ij is the user access sub-problem, and the problem of solving the variable b ij is the bandwidth allocation sub-problem. The present invention will model and solve the above two sub-problems respectively, and finally propose a user access algorithm based on energy consumption and pairing theory.
超密集异构网中基于能耗与配对理论的用户接入算法User Access Algorithm Based on Energy Consumption and Pairing Theory in Ultra-Dense Heterogeneous Networks
带宽分配子问题Bandwidth Allocation Subproblem
当给定接入方案即(二元接入指示变量xij已知)时,原优化问题即转变为:When the access scheme is given (the binary access indicator variable x ij is known), the original optimization problem is transformed into:
代入(6)式求得的发射功率Pij,则上式转为求解:Substituting the transmitted power P ij obtained from formula (6), the above formula is transformed into the solution:
其中,Zj为第j个基站接入的用户集合,上式(11)、(12)需满足(1)、(3)、(5)式的约束条件。Among them, Z j is the set of users accessed by the jth base station, and the above equations (11) and (12) need to satisfy the constraints of (1), (3) and (5).
本发明实施例求解的优化函数加入了资源分配比例bij的乘积项。由于Pij是假设该用户占用相应基站的所有频率资源后的总发射功率,其并不能代表该用户在该基站上最终获得的发射功率。The optimization function solved by the embodiment of the present invention adds the product term of the resource allocation ratio b ij . Since P ij is the total transmission power after assuming that the user occupies all the frequency resources of the corresponding base station, it cannot represent the final transmission power obtained by the user on the base station.
因此,利用Pijbij才可以正确反映用户i在获得基站j的部分资源后所得到的发射功率。可以证明,(10)式的优化问题为凸优化问题,在优化变量的定义域范围内,该子问题存在唯一的极小值点。取出其中第j个基站的部分,记为Sj,可利用拉格朗日对偶函数进行求解。第j个基站的拉格朗日函数如下:Therefore, P ij b ij can correctly reflect the transmit power obtained by user i after obtaining some resources of base station j. It can be proved that the optimization problem in formula (10) is a convex optimization problem, and there is a unique minimum value point in this sub-problem within the domain of the optimization variable. Take out the part of the jth base station, denote it as S j , and use the Lagrange dual function to solve it. The Lagrangian function of the jth base station is as follows:
利用KKT条件,对拉格朗日函数求偏导数,并令其为0,则可以求得:Using the KKT condition to find the partial derivative of the Lagrangian function and set it to 0, we can get:
KKT条件是指对于带有等式和不等式约束的优化问题,构造相应的拉格朗日函数后,函数的最优值取得必须满足以下三个条件,即KKT条件:1.构造的拉格朗日函数对各个自变量求偏导数后的函数在该点的函数值为0;2.等式约束函数带入该最优点的函数值为0;3.不等式约束函数的线性组合而成的新函数在该点的函数值为0。The KKT condition means that for an optimization problem with equality and inequality constraints, after constructing the corresponding Lagrangian function, the optimal value of the function must meet the following three conditions, namely the KKT condition: 1. The constructed Lagrangian The value of the function at this point after the partial derivative of the daily function to each independent variable is 0; 2. The value of the function brought into the optimal point by the equality constraint function is 0; 3. The new linear combination of the inequality constraint function The function has a function value of 0 at this point.
具体到本文中,最优自变量必须满足上述三个条件,对于第一个,需要计算相应的偏导数函数。对于第二个,此处暂不用考虑,其依赖性依靠下文对λ的迭代选择取值进行限定。对于第三个,(13)式中没有不等式约束,故不用考虑。Specifically in this paper, the optimal independent variable must meet the above three conditions, and for the first one, the corresponding partial derivative function needs to be calculated. For the second one, we don’t need to consider it here, and its dependence is limited by the iterative selection value of λ below. For the third one, there is no inequality constraint in (13), so don't consider it.
