CN105759173B - The adaptive failure Section Location of power distribution network containing distributed generation resource - Google Patents
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Abstract
一种含分布式电源的配电网的自适应故障区段定位方法,将含分布式电源的配电网划分为多个双端无分支的区段。在已知所有区段的线路参数的条件下,采集各个区段两端节点处的电压、电流信息,经相模变换得到节点处的模电压、模电流以及线路的模参数,节点模电流经傅里叶变换得到节点模电流相位角。利用区段的线路空载检测和模电流差流检测,仅当区段内的线路非空载并且该区段的模电流差流过流的情况下启动区段的故障判定,通过区段的模电流相角差值绝对值与判定阈值的比较,得出区段的故障判定结果。利用含分布式电源的配电网内所有区段的故障判定结果生成系统故障判定矩阵,通过对系统故障判定矩阵中元素值的判定,得出故障点所在区段。
An adaptive fault section location method for a distribution network with distributed power sources, which divides the distribution network with distributed power sources into multiple double-ended and branchless sections. Under the condition that the line parameters of all sections are known, the voltage and current information at the nodes at both ends of each section are collected, and the mode voltage and current at the node and the mode parameters of the line are obtained through phase-mode transformation. The mode current of the node is obtained by Fu The phase angle of the nodal mode current is obtained by the Lie transform. Using the line no-load detection and differential current detection of the section, the fault judgment of the section is started only when the line in the section is not unloaded and the differential current of the section is overcurrent. Comparing the absolute value of the phase angle difference of the mode current with the judgment threshold, the fault judgment result of the section is obtained. The system fault judgment matrix is generated by using the fault judgment results of all sections in the distribution network containing distributed power generation, and the section where the fault point is located is obtained by judging the element values in the system fault judgment matrix.
Description
技术领域technical field
本发明涉及一种含分布式电源的配电网的故障区段定位方法。The invention relates to a method for locating a fault section of a distribution network with a distributed power supply.
背景技术Background technique
配电网故障定位技术能够在配电网故障后准确找出故障所在方位,有利于配电网故障的准确隔离以及快速及时的维修处理。同时,配电网故障的准确定位也是故障后配电网供电恢复的先决条件。因此,配电网故障定位技术对整个配电网的安全、稳定、高效运行有着重要的意义和作用。The distribution network fault location technology can accurately find out the location of the fault after the distribution network fault, which is conducive to the accurate isolation of the distribution network fault and the rapid and timely maintenance and treatment. At the same time, the accurate location of the distribution network fault is also a prerequisite for the restoration of the power supply of the distribution network after the fault. Therefore, distribution network fault location technology has an important significance and effect on the safe, stable and efficient operation of the entire distribution network.
随着分布式发电技术的日渐成熟与微网运行控制技术的进步,越来越多的分布式电源(Distributed Generators,DG)不断接入配电网,使得传统的被动配电网变为含有分布式电源的有源配电网,其中双向的潮流、分布式电源出力的波动性以及逆变型分布式电源的低短路电流输出特性使得传统的配电网保护与故障定位方法的整定难度加大,并容易造成误动、拒动的情况,因而不再适用。With the maturity of distributed generation technology and the progress of micro-grid operation control technology, more and more distributed generators (Distributed Generators, DG) are continuously connected to the distribution network, making the traditional passive distribution network into a distribution network. In the active distribution network of distributed power supply, the two-way power flow, the fluctuation of distributed power output and the low short-circuit current output characteristics of inverter distributed power make the setting of traditional distribution network protection and fault location methods more difficult. , and it is easy to cause false movement and refusal to move, so it is no longer applicable.
中国发明专利201210532103.3公开了一种基于阻抗模型短路故障特征的含DG配电网故障区间判定方法,该方法通过建立分析模型得出故障区间判定的电流阈值,在实际应用中受模型参数准确度与网络运行拓扑变化的影响大,不具备自适应性。中国发明专利201510170001.5公开了一种基于FTU的配电网故障定位方法,该方法利用矩阵算法确定故障所在区间,其定位的准确性依赖于各个FTU对节点过流情况的正确判定以及可靠的通信,错误的故障信息或信号畸变将可能导致故障定位精度降低甚至出错。N.Perera等人在《IEEE TRANSACTIONS ON POWER DELIVERY》2008年第23卷第4期所著《Isolation ofFaults in Distribution Networks with Distributed Generators》中通过比较小波系数的符号实现故障区段的定位,但小波算法冗长复杂,对硬件的采样率及数据处理能力要求高,高昂的配置成本使其在配电网中难以实现应用。Chinese invention patent 201210532103.3 discloses a method for determining the fault interval of a distribution network containing DG based on the short-circuit fault characteristics of the impedance model. This method obtains the current threshold for fault interval judgment by establishing an analysis model. In practical applications, it is affected by the accuracy of the model parameters and the Network operation topology changes have a great impact and are not self-adaptive. Chinese invention patent 201510170001.5 discloses a distribution network fault location method based on FTU. This method uses matrix algorithm to determine the fault location. The accuracy of the location depends on the correct judgment of each FTU on the node's overcurrent situation and reliable communication. Wrong fault information or signal distortion may lead to reduced accuracy or even errors in fault location. In "Isolation of Faults in Distribution Networks with Distributed Generators" written by N.Perera et al. in "IEEE TRANSACTIONS ON POWER DELIVERY", Volume 23, Issue 4, 2008, the location of the fault section is realized by comparing the signs of the wavelet coefficients, but the wavelet algorithm It is tedious and complex, requires high sampling rate and data processing capability of hardware, and high configuration cost makes it difficult to realize application in distribution network.
目前,国内外对于含分布式电源的配电网的故障定位的研究多以节点电流作为主要的故障特征信息源,即这些方法用于判定含分布式电源的配电网内故障所在方位的故障特征量均是节点电流或由节点电流经变换或处理产生的。考虑到含分布式电源的配电网的拓扑结构复杂,设备种类繁多且操作频度高,分布式电源的出力易受环境因素影响而产生波动,整个网络的运行状态将时刻发生变化,这使得整个网络内各个节点处的判定阈值需要实时的计算整定,否则将无法保证故障定位的准确性和可靠性。因此,以节点电流为故障特征信息源的故障定位方法在含分布式电源的配电网中应用时必须配置相应的阈值实时更新机制,这些方法必须通过对判定阈值高频率的刷新以产生保证其可靠、有效所必需的自适应性。然而,每一次阈值的整定都要收集全网的状态信息,阈值的计算将产生可观的计算量,整定阈值的更新需要高速、可靠的通信系统支撑,这些因素使得故障定位的判定阈值在实际情况下难以做到对系统运行状态变化的快速跟踪,进而造成这些方法在自适应性上的不足。At present, domestic and foreign studies on fault location of distribution networks with distributed generation mostly use node current as the main source of fault characteristic information, that is, these methods are used to determine the location of faults in distribution networks with distributed generation. The characteristic quantities are all node currents or generated by transforming or processing node currents. Considering that the distribution network with distributed power has a complex topology, a wide variety of equipment and high frequency of operation, the output of distributed power is easily affected by environmental factors and fluctuates, and the operating status of the entire network will change from time to time, which makes The judgment thresholds at each node in the entire network need to be calculated and adjusted in real time, otherwise the accuracy and reliability of fault location cannot be guaranteed. Therefore, when the fault location method using node current as the source of fault characteristic information is applied in a distribution network with distributed power generation, it must be configured with a corresponding threshold real-time update mechanism. Adaptability necessary for reliability and efficiency. However, the state information of the entire network must be collected every time the threshold is set, and the calculation of the threshold will generate a considerable amount of calculation. The update of the threshold needs to be supported by a high-speed and reliable communication system. However, it is difficult to quickly track the changes of the system's operating state, which leads to the lack of adaptability of these methods.
随着配电网中分布式电源渗透率的不断提升与智能配电网的发展,未来智能化的配电网将具有更高的分布式电源渗透率和更加灵活多变的拓扑结构,网络内部发电与用电具有较大的自由度和较强的波动性,这将会对故障定位方法适应复杂多变的运行状态的能力提出更高的要求,即要求故障定位方法具备较强的自适应性。因此,现有的含分布式电源的配电网的故障定位方法并不能够适应智能配电网的发展趋势。With the continuous improvement of the distributed power penetration rate in the distribution network and the development of the smart distribution network, the intelligent distribution network in the future will have a higher distributed power penetration rate and a more flexible topological structure. Power generation and power consumption have a greater degree of freedom and strong volatility, which will put forward higher requirements for the ability of the fault location method to adapt to complex and changeable operating conditions, that is, the fault location method is required to have a strong self-adaption sex. Therefore, the existing fault location methods for distribution networks with distributed generation cannot adapt to the development trend of smart distribution networks.
综上所述,在智能配电网发展的潮流中,面对高分布式电源渗透率的含分布式电源的配电网的快速保护、故障小范围隔离以及故障后供电恢复实现系统自愈的实际需求,在含分布式电源的配电网中仍然需要一种更加快速、有效,并具备良好自适应性的在线故障定位方法。To sum up, in the trend of smart distribution network development, in the face of the high penetration rate of distributed power distribution network with distributed power, rapid protection, small-scale fault isolation, and power supply recovery after faults to achieve system self-healing According to the actual demand, a faster, more effective, and better adaptive online fault location method is still needed in the distribution network with distributed power generation.
发明内容Contents of the invention
本发明的目的在于针对现有的含分布式电源的配电网的故障定位方法所存在的自适应性不足的问题,提出一种适用于含分布式电源的配电网的自适应故障区段定位方法。The purpose of the present invention is to propose a self-adaptive fault section suitable for the distribution network containing distributed power in view of the insufficient self-adaptability existing in the fault location method of the distribution network containing distributed power positioning method.
本发明可以在含分布式电源的配电网中实现在线的故障区段定位,能够在含分布式电源的配电网内发生多种故障,如单相接地短路、两相接地短路、两相相间短路、三相短路的情况下快速、准确、可靠地定位故障,且不受非故障扰动的影响,具有良好的自适应性与通用性,适用于同时含有多种类型线路,如单相线路、两相线路、三相线路的含分布式电源的配电网。The present invention can realize online fault section positioning in the distribution network containing distributed power sources, and various faults can occur in the distribution network containing distributed power sources, such as single-phase ground short circuit, two-phase ground short circuit, two-phase In the case of phase-to-phase short circuit and three-phase short circuit, it can quickly, accurately and reliably locate faults, and is not affected by non-fault disturbances. It has good adaptability and versatility, and is suitable for multiple types of lines at the same time, such as single-phase Line, two-phase line, three-phase line distribution network with distributed power supply.
