CN107742978B - Charge pump circuit with enhancing driving capability - Google Patents
Charge pump circuit with enhancing driving capability Download PDFInfo
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- CN107742978B CN107742978B CN201711079617.7A CN201711079617A CN107742978B CN 107742978 B CN107742978 B CN 107742978B CN 201711079617 A CN201711079617 A CN 201711079617A CN 107742978 B CN107742978 B CN 107742978B
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- H—ELECTRICITY
- H02—GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
- H02M—APPARATUS FOR CONVERSION BETWEEN AC AND AC, BETWEEN AC AND DC, OR BETWEEN DC AND DC, AND FOR USE WITH MAINS OR SIMILAR POWER SUPPLY SYSTEMS; CONVERSION OF DC OR AC INPUT POWER INTO SURGE OUTPUT POWER; CONTROL OR REGULATION THEREOF
- H02M3/00—Conversion of DC power input into DC power output
- H02M3/02—Conversion of DC power input into DC power output without intermediate conversion into AC
- H02M3/04—Conversion of DC power input into DC power output without intermediate conversion into AC by static converters
- H02M3/06—Conversion of DC power input into DC power output without intermediate conversion into AC by static converters using resistors or capacitors, e.g. potential divider
- H02M3/07—Conversion of DC power input into DC power output without intermediate conversion into AC by static converters using resistors or capacitors, e.g. potential divider using capacitors charged and discharged alternately by semiconductor devices with control electrode, e.g. charge pumps
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Abstract
本申请提供了一种电荷泵包括电荷泵主模块,该电荷泵主模块包括X个第一级电荷泵单元,其中X为大于1的正整数;时钟模块,为输出时钟序列以调整所述第一级电荷泵单元之间的耦合关系以及所述第一级电荷泵单元内部的耦合关系;倍率选择模块,为根据需要的输出倍率控制所述时钟模块输出相应的时钟序列;所述电荷泵主模块根据所接收到的时钟序列将所述X个第一级电荷泵单元重组为Y个第二级电荷泵单元,Y为大于等于1但小于等于X的正整数,其中针对每个整数或整数分之一倍率,所述Y个第二级电荷泵单元具有相同的等效电容值,或者各个所述第二级电荷泵单元中所包含的第一级电荷泵单元的个数差小于等于1。本申请还提供了利用电荷泵调整电压的方法。
The application provides a charge pump including a charge pump main module, the charge pump main module includes X first-stage charge pump units, where X is a positive integer greater than 1; a clock module is used to output a clock sequence to adjust the first The coupling relationship between the first-stage charge pump units and the coupling relationship inside the first-stage charge pump unit; the magnification selection module controls the clock module to output a corresponding clock sequence according to the required output magnification; the charge pump main The module reorganizes the X first-stage charge pump units into Y second-stage charge pump units according to the received clock sequence, Y is a positive integer greater than or equal to 1 but less than or equal to X, wherein for each integer or integer One-half of the ratio, the Y second-stage charge pump units have the same equivalent capacitance value, or the difference in the number of first-stage charge pump units contained in each of the second-stage charge pump units is less than or equal to 1 . The present application also provides a method for adjusting voltage using a charge pump.
Description
技术领域technical field
本申请涉及集成电路领域,特别涉及具有高输出驱动能力的全倍率电荷泵。The application relates to the field of integrated circuits, in particular to a full rate charge pump with high output driving capability.
背景技术Background technique
电荷泵结构被广泛的用于显示屏或手持设备的电源管理系统设计。电荷泵也称为开关电容式电压变换器,是一种利用电容而非电感或变压器来储能的直流变换器。通过电荷泵能使输入电压升高或降低,甚至可以用于产生负电压。电荷泵结构采用开关阵列以一定的方式控制电容器充电和放电,使输入电压以一定因数倍增或倍减,从而得到所需要的输出电压。由于(电容型)电荷泵并不包括电感器,因此可以避免由电感器带来的电磁干扰。The charge pump structure is widely used in the power management system design of display screens or handheld devices. A charge pump, also known as a switched capacitor voltage converter, is a type of DC converter that uses capacitors instead of inductors or transformers to store energy. The input voltage can be raised or lowered by a charge pump, and can even be used to generate negative voltages. The charge pump structure uses a switch array to control the charging and discharging of capacitors in a certain way, so that the input voltage is multiplied or subtracted by a certain factor, so as to obtain the required output voltage. Since the (capacitive) charge pump does not include an inductor, electromagnetic interference caused by the inductor can be avoided.
无论对于何种应用来说,使用者都希望电荷泵输出电压的倍率能够在比较宽的范围内变化,这样可以有效提高功率效率和纹波性能。当电荷泵输入电压较小时,可以选用高倍率工作模式,反之则可以采用低倍率工作模式。特别地,对于片上的电源模块来说,由于其集成度高,所以颇受使用者喜爱。片上的电源模块一般采用片上Dickson电荷泵设计,主要看中其芯片面积小,寄生电容带来的损耗也小的特点。Regardless of the application, the user hopes that the multiple of the charge pump output voltage can be varied within a relatively wide range, which can effectively improve power efficiency and ripple performance. When the input voltage of the charge pump is small, the high rate operation mode can be selected, otherwise the low rate operation mode can be used. In particular, the on-chip power module is very popular among users due to its high level of integration. The on-chip power module is generally designed with an on-chip Dickson charge pump, mainly due to its small chip area and small loss caused by parasitic capacitance.
以传统的N级降压型Dickson电荷泵为例,输入电压为VDD,其输出电压为VDD/(N+1),即产生电压倍率为1/(N+1)。如图1所示,当电荷泵从一个倍率切换成另一个倍率时,比如:当电荷泵从1/5倍率变换成1/3倍率时,传统的方法是让前三级并联,成为新的一级,这样,Dickson电荷泵就从本来的4级结构变成2级结构,倍率也变成1/3。这种方案虽然有效地利用了所有片上电容,可以改善带载能力,但是对于电荷泵输出驱动能力也却有待改善。这是因为组合后的各电荷泵单元的电容分布不平均,因此电荷泵电路无法实现最大的输出驱动能力。Taking the traditional N-stage step-down Dickson charge pump as an example, the input voltage is V DD , and its output voltage is V DD /(N+1), that is, the generated voltage multiplier is 1/(N+1). As shown in Figure 1, when the charge pump is switched from one magnification to another, for example: when the charge pump is converted from 1/5 magnification to 1/3 magnification, the traditional method is to connect the first three stages in parallel to become a new In this way, the Dickson charge pump changes from the original 4-stage structure to a 2-stage structure, and the magnification becomes 1/3. Although this solution effectively utilizes all the on-chip capacitors and can improve the load carrying capacity, the output drive capability of the charge pump also needs to be improved. This is because the capacitance distribution of the combined charge pump units is uneven, so the charge pump circuit cannot achieve the maximum output driving capability.
因此需要提供的电荷泵是能够实现所有的整数或整数分之一倍率以提高系统功率,同时还能提供更好的输出驱动能力。Therefore, it is necessary to provide a charge pump that can realize all integer or integer multiples to increase system power and provide better output drive capability.
发明内容Contents of the invention
针对当前技术中存在的问题,本申请提供了一种电荷泵,包括电荷泵主模块,所述电荷泵主模块包括X个第一级电荷泵单元,其中X为大于1的正整数;时钟模块,被配置为输出时钟序列以调整所述第一级电荷泵单元之间的耦合关系以及所述第一级电荷泵单元内部的耦合关系;倍率选择模块,被配置为根据需要的输出倍率控制所述时钟模块输出相应的时钟序列;其中,所述电荷泵主模块根据所接收到的时钟序列将所述X个第一级电荷泵单元重组为Y个第二级电荷泵单元,Y为大于等于1但小于等于X的正整数,其中针对每个整数或整数分之一倍率,所述Y个第二级电荷泵单元具有相同的等效电容值,或者各个所述第二级电荷泵单元中所包含的第一级电荷泵单元的个数差小于等于1。In view of the problems existing in the current technology, the application provides a charge pump, including a charge pump main module, the charge pump main module includes X first-stage charge pump units, where X is a positive integer greater than 1; the clock module , configured to output a clock sequence to adjust the coupling relationship between the first-stage charge pump units and the coupling relationship inside the first-stage charge pump unit; the magnification selection module is configured to control the output magnification according to the needs The clock module outputs a corresponding clock sequence; wherein, the charge pump main module reorganizes the X first-stage charge pump units into Y second-stage charge pump units according to the received clock sequence, and Y is greater than or equal to 1 but a positive integer less than or equal to X, wherein for each integer or multiple of an integer, the Y second-stage charge pump units have the same equivalent capacitance value, or each of the second-stage charge pump units The number difference of the included first-stage charge pump units is less than or equal to 1.