对上式的拉格朗日函数求一阶导数,其一阶导数值小于0。计算过程不再列出。所以f(bij)=λ在定义域范围内是关于自变量的单调递减函数。即如果能求得合适的λ取值,即可求解出该带宽分配子问题的最优解。本发明实施例采用折半搜索迭代法来求解最优的λ取值。λ的最大取值和最小取值分别用λmax和λmin表示。满足:Calculate the first order derivative of the Lagrangian function of the above formula, and its first order derivative value is less than 0. Calculations are no longer listed. So f(b ij )=λ is a monotonically decreasing function with respect to the independent variable within the scope of the definition domain. That is, if the appropriate value of λ can be obtained, the optimal solution of the bandwidth allocation sub-problem can be obtained. The embodiment of the present invention uses a half-search iterative method to find the optimal value of λ. The maximum and minimum values of λ are denoted by λ max and λ min respectively. Satisfy:
将同时满足(16)式和(17)式的自变量取值代入(15)式中,可求得一系列λ取值,即:The value of the independent variable that will satisfy both (16) and (17) Substituting into formula (15), a series of λ values can be obtained, namely:
则可以得到 then you can get
将上式求得的自变量取值代入(15)式中,同样可求得一系列λ取值,则:Take the value of the independent variable obtained from the above formula Substituting into formula (15), a series of λ values can also be obtained, then:
其中,为接入第j个基站中第i个用户对应其自己计算的最小λ取值。由计算得到的λ的最大值和最小值所划分的区间,即可作为折半搜索迭代法中λ的初始计算范围。in, It is the minimum value of λ calculated by itself for the i-th user accessing the j-th base station. The interval divided by the calculated maximum and minimum values of λ can be used as the initial calculation range of λ in the half-search iterative method.
本发明实施例采用折半搜索迭代法来求解最优的λ取值的过程如下:将接入第j个基站的所有用户依照计算得到的带宽分配比例进行如下的验证过程:The embodiment of the present invention adopts the half search iteration method to solve the optimal λ value process as follows: all users accessing the jth base station are verified according to the calculated bandwidth allocation ratio as follows:
如果相加之和小于1,说明在该轮迭代过程中,λ取值过大,后续迭代需要令λmax=λ(n);If the sum of the additions is less than 1, it means that the value of λ is too large in the iterative process of this round, and the subsequent iteration needs to make λ max = λ (n) ;
如果相加之和大于1,说明在该轮迭代过程中,λ取值过小,后续迭代需要令λmin=λ(n)。If the sum is greater than 1, it means that the value of λ is too small during this round of iteration, and λ min =λ (n) needs to be set in subsequent iterations.
不断重复上述迭代过程,即令λ(n+1)=(λmax+λmin)/2,继续计算各用户相应的带宽分配比例,直到最终相加之和恰好为1时,算法停止迭代过程,此时的带宽分配比例即为满足各用户最低速率要求下的最优解,根据求解出的基站j接入的各个用户的bij根据式(7)计算出基站j的总发射功率。Repeat the iterative process above, that is, let λ (n+1) = (λ max + λ min )/2, continue to calculate the corresponding bandwidth allocation ratio of each user, until the final sum is exactly 1, the algorithm stops the iterative process, The bandwidth allocation ratio at this time is the optimal solution that satisfies the minimum rate requirements of each user. According to the calculated b ij of each user accessed by base station j, the total transmit power of base station j is calculated according to formula (7).
上文处理的为确定用户接入时基站对各个接入用户的带宽资源分配及发射功率计算,求解xij的过程为后续接入子过程确定。What is dealt with above is to determine the bandwidth resource allocation and transmission power calculation of each access user by the base station when the user accesses, and the process of solving x ij is determined by the subsequent access sub-process.