本发明所采取的技术方案是:The technical scheme that the present invention takes is:
本发明方法首先对一个含分布式电源的配电网进行区段划分,并对该含分布式电源的配电网内的各个节点和区段编号;然后,采集该含分布式电源的配电网中的各个区段内两端节点处的电压和电流信号,利用设计的相模变换矩阵,对区段进行相模变换,将区段内耦合的电气量转化为相互独立的模量,得出各个模量所对应的模电压、模电流、线路单位长度的串联模阻抗与并联模导纳。接着,选择一个适宜的模量用于区段故障的判定。经区段的线路空载检测与模电流差流检测,仅在当区段内的线路非空载并且区段的模电流差流过流的情况下,进行区段故障的判定。进入区段故障判定过程后,求取所选取的用于区段故障判定的模量对应区段的模电流相角差值的绝对值,并通过所求的模电流相角差值的绝对值与判定阈值的比较得出区段的故障判定结果。最后,利用含分布式电源的配电网内各个区段的故障判定结果,根据系统故障判定矩阵的生成与判定方法,对该含分布式电源的配电网进行故障判定与故障定位,并得到当前时刻下的故障定位结果。The method of the present invention first divides a distribution network containing distributed power sources into sections, and numbers each node and section in the distribution network containing distributed power sources; then, collects the distribution network containing distributed power sources The voltage and current signals at the nodes at both ends of each section in the network, use the designed phase-mode transformation matrix to perform phase-mode transformation on the section, convert the coupled electrical quantities in the section into mutually independent modulus, and obtain each The modulus corresponds to the mode voltage, mode current, series mode impedance and parallel mode admittance per unit length of the line. Then, choose an appropriate modulus for section fault judgment. After the line no-load detection and differential current detection of the section, only when the line in the section is not empty and the differential current of the section is overcurrent, the judgment of the section fault is carried out. After entering the section fault judgment process, obtain the absolute value of the mode current phase angle difference of the section corresponding to the modulus selected for section fault judgment, and pass the absolute value of the mode current phase angle difference obtained The comparison with the decision threshold yields a fault decision result for the segment. Finally, using the fault judgment results of each section in the distribution network containing distributed generation, according to the generation and judgment method of the system fault judgment matrix, the fault judgment and fault location of the distribution network containing distributed generation are carried out, and the obtained The fault location result at the current moment.
本发明方法的具体步骤如下:The concrete steps of the inventive method are as follows:
(一)对含分布式电源的配电网进行区段划分(1) Segmentation of the distribution network with distributed power generation
所述含分布式电源的配电网的区段划分方法为:在一个含分布式电源的配电网内,将该配电网按其拓扑结构划分为若干个双端无分支区段,即所划分的各个区段有且仅有两个端节点,且区段在两个端节点之间无其他分支路。完成区段划分后,对节点和区段进行编号,为各个节点和区段赋予其唯一的编号。The section division method of the distribution network containing distributed power sources is as follows: in a distribution network containing distributed power sources, the distribution network is divided into several double-ended and branch-free sections according to its topology, that is, Each divided section has one and only two end nodes, and the section has no other branch roads between the two end nodes. After completing the section division, number the nodes and sections, and give each node and section a unique number.
(二)对含分布式电源的配电网内区段进行相模变换,将区段内耦合的电气量转化为相互独立的模量(2) Perform phase-mode transformation on the section of the distribution network containing distributed power, and convert the coupled electrical quantities in the section into mutually independent moduli
在步骤(一)的基础上,采集该含分布式电源的配电网中各个区段内两端节点处的电压和电流信号,利用设计的相模变换矩阵,对区段进行相模变换,将区段内耦合的电气量转化为相互独立的模量,得出各个模量所对应的模电压、模电流、线路单位长度的串联模阻抗与并联模导纳。On the basis of step (1), the voltage and current signals at the nodes at both ends of each section in the distributed power distribution network are collected, and the phase-mode transformation is performed on the section by using the designed phase-mode transformation matrix, and the section The electrical quantity coupled in the section is transformed into mutually independent moduli, and the corresponding mode voltage, mode current, series mode impedance and parallel mode admittance of the unit length of the line are obtained for each modulus.
(1)所述的相模变换矩阵的设计方法如下:(1) The design method of described phase mode transformation matrix is as follows:
一般情况下,含分布式电源的配电网中往往同时含有三相线路、两相线路以及单相线路,经区段划分后形成相应的三相区段、两相区段以及单相区段。对于含分布式电源的配电网中的某一个n相区段,n=1,2,3,令该区段内的线路以其一端节点为长度的原点,其线路长度变化的正方向为原点指向该区段另一端节点,可定义该区段的线路上沿径向正方向长度为x的某一点处的电压矩阵为U(n)(x),流经该点的电流矩阵为I(n)(x),其对应的表达式的形式如下所示:In general, distribution networks with distributed power sources often contain three-phase lines, two-phase lines and single-phase lines at the same time, and the corresponding three-phase sections, two-phase sections and single-phase sections are formed after section division . For a certain n-phase section in the distribution network with distributed power generation, n=1, 2, 3, let the line in this section take its end node as the origin of the length, and the positive direction of the line length change is The origin points to the node at the other end of the section. It can be defined that the voltage matrix at a certain point along the positive radial direction of the section is U (n) (x), and the current matrix flowing through this point is I (n) (x), the corresponding expression form is as follows:
其中,Ui(x)为该区段内线路长度为x的点处第i相的相电压;Ii(x)为该区段内线路长度为x的点处第i相的相电流,i=1,…,n。Among them, U i (x) is the phase voltage of the i-th phase at the point of the line length x in the section; I i (x) is the phase current of the i-th phase at the point of the line length x in the section, i=1,...,n.
根据传输线的分布参数模型可定义该区段内线路单位长度的串联阻抗矩阵为Z(n),单位为Ω/km;并联导纳矩阵为Y(n),单位为S/km。其对应的表达式的形式如下所示:According to the distribution parameter model of the transmission line, the series impedance matrix of the unit length of the line in this section can be defined as Z (n) in Ω/km; the parallel admittance matrix is Y (n) in S/km. The form of the corresponding expression is as follows:
其中,zij,i=j,表示该区段内线路单位长度的串联自阻抗;zij,i≠j,表示该区段内线路单位长度的串联互阻抗;yij,i=j,表示该区段内线路单位长度的并联自导纳;yij,i≠j,表示该区段内线路单位长度的并联互导纳。Among them, z ij , i=j, represents the series self-impedance per unit length of the line in this section; z ij , i≠j, represents the series mutual impedance of the line unit length in this section; y ij , i=j, represents The parallel self-admittance per unit length of the line in this section; y ij , i≠j, represents the parallel mutual admittance per unit length of the line in this section.
由此,可以写出该区段内线路的分布参数模型的微分方程式:Therefore, the differential equation of the distributed parameter model of the line in this section can be written:
经研究可得,若存在一个矩阵Φ(n),且满足下式所述条件:After research, it can be obtained that if there is a matrix Φ (n) that satisfies the conditions described in the following formula:
Φ(n) -1·(Z(n)·Y(n))·Φ(n)=λ(n) (3)Φ (n) -1 · (Z (n) · Y (n) ) · Φ (n) = λ (n) (3)
其中,λ(n)=diag(λ11,…,λnn),为式(3)的特征根矩阵。则利用矩阵Φ(n)对该区段内线路上的电气相量以及线路参数做变换,可实现耦合相量与参数的解耦。in, λ (n) = diag(λ 11 ,…,λ nn ), which is the characteristic root matrix of formula (3). Then, the matrix Φ (n) is used to transform the electrical phasor and line parameters on the line in this section, so as to realize the decoupling of the coupling phasor and parameters.
可用于含分布式电源的配电网内某一个区段的相模变换公式如下:The phase-mode transformation formula that can be used in a certain section of the distribution network with distributed power generation is as follows:
利用矩阵Φ(n)将该区段内线路中各相之间相互耦合的线路参数解耦,将该区段内线路中耦合的电气相量变换为相互间独立的电气模分量,称为相模变换,其变换式如下所示:Use the matrix Φ (n) to decouple the line parameters of the mutual coupling between the phases in the line in the section, and transform the coupled electrical phasors in the line in the section into independent electrical mode components, called phase mode Transformation, the transformation formula is as follows:
其中,为经相模变换所得的该区段内某一点处的节点电压模量矩阵;为经相模变换所得的该区段内某一点处的节点电流模量矩阵;为经相模变换所得的该区段内线路单位长度的串联模阻抗矩阵;为经相模变换所得的该区段内线路单位长度的并联模导纳矩阵。in, is the node voltage modulus matrix at a certain point in the section obtained by phase mode transformation; is the node current modulus matrix at a point in the section obtained by phase mode transformation; is the series-mode impedance matrix of the unit length of the line in the section obtained through phase-mode transformation; is the parallel mode admittance matrix of the line unit length in the section obtained by phase-mode transformation.
根据式(1)、式(2)、式(4)、式(5)、式(6)及式(7),可以导出经相模变换所得的与该区段内线路等效的分布参数模型的微分方程式:According to formula (1), formula (2), formula (4), formula (5), formula (6) and formula (7), the distributed parameter model equivalent to the line in this section obtained by phase mode transformation can be derived The differential equation for :
在上述的等效模型中,选取某一个模量k,k=1,…,n,即选取该区段线路等效模型中的第k个模量所形成的等效的单相区段,根据式(8)、式(9)可以写出该等效单相区段的分布参数模型的微分方程式:In the above equivalent model, select a certain modulus k, k=1,...,n, that is, select the equivalent single-phase section formed by the kth modulus in the equivalent model of the line in this section, According to formula (8) and formula (9), the differential equation of the distributed parameter model of the equivalent single-phase section can be written:
其中,和分别为经相模变换所得的该区段内某一点处的节点模电压与节点模电流;和分别为经相模变换所得的该区段内线路单位长度的串联模阻抗与并联模导纳。in, and are the node-mode voltage and node-mode current at a point in the section obtained through phase-mode transformation, respectively; and are the series-mode impedance and parallel-mode admittance of the line unit length in the section obtained through phase-mode transformation, respectively.
某一个n相区段经相模变换所得的第k个模量所等效的单相区段中的节点模电压节点模电流的实质为该n相区段中各相的电压相量、电流相量的线性组合。根据相量叠加原理,同频率的相量之和仍为该频率下的相量,其数学表达式如下:The node mode voltage in the single-phase section equivalent to the kth modulus obtained by phase-mode transformation of an n-phase section Nodal mode current The essence of is the linear combination of the voltage phasor and current phasor of each phase in the n-phase segment. According to the principle of phasor superposition, the sum of phasors at the same frequency is still the phasor at this frequency, and its mathematical expression is as follows:
在式(12)和式(13)中,si为该n相区段各相电压相量线性组合的系数,vi为该n相区段各相电流相量线性组合的系数,i=1,…,n。通过选取合适的si和vi,可在该n相区段内实现利用单一模量的变化反映各个相量的变化。因此,选择合适的vi值,可利用该n相区段的等效单相区段的模电流相角差值代替各相区段的相电流相角差值,判定该区段内发生的各类故障,包含:单相接地短路、两相接地短路、两相相间短路、三相短路,共四个大类故障。In formula (12) and formula (13), s i is the coefficient of the linear combination of voltage phasors of each phase in the n-phase section, v i is the coefficient of the linear combination of current phasors in each phase of the n-phase section, i= 1,...,n. By selecting appropriate s i and v i , the change of a single modulus can be used to reflect the change of each phasor in the n-phase segment. Therefore, to select an appropriate value of v, the phase angle difference of the phase current of the equivalent single-phase section of the n-phase section can be used to replace the phase angle difference of the phase current of each phase section to determine the occurrence in this section Various types of faults, including: single-phase ground short circuit, two-phase ground short circuit, two-phase phase-to-phase short circuit, three-phase short circuit, a total of four major types of faults.