特别的,在所述Y个第二级电荷泵单元具有相同的等效电容值的情况下,与所述电荷泵输入端耦合的第一个第一级电荷泵单元的电容值和与所述电荷泵输出端耦合的第X个第一级电荷泵单元的电容值为标准值,其他所述第一级电荷泵单元的电容值小于所述标准值。Specifically, in the case that the Y second-stage charge pump units have the same equivalent capacitance value, the sum of the capacitance value of the first first-stage charge pump unit coupled to the input terminal of the charge pump is the same as the The capacitance value of the Xth first-stage charge pump unit coupled to the output terminal of the charge pump is a standard value, and the capacitance values of the other first-stage charge pump units are smaller than the standard value.
特别的,所述电荷泵还包括输出电容,耦合在所述电荷泵的输出端和地电平之间。In particular, the charge pump further includes an output capacitor coupled between the output terminal of the charge pump and the ground level.
特别的,当所述电荷泵的最大或最小可实现倍率为n+1或1/(n+1),所述X个第一级电荷泵单元的总电容值之和等效于n个单位电容之和,i+1为实际需要的倍率且i为小于等于n的正整数,j为小于等于i的正整数,对于第j个第二级电荷泵单元来说,aij=n*j/i的整数部分加1代表第j个第二级电荷泵单元所在的单位电容序号,其分数部分代表在第j个第二级电荷泵单元所在的单位电容内的分割位置。In particular, when the maximum or minimum achievable rate of the charge pump is n+1 or 1/(n+1), the sum of the total capacitance values of the X first-stage charge pump units is equivalent to n units The sum of capacitors, i+1 is the actual required multiplier and i is a positive integer less than or equal to n, j is a positive integer less than or equal to i, for the jth second-stage charge pump unit, a ij =n*j The integer part of /i plus 1 represents the serial number of the unit capacitor where the j-th second-stage charge pump unit is located, and its fractional part represents the division position in the unit capacitor where the j-th second-stage charge pump unit is located.
特别的,每个所述第一级电荷泵单元包括一电容,其第一端通过第一开关耦合到前一个第一级电荷泵单元的输出端,并且所述电容的第一端通过第二开关耦合到下一个第一级电荷泵单元的输入端,所述电容的第二端通过第三开关耦合到所述电荷泵的输出端,所述电容的第二端通过第四开关耦合到地电平;其中所述时钟序列包括两个相反的时钟信号,被配置为分别控制所述第一至第四开关中的一个或多个。Particularly, each of the first-stage charge pump units includes a capacitor, the first end of which is coupled to the output end of the previous first-stage charge pump unit through the first switch, and the first end of the capacitor is connected through the second The switch is coupled to the input terminal of the next first-stage charge pump unit, the second terminal of the capacitor is coupled to the output terminal of the charge pump through the third switch, and the second terminal of the capacitor is coupled to the ground through the fourth switch level; wherein the clock sequence includes two opposite clock signals configured to respectively control one or more of the first to fourth switches.
本申请还提供了一种显示器,包括前述任一所述的电荷泵。The present application also provides a display, including the charge pump described above.
本申请还提供了一种闪存装置,包括前述任一所述的电荷泵。The present application also provides a flash memory device, including the charge pump described above.
本申请还提供了一种电源,包括前述任一所述的电荷泵。The present application also provides a power supply, including the charge pump described above.
本申请还提供了一种采用电荷泵调整电压的方法,其中所述电荷泵包括电荷泵主模块,时钟模块和倍率选择模块,所述方法包括所述倍率选择模块根据所需输出倍率控制时钟模块的产生相应的时钟序列;所述时钟模块在所述倍率选择模块的控制下,输出所述相应的时钟序列;所述电荷泵主模块根据所接收到的时钟序列将所述电荷泵主模块中的X个第一级电荷泵单元重组为Y个第二级电荷泵单元,Y为大于等于1但小于等于X的正整数,其中针对每个整数或整数分之一倍率,所述Y个第二级电荷泵单元具有相同的等效电容值,或者各个所述第二级电荷泵单元中所包含的第一级电荷泵单元的个数差小于等于1。The present application also provides a method for adjusting voltage using a charge pump, wherein the charge pump includes a charge pump main module, a clock module and a multiplier selection module, and the method includes that the multiplier selection module controls the clock module according to the required output ratio The corresponding clock sequence is generated; the clock module outputs the corresponding clock sequence under the control of the multiplier selection module; the charge pump main module outputs the The X first-stage charge pump units are reorganized into Y second-stage charge pump units, Y is a positive integer greater than or equal to 1 but less than or equal to X, wherein for each integer or one-integer multiple, the Y first The two-stage charge pump units have the same equivalent capacitance value, or the difference in the number of the first-stage charge pump units contained in each of the second-stage charge pump units is less than or equal to 1.
本申请还提供了一种利用电荷泵进行电压调整的方法,其中所述电荷泵包括电荷泵主模块,时钟模块和倍率选择模块,所述电荷泵主模块包括X个第一级电荷泵单元,每个所述第一级电荷泵单元具有相同的电容值,所述方法包括将所述X个第一级电荷泵单元分成两组,一组包括m个第二级电荷泵单元,另一组包括n个第二级电荷泵单元;其中所述m个第二级电荷泵单元中的每一个包括k个第一级电荷泵单元,所述n个第二级电荷泵单元中的每一个包括k-1个第一级电荷泵单元;如果X=1,停止所有操作,否则使X=X-1,将n个第二级电荷泵中的一个拆分为k-1个第一级电荷泵单元;当(n-1)≥(k-1)时,将所述k-1个第一级电荷泵单元插入n-1个由k-1个第一级电荷泵单元组成的第二级电荷泵单元中,从而形成两组新的第二级电荷泵单元,一组包括m+k-1个第二级电荷泵单元,该组中每个第二级电荷泵单元包括k个第一级电荷泵单元;另一组包括n-k个第二级电荷泵单元,该组每个第二级电荷泵单元包括k-1个第一级电荷泵单元;当(n-1)<(k-1)且(k-n)<m时,将所述k-1个第一级电荷泵单元插入n-1个由k-1个第一级电荷泵单元组成的第二级电荷泵单元以及k-n个由k个第一级电荷泵单元组成的第二级电荷泵单元中,从而形成两组新的第二级电荷泵单元,一组包括(n-1)+(m-(k-n))个第二级电荷泵单元,该组中每个第二级电荷泵单元包括k个第一级电荷泵单元;另一组包括k-n个第二级电荷泵单元,该组每个第二级电荷泵单元包括k+1个第一级电荷泵单元。The present application also provides a method for voltage adjustment using a charge pump, wherein the charge pump includes a charge pump main module, a clock module and a multiplier selection module, and the charge pump main module includes X first-stage charge pump units, Each of the first-stage charge pump units has the same capacitance value, the method includes dividing the X first-stage charge pump units into two groups, one group includes m second-stage charge pump units, and the other group Including n second-stage charge pump units; wherein each of the m second-stage charge pump units includes k first-stage charge pump units, and each of the n second-stage charge pump units includes k-1 first-stage charge pump units; if X=1, stop all operations, otherwise make X=X-1, split one of n second-stage charge pumps into k-1 first-stage charges pump unit; when (n-1)≥(k-1), insert the k-1 first-stage charge pump units into n-1 second charge pump units consisting of k-1 first-stage charge pump units In the first-stage charge pump unit, thereby forming two groups of new second-stage charge pump units, one group includes m+k-1 second-stage charge pump units, and each second-stage charge pump unit in this group includes k-th One-stage charge pump unit; another group includes n-k second-stage charge pump units, and each second-stage charge pump unit of this group includes k-1 first-stage charge pump units; when (n-1)<(k -1) and (k-n)<m, insert the k-1 first-stage charge pump units into n-1 second-stage charge pump units composed of k-1 first-stage charge pump units and k-n In a second-stage charge pump unit composed of k first-stage charge pump units, two new sets of second-stage charge pump units are formed, and one group includes (n-1)+(m-(k-n)) units The second-stage charge pump unit, each second-stage charge pump unit in this group includes k first-stage charge pump units; the other group includes k-n second-stage charge pump units, and each second-stage charge pump unit in this group The unit includes k+1 first-stage charge pump units.
本申请所提供的电荷泵以及利用这样的电荷泵进行电压调整的方法,针对所有的整数或整数分之一倍率都提供了等效电容值相同或者基本相同的电荷泵单元,针对特定的倍率来说,电荷泵的输出驱动能力提高33%或更高。The charge pump provided in the present application and the method for adjusting the voltage using such a charge pump provide charge pump units with the same or substantially the same equivalent capacitance for all integer or fractional multiples, and for specific multiples Say, the output drive capability of the charge pump is increased by 33% or more.
以下将参照附图对本申请的示例性实施例的详细描述。Hereinafter, a detailed description will be given of exemplary embodiments of the present application with reference to the accompanying drawings.