用户接入过程中效用函数的确定Determination of Utility Function in User Access Process
用户集合的效用函数为:The utility function of the user set is:
βt为不同类型的基站对应的偏置值,SINRij为基站j对用户i的信干噪比,t=1,2,3分别代表宏基站、微微基站和家庭基站,α为权重因子,Lj为当前第j个基站的负载, β t is the offset value corresponding to different types of base stations, SINR ij is the signal-to-interference and noise ratio of base station j to user i, t=1, 2, and 3 represent macro base stations, pico base stations and home base stations respectively, α is a weighting factor, L j is the load of the jth base station at present,
基站集合的效用函数定义为:The utility function of the base station set is defined as:
即依靠(22)式确定,对于给定的某个基站,基站对每个用户的效用函数是该用户实际的信干噪比,这个信噪比SINRij是在用户i向基站j提交申请的时候基站可以获取到的性能参数。后续接入过程中基站依靠这个信干噪比的大小对所有向其提出申请的用户进行偏好排序,显然,如果确定某个用户不能接入该基站,则对其的效用函数值为0。That is, it is determined by formula (22). For a given base station, the utility function of the base station for each user is the actual SINR of the user. This SINR ij is obtained when user i submits an application to base station j The performance parameters that the base station can obtain at that time. In the subsequent access process, the base station ranks all users who apply for it based on the SINR. Obviously, if it is determined that a user cannot access the base station, the utility function value for it is 0.
用户接入算法的具体实现过程The specific implementation process of the user access algorithm
用户测量并计算该用户与每个基站之间的信干噪比SINR值;The user measures and calculates the SINR value between the user and each base station;
根据用户与每个基站之间的SINR值计算出在用户侧每个基站对该用户的效用函数值,用户向对自己效用函数值最高的基站发送接入申请,该接入申请中携带与用户和该基站之间的SINR值相关的信道质量信息。According to the SINR value between the user and each base station, the utility function value of each base station on the user side is calculated for the user, and the user sends an access application to the base station with the highest utility function value for the user. Channel quality information related to the SINR value between the base stations.
基站接收到多个用户发送的接入申请后,对每个用户提供的信道质量信息进行处理,并将从接入申请中提取出来的SINR值作为基站侧发送该接入请求的用户的效用函数值,根据基站侧用户的效用函数值对多个用户进行排序,基站根据基站侧效用函数值最高的用户的速率请求和干扰情况判断该效用函数值最高的用户是否能够接入该基站,如果是,则反馈接入成功的信息给所述效用函数值最高的用户;否则,反馈接入失败的信息给所述效用函数值最高的用户。After the base station receives the access application sent by multiple users, it processes the channel quality information provided by each user, and uses the SINR value extracted from the access application as the utility function of the user who sent the access request on the base station side value, according to the utility function value of the user on the base station side, sort multiple users, and the base station judges whether the user with the highest utility function value can access the base station according to the rate request and interference situation of the user with the highest utility function value on the base station side, if it is , feed back information about successful access to the user with the highest value of the utility function; otherwise, feed back information about failed access to the user with the highest value of the utility function.
基站将基站侧效用函数值最高的用户作为待接入用户,采用拉格朗日对偶法和折半搜索迭代法重新计算该待接入用户和原有已接入用户的带宽分配比例,若满足用户速率以及基站总消耗功率优化的要求,即满足此时各用户的带宽比例相加为1,则判断允许所述待接入用户接入基站,更新相应的xij为1,并反馈接入成功的信息给所述待接入用户,同时所述基站更新自身的当前负载。The base station takes the user with the highest utility function value on the base station side as the user to be accessed, and uses the Lagrangian dual method and the half search iteration method to recalculate the bandwidth allocation ratio between the user to be accessed and the original accessed user. Rate and base station total power consumption optimization requirements, that is, satisfying the bandwidth ratio of each user at this time adds up to 1, then it is judged that the user to be accessed is allowed to access the base station, the corresponding x ij is updated to 1, and the access is successful information to the user to be accessed, and at the same time, the base station updates its own current load.
若不满足用户速率以及基站总消耗功率优化的要求,则基站判断所述待接入用户不能够接入该基站,反馈接入失败的信息给所述待接入用户,所述待接入用户接收到接入失败的信息后,将用户侧原申请基站的效用函数值置为0,该用户再次选择剩余基站中效用函数值最大的一个基站递交接入申请。If the user rate and the optimization requirements of the total power consumption of the base station are not satisfied, the base station judges that the user to be accessed cannot access the base station, and feeds back information about the access failure to the user to be accessed, and the user to be accessed After receiving the access failure information, the utility function value of the base station originally applied by the user side is set to 0, and the user selects the base station with the largest utility function value among the remaining base stations to submit the access application.