考虑到n相区段各相电压相量线性组合的系数si的取值实际上为节点电压相模变换矩阵中第k行第i列元素的值,以及n相区段各相电流相量线性组合的系数vi的取值实际上为节点电流相模变换矩阵中第k行第i列元素的值。为了使该n相区段在发生各类故障的情况下,如单相接地短路、两相接地短路、两相相间短路、三相短路,能够反映经相模变换所得的第k个模量所等效的单相区段的故障,即当该n相区段内发生故障时,其经相模变换所得的第k个模量所等效的单相区段内亦发生故障,这就需要对矩阵Φ(n)内各个元素的取值按照一定规则进行设计和选取。Considering that the value of the coefficient si of the linear combination of the voltage phasors of each phase in the n-phase section is actually the value of the element in the kth row and column i in the node voltage phase-mode transformation matrix, and the linearity of the current phasors of each phase in the n-phase section The value of the combined coefficient v i is actually the value of the kth row and ith column element in the node current phase-mode transformation matrix. In order to make the n-phase section reflect the kth modulus obtained by phase-mode transformation in the case of various faults, such as single-phase ground short circuit, two-phase ground short circuit, two-phase phase-to-phase short circuit, and three-phase short circuit The fault of the equivalent single-phase section, that is, when a fault occurs in the n-phase section, a fault occurs in the single-phase section equivalent to the kth modulus obtained by phase-mode transformation, which requires The value of each element in the matrix Φ (n) is designed and selected according to certain rules.
若该n相区段内的线路参数是换位平衡的,有下式成立:If the line parameters in the n-phase section are transposition balanced, the following formula holds:
其中,为该n相区段内线路的参数矩阵,α为矩阵内对角线元素,β为矩阵内非对角线元素,显然为一个对称矩阵。in, is the parameter matrix of the line in the n-phase section, and α is the matrix Inner diagonal elements, β is the matrix Inner off-diagonal elements, obviously is a symmetric matrix.
为了将该n相区段内耦合的线路参数解耦,需要有一个对称的变换矩阵使下式满足:In order to decouple the coupled line parameters in this n-phase segment, a symmetric transformation matrix is required satisfy the following formula:
其中, 为式(15)的特征根矩阵。in, is the characteristic root matrix of formula (15).
但是,考虑到实际的含分布式电源的配电网内的线路参数并不是换位平衡的,单相线路除外,对于线路参数非换位平衡的两相区段或是三相区段,其线路参数矩阵K(n)变为:However, considering that the line parameters in the actual distribution network with distributed generation are not transposition balanced, except for single-phase lines, for two-phase sections or three-phase sections with non-transposition balanced line parameters, its The line parameter matrix K (n) becomes:
其中,n为区段内线路的相数;K(n)为一个对称矩阵,且有κij=κji成立,i=1,…,n,j=1,…,n,且i≠j。利用矩阵无法将K(n)化为一个对角阵,因此,需要找到能够将K(n)化为对角阵的矩阵Φ(n),将区段内相互耦合的线路解耦,可通过下述方法对适用于区段内线路参数非换位平衡的相模变换矩阵进行设计。Among them, n is the phase number of the line in the section; K (n) is a symmetrical matrix, and κ ij = κ ji is established, i=1,...,n, j=1,...,n, and i≠j . use matrix It is impossible to turn K (n) into a diagonal matrix, so it is necessary to find a matrix Φ (n) that can turn K (n) into a diagonal matrix, and decouple the mutually coupled lines in the section, which can be achieved through the following Methods The phase-mode transformation matrix suitable for non-transposition balance of line parameters in the section is designed.
考虑线路参数非换位平衡的相模变换矩阵的设计方法如下:The design method of the phase-mode transformation matrix considering the non-transposition balance of line parameters is as follows:
该方法首先需要已知区段内的相数n,电压、电流相量的基波频率f,区段内线路单位长度的串联电阻矩阵R(n),单位为Ω/km,串联电感矩阵L(n),单位为H/km,以及并联电容矩阵C(n),单位为F/km,它们的数学表达式分别为:This method first needs to know the number of phases n in the section, the fundamental frequency f of the voltage and current phasors, the series resistance matrix R (n) of the line unit length in the section, the unit is Ω/km, and the series inductance matrix L (n) , the unit is H/km, and the parallel capacitance matrix C (n) , the unit is F/km, their mathematical expressions are respectively:
其中,rij表示该区段内线路单位长度的串联自阻,i=j;rij表示该区段内线路单位长度的串联互阻,i≠j;lij表示该区段内线路单位长度的串联自感,i=j;lij表示该区段内线路单位长度的串联互感,i≠j;cij表示该区段内线路单位长度的并联自电容,i=j;cij表示该区段内线路单位长度的并联互电容,i≠j。Among them, r ij represents the series self-resistance of the line unit length in this section, i=j; r ij represents the series mutual resistance of the line unit length in this section, i≠j; l ij represents the line unit length in this section The series self-inductance of the line, i=j; l ij represents the series mutual inductance of the line unit length in this section, i≠j; c ij represents the parallel self-capacitance of the line unit length in this section, i=j; c ij represents the Parallel mutual capacitance of line unit length in the section, i≠j.
该线路参数非换位平衡的相模变换矩阵的设计方法包含如下八个步骤:The design method of the phase-mode transformation matrix of the line parameter non-transposition balance comprises the following eight steps:
步骤1、求取区段内线路的参数矩阵K(n)。K(n)的求取可以依据以下计算公式:Step 1. Obtain the parameter matrix K (n) of the lines in the section. The calculation of K (n) can be based on the following calculation formula:
K(n)=[R(n)+j·(2πf)·L(n)]·[j·(2πf)·C(n)] (16)K (n) = [R (n) + j (2πf) L (n) ] [j (2πf) C (n) ] (16)
其中,j2=-1。Among them, j 2 =-1.
步骤2、计算线路参数矩阵K(n)对应的线路参数换位平衡的矩阵矩阵的计算方法如下:Step 2, calculate the matrix of the line parameter transposition balance corresponding to the line parameter matrix K (n) matrix The calculation method is as follows:
若 like
则有 then there is
其中α和β分别满足以下公式:where α and β respectively satisfy the following formulas:
步骤3、设计矩阵将矩阵写成如下所示的形式:Step 3. Design Matrix the matrix Written in the form shown below:
其中,aij为矩阵中的元素,且有aij=aji成立,i=1,…,n,j=1,…,n,且i≠j;A为矩阵的系数,有 Among them, a ij is the element in the matrix, and a ij = a ji is established, i=1,...,n, j=1,...,n, and i≠j; A is the coefficient of the matrix, and there is
根据区段的相数n,按照如下所示的三条约束规则对矩阵内各个元素的取值进行设计:According to the phase number n of the section, the matrix is arranged according to the three constraint rules as shown below The value of each element in the design:
①当n=1时,即该区段为单相区段,中的元素应当满足下式所述的约束条件:a11=1① When n=1, that is, the section is a single-phase section, The elements in should satisfy the constraints described in the following formula: a 11 =1
②当n=2时,即该区段为两相区段,中的元素应当满足下式所述的约束条件:②When n=2, that is, the section is a two-phase section, The elements in should satisfy the constraints described in the following formula:
③当n=3时,即该区段为三相区段,中的元素应当满足下式所述的约束条件:③When n=3, that is, the section is a three-phase section, The elements in should satisfy the constraints described in the following formula:
步骤4、计算矩阵的特征值矩阵矩阵的特征值矩阵的计算可依据以下公式:Step 4. Calculate the matrix The eigenvalue matrix of matrix The eigenvalue matrix of can be calculated according to the following formula:
步骤5、利用矩阵和矩阵K(n),计算矩阵矩阵的计算公式为:Step 5. Use the matrix and matrix K (n) , computing the matrix matrix The calculation formula is:
步骤6、计算一阶扰动量矩阵W(n)。Step 6. Calculate the first-order disturbance matrix W (n) .
一阶扰动量矩阵 First order perturbation matrix
其中,wij为矩阵W(n)中的元素,i=1,…,n,j=1,…,n,且满足以下条件:Among them, w ij is the element in the matrix W (n) , i=1,...,n, j=1,...,n, and satisfy the following conditions:
步骤7、计算矩阵K(n)的变换矩阵Φ(n)。计算矩阵K(n)的变换矩阵Φ(n)可依据以下计算公式:Step 7. Calculate the transformation matrix Φ (n) of the matrix K (n) . The transformation matrix Φ (n ) of the calculation matrix K (n) can be based on the following calculation formula:
其中,E(n)为一个n阶的单位矩阵。Among them, E (n) is an n-order identity matrix.
步骤8、对变换矩阵Φ(n)进行施密特对角化处理,经矩阵转置后,最终可得所需的相模变换矩阵Φ(n) T。Step 8: Perform Schmidt diagonalization on the transformation matrix Φ (n) , and after matrix transposition, the required phase-mode transformation matrix Φ (n) T can be finally obtained.
利用以上方法,不论n相区段内的线路参数是否为换位平衡,均能够对该区段的相模变换矩阵进行设计,并得出适用该区段的相模变换矩阵Φ(n) T,利用该相模变换矩阵Φ(n) T,可将该区段内的n个互相耦合电气相量等效的转换为n个相互独立的电气模量。Using the above method, no matter whether the line parameters in the n-phase section are transposition balance or not, the phase-mode transformation matrix of this section can be designed, and the phase-mode transformation matrix Φ (n) T applicable to this section can be obtained. The phase-to-mode transformation matrix Φ (n) T can equivalently convert n mutually coupled electrical phasors in the section into n mutually independent electrical moduli.
(2)所述的相模变换的变换公式如下:(2) the transformation formula of described phase mode transformation is as follows:
若矩阵Φ(n) T为考虑线路参数非换位平衡的相模变换矩阵的设计方法所得出的相模变换矩阵,则有Φ(n) -1=Φ(n) T成立,因此可对式(4)、式(5)、式(6)以及式(7)所述的相模变换公式进行简化,得出本发明所采用的适用于含分布式电源的配电网的相模变换公式,具体如下:If the matrix Φ (n) T is the phase-mode transformation matrix obtained by the design method of the phase-mode transformation matrix considering the line parameter non-transposition balance, then Φ (n) -1 = Φ (n) T is established, so the formula ( 4), formula (5), formula (6) and the phase-mode transformation formula described in formula (7) are simplified, draw the phase-mode transformation formula that the present invention adopts being applicable to the distribution network that contains distributed power supply, specifically as follows :
令含分布式电源的配电网中某一个n相区段内的任意一个节点处的节点电压矩阵为U(n)、节点电流矩阵为I(n),该节点所在线路单位长度的串联阻抗矩阵为Z(n),该节点所在线路单位长度的并联导纳矩阵为Y(n),其中:Let the node voltage matrix at any node in a certain n-phase section in the distribution network containing distributed power generation be U (n) and the node current matrix be I (n) , the series impedance of the unit length of the line where the node is located The matrix is Z (n) , and the parallel admittance matrix per unit length of the line where the node is located is Y (n) , where:
则有以下的相模变换公式,可实现该区段内的电气量与线路参数的解耦:Then there is the following phase-mode transformation formula, which can realize the decoupling of electrical quantities and line parameters in this section:
其中,为经相模变换所得的节点模电压矩阵;为经相模变换所得的节点模电流矩阵;为经相模变换所得的该区段内线路单位长度的串联模阻抗矩阵;为经相模变换所得的该区段内线路单位长度的并联模导纳矩阵。in, is the node-mode voltage matrix obtained through phase-mode transformation; is the node-mode current matrix obtained through phase-mode transformation; is the series-mode impedance matrix of the unit length of the line in the section obtained through phase-mode transformation; is the parallel mode admittance matrix of the line unit length in the section obtained by phase-mode transformation.