附图说明Description of drawings
参考附图示出并阐明实施例。这些附图用于阐明基本原理,从而仅仅示出了对于理解基本原理必要的方面。这些附图不是按比例的。在附图中,相同的附图标记表示相似的特征。Embodiments are shown and explained with reference to the figures. The figures serve to clarify the basic principles and thus only show the aspects which are necessary for understanding the basic principles. The drawings are not to scale. In the drawings, the same reference numerals denote similar features.
图1所示为根据本申请一个实施例的电荷泵结构模块示意图;FIG. 1 is a schematic diagram of a charge pump structure module according to an embodiment of the present application;
图2所示为根据本申请一个实施例的电荷泵主模块结构示意图;FIG. 2 is a schematic structural diagram of a charge pump main module according to an embodiment of the present application;
图3a-图3d所示为图2所示的电荷泵主模块的工作状态示意图;Figures 3a-3d are schematic diagrams of the working state of the main module of the charge pump shown in Figure 2;
图4所示为用于本申请实施例的时钟信号示意图;FIG. 4 is a schematic diagram of a clock signal used in an embodiment of the present application;
图5所示为根据本申请一个实施例构造全倍率电荷泵的方法流程图;FIG. 5 shows a flowchart of a method for constructing a full rate charge pump according to an embodiment of the present application;
图6所示为根据本申请一个实施例构造全倍率电荷泵的状态图;FIG. 6 shows a state diagram of constructing a full rate charge pump according to one embodiment of the present application;
图7所示为根据本申请一个实施例的最小倍率为1/7的电荷泵电路的结构示意图;FIG. 7 is a schematic structural diagram of a charge pump circuit with a minimum magnification of 1/7 according to an embodiment of the present application;
图8a-图8d所示为根据本申请另一实施例的电荷泵主模块的工作状态示意图;8a-8d are schematic diagrams showing the working state of the main module of the charge pump according to another embodiment of the present application;
图9所示为根据本申请一个实施例的针对不同倍率电荷泵中电荷泵单元重新组合的方案列表;以及FIG. 9 shows a scheme list for recombination of charge pump units in charge pumps with different rates according to an embodiment of the present application; and
图10所示为根据本申请一个实施例的利用电荷泵进行电压调整的方法。FIG. 10 shows a method for voltage regulation using a charge pump according to an embodiment of the present application.
具体实施方式Detailed ways
以下将参照附图来详细描述本申请的各示例性实施例。应注意的是,除非另外具体说明,否则在这些实施例中阐述的部件和步骤的相对布置、数字表达式和数值不限制本申请的范围。Exemplary embodiments of the present application will be described in detail below with reference to the accompanying drawings. It should be noted that the relative arrangements of components and steps, numerical expressions and numerical values set forth in these embodiments do not limit the scope of the present application unless specifically stated otherwise.
以下对至少一个示例性实施例的描述实际上仅仅是说明性的,而不是作为对本申请及其应用或使用的任何限制。The following description of at least one exemplary embodiment is merely illustrative in nature and not intended as any limitation of the application, its application or uses.
对于相关领域普通技术人员已知的技术、方法和设备可能不作详细讨论,但在适当情况下,所述技术、方法和设备应当被视为说明书的一部分。Techniques, methods and devices known to those of ordinary skill in the relevant art may not be discussed in detail, but where appropriate, such techniques, methods and devices should be considered part of the description.
在这里示出和讨论的所有例子中,任何具体值应被解释为仅仅是示例性的,而不是作为限制。因此,示例性实施例的其它例子可以具有不同的值。In all examples shown and discussed herein, any specific values should be construed as exemplary only, and not as limitations. Therefore, other instances of the exemplary embodiment may have different values.
应注意的是,相似的标号和字母在下面的附图中表示类似项,因此,一旦某一项在一个附图中被定义,则在随后的附图中不需要对其进行进一步讨论。It should be noted that like numerals and letters denote like items in the following figures, therefore, once an item is defined in one figure, it does not require further discussion in subsequent figures.
对于N级Dickson电荷泵,i为大于等于1而小于等于N的正整数,Ci为第i级电荷泵单元的电容值,f为电荷泵工作频率,IL为电荷泵输出电流,电荷泵的内阻Rssl,则输出电压VOUT可以表示为:For an N-stage Dickson charge pump, i is a positive integer greater than or equal to 1 and less than or equal to N, C i is the capacitance value of the i-th charge pump unit, f is the operating frequency of the charge pump, IL is the output current of the charge pump, and the charge pump internal resistance R ssl , the output voltage V OUT can be expressed as:
其中电荷泵的内阻Rssl和输出电流IL分别可以表示为where the internal resistance R ssl and the output current I L of the charge pump can be expressed as
电荷泵的总电容值可以通过以下公式来表达,The total capacitance value of the charge pump can be expressed by the following formula,
根据均值不等式,在输出电压和频率一定的情况下,当且仅当所有电荷泵单元的电容均等时,即C1=C2=…=CN,输出电流IL最大:According to the mean value inequality, when the output voltage and frequency are constant, if and only if the capacitances of all charge pump units are equal, that is, C 1 =C 2 =...=C N , the output current I L is the largest:
现有做法是将N个电荷泵单元的电容值设为相同,当电荷泵由N倍或1/N倍切换成另一个倍率时,现有的设置方法是简单地把其他的电荷泵单元的电容分配给例如第一个电荷泵单元,合并后的第一个电荷泵单元的电容值会比其他电荷泵单元大很多,而电荷泵的驱动能力就因此会受到影响,并且这样的设置很容易导致第一个电荷泵单元充放电不完全(因为RC过大),很可能限制电荷泵的整体工作频率而导致较低的驱动能力。The existing practice is to set the capacitance values of N charge pump units to be the same. When the charge pump is switched from N times or 1/N times to another multiplier, the existing setting method is to simply set the capacitor values of other charge pump units Capacitors are allocated to, for example, the first charge pump unit, and the capacitance value of the combined first charge pump unit will be much larger than that of other charge pump units, and the drive capability of the charge pump will be affected accordingly, and such a setting is easy Incomplete charging and discharging of the first charge pump unit (because RC is too large) may limit the overall operating frequency of the charge pump and result in lower drive capability.
为了克服上述问题,本申请公开的电荷泵及利用电荷泵调整电压的方法在实现全倍率、充分利用片上电容的同时,还提供了更好的输出驱动能力。In order to overcome the above problems, the charge pump disclosed in the present application and the method for adjusting voltage by using the charge pump provide better output driving capability while realizing full rate and making full use of the on-chip capacitance.
图1所示为电荷泵的模块示意图。其中,电荷泵100可以包括倍率选择模块102被配置接收输入信号,产生输出信号相对于输入信号的倍率,还根据该倍率产生控制信号,以控制时钟模块选择相应的时钟序列。时钟模块104被配置为在倍率选择模块102的控制下选择相应的时钟序列,从而控制电荷泵主模块106中各个开关的开合状态。电荷泵100还包括电荷泵主模块106其中包括多个电荷泵单元,电荷泵单元中包括电容以及开关阵列,每个电荷泵单元内部包括开关,在每个电荷泵单元之间也包括开关。这些开关的开合状态被从所述时钟模块104接收到的时钟序列所控制。Figure 1 shows the block diagram of the charge pump. Wherein, the charge pump 100 may include a multiplier selection module 102 configured to receive an input signal, generate a multiplier of the output signal relative to the input signal, and generate a control signal according to the multiplier, so as to control the clock module to select a corresponding clock sequence. The clock module 104 is configured to select a corresponding clock sequence under the control of the multiplier selection module 102 , so as to control the on-off state of each switch in the charge pump main module 106 . The charge pump 100 also includes a charge pump main module 106 which includes a plurality of charge pump units. The charge pump units include capacitors and switch arrays. Each charge pump unit includes switches inside and switches between each charge pump unit. The opening and closing states of these switches are controlled by the clock sequence received from the clock module 104 .
图2为根据本申请一个实施例的降压型电荷泵部分结构示意图。图2示出了电荷泵主模块和输出电容CL。根据一个实施例,该电荷泵的最大输出倍率为5倍或1/5倍。在这个实施例中,电荷泵主模块包括六个电荷泵单元,并且从输入端到输出端的方向上各电荷泵单元包括的电容值分别是C,1/3C,2/3C,2/3C,和C,其中C代表单元电容值。每个电荷泵单元中电容的下极板都分别通过开关耦合到输出电压VOUT和地电平;相邻电荷泵单元中电容的上极板通过开关彼此耦合。第一个(也就是最靠近输入端的)电荷泵单元的电容的上极板还通过开关耦合到电荷泵的输入端用于接收输入信号例如VDD。第六个(也就是最靠近输出端的)电荷泵单元的上极板还耦合到输出电容CL的上极板以及电荷泵输出端。输出电容CL的下极板耦合到地电平。FIG. 2 is a schematic diagram of a partial structure of a step-down charge pump according to an embodiment of the present application. Figure 2 shows the charge pump main block and output capacitor C L . According to one embodiment, the maximum output ratio of the charge pump is 5 times or 1/5 times. In this embodiment, the charge pump main module includes six charge pump units, and the capacitance values included in each charge pump unit in the direction from the input end to the output end are C, 1/3C, 2/3C, 2/3C, and C, where C represents the cell capacitance value. The lower plates of the capacitors in each charge pump unit are respectively coupled to the output voltage V OUT and the ground level through switches; the upper plates of the capacitors in adjacent charge pump units are coupled to each other through switches. The upper plate of the capacitor of the first (ie, closest to the input) charge pump cell is also coupled via a switch to the input of the charge pump for receiving an input signal such as V DD . The upper plate of the sixth (ie, closest to the output) charge pump cell is also coupled to the upper plate of the output capacitor CL and to the charge pump output. The lower plate of output capacitor CL is coupled to ground level.