重复上述过程,直到所有用户都能接入基站后,用户接入算法停止。The above process is repeated until all users can access the base station, and the user access algorithm stops.
用户收到基站的反馈信息后,决定下一轮接入申请的动作。如果某用户的接入申请成功后,则系统将该用户从待接入用户队列中移除;如果某用户的接入申请被拒绝后,则该用户根据用户效用函数的计算规则将原申请基站的效用置为0,然后再次选择剩余基站中效用函数值最大的一个递交接入申请。重复上述过程,直到所有用户都能接入基站后,算法停止。After receiving the feedback information from the base station, the user decides the action for the next round of access application. If a user's access application is successful, the system will remove the user from the waiting queue; if a user's access application is rejected, the user will remove the original application base station The utility of the base station is set to 0, and then the one with the largest utility function value among the remaining base stations is selected again to submit an access application. Repeat the above process until all users can access the base station, the algorithm stops.
仿真结果与分析Simulation Results and Analysis
仿真设置simulation settings
仿真系统中有一个宏基站,覆盖半径为500m,其最大发射功率为46dBm,10个Pico基站和40个Femto基站及相应的用户均匀分布在该研究范围内,最大发射功率分别为35dBm和20dBm。具体仿真使用到的一些参数如下表1所示。In the simulation system, there is a macro base station with a coverage radius of 500m and a maximum transmission power of 46dBm. 10 Pico base stations and 40 Femto base stations and corresponding users are evenly distributed in the research area, and the maximum transmission power is 35dBm and 20dBm respectively. Some parameters used in the specific simulation are shown in Table 1 below.
表1仿真参数设置Table 1 Simulation parameter settings
在基站功耗方面,使用上文提到的线性功耗模型,不同类型基站的功耗模型参数如下表2所示:In terms of base station power consumption, using the linear power consumption model mentioned above, the power consumption model parameters of different types of base stations are shown in Table 2 below:
表2基站线性功耗模型参数Table 2 Base station linear power consumption model parameters
仿真性能指标Simulation Performance Indicators
本发明采用速率功耗比,也即功耗效率作为主要的评价指标,其定义为系统的总吞吐量和系统中所有基站的总消耗功率之比。The present invention uses the ratio of rate to power consumption, that is, the power consumption efficiency as the main evaluation index, which is defined as the ratio of the total throughput of the system to the total power consumption of all base stations in the system.
在公平性部分,使用Jain公平性因子作为主要评价指标,其计算方式如下:In the fairness part, the Jain fairness factor is used as the main evaluation index, and its calculation method is as follows:
其中,rn为第n个用户的相关性能,N为系统中所有用户的总数。具体到本发明中,上式提到的用户将被替换成系统中的基站,相关性能为各个基站服务其所有接入用户的总吞吐量和接入用户的数量。Among them, r n is the correlation performance of the nth user, and N is the total number of all users in the system. Specifically in the present invention, the users mentioned in the above formula will be replaced by base stations in the system, and the related performance is the total throughput and the number of access users served by each base station for all its access users.
仿真结果分析Simulation result analysis
本发明所提算法为基于配对理论和功耗改善,利用最大信干噪比进行接入的算法(Matching Theory and Power consumption improvement-based,MTPI—SINR),而对比算法主要有基于配对理论和带宽平均分配(Matching Theory and Band AllocationAveraging,MTBAA—SINR)的,有基于配对理论和功率最小化(Matching Theory and PowerMinimization,MTPM—SINR),即现有文献提出的不准确的发射功率最小化结合配对理论的接入和功率调整算法,以及基于配对理论和功耗改善,利用最大信道增益进行接入的算法(MTPI—CH)。下文为相关仿真结果的具体分析。The algorithm proposed in the present invention is an algorithm based on matching theory and power consumption improvement, using the maximum SINR for access (Matching Theory and Power consumption improvement-based, MTPI-SINR), and the comparison algorithm is mainly based on matching theory and bandwidth Matching Theory and Band AllocationAveraging (MTBAA—SINR) is based on pairing theory and power minimization (Matching Theory and PowerMinimization, MTPM—SINR), that is, the inaccurate transmission power minimization combined with pairing theory proposed in the existing literature The access and power adjustment algorithm, and based on the pairing theory and power consumption improvement, the algorithm for access using the maximum channel gain (MTPI-CH). The following is the specific analysis of the relevant simulation results.