(三)分析含分布式电源的配电网内区段的模电流相角差值(3) Analysis of the phase angle difference of the mode current in the section of the distribution network containing distributed power
含分布式电源的配电网内区段的模电流相角差值的定义为:对于含分布式电源的配电网内的某一个区段,令该区段两端的节点编号分别为p、q,则节点p、q处的模电流Ip、Iq所对应的模电流相位角分别为θp、θq,若该区段内模电流的规定正方向为由节点p指向节点q,则可定义该区段的模电流相角差值为该区段两端节点处的模电流相位角度值之差,且有定义式为:Δθ=θp-θq,其中Δθ为节点p、q之间的区段的模电流相角差值。The definition of the mode current phase angle difference of a section in a distribution network containing a distributed power source is as follows: For a certain section in a distribution network containing a distributed power source, let the node numbers at both ends of the section be p, q, then the mode current phase angles corresponding to the mode currents I p and I q at nodes p and q are θ p and θ q respectively. If the specified positive direction of the mode current in this section is from node p to node q, Then the phase angle difference of the mode current in this section can be defined as the difference between the phase angle values of the mode current at the nodes at both ends of the section, and the definition formula is: Δθ=θ p -θ q , where Δθ is the node p, The mode current phase angle difference of the segment between q.
分别对含分布式电源的配电网内的某一个等效单相区段在正常运行与区段内发生故障的情况下的模电流相角差值进行分析:The phase angle difference of the mode current of an equivalent single-phase section in the distribution network with distributed power generation under the condition of normal operation and failure in the section is analyzed respectively:
当该等效单相区段内没有故障,即处在正常运行的情况下时,令该区段两端节点p、q处的模电压分别为节点p、q处的模电流分别为电流的正方向为沿线路径向由节点p指向节点q,该区段的线路长度为L,则可将该等效单相区段的分布参数模型转化为集中参数π型线模型。经相量分析可得,由于线路参数中考虑到并联导纳的影响,该等效单相区段两端节点p、q处的模电流与之间存在一个很小的偏差量有 的存在导致该等效单相区段的模电流相角差值的绝对值为一个大于0°的小角度,其中,可以利用以下公式进行估算:When there is no fault in the equivalent single-phase section, that is, under the condition of normal operation, the modulus voltages at the nodes p and q at both ends of the section are respectively The mode currents at nodes p and q are respectively The positive direction of the current is from node p to node q along the radial direction of the line, and the line length of this section is L, so the distributed parameter model of the equivalent single-phase section can be transformed into a concentrated parameter π-shaped line model. Through phasor analysis, it can be obtained that due to the influence of parallel admittance in the line parameters, the mode current at the nodes p and q at both ends of the equivalent single-phase section and There is a small deviation between Have The existence of leads to the absolute value of the phase angle difference of the modulus current of the equivalent single-phase segment is a small angle greater than 0°, where, It can be estimated using the following formula:
其中,为该等效单相区段一端节点p处的模电压,为该等效单相区段另一端节点q处的模电压;为该等效单相区段内线路单位长度的串联模阻抗,为该等效单相区段内线路单位长度的并联模导纳;L为该等效区段内的线路长度。in, is the modulus voltage at one end node p of the equivalent single-phase section, is the modulus voltage at the node q at the other end of the equivalent single-phase section; is the series mode impedance per unit length of the line in the equivalent single-phase section, is the parallel mode admittance per unit length of the line in the equivalent single-phase section; L is the line length in the equivalent section.
当该等效单相区段内发生故障时,该区段两端节点p、q处的模电压将会分别变为 令节点p、q处的故障模电流分别为故障点所在位置距离节点p的长度为Lp,距离另一节点q的长度为Lq,有L=Lp+Lq。令故障点处的短路阻抗为Zf,可同样地将该区段故障后的等效分布参数线模型简化为集中参数π型线模型,经推导可得和的表达式:When a fault occurs in the equivalent single-phase section, the modulus voltages at the nodes p and q at both ends of the section will become Let the fault mode currents at nodes p and q be respectively The location of the fault point is L p from node p, and L q from another node q, so L=L p +L q . Assuming that the short-circuit impedance at the fault point is Z f , the equivalent distributed parameter line model after the section fault can be simplified into a lumped parameter π-shaped line model, which can be obtained by derivation and expression for:
其中,为该等效单相区段内发生故障后其一端节点p处的模电压,为该等效单相区段内发生故障后其另一端节点q处的模电压;为该等效单相区段内线路单位长度的串联模阻抗,为该等效单相区段内线路单位长度的并联模导纳;Zf为故障点处的短路阻抗;Lp为故障点所在位置距离节点p的长度,Lq为故障点所在位置距离节点q的长度。in, is the modulus voltage at one end node p of the equivalent single-phase section after a fault occurs, is the modulus voltage at the node q at the other end of the equivalent single-phase section after a fault occurs; is the series mode impedance per unit length of the line in the equivalent single-phase section, is the parallel mode admittance per unit length of the line in the equivalent single-phase section; Z f is the short-circuit impedance at the fault point; L p is the distance from the fault point to node p; L q is the distance from the fault point to node The length of q.
经相量分析可得,在该等效单相区段内发生故障的情况下,节点p处的故障模电流与节点q处的故障模电流反向,有与夹角接近180°,这使得该等效单相区段的模电流相角差值的绝对值远大于 According to the phasor analysis, in the case of a fault in the equivalent single-phase section, the fault mode current at node p and the fault mode current at node q reverse, there is and The included angle is close to 180°, which makes the absolute value of the phase angle difference of the mode current of the equivalent single-phase section far greater than
(四)选择一个适宜的模量用于区段故障的判定(4) Select an appropriate modulus for the judgment of section faults
判定故障所用模量的选取规则如下:The selection rules for the modulus used to determine the fault are as follows:
判定故障所用模量的选取规则为:在经相模变换所得的n个相互独立的电气模量中,选择其中某一个特定的模量,使得利用该模量所等效的单相区段内的模电流相角差值可以判定实际该n相区段内发生的各类故障,如:单相接地短路、两相接地短路、两相相间短路、三相短路。可按照下述的经验规则选取故障判定所用的模量:The selection rule for the modulus used to determine the fault is: among the n mutually independent electrical moduli obtained through phase-mode transformation, select a specific modulus so that the The phase angle difference of the analog current can determine various faults that actually occur in the n-phase section, such as: single-phase ground short circuit, two-phase ground short circuit, two-phase phase-to-phase short circuit, and three-phase short circuit. The modulus used for fault determination can be selected according to the following rule of thumb:
①当n=1时,即该区段为单相区段,相模变换矩阵中仅含有一行元素,经相模变换后可得一个等效的模量,仅需直接选择该模量作为故障判定所利用的模量;①When n=1, that is, the section is a single-phase section, and the phase-mode transformation matrix contains only one row of elements, an equivalent modulus can be obtained after phase-mode transformation, and it is only necessary to directly select this modulus as the fault judgment Modulus utilized;
②当n=2时,即该区段为两相区段,相模变换矩阵中含有两行元素,经相模变换后可得两个等效的模量,按照其行标号可令这两个模量分别为模量1和模量2,可优先选择模量1作为故障判定所利用的模量;②When n=2, that is, the segment is a two-phase segment, and the phase-mode transformation matrix contains two rows of elements, after phase-mode transformation, two equivalent moduli can be obtained, and the two modes can be made according to their row labels The quantities are modulus 1 and modulus 2 respectively, and modulus 1 can be preferentially selected as the modulus used for fault judgment;
③当n=3时,即该区段为三相区段,相模变换矩阵中含有三行元素,经相模变换后可得三个等效的模量,按照其行标号可令这三个模量分别为模量1、模量2和模量3:考虑到模量1为地分量,不能反映出三相故障的情况,在该情况下无法判定故障的发生;与此同时,模量2与模量3能够反映出各类故障情况:单相接地短路、两相接地短路、两相相间短路、三相短路,因此,可在模量2与模量3之间选择一个模量作为故障判定所利用的模量,如无特殊要求,可以优先选择模量2。③When n=3, that is, the section is a three-phase section, and the phase-mode transformation matrix contains three rows of elements. After the phase-mode transformation, three equivalent moduli can be obtained. According to the row labels, the three modules can be The quantities are modulus 1, modulus 2 and modulus 3: considering that modulus 1 is the ground component, it cannot reflect the situation of a three-phase fault, and it is impossible to determine the occurrence of the fault in this case; at the same time, modulus 2 And modulus 3 can reflect various fault conditions: single-phase ground short circuit, two-phase ground short circuit, two-phase phase-to-phase short circuit, three-phase short circuit, therefore, a modulus between modulus 2 and modulus 3 can be selected as the As for the modulus used for fault judgment, if there is no special requirement, modulus 2 can be preferred.
(五)进行区段的线路空载检测与模电流差流检测,仅在当区段内的线路非空载并且区段的模电流差流过流的情况下,进行区段故障的判定,得出区段的故障判定结果。(5) Carry out section line no-load detection and mode current differential current detection, and only when the line in the section is not no-load and the mode current difference of the section flows through the current situation, the judgment of the section fault is carried out, The fault judgment result of the section is obtained.
(1)适用于含分布式电源的配电网的区段线路空载检测方法如下:(1) The no-load detection method for section lines suitable for distribution networks with distributed power sources is as follows:
如前所述,本发明在含分布式电源的配电网内的某一个区段内,首先,通过步骤(二)中所述的考虑线路参数非换位平衡的相模变换矩阵的设计方法可得出适用于该区段的相模变换矩阵;然后,依据所述的适用于含分布式电源的配电网的相模变换公式,对该区段进行相模变换;接着,根据步骤(四)中所述的故障判定所利用的模量的选取规则,选出在该区段中所采用的模量的编号;最后,依据适用于含分布式电源的配电网的等效单相区段故障判定方法,在所选定的模量所等效的单相区段中进行故障判定,得出的判定结果即是含分布式电源的配电网中该区段内的故障判定结果。即:在含分布式电源的配电网内的某一个区段中,可通过某一个单一模量判定区段内发生的各类故障:单相接地短路、两相接地短路、两相相间短路、三相短路等故障。As mentioned above, in a certain section of the distribution network containing distributed power sources in the present invention, first, through the design method of the phase-mode transformation matrix that considers the non-transposition balance of line parameters described in step (2), the Obtain the phase-mode transformation matrix that is applicable to this section; Then, carry out phase-mode transformation to this section according to the phase-mode transformation formula that is applicable to the distribution network containing distributed power; Then, according to step (4) in According to the selection rules of the modulus used in the fault judgment described above, select the number of the modulus used in this section; finally, according to the equivalent single-phase section fault judgment applicable to the distribution network containing distributed power method, the fault judgment is carried out in the single-phase section equivalent to the selected modulus, and the judgment result obtained is the fault judgment result in this section in the distribution network containing distributed power generation. That is: in a certain section of the distribution network containing distributed power sources, various faults occurring in the section can be judged by a single modulus: single-phase ground short circuit, two-phase ground short circuit, two-phase phase-to-phase fault Short circuit, three-phase short circuit and other faults.
考虑到在含分布式电源的配电网内,如果其中某一个区段内的线路为空载状态,较低的电流可能造成电流相位角的测量误差增大,进而可能导致适用于含分布式电源的配电网的等效单相区段故障判定方法出现误判的情况,因而,该方法并不适用于空载线路区段内故障的判定。因此,需要对该区段内的线路是否运行在空载状态进行检测,在线路空载时闭锁区段的故障判定。Considering that in the distribution network with distributed power, if the line in one section is in the no-load state, the lower current may cause the measurement error of the current phase angle to increase, which may lead to the application of distributed power. The fault judgment method of the equivalent single-phase section of the power distribution network has a misjudgment, so this method is not suitable for the judgment of the fault in the no-load line section. Therefore, it is necessary to detect whether the line in the section is running in an unloaded state, and block the fault judgment of the section when the line is unloaded.