值得注意的是,虽然本申请作为示例性说明的例子可能是降压型电荷泵。但是本领域技术人员知晓,基于本申请所公开的技术方案可以在不付出创造性劳动的情况下实现相应的升压型电荷泵。It should be noted that although the example described in this application may be a step-down charge pump. However, those skilled in the art know that based on the technical solution disclosed in the present application, the corresponding boost charge pump can be realized without creative effort.
图3a-图3d所示为图2所示的电荷泵部分结构工作在不同输出倍率下的工作状态示意图。图4为用于图2所示的电荷泵的时钟序列示意图。FIG. 3a-FIG. 3d are schematic diagrams of the working state of the part structure of the charge pump shown in FIG. 2 working at different output ratios. FIG. 4 is a schematic diagram of a clock sequence for the charge pump shown in FIG. 2 .
图3a所示为图2所示的电荷泵部分结构工作在输出倍率为1/5的工作模式的状态示意图。可以采用图4所示的两个时钟信号Φ1和Φ2对电荷泵单元内部以及电荷泵单元之间的开关状态进行控制。FIG. 3a is a schematic diagram showing the state of the part of the structure of the charge pump shown in FIG. 2 working in the working mode with an output ratio of 1/5. Two clock signals Φ 1 and Φ 2 shown in FIG. 4 can be used to control the switching states inside the charge pump unit and between the charge pump units.
根据一个实施例,本实施例中的电荷泵主模块包括6个电荷泵单元和一个输出电容CL。时钟信号Φ1控制着输入端与第一电荷泵单元之间的开关S1、第三电荷泵单元与第四电荷泵单元之间的开关S4、和第六电荷泵单元与输出端之间的开关S7的状态;Φ1还控制着第一和第四以及第五电荷泵单元与输出电压VOUT之间的开关S8、S14和S16的状态,以及第二、第三和第六电荷泵单元与地电平之间的开关S11、S13和S19的状态。According to an embodiment, the charge pump main module in this embodiment includes 6 charge pump units and an output capacitor C L . The clock signal Φ 1 controls the switch S 1 between the input terminal and the first charge pump unit, the switch S 4 between the third charge pump unit and the fourth charge pump unit, and the switch S 4 between the sixth charge pump unit and the output terminal The state of the switch S 7 ; Φ 1 also controls the state of the switches S 8 , S 14 and S 16 between the first and fourth and fifth charge pump units and the output voltage V OUT , and the states of the second, third and States of switches S 11 , S 13 and S 19 between the sixth charge pump unit and ground.
根据一个实施例,Φ2控制着第一电荷泵单元与第二电荷泵之间的开关S2的状态,以及第五电荷泵单元与第六电荷泵单元之间的开关S6的状态;Φ2还控制着第一、第四和第五电荷泵单元与地电平之间的开关S9、S15和S17的状态,以及第二、第三和第六电荷泵单元与输出电压VOUT之间的开关S10、S12和S18的状态。According to one embodiment, Φ2 controls the state of switch S2 between the first charge pump unit and the second charge pump unit, and the state of switch S6 between the fifth charge pump unit and the sixth charge pump unit ; Φ 2 also controls the state of the switches S9 , S15 and S17 between the first, fourth and fifth charge pump units and the ground level, and the connection between the second, third and sixth charge pump units and the output voltage V The state of switches S 10 , S 12 and S 18 between OUT .
根据一个实施例,第二与第三电荷泵单元之间的开关S3,以及第四与第五电荷泵单元之间的开关S5都被设为恒导通状态,或者说是在有效电平(例如高电平)的控制下这两个开关始终导通。According to one embodiment, the switch S 3 between the second and the third charge pump unit, and the switch S 5 between the fourth and the fifth charge pump unit are all set to a constant conduction state, or in other words, at an effective voltage These two switches are always turned on under the control of level (for example, high level).
根据一个实施例,如图4所示,Φ1和Φ2为有效电平例如高电平不交叠的两个时钟信号。According to an embodiment, as shown in FIG. 4 , Φ 1 and Φ 2 are two clock signals whose active levels, such as high levels, do not overlap.
根据一个的实施例,当Φ1=1Φ2=0的时候,开关S1和S8导通、开关S2和S9断开,第一电荷泵单元的电容C1被输入电压VDD充电到VDD-VOUT。According to one embodiment, when Φ 1 =1 Φ 2 =0, the switches S 1 and S 8 are turned on, the switches S 2 and S 9 are turned off, and the capacitor C 1 of the first charge pump unit is charged by the input voltage V DD to V DD -V OUT .
当Φ1=0Φ2=1的时候,开关S2导通,第一电荷泵单元的电容C1放电。开关S10和S12导通、开关S11和S13断开,由于开关S3恒导通,第二、第三电荷泵单元的电容C2和C3并联,等效电容值为C,并被充电至VDD-2VOUT。When Φ 1 =0 and Φ 2 =1, the switch S 2 is turned on, and the capacitor C 1 of the first charge pump unit is discharged. The switches S10 and S12 are turned on, and the switches S11 and S13 are turned off. Since the switch S3 is always turned on, the capacitors C2 and C3 of the second and third charge pump units are connected in parallel, and the equivalent capacitance value is C, and is charged to V DD -2V OUT .
当再一次Φ1=1Φ2=0的时候,开关S4导通,第二、第三电荷泵单元中的电容C2和C3一起放电。开关S14和S16导通、开关S15和S17断开,由于开关S5恒导通,第四、第五电荷泵单元的电容C4和C5并联,等效电容值为C,并被充电至VDD-3VOUT。When Φ 1 =1 Φ 2 =0 again, the switch S 4 is turned on, and the capacitors C 2 and C 3 in the second and third charge pump units are discharged together. The switches S14 and S16 are turned on, and the switches S15 and S17 are turned off. Since the switch S5 is always turned on, the capacitors C4 and C5 of the fourth and fifth charge pump units are connected in parallel, and the equivalent capacitance value is C, and is charged to V DD -3V OUT .
当再一次Φ1=0Φ2=1的时候,开关S6导通,第四和第五电荷泵单元中的电容C4和C5一起放电,开关S18导通,开关S19断开,第六电荷泵单元的电容C6被充电至VDD-4VOUT。When Φ 1 =0 Φ 2 =1 again, the switch S 6 is turned on, the capacitors C 4 and C 5 in the fourth and fifth charge pump units are discharged together, the switch S 18 is turned on, and the switch S 19 is turned off, The capacitor C 6 of the sixth charge pump unit is charged to V DD −4V OUT .
当再一次Φ1=1Φ2=0的时候,开关S7导通,第六电荷泵单元的电容C6向输出电容CL放电,并向输出端提供输出信号VDD-4VOUT=VOUT。因此可知,VOUT=1/5VDD。When Φ 1 =1 Φ 2 =0 again, the switch S 7 is turned on, the capacitor C 6 of the sixth charge pump unit discharges to the output capacitor CL , and provides an output signal V DD -4V OUT =V OUT to the output terminal . Therefore, it can be seen that V OUT =1/5V DD .
在这个实施例中,由六个第一级电容C1至C6重新组合而成的第二级电容C1,C2+C3,C4+C5,C6的等效电容值都为C。根据前述的理论,在1/5倍率下,电荷泵各单元的电容值相等,因此实现了最大输出驱动能力。In this embodiment, the equivalent capacitance values of the second-stage capacitor C1, C 2 +C 3 , C 4 +C 5 , and C 6 formed by recombining the six first-stage capacitors C 1 to C 6 are c. According to the aforementioned theory, under 1/5 magnification, the capacitance values of each unit of the charge pump are equal, thus realizing the maximum output driving capability.
图3b所示为图2所示的电荷泵部分结构工作在输出倍率为1/4的工作模式的状态示意图。同样可以采用图4所示的两个时钟信号Φ1和Φ2对电荷泵单元内部以及电荷泵单元之间的开关状态进行控制。FIG. 3b is a schematic diagram showing the state of the part of the structure of the charge pump shown in FIG. 2 working in an operating mode with an output ratio of 1/4. Similarly, the two clock signals Φ1 and Φ2 shown in FIG. 4 can be used to control the switching states inside the charge pump unit and between the charge pump units.