图2为本发明实施例提供的一种系统吞吐量与总功耗比值随用户个数变化情况示意图,即能耗效率随系统用户数量变化而变化的结果。从整体的趋势来看,该值随自变量的增加而减少,这是由于基站带宽资源有限,所以随着用户数量的增加,系统最终的实际总吞吐量呈现下降的态势。从纵向上来看,不同算法间在系统相同用户数量的前提下的性能表现有差异。可以看到,本发明所提算法在功耗效率方面表现优异,优于其他三种算法。Fig. 2 is a schematic diagram of the variation of the ratio of system throughput to total power consumption with the number of users provided by an embodiment of the present invention, that is, the result of the variation of energy consumption efficiency with the number of system users. From the overall trend, the value decreases with the increase of the independent variable. This is due to the limited bandwidth resources of the base station, so as the number of users increases, the final actual total throughput of the system shows a downward trend. From a vertical perspective, the performance of different algorithms is different under the premise of the same number of users in the system. It can be seen that the algorithm proposed in the present invention has excellent performance in terms of power consumption efficiency, which is better than the other three algorithms.
图3为系统基站各自吞吐量的Jain公平性因子随系统用户数量变化而变化的示意图。从整体的趋势来看,该值随自变量的增加而增加。纵向对比后发现,在相同用户数量的基础上,MTPI算法不管是以最大信干噪比还是以最大信道增益为基础的,其吞吐量公平性均优于其余两种算法。原因是经过功耗改善后,各个基站的发射功率基本可以调整到最佳,又由于各基站的吞吐量不仅和其自身发射功率相关,还与其他基站的发射功率密切相关,因此每个基站的总吞吐量在本发明算法中相较带宽平均分配进而进行功率优化以及传统功率优化条件(均未准确调整发射功率)下的一致性和公平性更高。FIG. 3 is a schematic diagram of Jain fairness factors of respective throughputs of system base stations changing as the number of system users changes. From the overall trend, the value increases with the increase of the independent variable. After longitudinal comparison, it is found that, on the basis of the same number of users, whether the MTPI algorithm is based on the maximum SINR or the maximum channel gain, its throughput fairness is better than the other two algorithms. The reason is that after the power consumption is improved, the transmit power of each base station can basically be adjusted to the best, and because the throughput of each base station is not only related to its own transmit power, but also closely related to the transmit power of other base stations, so the throughput of each base station The consistency and fairness of the total throughput in the algorithm of the present invention are higher than those under the conditions of average bandwidth allocation and then power optimization and traditional power optimization conditions (no accurate adjustment of transmission power).
图4为系统各个基站最终接入用户数量的Jain公平性因子随系统用户数量变化而变化示意图。四种算法下,随自变量的增加,该项数值均呈现上升趋势。图4表明,MTPI算法不管是以最大信干噪比还是以最大信道增益为基础的,其基站接入数量公平性均优于其余两种算法。原因和图3一致。FIG. 4 is a schematic diagram showing how the Jain fairness factor of the number of final access users of each base station of the system changes with the number of system users. Under the four algorithms, with the increase of the independent variable, the value of this item shows an upward trend. Figure 4 shows that whether the MTPI algorithm is based on the maximum SINR or the maximum channel gain, the fairness of the number of base station accesses is better than the other two algorithms. The reason is consistent with Figure 3.
综上所述,本发明实施例研究了给定目标速率条件下的用户接入及能效优化问题。首先针对现有文献功率优化表达方式的不足,在改进基站总发射功率模型的基础上,利用拉格朗日对偶和二分法对接入过程中的用户分配资源比例和基站为每个接入用户提供的发射功率进行了优化和调节,使功耗优化模型能更准确反映基站的实际发射功率和功耗。To sum up, the embodiment of the present invention studies the problem of user access and energy efficiency optimization under the condition of a given target rate. First of all, aiming at the deficiency of the power optimization expression in the existing literature, on the basis of improving the total transmission power model of the base station, using Lagrangian duality and dichotomy method to allocate resource ratio of users in the access process and base station for each access user The provided transmit power is optimized and adjusted so that the power consumption optimization model can more accurately reflect the actual transmit power and power consumption of the base station.