在第k个模量所等效的单相区段内,令该区段两端的节点分别为节点p、q,则该区段内节点p、q处的节点模电压分别为节点模电流分别为该区段内线路单位长度的串联模阻抗为并联模导纳为若该区段内线路的长度为L,对该等效单相区段的集中参数π型线模型进行分析,可用如下公式估算该区段内的空载模电流幅值:In the single-phase section equivalent to the kth modulus, let the nodes at both ends of the section be nodes p and q respectively, then the node modulus voltages at nodes p and q in this section are respectively The node-mode currents are The series mode impedance per unit length of the line in this section is The parallel mode admittance is If the length of the line in this section is L, the lumped parameter π-shaped line model of this equivalent single-phase section is analyzed, and the no-load mode current amplitude in this section can be estimated by the following formula:
其中,为该等效单相区段内节点p处的节点模电压,为该等效单相区段内节点q处的节点模电压;为该等效单相区段线路单位长度的并联模导纳;L为该等效单相区段内线路的长度。in, is the nodal-mode voltage at node p in the equivalent single-phase segment, is the node-mode voltage at node q in the equivalent single-phase section; is the parallel mode admittance per unit length of the line in the equivalent single-phase section; L is the length of the line in the equivalent single-phase section.
基于以上分析,适用于含分布式电源的配电网的区段线路空载检测方法首先需要已知区段内故障判定所选用的模量编号k,模量k所对应的等效单相区段内两端节点p、q处的节点模电压节点模电流该等效单相区段内线路单位长度的串联模阻抗和并联模导纳该区段内线路的长度L,以及该区段内线路的额定电压幅值Unom。该方法包含如下所示的三个步骤:Based on the above analysis, the section line no-load detection method applicable to the distribution network with distributed power generation first needs to know the modulus number k selected for fault judgment in the section, and the equivalent single-phase area corresponding to the modulus k Nodal modulus voltage at nodes p and q at both ends of the segment Nodal mode current The series mode impedance of the unit length of the line in the equivalent single-phase section and parallel mode admittance The length L of the line in the section, and the rated voltage amplitude U nom of the line in the section. The method consists of three steps as follows:
步骤1、计算并更新模量k对应的等效单相区段的空载模电流判定阈值阈值整定公式如下:Step 1. Calculate and update the no-load mode current judgment threshold of the equivalent single-phase section corresponding to the modulus k The threshold setting formula is as follows:
其中,为该等效单相区段内节点p处的节点模电压,为该等效单相区段内节点q处的节点模电压;Unom为该等效单相区段内线路的额定电压幅值;为该等效单相区段线路单位长度的并联模导纳;L为该等效单相区段内线路的长度;η0k为阈值整定计算的安全系数,一般情况下可取η0k=0.8~1.2。in, is the nodal-mode voltage at node p in the equivalent single-phase segment, is the node mode voltage at node q in the equivalent single-phase section; U nom is the rated voltage amplitude of the line in the equivalent single-phase section; is the parallel mode admittance per unit length of the line in the equivalent single - phase section; L is the length of the line in the equivalent single-phase section; 1.2.
步骤2、判定模量k对应的等效单相区段的空载状态。读取模量k对应的等效单相区段两端节点p、q处的节点模电流其电流的幅值分别对应为依照以下判据进行判定:若有且成立,则该等效单相区段为空载运行状态,即该区段为空载运行状态;若有或成立,则该等效单相区段为非空载运行状态,即该区段为非空载运行状态。Step 2. Determine the no-load state of the equivalent single-phase section corresponding to the modulus k. Read the node-mode current at the nodes p and q at both ends of the equivalent single-phase section corresponding to the modulus k The magnitude of the current corresponds to Judge according to the following criteria: if any and is established, the equivalent single-phase section is in the no-load operation state, that is, the section is in the no-load operation state; if there is or If it is established, the equivalent single-phase section is in the non-no-load operation state, that is, the section is in the non-no-load operation state.
步骤3、输出判定结果。Step 3, outputting the judgment result.
可通过上述的适用于含分布式电源的配电网的区段线路空载检测方法,判定含分布式电源的配电网内的某一个区段是否处于空载运行的状态:如果该区段为空载运行,则闭锁区段的故障判定;如果该区段不是空载运行,则不闭锁区段的故障判定。It can be determined whether a certain section in the distribution network containing distributed If it is no-load operation, then block the fault judgment of the section; if the section is not no-load operation, then do not block the fault judgment of the section.
(2)适用于含分布式电源的配电网内区段的模电流差流检测方法如下:(2) The differential current detection method applicable to the distribution network section containing distributed power is as follows:
为了进一步提升在含分布式电源的配电网内的某一个区段内的故障判定的可靠度,防止误判,必要的情况下,在该区段内的故障判定过程中,在区段线路空载检测之后,还可以增加区段的模电流差流检测,利用区段的模电流差流的过流来启动适用于含分布式电源的配电网的等效单相区段故障判定方法,以判定该模量所等效的单相区段内是否发生故障。一般地,在适用于含分布式电源的配电网的等效单相区段故障判定方法中采用判据一,或判据二中的连续采样点数N=1的情况下,必须增加区段的模电流差流检测这一环节;其他情况下,可根据实际情况以及需要选择是否增加该环节。In order to further improve the reliability of fault judgment in a certain section of the distribution network containing distributed power generation and prevent misjudgment, if necessary, during the fault judgment process in this section, the section line After the no-load detection, it is also possible to increase the differential mode current detection of the section, and use the overcurrent of the differential mode current of the section to start the equivalent single-phase section fault judgment method suitable for distribution networks with distributed power sources , to determine whether a fault occurs in the single-phase section to which the modulus is equivalent. Generally, when criterion 1 is adopted in the equivalent single-phase section fault judgment method applicable to the distribution network with distributed generation, or the number of continuous sampling points in criterion 2 is N=1, the section must be increased In other cases, you can choose whether to add this link according to the actual situation and needs.
所述含分布式电源的配电网内区段的模电流差流的定义为:在含分布式电源的配电网内的某一个区段内,令该区段两端的节点分别为节点p、q,在该区段经过相模变换后的某一个模量k所形成的等效单相区段中的两端节点p、q处的节点模电流分别为令该区段内的电流正方向为由节点p指向节点q,则可定义该区段模量k的模电流差流的计算公式为: The definition of the mode current differential flow of the section in the distribution network containing distributed power sources is: in a certain section in the distribution network containing distributed power sources, let the nodes at both ends of the section be node p , q, the node-mode currents at the nodes p and q in the equivalent single-phase section formed by a certain modulus k after phase-mode transformation in this section are respectively Let the positive direction of the current in this section be from node p to node q, then the modulus current differential flow of modulus k in this section can be defined The calculation formula is:
一般情况下,正常运行的含分布式电源的配电网中的区段的模电流差流的幅值不会超过该区段内线路的空载电流幅值。因此,适用于含分布式电源的配电网内区段的模电流差流检测方法需要已知区段内故障判定所选用的编号为k的模量,模量k所对应的等效单相区段内两端节点p、q处的节点模电压节点模电流该等效单相区段内线路在单位长度下的串联模阻抗和并联模导纳该区段内线路的长度L,以及该区段内线路的额定电压幅值Unom。所述模电流差流检测方法包含如下所示的四个步骤:In general, the amplitude of the differential mode current of a section in a distribution network with distributed power generation in normal operation will not exceed the no-load current amplitude of the line in this section. Therefore, the modulus current differential current detection method suitable for the section of the distribution network containing distributed power needs to know the modulus numbered k used for fault judgment in the section, and the equivalent single-phase current corresponding to the modulus k Nodal modulus voltage at nodes p and q at both ends of the segment Nodal mode current The series mode impedance of the line in the equivalent single-phase section under unit length and parallel mode admittance The length L of the line in the section, and the rated voltage amplitude U nom of the line in the section. The method for detecting the differential current of the molded current includes four steps as follows:
步骤1、计算并更新模量k对应的等效单相区段的模电流差流的判定阈值阈值整定公式如下:Step 1. Calculate and update the judgment threshold of the modulus current differential current in the equivalent single-phase section corresponding to the modulus k The threshold setting formula is as follows:
其中,为该等效单相区段内节点p处的节点模电压,为该等效单相区段内节点q处的节点模电压;Unom为该等效单相区段内线路的额定电压幅值;为该等效单相区段线路单位长度的并联模导纳;L为该等效单相区段内线路的长度;ηdk为阈值整定计算的安全系数,一般情况下可取ηdk=1.1~1.3。in, is the nodal-mode voltage at node p in the equivalent single-phase segment, is the node mode voltage at node q in the equivalent single-phase section; U nom is the rated voltage amplitude of the line in the equivalent single-phase section; is the parallel mode admittance per unit length of the line in the equivalent single-phase section; L is the length of the line in the equivalent single -phase section; 1.3.
步骤2、计算模量k对应的等效单相区段的模电流差流。读取模量k对应的等效单相区段两端节点p、q处的节点模电流依据含分布式电源的配电网内区段的模电流差流的定义,计算该区段模量k的模电流差流 Step 2. Calculating the differential modulus current of the equivalent single-phase section corresponding to the modulus k. Read the node-mode current at the nodes p and q at both ends of the equivalent single-phase section corresponding to the modulus k According to the definition of the modulus current differential flow in the section of the distribution network containing distributed power generation, calculate the modulus k of the modulus current differential flow of the section
步骤3、判定该区段模量k的模电流差流是否过流,判据为:当该区段模量k的模电流差流幅值大于判定阈值时,即时,则该区段的模电流差流过流;当该区段模量k的模电流差流幅值小于或等于判定阈值时,即时,则该区段的模电流差流不过流。Step 3. Determine whether the modulus k of the section modulus k is overcurrent, and the criterion is: when the magnitude of the modulus k of the section modulus k greater than the judgment threshold when , then the mode current difference of this section flows through the current; when the mode current difference amplitude of the section modulus k Less than or equal to the decision threshold when , the mode current difference in this section cannot flow.
步骤4、输出判定结果。Step 4, outputting the judgment result.
利用以上方法可以在含分布式电源的配电网内的区段中判定用于故障判定的模量的模电流差流是否过流,若过流,则启动区段的故障判定,对该模量所等效的单相区段内是否发生故障进行判定;若不过流,则闭锁区段的故障判定,在该模量所等效的单相区段中不进行故障的判定。Using the above method, it is possible to determine whether the modulus current differential current used for fault judgment is overcurrent in the section of the distribution network containing distributed power. If it is overcurrent, the fault judgment of the section will be started. Determine whether a fault occurs in the single-phase section to which the modulus is equivalent; if there is no flow, then block the fault judgment of the section, and do not perform fault judgment in the single-phase section to which the modulus is equivalent.
(3)适用于含分布式电源的配电网的等效单相区段故障判定方法如下:(3) The equivalent single-phase section fault judgment method applicable to the distribution network with distributed generation is as follows:
通过选定的用于区段故障判定的模量所等效的单相区段内的故障判定,可等效地判定实际区段内发生的各类故障,如:单相接地短路、两相接地短路、两相相间短路以及三相短路故障,得出区段的故障判定结果。Through the fault judgment in the single-phase section equivalent to the selected modulus for section fault judgment, various faults that occur in the actual section can be equivalently judged, such as: single-phase ground short circuit, two-phase Ground short circuit, two-phase phase-to-phase short circuit and three-phase short circuit fault, get the fault judgment result of the section.