根据一个实施例,Φ1控制着电荷泵单元之间的开关S1和S5的状态;Φ1还控制着电荷泵单元内部开关S8、S10、S13、S15、S16和S18的状态。Φ2控制着电荷泵单元之间的开关S3和S7的状态;Φ2还控制着电荷泵单元内部开关S9、S11、S12、S14、S17和S19的状态。According to one embodiment, Φ 1 controls the state of switches S 1 and S 5 between the charge pump units; Φ 1 also controls the internal switches S 8 , S 10 , S 13 , S 15 , S 16 and S 18 status. Φ 2 controls the state of switches S 3 and S 7 between the charge pump units; Φ 2 also controls the states of switches S 9 , S 11 , S 12 , S 14 , S 17 and S 19 inside the charge pump unit.
根据一个实施例,第一与第二电荷泵单元之间的开关S2,第三和第四电荷泵单元之间的开关S4,以及第五和第六电荷泵单元之间的开关S6都被设为恒导通状态,或者说是在有效电平(例如高电平)的控制下这两个开关始终导通。According to one embodiment, the switch S 2 between the first and second charge pump unit, the switch S 4 between the third and fourth charge pump unit, and the switch S 6 between the fifth and sixth charge pump unit Both are set to a constant conduction state, or in other words, these two switches are always on under the control of an active level (such as a high level).
根据一个实施例,如图4所示,Φ1和Φ2为有效电平例如高电平不交叠的两个时钟信号。According to an embodiment, as shown in FIG. 4 , Φ 1 and Φ 2 are two clock signals whose active levels, such as high levels, do not overlap.
根据一个的实施例,当Φ1=1Φ2=0的时候,开关S1、S8和S10导通、开关S3、S9和S11断开。由于开关S2恒导通,第一、第二电荷泵单元的电容C1和C2并联,等效电容值为(1+1/3)C,被充电至VDD-VOUT。According to an embodiment, when Φ 1 =1 Φ 2 =0, the switches S 1 , S 8 and S 10 are turned on, and the switches S 3 , S 9 and S 11 are turned off. Since the switch S 2 is always turned on, the capacitors C 1 and C 2 of the first and second charge pump units are connected in parallel, and the equivalent capacitance value is (1+1/3)C, which is charged to V DD -V OUT .
当Φ1=0Φ2=1的时候,开关S3导通,第一和第二电荷泵单元的电容C1和C2放电。开关S12和S14导通、开关S13和S15断开,由于开关S4恒导通,第三、第四电荷泵单元的电容C3和C4并联,等效电容值为(1+1/3)C,并被充电至VDD-2VOUT。When Φ 1 =0 Φ 2 =1, the switch S 3 is turned on, and the capacitors C 1 and C 2 of the first and second charge pump units are discharged. The switches S12 and S14 are turned on, and the switches S13 and S15 are turned off. Since the switch S4 is always turned on, the capacitors C3 and C4 of the third and fourth charge pump units are connected in parallel, and the equivalent capacitance value is (1 +1/3)C and is charged to V DD -2V OUT .
当再一次Φ1=1Φ2=0的时候,开关S5导通,第三、第四电荷泵单元中的电容C3和C4一起放电。开关S16和S18导通、开关S17和S19断开,由于开关S5恒导通,第五、第六电荷泵单元的电容C5和C6并联,等效电容值为(1+1/3)C,并被充电至VDD-3VOUT。When Φ 1 =1 Φ 2 =0 again, the switch S 5 is turned on, and the capacitors C 3 and C 4 in the third and fourth charge pump units are discharged together. The switches S16 and S18 are turned on, and the switches S17 and S19 are turned off. Since the switch S5 is constantly turned on, the capacitors C5 and C6 of the fifth and sixth charge pump units are connected in parallel, and the equivalent capacitance value is (1 +1/3)C and is charged to V DD -3V OUT .
当再一次Φ1=0Φ2=1的时候,开关S7导通,第五和第六电荷泵单元的电容C5和C6向输出电容CL放电,并向输出端提供输出信号VDD-3VOUT=VOUT。因此可知,VOUT=1/4VDD。When Φ 1 =0 Φ 2 =1 again, the switch S 7 is turned on, the capacitors C 5 and C 6 of the fifth and sixth charge pump units discharge to the output capacitor CL , and provide the output signal V DD to the output terminal -3V OUT =V OUT . Therefore, it can be seen that V OUT =1/4V DD .
在这个实施例中,由C1+C2,C3+C4,C5+C6这三个由第一级电容C1-C6重新组合而成的第二级电容的等效电容值都为(1+1/3)C。根据前述的理论,这样的安排可以实现电荷泵最大输出电流。In this embodiment, the equivalent capacitance of the second-stage capacitor formed by C 1 +C 2 , C 3 +C 4 , and C 5 +C 6 is recombined by the first-stage capacitor C 1 -C 6 The values are all (1+1/3)C. According to the aforementioned theory, such an arrangement can realize the maximum output current of the charge pump.
类似的,图3c和图3d所示为图2中的电荷泵部分结构在实现1/3和1/2倍率情况下的工作状态图。在图3c中,由C1+C2+C3和C4+C5+C6重新组合成两个第二级电容,每个第二级电容的等效电容值为2C。在图3d中,由C1+C2+C3+C4+C5+C6重新组合成一个第二级电容,其等效电容值为4C。Similarly, Fig. 3c and Fig. 3d show the working status diagrams of the part structure of the charge pump in Fig. 2 in the case of realizing 1/3 and 1/2 magnification. In FIG. 3c, C 1 +C 2 +C 3 and C 4 +C 5 +C 6 are recombined into two second-stage capacitors, and the equivalent capacitance value of each second-stage capacitor is 2C. In Figure 3d, C 1 +C 2 +C 3 +C 4 +C 5 +C 6 are recombined to form a second-stage capacitor with an equivalent capacitance of 4C.
本申请中采用了降压型电荷泵来进行阐述。本领域普通技术人员可以基于本申请所公开的信息实现升压型电荷泵。In this application, a step-down charge pump is used for illustration. A person skilled in the art can implement a boost charge pump based on the information disclosed in this application.
由此可见,采用本申请实施例中的电荷泵,在实现所有整数倍率的同时,保证了与特定倍率相对应的各二级电荷泵单元的等效电容值相同,从而使电荷泵在各倍率下都能达到最大的输出驱动能力。It can be seen that, by using the charge pump in the embodiment of the present application, while realizing all integer multiples, it is ensured that the equivalent capacitance values of each secondary charge pump unit corresponding to a specific multiple are the same, so that the charge pump can operate at each multiple can achieve the maximum output drive capability.
图5所示为根据本申请一实施例的一种构造全倍率电荷泵的方法。在本实施例中的电荷泵可以实现最大1/(n+1)的输出倍率,其中n为大于等于1的正整数。FIG. 5 shows a method for constructing a full-rate charge pump according to an embodiment of the present application. The charge pump in this embodiment can achieve a maximum output magnification of 1/(n+1), where n is a positive integer greater than or equal to 1.
在步骤502,设置n个电荷泵单元,其中每个电荷泵单元包括的电容值相同。In step 502, n charge pump units are set, wherein each charge pump unit includes the same capacitance value.
在步骤504,对除第1和第n个电荷泵单元外的电荷泵单元中的电容进行分割,其中分割点为aij=n*j/i,其中i为实际所需要实现的电荷泵级数(其对应倍率可以为例如1/(i+1)),i为大于等于1小于等于n的正整数,j为大于等于1小于等于i的正整数,aij的整数部分与要分割的电容序号相关,例如aij的整数部分加1为待分割的电容序号。aij的分数部分与分割点在待分割电容中的位置相关,例如代表着在该待分割电容中的位置点。In step 504, the capacitors in the charge pump units except the 1st and nth charge pump units are divided, wherein the division point is a ij =n*j/i, where i is the actual charge pump stage that needs to be realized number (the corresponding multiplier can be, for example, 1/(i+1)), i is a positive integer greater than or equal to 1 and less than or equal to n, j is a positive integer greater than or equal to 1 and less than or equal to i, and the integer part of a ij is the same as the The serial number of the capacitor is related, for example, adding 1 to the integer part of a ij is the serial number of the capacitor to be divided. The fraction of a ij is related to the position of the division point in the capacitor to be divided, for example, it represents the position point in the capacitor to be divided.