本发明提出了一种用于超密集部署场景下的用户接入算法,解决了给定目标速率条件下基于能效优化的用户接入问题。仿真结果表明,本发明的算法具有良好的公平性,且在功耗效率上优于其他对比算法。The present invention proposes a user access algorithm used in an ultra-dense deployment scenario, and solves the problem of user access based on energy efficiency optimization under a given target rate condition. Simulation results show that the algorithm of the present invention has good fairness, and is superior to other comparative algorithms in terms of power consumption efficiency.
本领域普通技术人员可以理解:附图只是一个实施例的示意图,附图中的模块或流程并不一定是实施本发明所必须的。Those skilled in the art can understand that the accompanying drawing is only a schematic diagram of an embodiment, and the modules or processes in the accompanying drawing are not necessarily necessary for implementing the present invention.
通过以上的实施方式的描述可知,本领域的技术人员可以清楚地了解到本发明可借助软件加必需的通用硬件平台的方式来实现。基于这样的理解,本发明的技术方案本质上或者说对现有技术做出贡献的部分可以以软件产品的形式体现出来,该计算机软件产品可以存储在存储介质中,如ROM/RAM、磁碟、光盘等,包括若干指令用以使得一台计算机设备(可以是个人计算机,服务器,或者网络设备等)执行本发明各个实施例或者实施例的某些部分所述的方法。It can be seen from the above description of the implementation manners that those skilled in the art can clearly understand that the present invention can be implemented by means of software plus a necessary general hardware platform. Based on this understanding, the essence of the technical solution of the present invention or the part that contributes to the prior art can be embodied in the form of software products, and the computer software products can be stored in storage media, such as ROM/RAM, disk , CD, etc., including several instructions to make a computer device (which may be a personal computer, server, or network device, etc.) execute the methods described in various embodiments or some parts of the embodiments of the present invention.
本说明书中的各个实施例均采用递进的方式描述,各个实施例之间相同相似的部分互相参见即可,每个实施例重点说明的都是与其他实施例的不同之处。尤其,对于装置或系统实施例而言,由于其基本相似于方法实施例,所以描述得比较简单,相关之处参见方法实施例的部分说明即可。以上所描述的装置及系统实施例仅仅是示意性的,其中所述作为分离部件说明的单元可以是或者也可以不是物理上分开的,作为单元显示的部件可以是或者也可以不是物理单元,即可以位于一个地方,或者也可以分布到多个网络单元上。可以根据实际的需要选择其中的部分或者全部模块来实现本实施例方案的目的。本领域普通技术人员在不付出创造性劳动的情况下,即可以理解并实施。Each embodiment in this specification is described in a progressive manner, the same and similar parts of each embodiment can be referred to each other, and each embodiment focuses on the differences from other embodiments. In particular, for the device or system embodiments, since they are basically similar to the method embodiments, the description is relatively simple, and for relevant parts, refer to part of the description of the method embodiments. The device and system embodiments described above are only illustrative, and the units described as separate components may or may not be physically separated, and the components shown as units may or may not be physical units, that is, It can be located in one place, or it can be distributed to multiple network elements. Part or all of the modules can be selected according to actual needs to achieve the purpose of the solution of this embodiment. It can be understood and implemented by those skilled in the art without creative effort.
以上所述,仅为本发明较佳的具体实施方式,但本发明的保护范围并不局限于此,任何熟悉本技术领域的技术人员在本发明揭露的技术范围内,可轻易想到的变化或替换,都应涵盖在本发明的保护范围之内。因此,本发明的保护范围应该以权利要求的保护范围为准。The above is only a preferred embodiment of the present invention, but the scope of protection of the present invention is not limited thereto. Any person skilled in the art can easily conceive of changes or modifications within the technical scope disclosed in the present invention. Replacement should be covered within the protection scope of the present invention. Therefore, the protection scope of the present invention should be determined by the protection scope of the claims.
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