若区段内故障判定所选用的模量的编号为k,那么,在模量k所等效的单相区段内可通过设置合理的区段模电流相角差值绝对值的阈值σk,以判断该等效单相区段内是否发生故障,判据如下:If the number of the modulus selected for fault judgment in the section is k, then, in the single-phase section equivalent to the modulus k, a reasonable threshold σ k of the absolute value of the phase angle difference of the section mode current can be set , to judge whether there is a fault in the equivalent single-phase section, the criterion is as follows:
判据一:当该等效单相区段的模电流相角差值的绝对值小于或等于其阈值σk,即时,该区段内没有故障;当该等效单相区段的模电流相角差值的绝对值大于其阈值σk,即时,该区段内发生故障。Criterion 1: When the absolute value of the phase angle difference of the modular current in the equivalent single-phase section is less than or equal to its threshold σ k , that is When , there is no fault in this section; when the absolute value of the phase angle difference of the modulus current in the equivalent single-phase section greater than its threshold σ k , that is , a fault occurs in this section.
判据二:在实际应用情况下,为了降低该方法误动作的可能性,避免瞬时故障造成区段线路的跳闸,可以采用以下改进型判据:若该等效单相区段的模电流相角差值的绝对值大于其阈值σk,即且在连续N个采样点处均成立时,则判定该区段内发生故障;否则,该区段内没有故障。其中,N≥1,且N∈Z,N的取值可以根据实际情况以及需要进行选取,N值越大,区段故障判定的灵敏度越低、快速性越差;当N=1时,该判据与判据一等效。Criterion 2: In practical applications, in order to reduce the possibility of misoperation of this method and avoid tripping of section lines caused by instantaneous faults, the following improved criterion can be adopted: if the analog current phase of the equivalent single-phase section Absolute value of angular difference greater than its threshold σ k , that is And when it is true at consecutive N sampling points, it is determined that there is a fault in this section; otherwise, there is no fault in this section. Among them, N≥1, and N∈Z, the value of N can be selected according to the actual situation and needs, the larger the value of N, the lower the sensitivity and the worse the rapidity of section fault judgment; when N=1, the The criterion is equivalent to criterion one.
其中,等效单相区段的模电流相角差值的阈值σk的整定不仅与该等效单相区段正常运行时的模电流相角差值的绝对值有关,还与电流测量的相位角度误差δ以及角度数值计算误差ε有关,阈值σk的整定公式为:Among them, the setting of the threshold σ k of the phase angle difference of the mode current in the equivalent single-phase section is not only related to the absolute value of the phase angle difference of the mode current in the normal operation of the equivalent single-phase section, but also related to the current measurement The phase angle error δ is related to the angle numerical calculation error ε, and the setting formula of the threshold σ k is:
上式中,为该等效单相区段两端节点p处的节点模电压,为该等效单相区段两端节点q处的节点模电压;为该等效单相区段线路单位长度的串联模阻抗,为该等效单相区段线路单位长度的并联模导纳;L为该等效单相区段内线路的长度;ηSk为阈值整定的安全系数,一般情况下可取ηSk=1~1.5。In the above formula, is the nodal mode voltage at the node p at both ends of the equivalent single-phase section, is the node-mode voltage at node q at both ends of the equivalent single-phase section; is the series mode impedance per unit length of the equivalent single-phase section line, is the parallel mode admittance per unit length of the line in the equivalent single-phase section; L is the length of the line in the equivalent single-phase section; .
一般情况下,电流测量装置中的电流互感器的选型在参考电流互感器10%误差曲线的条件下将会产生±7°的电流相位角度测量误差,即δ=7°;电流相位角度的数值计算误差往往较小,往往可以忽略不计,如需要考虑以提升方法的可靠性,可以根据实际情况选取ε=0.5°~1°。(六)利用含分布式电源的配电网内各个区段的故障判定结果,根据系统故障判定矩阵的生成与判定方法,对该含分布式电源的配电网进行故障判定与故障定位,并得到当前时刻下的故障定位结果。In general, the selection of the current transformer in the current measuring device will produce a current phase angle measurement error of ±7° under the condition of referring to the 10% error curve of the current transformer, that is, δ=7°; Numerical calculation errors are often small and often negligible. If it is necessary to consider improving the reliability of the method, ε=0.5°~1° can be selected according to the actual situation. (6) Using the fault judgment results of each section in the distribution network containing distributed power, according to the generation and judgment method of the system fault judgment matrix, perform fault judgment and fault location on the distribution network containing distributed power, and Obtain the fault location result at the current moment.
系统故障判定矩阵的生成与判定方法如下:The generation and judgment methods of the system fault judgment matrix are as follows:
步骤1、读取含分布式电源的配电网内各个区段的故障判定结果,生成系统故障判定矩阵Γ。所述的系统故障判定矩阵Γ为一个行矩阵,且有Γ=[γ1 γ2 … γh],其中,h为该含分布式电源的配电网内区段的总个数;γi为第i个区段的故障状态(i=1,…,h),若该区段内部发生故障,则γi=1;若该区段内部没有故障,则γi=0。Step 1. Read the fault judgment results of each section in the distribution network containing distributed power, and generate the system fault judgment matrix Γ. The system failure judgment matrix Γ is a row matrix, and Γ=[γ 1 γ 2 ... γ h ], where h is the total number of sections in the distribution network containing distributed power; γ i is the failure state of the i-th section (i=1,...,h), if a failure occurs in the section, then γ i =1; if there is no failure in the section, then γ i =0.
步骤2、根据系统故障判定矩阵Γ作如下进一步判定,判据为:若系统故障判定矩阵Γ中所有的元素的值均为0,则该含分布式电源的配电网中没有故障发生,处于正常运行的状态;若系统故障判定矩阵Γ中存在某一个或某几个元素的值为1,则该含分布式电源的配电网内存在故障,且故障点分别在系统故障判定矩阵Γ中元素值为1的元素编号所对应的区段中。Step 2. Make the following further judgments according to the system fault judgment matrix Γ, the criterion is: if the value of all elements in the system fault judgment matrix Γ is 0, then there is no fault in the distribution network containing distributed generation, and it is in the The state of normal operation; if there is one or several elements in the system fault judgment matrix Γ with a value of 1, then there is a fault in the distribution network containing distributed power, and the fault points are in the system fault judgment matrix Γ In the segment corresponding to the element number whose element value is 1.
步骤3、输出故障定位结果:若该含分布式电源的配电网内没有故障,则输出“正常运行”;若该含分布式电源的配电网内发生故障,则输出“系统故障”,并接着输出所有的故障点所在的区段编号。Step 3. Output the fault location result: if there is no fault in the distribution network containing distributed power, output "normal operation"; if there is a fault in the distribution network containing distributed power, output "system failure", And then output the section numbers where all the fault points are located.
本发明适用于含分布式电源的配电网的自适应故障区段定位方法能够在系统内进行实时在线的故障定位,并能够在系统发生故障时快速隔离故障区段。实时在线应用情况下的该方法包含以下四个步骤:The self-adaptive fault section location method applicable to the distribution network with distributed power sources of the present invention can perform real-time online fault location in the system, and can quickly isolate the fault section when the system fails. The method in the case of a real-time online application comprises the following four steps:
步骤1、根据含分布式电源的配电网的区段划分方法与编号要求,在一个含分布式电源的配电网内划分出若干个双端无分支的区段,并对该含分布式电源的配电网内的各个节点、区段按要求编号。Step 1. According to the section division method and numbering requirements of the distribution network containing distributed Each node and section in the distribution network of the power supply shall be numbered as required.
步骤2、将适用于含分布式电源的配电网的自适应区段故障判定方法应用于该含分布式电源的配电网中的每一个区段,利用该方法判定当前时刻下该含分布式电源的配电网内的各个区段内部是否发生故障,并得出判定结果。Step 2. Apply the self-adaptive section fault judgment method applicable to the distribution network containing distributed power to each section in the distribution network containing distributed Whether there is a fault in each section of the distribution network of the conventional power supply, and the judgment result is obtained.
步骤3、利用含分布式电源的配电网内各个区段的故障判定结果,根据系统故障判定矩阵的生成与判定方法,对该含分布式电源的配电网进行故障判定与故障定位,并得到当前时刻下的故障定位结果。Step 3. Using the fault judgment results of each section in the distribution network containing distributed power sources, according to the generation and judgment method of the system fault judgment matrix, perform fault judgment and fault location on the distribution network containing distributed power sources, and Obtain the fault location result at the current moment.
步骤4、进入当前时刻之后的下一个时刻,返回步骤2。Step 4. Enter the next moment after the current moment, and return to step 2.
利用上述方法,可在含分布式电源的配电网内实现自适应的在线故障区段定位。其中,在所述的适用于含分布式电源的配电网的自适应区段故障判定方法中,已知该区段为一个n相区段,且该区段两端的节点分别为节点p和q,该区段的线路长度为L,该区段内线路的额定电压幅值为Unom,以及该区段内的线路单位长度的串联电阻矩阵R(n)、串联电感矩阵L(n)和并联电容矩阵C(n),根据实际情况确定是否在该区段内启用模电流差流检测。则该方法包含以下十一个步骤:Using the above method, adaptive online fault section location can be realized in the distribution network with distributed power generation. Wherein, in the adaptive section fault determination method applicable to distribution networks containing distributed power sources, it is known that the section is an n-phase section, and the nodes at both ends of the section are nodes p and q, the length of the line in this section is L, the rated voltage amplitude of the line in this section is U nom , and the series resistance matrix R (n) and series inductance matrix L (n) of the line unit length in this section and the parallel capacitance matrix C (n) , determine whether to enable differential current detection of the mode current in this section according to the actual situation. Then the method includes the following eleven steps:
步骤1、输入当前时刻下所需的电气变量。所需的电气变量包含:该区段线路上的相电压、相电流的基波频率f;该区段的两端节点p、q处的n相节点电压矩阵与n相节点电流矩阵 Step 1. Input the required electrical variables at the current moment. The required electrical variables include: the phase voltage on the line of the section, the fundamental frequency f of the phase current; the n-phase node voltage matrix at the nodes p and q at both ends of the section and n-phase node current matrix
步骤2、利用考虑线路参数非换位平衡的相模变换矩阵的设计方法,设计一个可用于该n相区段的相模变换矩阵Φ(n) T。Step 2. Design a phase-mode transformation matrix Φ (n) T that can be used in the n-phase section by using the design method of the phase-mode transformation matrix considering the non-transposition balance of line parameters.