图6为图5所示方法针对不同的倍率进行电容分割的示意图。当要输出的倍率为最大或最小输出倍率n+1或者1/(n+1)的时候,an,j=n*j/n,j为大于等于1小于等于n的正整数,电荷泵恰好有n个电荷泵单元,因此不必对各电荷泵单元中的电容进行分割。当所需要的输出倍率为n或者1/n的时候,an-1,j=n*j/(n-1),j为大于等于1小于等于n-1的正整数,可以按照这个规律根据所需倍率逐级调节对标准电荷泵单元的分割。FIG. 6 is a schematic diagram of the method shown in FIG. 5 performing capacitance division for different magnifications. When the magnification to be output is the maximum or minimum output magnification n+1 or 1/(n+1), a n,j =n*j/n, j is a positive integer greater than or equal to 1 and less than or equal to n, the charge pump There are exactly n charge pump units, so it is not necessary to divide the capacitors in each charge pump unit. When the required output magnification is n or 1/n, a n-1, j = n*j/(n-1), j is a positive integer greater than or equal to 1 and less than or equal to n-1, which can be based on this rule The required multiplier stepwise adjusts the division of standard charge pump cells.
图7为图5所示的方法在n=6的情况下对电容进行分割的示意图。当i=6的时候,不必对6个电荷泵单元中的电容进行分割。FIG. 7 is a schematic diagram of dividing the capacitance by the method shown in FIG. 5 under the condition of n=6. When i=6, it is not necessary to divide the capacitors in the six charge pump units.
当i=5的时候,a5,j分别为6/5,12/5,18/5,24/5和6,意味着在第2电荷泵单元的电容的1/5处、在第3电荷泵单元的电容的2/5处、在第4电荷泵单元的电容的3/5处,在第5电荷泵单元的电容的4/5处进行分割。When i=5, a 5, j are 6/5, 12/5, 18/5, 24/5 and 6 respectively, which means that at 1/5 of the capacitance of the second charge pump unit, at the third The division is performed at 2/5 of the capacitance of the charge pump unit, at 3/5 of the capacitance of the fourth charge pump unit, and at 4/5 of the capacitance of the fifth charge pump unit.
当i=4的时候,a4,j分别为3/2,3,9/2,和6,意味着在第2电荷泵单元的电容的1/2处和第5电荷泵单元的电容的1/2处进行分割。When i=4, a 4, j are 3/2, 3, 9/2, and 6 respectively, which means that at 1/2 of the capacitance of the second charge pump unit and at the capacitance of the fifth charge pump unit 1/2 for splitting.
当i=3的时候,a3,j分别为2,4,和6,不需要对电荷泵单元的电容进行分割。When i=3, a 3, j are 2, 4, and 6 respectively, and there is no need to divide the capacitance of the charge pump unit.
当i=2的时候,a2,j分别为3和6,不需要对电荷泵单元的电容进行分割。When i=2, a 2 and j are 3 and 6 respectively, and there is no need to divide the capacitance of the charge pump unit.
综上所述,为了利用图6所示的电荷泵实现1至7或1至1/7的倍率,第2电荷泵单元的电容需要被分割2次,分割点为该电容的1/5和1/2处;第3电荷泵单元的电容需要被分割1次,分割点为该电容的2/5处;第4电荷泵单元的电容需要被分割1次,分割点为该电容的3/5处;第5电荷泵单元的电容需要被分割2次,分割点为该电容的1/2和4/5处;第1和第6电荷泵单元的电容不需要被分割。To sum up, in order to use the charge pump shown in Figure 6 to achieve a magnification of 1 to 7 or 1 to 1/7, the capacitance of the second charge pump unit needs to be divided twice, and the division point is 1/5 of the capacitance and 1/2; the capacitance of the third charge pump unit needs to be divided once, and the division point is 2/5 of the capacitance; the capacitance of the fourth charge pump unit needs to be divided once, and the division point is 3/5 of the capacitance 5 places; the capacitor of the fifth charge pump unit needs to be divided twice, and the division points are 1/2 and 4/5 of the capacitor; the capacitors of the first and sixth charge pump units do not need to be divided.
所以,为了实现上述所有的倍率,在电荷泵主模块的设计中,一共需要设置12个小电容,电容值比例依次为:1,1/5,3/10,1/2,2/5,3/5,3/5,2/5,1/2,3/10,1/5,1。这些电容可以被称为第一级电容,包含这12个小电容的电荷泵单元可以被称为第一级电荷泵单元。根据上述实施例,针对所需要实现的不同倍率,可以对这些第一级电荷泵单元进行组合形成等效电容值相同的第二级电荷泵单元,从而保证电荷泵在各倍率下都具有最大的输出驱动能力。Therefore, in order to achieve all the above multipliers, in the design of the main module of the charge pump, a total of 12 small capacitors need to be set, and the ratios of the capacitor values are: 1, 1/5, 3/10, 1/2, 2/5, 3/5, 3/5, 2/5, 1/2, 3/10, 1/5, 1. These capacitors may be referred to as first-stage capacitors, and the charge pump unit including these 12 small capacitors may be referred to as a first-stage charge pump unit. According to the above-mentioned embodiment, according to the different magnifications that need to be realized, these first-stage charge pump units can be combined to form a second-stage charge pump unit with the same equivalent capacitance value, so as to ensure that the charge pump has the maximum performance at each magnification. output drive capability.
图8a-图8d所示为图1所示的电荷泵的另一个实施例在不同输出倍率下的工作状态示意图。在本实施例中,电荷泵主模块中的每个电荷泵单元具有相同的电容。与传统的电荷泵不同的是,在变换输出倍率的时候,为了实现尽可能大的输出驱动能力,倍率选择模块会通过计算使得重新组合后的第二级电荷泵单元的电容值尽量平均。8a-8d are schematic diagrams showing the working states of another embodiment of the charge pump shown in FIG. 1 at different output ratios. In this embodiment, each charge pump unit in the charge pump main module has the same capacitance. Different from the traditional charge pump, when changing the output ratio, in order to achieve the largest possible output drive capability, the ratio selection module will make the capacitance value of the recombined second-stage charge pump unit as average as possible through calculation.
图8a所示为本实施例的电荷泵部分结构工作在输出倍率为1/5的工作状态示意图。可以采用图4所示的两个时钟信号Φ1和Φ2对电荷泵单元内部以及电荷泵单元之间的开关状态进行控制。据一个实施例,本实施例中的电荷泵主模块包括4个电荷泵单元和一个输出电容CL。由于电荷泵主模块的四个电荷泵单元本来电容值就是相等的,因此在实现1/5倍率的情况下不需要对电荷泵单元进行重新组合就可以实现最大输出驱动能力。FIG. 8 a is a schematic diagram of the working state of the part of the structure of the charge pump in this embodiment working at an output ratio of 1/5. Two clock signals Φ 1 and Φ 2 shown in FIG. 4 can be used to control the switching states inside the charge pump unit and between the charge pump units. According to an embodiment, the charge pump main module in this embodiment includes 4 charge pump units and an output capacitor C L . Since the capacitance values of the four charge pump units of the charge pump main module are equal, the maximum output driving capability can be achieved without recombining the charge pump units in the case of realizing a 1/5 multiplier.
图8b所示为本实施例的电荷泵部分结构工作在输出倍率为1/4的工作模式的状态示意图。FIG. 8 b is a schematic diagram showing the state of the charge pump part structure of this embodiment working in the working mode with an output ratio of 1/4.
根据一个实施例,时钟信号Φ1控制着输入端与第一电荷泵单元之间的开关S1、第三电荷泵单元与第四电荷泵单元之间的开关S4的状态;Φ1还控制着第一、第二和第四电荷泵单元与输出电压VOUT之间的开关S6、S8和S12的状态,以及第三电荷泵单元与地电平之间的开关S11的状态。According to one embodiment, the clock signal Φ 1 controls the state of the switch S 1 between the input terminal and the first charge pump unit, the switch S 4 between the third charge pump unit and the fourth charge pump unit; Φ 1 also controls The states of the switches S6 , S8 and S12 between the first, second and fourth charge pump units and the output voltage VOUT , and the state of the switch S11 between the third charge pump unit and the ground level .
根据一个实施例,Φ2控制着第二电荷泵单元与第三电荷泵之间的开关S3的状态,以及第四电荷泵单元与输出端之间的开关S5的状态;Φ2还控制着第一、第二和第四电荷泵单元与地电平之间的开关S7、S9和S13的状态,以及第三电荷泵单元与输出电压VOUT之间的开关S10的状态。According to one embodiment, Φ2 controls the state of switch S3 between the second charge pump unit and the third charge pump, and the state of switch S5 between the fourth charge pump unit and the output ; Φ2 also controls The state of switches S7, S9 and S13 between the first, second and fourth charge pump units and ground level, and the state of switch S10 between the third charge pump unit and the output voltage VOUT .
根据一个实施例,第一与第二电荷泵单元之间的开关S2被设为恒导通状态,或者说是在有效电平(例如高电平)的控制下这个开关始终导通。According to one embodiment, the switch S2 between the first and second charge pump units is set to a constant conduction state, or in other words, the switch is always turned on under the control of an active level (eg high level).