步骤3、利用相模变换矩阵Φ(n) T,依据适用于含分布式电源的配电网的相模变换公式,对该区段的两端节点p、q处的n相节点电压矩阵与n相节点电流矩阵分别作相模变换,得出该区段两端节点p、q处的模电压矩阵与模电流矩阵并求取该区段线路单位长度的串联模阻抗矩阵与并联模导纳矩阵 Step 3. Using the phase-mode transformation matrix Φ (n) T , according to the phase-mode transformation formula applicable to the distribution network containing distributed power sources, the n-phase node voltage matrix at the nodes p and q at both ends of the section and n-phase node current matrix Perform phase-to-mode transformation respectively to obtain the mode voltage matrix at nodes p and q at both ends of the section and mode current matrix And calculate the series mode impedance matrix of the unit length of the line in this section with parallel mode admittance matrix
步骤4、根据故障判定所利用的模量的选取规则,选出在该区段中所采用的模量的编号,记为k。与此同时,基于选定的模量k,提取以下所需的量值,它们分为为:该区段两端节点p、q处的第k个模电压与第k个模电流该区段经相模变换后所得第k个模量所等效的线路单位长度的串联模阻抗与并联模导纳 Step 4. Select the number of the modulus used in this section according to the selection rule of the modulus used for fault judgment, and denote it as k. At the same time, based on the selected modulus k, the following required magnitudes are extracted, which are divided into: kth modulus voltage at nodes p, q at both ends of the segment with the kth mode current The series mode impedance of the unit length of the line equivalent to the kth modulus obtained after the phase-mode transformation of this section with parallel mode admittance
步骤5、利用适用于含分布式电源的配电网的区段线路空载检测方法,判定该区段是否为空载运行。若该区段处于空载运行状态,则进入当前时刻之后的下一个时刻并返回步骤1;若该区段处于非空载运行状态,则进入步骤6。Step 5. Using the section line no-load detection method applicable to the distribution network with distributed power sources, determine whether the section is in no-load operation. If the section is in the no-load running state, enter the next moment after the current moment and return to step 1; if the section is in the non-no-load running state, go to step 6.
步骤6、判断是否需要进行区段的模电流差流检测,若是,则进入步骤7;若否,则进入步骤8。Step 6, judging whether it is necessary to detect the differential mode current of the section, if yes, go to step 7; if not, go to step 8.
步骤7、利用适用于含分布式电源的配电网内区段的模电流差流检测方法,判定该区段内模量k对应的模电流差流是否过流。若该区段内模量k对应的模电流差流未发生过流,则进入当前时刻之后的下一个时刻并返回步骤1;若该区段内模量k对应的模电流差流发生过流,则进入步骤8。Step 7. Using the differential mode current detection method applicable to the section of the distribution network containing distributed power sources, determine whether the differential mode current corresponding to the modulus k in the section is overcurrent. If the modulus k corresponding to the modulus k in this section does not over-current, enter the next moment after the current moment and return to step 1; , go to step 8.
步骤8、在所选定的第k个模量所等效的单相区段中,利用该区段两端节点p、q处的第k个模电流矩阵经傅里叶变换求得与其模电流相对应的模电流相位角依据含分布式电源的配电网内区段的电流相角差值的定义,计算该等效单相区段的模电流相角差值的绝对值 Step 8. In the single-phase section equivalent to the selected kth modulus, use the kth mode current matrix at the nodes p and q at both ends of the section Obtain the phase angle of the mode current corresponding to the mode current through Fourier transform According to the definition of the current phase angle difference of the section in the distribution network with distributed power generation, the absolute value of the modular current phase angle difference of the equivalent single-phase section is calculated
步骤9、在第k个模量所等效的单相区段中,利用适用于含分布式电源的配电网的等效单相区段故障判定方法,首先依据该方法中提出的阈值整定公式实时更新判定阈值,然后利用该等效单相区段的模电流相角差值绝对值依照该方法中提出的判据对该等效单相区段内是否发生故障进行判定,得出判定结果。Step 9. In the single-phase section equivalent to the k-th modulus, use the equivalent single-phase section fault judgment method suitable for distribution networks with distributed power sources, and first set the threshold according to the method proposed The formula updates the judgment threshold in real time, and then uses the absolute value of the phase angle difference of the mode current in the equivalent single-phase section According to the criterion proposed in the method, whether a fault occurs in the equivalent single-phase section is judged, and the judgment result is obtained.
步骤10、利用步骤九得出的判定结果,进行如下判定:若判定结果为没有故障,则该区段内部没有故障,保存故障判定结果,然后进入当前时刻之后的下一个时刻并返回步骤1;若判定结果为发生故障,则该区段内部发生故障,并进入下一个步骤。Step 10, use the judgment result obtained in step 9 to make the following judgment: if the judgment result is no fault, then there is no fault inside the section, save the fault judgment result, and then enter the next time after the current time and return to step 1; If the judgment result is that a fault occurs, a fault occurs inside the section, and the next step is entered.
步骤11、保存故障判定结果,立即发出保护动作信号,以迅速隔离该故障区段。待故障经检查和维修排除后,通过人工控制返回步骤1。Step 11. Save the fault judgment result, and immediately send out a protection action signal to quickly isolate the faulty section. After the fault is checked and repaired, return to step 1 through manual control.
利用上述适用于含分布式电源的配电网的自适应区段故障判定方法,能够在含分布式电源的配电网内的任意一个区段内,实现实时快速、准确可靠的区段内故障的判定。鉴于该方法通过傅里叶变换从节点电流中得出与其对应的电流相位角,考虑到傅里叶变换需要至少一个电流周波长度的初始化时间,若含分布式电源的配电网内的电压、电流基波频率为f,则这个初始化时间长度为1/f,因此,在含分布式电源的配电网开始运行后,经系统初始化,可在该含分布式电源的配电网的任意一个区段内应用该方法,以实现对该区段内部发生的故障的判定。此外,该方法在每一个采样周期都可对该方法内所用的所有判定阈值进行计算整定并进行实时更新,保证了该方法的自适应性,应用该方法的采样频率应不低于10kHz。Utilizing the above-mentioned self-adaptive section fault judgment method applicable to distribution network with distributed generation, it is possible to realize real-time, fast, accurate and reliable intra-section fault detection in any section of distribution network with distributed generation judgment. In view of the fact that the method obtains the corresponding current phase angle from the node current through Fourier transform, and considering that the Fourier transform requires at least one current cycle length initialization time, if the voltage in the distribution network including distributed power, If the current fundamental frequency is f, then the length of initialization time is 1/f. Therefore, after the distribution network with distributed The method is applied in the section to realize the judgment of the faults in the section. In addition, this method can calculate, set and update all the judgment thresholds used in the method in each sampling period, which ensures the adaptability of the method. The sampling frequency of the method should not be lower than 10kHz.
本发明含分布式电源的配电网的自适应故障区段定位方法提出了一种基于模电流相角差值的、适用于含分布式电源的配电网的自适应故障区段定位方法,与现有技术相比,该方法所能产生的有益效果是:The self-adaptive fault section location method of the distribution network containing distributed power sources in the present invention proposes an adaptive fault section location method based on the phase angle difference of the mode current and applicable to the distribution network containing distributed power sources, Compared with prior art, the beneficial effect that this method can produce is:
第一,本发明可用于含分布式电源的配电网的故障定位,能够在多种故障情况下:单相接地短路、两相接地短路、两相相间短路、三相短路,准确可靠的实现故障的区段定位,且不受各类非故障扰动的影响,具备判定阈值的整定计算与实时更新机制,有着良好的自适应性;First, the present invention can be used for fault location of a distribution network containing distributed power sources, and can accurately and reliably locate faults in a variety of fault situations: single-phase ground short circuit, two-phase ground short circuit, two-phase phase-to-phase short circuit, three-phase short circuit Realize the section location of the fault, and is not affected by various non-fault disturbances, has the setting calculation and real-time update mechanism of the judgment threshold, and has good adaptability;
第二,本发明提出的故障定位方法是一种在线故障定位方法,能够在含分布式电源的配电网运行过程中实时的进行快速的故障判定与故障定位,有利于含分布式电源的配电网内故障的快速处理与小范围隔离;Second, the fault location method proposed by the present invention is an online fault location method, which can quickly perform fault judgment and fault location in real time during the operation of the distribution network containing distributed power sources, which is beneficial to distribution networks containing distributed power sources Rapid processing and small-scale isolation of faults in the power grid;
第三,本发明提出的故障定位方法的配置十分灵活且具有通用性,可在含分布式电源的配电网内同时对多个多种类型的区段:单相区段、两相区段、三相区段内发生的各类故障进行准确的故障判定与定位。Thirdly, the configuration of the fault location method proposed by the present invention is very flexible and versatile, and can simultaneously detect multiple types of sections in a distribution network containing distributed power sources: single-phase sections, two-phase sections , All kinds of faults that occur in the three-phase section are accurately judged and located.
附图说明Description of drawings
图1为本发明的方法原理图;Fig. 1 is a schematic diagram of the method of the present invention;
图2为应用本发明的含分布式电源的配电网实施例的结构示意图;Fig. 2 is a schematic structural diagram of an embodiment of a distribution network including a distributed power supply applying the present invention;
图3为实施例的信息处理与数据计算模块的工作原理图;Fig. 3 is the working principle diagram of the information processing and data calculation module of the embodiment;
图4为实施例的故障判定与保护控制模块的工作原理图;Fig. 4 is the working principle diagram of the fault judgment and protection control module of the embodiment;
图5为实施例的控制中心的工作原理图。Fig. 5 is a working principle diagram of the control center of the embodiment.
具体实施方式Detailed ways
下面结合附图和具体实施方式对本发明做进一步说明。The present invention will be further described below in conjunction with the accompanying drawings and specific embodiments.
图1为本发明的方法原理图。在一个含分布式电源的配电网内,在已知该含分布式电源的配电网内所有线路参数的条件下,如图1所示,首先执行步骤001,将该含分布式电源的配电网分为多个双端无分支区段,对该含分布式电源的配电网内的各个节点和区段编号。然后,执行步骤002,采集该含分布式电源的配电网内的各个区段内的信息,执行步骤003,对区段内的电气量做相模变换,将区段内耦合的电气量转化为相互独立的模量,得到各个模量所对应的模电压、模电流、线路单位长度的串联模阻抗与并联模导纳。接着,执行步骤004,选取判定故障所用的模量,经步骤005对区段的线路进行空载检测,若区段的线路为非空载,则进入步骤006;若区段的线路为空载,则返回步骤002。进入步骤006后,对区段进行模电流差流检测,若区段的模电流差流过流,则进入步骤007;若区段的模电流差流不过流,则返回步骤002。执行步骤007,求取所选取的用于区段故障判定的模量对应区段的模电流相角差值的绝对值,并执行步骤008,进行区段的故障判定,通过所求的模电流相角差值的绝对值与判定阈值的比较得出区段的故障判定结果。最后,利用该含分布式电源的配电网内所有的区段的故障判定结果,执行步骤009生成系统故障判定矩阵,执行步骤010对系统故障判定矩阵进行判定,得出故障定位结果,然后返回步骤002。Fig. 1 is the schematic diagram of the method of the present invention. In a distribution network containing distributed power, under the condition that all line parameters in the distribution network containing distributed The distribution network is divided into multiple double-ended branchless sections, and each node and section in the distribution network containing distributed power is numbered. Then, step 002 is executed to collect information in each section of the distribution network containing distributed power, and step 003 is executed to perform phase-to-mode transformation on the electrical quantity in the section, and convert the coupled electrical quantity in the section into The moduli are independent of each other, and the mode voltage, mode current, series mode impedance and parallel mode admittance of the line unit length corresponding to each modulus are obtained. Then, execute step 004, select the modulus used for judging the fault, carry out no-load detection to the line of the section through step 005, if the line of the section is non-empty load, then enter step 006; if the line of the section is no-load , return to step 002. After entering step 006, the differential mode current detection of the section is performed, and if the differential mode current of the section is overcurrent, then enter step 007; if the differential mode current of the section is not overcurrent, return to step 002. Execute step 007 to obtain the absolute value of the phase angle difference of the modulus corresponding to the selected modulus for segment fault judgment, and execute step 008 to perform fault judgment on the segment, and pass the obtained modulus current The comparison between the absolute value of the phase angle difference and the judgment threshold gives the fault judgment result of the section. Finally, use the fault judgment results of all sections in the distribution network containing distributed power, execute step 009 to generate a system fault judgment matrix, execute step 010 to judge the system fault judgment matrix, obtain the fault location result, and then return Step 002.