根据一个实施例,如图4所示,Φ1和Φ2为有效电平例如高电平不交叠的两个时钟信号。According to an embodiment, as shown in FIG. 4 , Φ 1 and Φ 2 are two clock signals whose active levels, such as high levels, do not overlap.
根据一个的实施例,当Φ1=1Φ2=0的时候,开关S1导通、开关S7和S9断开,由于开关S2恒导通,第一和第二电荷泵单元的电容C1和C2并联,并且被输入电压VDD充电到VDD-VOUT。According to one embodiment, when Φ 1 =1 Φ 2 =0, the switch S 1 is turned on, and the switches S 7 and S 9 are turned off. Since the switch S 2 is always turned on, the capacitances of the first and second charge pump units C 1 and C 2 are connected in parallel and are charged to V DD -V OUT by the input voltage V DD .
当Φ1=0Φ2=1的时候,开关S3导通,第一和第二电荷泵单元的电容C1和C2放电。开关S3和S10导通、开关S11断开,第三电荷泵单元的电容C3被充电至VDD-2VOUT。When Φ 1 =0 Φ 2 =1, the switch S 3 is turned on, and the capacitors C 1 and C 2 of the first and second charge pump units are discharged. The switches S 3 and S 10 are turned on, the switch S 11 is turned off, and the capacitor C 3 of the third charge pump unit is charged to V DD -2V OUT .
当再一次Φ1=1Φ2=0的时候,开关S4导通,C3放电。开关S12导通、开关S13断开,C4被充电至VDD-3VOUT。When Φ 1 =1 Φ 2 =0 again, switch S 4 is turned on, and C 3 discharges. Switch S 12 is turned on, switch S 13 is turned off, and C 4 is charged to V DD -3V OUT .
当再一次Φ1=0Φ2=1的时候,开关S5导通,第四电荷泵单元的电容C4向输出电容CL放电,并向输出端提供输出信号VDD-3VOUT=VOUT。因此可知,VOUT=1/4VDD。When Φ 1 =0 Φ 2 =1 again, the switch S 5 is turned on, the capacitor C 4 of the fourth charge pump unit discharges to the output capacitor CL , and provides an output signal V DD -3V OUT =V OUT to the output terminal . Therefore, it can be seen that V OUT =1/4V DD .
在这个实施例中,由包括C1和C2第一和第二电荷泵单元被重新组合为第二级的电荷泵单元,但是包括C3和C4的第一级电荷泵单元未经组合。In this embodiment, the first and second charge pump cells consisting of C1 and C2 are recombined as charge pump cells of the second stage, but the charge pump cells of the first stage consisting of C3 and C4 are not combined .
图8c所示为本实施例的电荷泵部分结构工作在输出倍率为1/3的工作模式的状态示意图。FIG. 8c is a schematic diagram showing the state of the part of the structure of the charge pump in this embodiment working in the working mode with an output ratio of 1/3.
根据一个实施例,时钟信号Φ1控制着输入端与第一电荷泵单元之间的开关S1、第四电荷泵单元与输出端之间的开关S5的状态;Φ1还控制着第一、第二电荷泵单元与输出电压VOUT之间的开关S6和S8的状态,以及第三和第四电荷泵单元与地电平之间的开关S11和S13的状态。According to one embodiment, the clock signal Φ 1 controls the state of the switch S 1 between the input terminal and the first charge pump unit, the switch S 5 between the fourth charge pump unit and the output terminal; Φ 1 also controls the state of the first charge pump unit , the states of the switches S6 and S8 between the second charge pump unit and the output voltage VOUT , and the states of the switches S11 and S13 between the third and fourth charge pump units and the ground level.
根据一个实施例,Φ2控制着第二电荷泵单元与第三电荷泵之间的开关S3的状态;Φ2还控制着第一和第二电荷泵单元与地电平之间的开关S7和S9的状态,以及第三和第四电荷泵单元与输出电压VOUT之间的开关S10和S12的状态。According to one embodiment, Φ2 controls the state of the switch S3 between the second charge pump unit and the third charge pump; Φ2 also controls the switch S between the first and second charge pump units and the ground level 7 and S9 , and the states of switches S10 and S12 between the third and fourth charge pump cells and the output voltage VOUT .
根据一个实施例,第一与第二电荷泵单元之间的开关S2和第三与第四电荷泵单元之间的开关S4被设为恒导通状态,或者说是在有效电平(例如高电平)的控制下这个开关始终导通。According to one embodiment, the switch S2 between the first and the second charge pump unit and the switch S4 between the third and the fourth charge pump unit are set to a constant conduction state, or in other words at an active level ( For example, under the control of high level), the switch is always on.
根据一个实施例,如图4所示,Φ1和Φ2为有效电平例如高电平不交叠的两个时钟信号。According to an embodiment, as shown in FIG. 4 , Φ 1 and Φ 2 are two clock signals whose active levels, such as high levels, do not overlap.
根据一个的实施例,当Φ1=1Φ2=0的时候,开关S1、S6和S8导通、开关S7和S9断开,由于开关S2恒导通,第一和第二电荷泵单元的电容C1和C2并联,并且被输入电压VDD充电到VDD-VOUT。According to one embodiment, when Φ 1 =1 Φ 2 =0, the switches S 1 , S 6 and S 8 are turned on, and the switches S 7 and S 9 are turned off. Since the switch S 2 is always on, the first and second Capacitors C 1 and C 2 of the two charge pump units are connected in parallel, and are charged to V DD -V OUT by the input voltage V DD .
当Φ1=0Φ2=1的时候,开关S3导通,第一和第二电荷泵单元的电容C1和C2放电。开关S10和S12导通、开关S11和S13断开,由于开关S4恒导通,第三电荷泵单元的电容C3和C4并联,并被充电至VDD-2VOUT。When Φ 1 =0 Φ 2 =1, the switch S 3 is turned on, and the capacitors C 1 and C 2 of the first and second charge pump units are discharged. The switches S 10 and S 12 are turned on, and the switches S 11 and S 13 are turned off. Since the switch S 4 is always turned on, the capacitors C 3 and C 4 of the third charge pump unit are connected in parallel and charged to V DD -2V OUT .
当再一次Φ1=1Φ2=0的时候,开关S5导通,C3和C4向输出电容CL放电,并向输出端提供输出信号VDD-2VOUT=VOUT。因此可知,VOUT=1/3VDD。When Φ 1 =1 Φ 2 =0 again, the switch S 5 is turned on, C 3 and C 4 discharge the output capacitor CL , and provide the output signal V DD −2V OUT =V OUT to the output terminal. Therefore, it can be seen that V OUT =1/3V DD .
在这个实施例中,由包括C1和C2的第一级电荷泵单元以及包括C3和C4的第一级电荷泵单元被分别重新组合为两组第二级的电荷泵单元。经过这样的重新组合后,两个第二级电荷泵单元的等效电容值相等,从而实现了1/3输出倍率下最大的输出驱动能力。In this embodiment, the first - stage charge pump units including C1 and C2 and the first - stage charge pump units including C3 and C4 are respectively recombined into two sets of second-stage charge pump units. After such a recombination, the equivalent capacitance values of the two second-stage charge pump units are equal, thereby realizing the maximum output driving capability under 1/3 output ratio.
图8d所示为本实施例的电荷泵部分结构工作在输出倍率为1/2的工作模式的状态示意图。在这种情况下直接将四个电荷泵单元组合为第二级电荷泵单元即可,因此在实现1/2的情况下不需要考虑第二级电荷泵单元等效电容尽量平均的问题。FIG. 8d is a schematic diagram showing the state of the charge pump part structure of this embodiment working in the working mode with an output ratio of 1/2. In this case, it is enough to directly combine the four charge pump units into the second-stage charge pump unit, so in the case of realizing 1/2, it is not necessary to consider the problem that the equivalent capacitance of the second-stage charge pump unit is as average as possible.
综上所述,从图8a-图8d所示的例子来看,对于在1/5倍率和1/3倍率的情况下各电荷泵单元电容值相等,特别是对于1/3的倍率的情况相对于传统的做法(也就是例如将第一、第二、第三个电荷泵单元组合成一个第二级电荷泵单元的情况)输出驱动能力提高了33.3%。To sum up, from the example shown in Figure 8a-Figure 8d, for the case of 1/5 magnification and 1/3 magnification, the capacitance values of each charge pump unit are equal, especially for the case of 1/3 magnification Compared with the traditional practice (that is, for example, combining the first, second and third charge pump units into one second-stage charge pump unit), the output driving capability is increased by 33.3%.
根据本申请一实施例的一种构造全倍率电荷泵的方法。该实施例中的电荷泵可以包括m*k+n*(k-1)个第一级电荷泵单元,每个第一级电荷泵单元的电容值相等。对于每一个整数分之一倍率来说,都可以将上述的第一级电荷泵单元划分为两组第二级电荷泵单元,一组包括m个第二级电荷泵单元,每个电荷泵单元包括k个第一级电荷泵单元;另一组包括n个第二级电荷泵单元,每个电荷泵单元包括k-1个第一级电荷泵单元;其中x=m+n,其中m,n,k为大于等于1的正整数。可以用公式(6)来表达上述组合关系。A method for constructing a full-rate charge pump according to an embodiment of the present application. The charge pump in this embodiment may include m*k+n*(k-1) first-stage charge pump units, and the capacitance values of each first-stage charge pump unit are equal. For each integer fraction multiplier In other words, the above-mentioned first-stage charge pump unit can be divided into two groups of second-stage charge pump units, one group includes m second-stage charge pump units, and each charge pump unit includes k first-stage charge pump units unit; another group includes n second-stage charge pump units, and each charge pump unit includes k-1 first-stage charge pump units; where x=m+n, wherein m, n, k are greater than or equal to 1 positive integer. The above combination relationship can be expressed by formula (6).
当要进一步实现倍率也就是倍率的时候,可以减少一个第二级电荷泵单元,例如最右边的n个由k-1个第一级电荷泵单元组成的第二级电荷泵单元中的一个,将该第二级电荷泵单元中的k-1个第一级电荷泵单元均匀地“插入”其他的n-1个由k-1个第一级电荷泵单元组成的第二级电荷泵单元以及m个由k个电荷泵单元组成的第二级电荷泵单元。when to further implement The magnification is When multiplying, one second-stage charge pump unit can be reduced, for example, one of the rightmost n second-stage charge pump units composed of k-1 first-stage charge pump units, the second-stage charge pump The k-1 first-stage charge pump units in the cell are evenly "inserted" into other n-1 second-stage charge pump units consisting of k-1 first-stage charge pump units and m second-stage charge pump units consisting of k charge The pump unit is composed of the second stage charge pump unit.
存在两种情况:当(n-1)≥(k-1)时,可以将最右边的一个由k-1个第一级电荷泵单元组成的第二级电荷泵单元均匀插入n-1个由k-1个第一级电荷泵单元组成的第二级电荷泵单元中,从而形成k-1个新的由k个第一级电荷泵单元组成的第二级电荷泵单元,以及n-k个由k-1个第一级电荷泵单元组成的第二级电荷泵单元,从而实现倍率。公式7体现了在倍率下为了达到接近最大的输出驱动能力而形成的组合方式。There are two situations: when (n-1)≥(k-1), the rightmost second-stage charge pump unit consisting of k-1 first-stage charge pump units can be evenly inserted into n-1 In the second-stage charge pump unit composed of k-1 first-stage charge pump units, k-1 new second-stage charge pump units composed of k first-stage charge pump units are formed, and nk A second-stage charge pump unit composed of k-1 first-stage charge pump units, thus realizing magnification. Equation 7 embodies in The combination method formed in order to achieve close to the maximum output drive capacity under the magnification.
当(n-1)<(k-1)且(k-n)<m时,将最右边的一个由k-1个第一级电荷泵单元组成的第二级电荷泵单元均匀插入n-1个由k-1个第一级电荷泵单元组成的第二级电荷泵单元中,从而形成(n-1)+(m-(k-n))个由k个第一级电荷泵单元组成的第二级电荷泵单元,以及k-n个由k+1个第一级电荷泵单元组成的第二级电荷泵单元,从而实现倍率。公式8体现了在倍率下为了达到接近最大的输出驱动能力而形成的组合方式。When (n-1)<(k-1) and (kn)<m, the rightmost second-stage charge pump unit consisting of k-1 first-stage charge pump units is evenly inserted into n-1 In the second-stage charge pump unit composed of k-1 first-stage charge pump units, thus forming (n-1)+(m-(kn)) second-stage charge pump units composed of k first-stage charge pump units stage charge pump unit, and kn second-stage charge pump units composed of k+1 first-stage charge pump units, so as to realize magnification. Equation 8 embodies in The combination method formed in order to achieve close to the maximum output drive capacity under the magnification.
图9所示的表格为根据上述实施例针对不同的输出倍率而进行的电荷泵单元的组合方式。其中虚线框中的组合方式是相对于传统的电荷泵来说驱动能力有提高的倍率。The table shown in FIG. 9 is the combination of charge pump units for different output ratios according to the above-mentioned embodiments. The combination in the dotted line box is the magnification of the driving ability compared with the traditional charge pump.
图10所示为根据本申请一个实施例的利用电荷泵进行电压调整的方法,其中该电荷泵的主模块包括x个第一级电荷泵单元,每个第一级电荷泵单元具有相同的电容值,x为大于等于1的正整数。FIG. 10 shows a method for voltage regulation using a charge pump according to an embodiment of the present application, wherein the main module of the charge pump includes x first-stage charge pump units, and each first-stage charge pump unit has the same capacitance Value, x is a positive integer greater than or equal to 1.
在步骤1002,将x个第一级电荷泵单元分成两组,一组包括m个第二级电荷泵单元,另一组包括n个第二级电荷泵单元;其中所述m个第二级电荷泵单元中的每一个包括k个第一级电荷泵单元,所述n个第二级电荷泵单元中的每一个包括k-1个第一级电荷泵单元;In step 1002, the x first-stage charge pump units are divided into two groups, one group includes m second-stage charge pump units, and the other group includes n second-stage charge pump units; wherein the m second-stage charge pump units Each of the charge pump units includes k first-stage charge pump units, and each of the n second-stage charge pump units includes k-1 first-stage charge pump units;
在步骤1004,如果x=1,则停止计算,否则进入到步骤1006;In step 1004, if x=1, then stop calculating, otherwise enter into step 1006;
在步骤1006,x=x-1,将n个第二级电荷泵中的一个拆分为k-1个第一级电荷泵单元;In step 1006, x=x-1, split one of the n second-stage charge pumps into k-1 first-stage charge pump units;
在步骤1008,检测n-1与k-1的关系;In step 1008, the relationship between n-1 and k-1 is detected;
在步骤1010,当(n-1)≥(k-1)时,将所述k-1个第一级电荷泵单元插入n-1个由k-1个第一级电荷泵单元组成的第二级电荷泵单元中,从而形成两组新的第二级电荷泵单元,一组包括m+k-1个第二级电荷泵单元,该组中每个第二级电荷泵单元包括k个第一级电荷泵单元;另一组包括n-k个第二级电荷泵单元,该组每个第二级电荷泵单元包括k-1个第一级电荷泵单元;In step 1010, when (n-1)≥(k-1), insert the k-1 first-stage charge pump units into n-1 first-stage charge pump units consisting of k-1 first-stage charge pump units In the second-stage charge pump unit, thus forming two groups of new second-stage charge pump units, one group includes m+k-1 second-stage charge pump units, and each second-stage charge pump unit in this group includes k The first-stage charge pump unit; another group includes n-k second-stage charge pump units, and each second-stage charge pump unit in this group includes k-1 first-stage charge pump units;
在步骤1012,当(n-1)<(k-1)且(k-n)<m时,将所述k-1个第一级电荷泵单元插入n-1个由k-1个第一级电荷泵单元组成的第二级电荷泵单元以及k-n个由k个第一级电荷泵单元组成的第二级电荷泵单元中,从而形成两组新的第二级电荷泵单元,一组包括(n-1)+(m-(k-n))个第二级电荷泵单元,该组中每个第二级电荷泵单元包括k个第一级电荷泵单元;另一组包括k-n个第二级电荷泵单元,该组每个第二级电荷泵单元包括k+1个第一级电荷泵单元。In step 1012, when (n-1)<(k-1) and (k-n)<m, insert the k-1 first-stage charge pump units into n-1 by k-1 first-stage In the second-stage charge pump unit composed of the charge pump unit and k-n second-stage charge pump units composed of k first-stage charge pump units, thus forming two groups of new second-stage charge pump units, one group includes ( n-1)+(m-(k-n)) second-stage charge pump units, each second-stage charge pump unit in this group includes k first-stage charge pump units; another group includes k-n second-stage charge pump units A charge pump unit, each second-stage charge pump unit in the group includes k+1 first-stage charge pump units.
虽然已经通过例子对本申请的一些特定实施例进行了详细说明,但是本领域的技术人员应该理解,以上例子仅是为了进行说明,而不是为了限制本申请的范围。本领域的技术人员应该理解,可在不脱离本申请的范围和精神的情况下,对以上实施例进行修改。本申请的范围由所附权利要求来限定。Although some specific embodiments of the present application have been described in detail through examples, those skilled in the art should understand that the above examples are only for illustration, rather than limiting the scope of the present application. Those skilled in the art will appreciate that modifications can be made to the above embodiments without departing from the scope and spirit of the application. The scope of the application is defined by the appended claims.
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