图2为应用本发明的含分布式电源的配电网实施例的结构示意图。如图2所示,在一个含分布式电源的配电网内,其母线101上接有分布式电源102和负载103。在该含分布式电源的配电网内,依据含分布式电源的配电网的区段划分方法与编号要求,将该配电网划分为若干个双端无分支的区段104,且区段104两端的节点分别为节点p105和节点q106,分别在节点p105和节点q106处配置一组测量元件107和断路器108。其中,测量元件107能够测量区段104内节点p105和节点q106处的节点电压信号与节点电流信号;断路器108可在区段104发生故障时切断故障回路,将故障的区段104隔离。定义区段104的电流正方向109为由节点p105指向节点q106,则可令节点p105为上游节点,节点q106为下游节点,并在上游的节点p105处配置故障定位主装置110,在下游的节点q106处配置故障定位从装置111,故障定位主装置110与故障定位从装置111通过光纤通信112互联,且故障定位主装置110与故障定位从装置111可接收来自测量元件107的测量信号,并能够向断路器108发送跳闸信号以控制断路器的动作。故障定位主装置110中包含信息处理与数据计算模块113和故障判定与保护控制模块114两个部分,故障定位从装置111中仅包含信息处理与数据计算模块113这一部分。信息处理与数据计算模块113能够将测量元件107采集到的测量信号进行变换、处理,并通过计算得出故障判定所需要的信息、量值,并将这些信息、量值的数据发送给故障判定与保护控制模块114;故障判定与保护控制模块114利用故障定位主装置110和故障定位从装置111内的信息处理与数据计算模块113发送的数据,对区段104内是否发生故障进行判定,并将故障判定结果通过通信链路116发送至控制中心115,当判定区段104内发生故障时,故障判定与保护控制模块114将会发出跳闸信号,该跳闸信号可通过故障定位主装置110经光纤通信112发送至故障定位从装置111,利用故障定位主装置110和故障定位从装置111控制断路器108动作,完成故障区段104的隔离。控制中心115通过通信链路116与该含分布式电源的配电网内的所有的区段104内故障定位主装置110实现交互,可接收各个区段104内的故障定位主装置110发送的故障判定结果,生成故障判定矩阵,并对整个含分布式电源的配电网内的各个区段104是否发生故障进行判定,可将故障所在的区段编号作为故障定位结果输出,最终实现含分布式电源的配电网内的在线故障区段定位。Fig. 2 is a schematic structural diagram of an embodiment of a distribution network including distributed power sources to which the present invention is applied. As shown in FIG. 2 , in a distribution network including distributed power sources, distributed power sources 102 and loads 103 are connected to the busbar 101 . In the distributed power distribution network, according to the section division method and numbering requirements of the distributed power distribution network, the distribution network is divided into several double-ended and branchless sections 104, and the section The nodes at both ends of the section 104 are node p105 and node q106 respectively, and a group of measuring elements 107 and circuit breakers 108 are arranged at node p105 and node q106 respectively. Among them, the measuring element 107 can measure the node voltage signal and the node current signal at the node p105 and node q106 in the section 104; the circuit breaker 108 can cut off the fault loop when the section 104 fails, and isolate the failed section 104. Define the positive current direction 109 of the section 104 as pointing from the node p105 to the node q106, then the node p105 can be set as the upstream node, and the node q106 can be the downstream node, and the fault location master device 110 is configured at the upstream node p105, and the downstream node The fault location slave device 111 is configured at q106, and the fault location master device 110 and the fault location slave device 111 are interconnected through optical fiber communication 112, and the fault location master device 110 and the fault location slave device 111 can receive the measurement signal from the measuring element 107, and can A trip signal is sent to the circuit breaker 108 to control the operation of the circuit breaker. The fault location master device 110 includes two parts, the information processing and data calculation module 113 and the fault judgment and protection control module 114 , and the fault location slave device 111 only includes the information processing and data calculation module 113 . The information processing and data calculation module 113 can transform and process the measurement signal collected by the measuring element 107, and obtain the information and value required for fault judgment through calculation, and send the data of these information and value to the fault judgment and protection control module 114; the fault determination and protection control module 114 utilizes the data sent by the information processing and data calculation module 113 in the fault location master device 110 and the fault location slave device 111 to determine whether a fault occurs in the section 104, and The fault judgment result is sent to the control center 115 through the communication link 116. When a fault occurs in the judgment section 104, the fault judgment and protection control module 114 will send a trip signal, which can be transmitted through the fault location main device 110 through the optical fiber The communication 112 is sent to the fault location slave device 111 , and the fault location master device 110 and the fault location slave device 111 are used to control the action of the circuit breaker 108 to complete the isolation of the fault section 104 . The control center 115 interacts with the fault location master devices 110 in all the sections 104 in the distribution network containing distributed power through the communication link 116, and can receive faults sent by the fault location master devices 110 in each section 104 Judgment result, generate a fault judgment matrix, and judge whether each section 104 in the entire distribution network containing distributed On-line fault section location within a power distribution network.
图3为实施例的信息处理与数据计算模块113的工作原理图。如图3所示,信息处理与数据计算模块113的工作原理如下所述:首先,信息处理与数据计算模块113经信息采集201可得节点处的各相电压、电流信息202,进而可知线路的相数204。利用节点处的各相电压、电流信息202,经锁相环PLL 203可得电压、电流的基波频率205。接着,利用线路的相数204、基波频率205、线路单位长度的串联电阻矩阵206、线路单位长度的串联电感矩阵207以及线路单位长度的并联电容矩阵208,依照考虑线路参数非换位平衡的相模变换矩阵的设计方法209,可得出相模变换矩阵210、线路单位长度的串联阻抗矩阵211以及线路单位长度的并联导纳矩阵212。接下来,利用节点处的各相电压、电流信息202、相模变换矩阵210、线路单位长度的串联阻抗矩阵211以及线路单位长度的并联导纳矩阵212,依据适用于含分布式电源的配电网的相模变换公式213,可得出节点模电流矩阵214、节点模电压矩阵215、线路单位长度的串联模阻抗矩阵216以及线路单位长度的并联模导纳矩阵217。然后,根据故障判定所利用的模量的选取规则,实现故障判定所利用的模量k的选取218,在节点模电流矩阵214、节点模电压矩阵215、线路单位长度的串联模阻抗矩阵216以及线路单位长度的并联模导纳矩阵217中,选出节点处k模电流219、节点处k模电压220、线路单位长度的串联k模阻抗221以及线路单位长度的并联k模导纳222。其中,节点处k模电流219经快速傅里叶变换FFT 223可求得节点处k模电流相位角224。最终,将节点处k模电流相位角224、节点处k模电流219、节点处k模电压220、线路单位长度的串联k模阻抗221以及线路单位长度的并联k模导纳222进行数据整合,发送数据至故障定位主装置中的故障判定与保护控制模块225。FIG. 3 is a working principle diagram of the information processing and data calculation module 113 of the embodiment. As shown in Figure 3, the working principle of the information processing and data calculation module 113 is as follows: First, the information processing and data calculation module 113 can obtain the voltage and current information 202 of each phase at the node through the information collection 201, and then know the line The number of phases is 204. Using the voltage and current information 202 of each phase at the node, the fundamental frequency 205 of the voltage and current can be obtained through the phase-locked loop PLL 203 . Next, using the phase number 204 of the line, the fundamental frequency 205, the series resistance matrix 206 of the line unit length, the series inductance matrix 207 of the line unit length, and the parallel capacitance matrix 208 of the line unit length, according to the non-transposition balance considering line parameters The design method 209 of the phase-mode transformation matrix can obtain the phase-mode transformation matrix 210 , the series impedance matrix 211 of the unit length of the line, and the parallel admittance matrix 212 of the unit length of the line. Next, using the phase voltage and current information 202 at the node, the phase-to-mode transformation matrix 210, the series impedance matrix 211 of the unit length of the line, and the parallel admittance matrix 212 of the unit length of the line, according to the distribution network with distributed power According to the phase-mode transformation formula 213, the node-mode current matrix 214, the node-mode voltage matrix 215, the series-mode impedance matrix 216 of the line unit length, and the parallel-mode admittance matrix 217 of the line unit length can be obtained. Then, according to the selection rules of the modulus used for fault judgment, the selection 218 of the modulus k used for fault judgment is realized. In the node mode current matrix 214, node mode voltage matrix 215, line unit length series mode impedance matrix 216 and In the parallel mode admittance matrix 217 per unit length of the line, the k-mode current 219 at the node, the k-mode voltage 220 at the node, the series k-mode impedance 221 per unit length of the line, and the parallel k-mode admittance 222 per unit length of the line are selected. Wherein, the k-mode current 219 at the node is subjected to a fast Fourier transform FFT 223 to obtain a phase angle 224 of the k-mode current at the node. Finally, the k-mode current phase angle 224 at the node, the k-mode current 219 at the node, the k-mode voltage 220 at the node, the series k-mode impedance 221 per unit length of the line, and the parallel k-mode admittance 222 per unit length of the line are integrated, Send the data to the fault judgment and protection control module 225 in the fault location master device.
在实际应用中需要注意的是,图2中所示的位于同一个区段104内的一组故障定位主装置110与故障定位从装置111中的信息处理与数据计算模块113的工作原理中的具体方法技术细节,例如:图3中所示的考虑线路参数非换位平衡的相模变换矩阵的设计方法209、适用于含分布式电源的配电网的相模变换公式213、以及故障判定所利用的模量k的选取218等,应始终保持一致。In practical applications, it should be noted that the information processing and data calculation module 113 in a group of fault location master devices 110 and fault location slave devices 111 located in the same section 104 shown in FIG. The technical details of the specific method, for example: the design method 209 of the phase-mode transformation matrix considering the non-transposition balance of line parameters shown in Figure 3, the phase-mode transformation formula 213 applicable to the distribution network with distributed power sources, and the fault judgment used The selection of modulus k, 218, etc., should always be consistent.
图4为实施例的故障判定与保护控制模块114的工作原理图。如图4所示,故障判定与保护控制模块114的工作原理如下所述,共包含以下十二个流程:Fig. 4 is a working principle diagram of the fault judgment and protection control module 114 of the embodiment. As shown in FIG. 4, the working principle of the fault judgment and protection control module 114 is as follows, including the following twelve processes:
流程一、故障判定与保护控制模块114经初始化设置301,可定义区段的线路长度303、区段线路的额定电压304以及区段的模电流差流检测控制信号305,其中,区段的模电流差流检测控制信号305的值为0时表示不进行区段的模电流差流检测;其值为1时表示需要进行区段的模电流差流检测;Process 1. The fault judgment and protection control module 114 can define the line length 303 of the section, the rated voltage 304 of the line of the section, and the differential current detection control signal 305 of the section through the initial setting 301. When the value of the current differential current detection control signal 305 is 0, it means that the differential current detection of the segment is not performed; when the value is 1, it indicates that the differential current detection of the segment is required;
流程二、接收当前时刻的数据302,所得数据中包含区段两端节点处的k模电流相角306、区段两端节点处的k模电压307、区段两端节点处的k模电流308、线路单位长度的串联k模阻抗309以及线路单位长度的并联k模导纳310,其中,线路单位长度的串联k模阻抗309和线路单位长度的并联k模导纳310来自于图1中所示的故障定位主装置110内的信息处理与数据计算模块113向故障判定与保护控制模块114发送的数据;Process 2: Receive the data 302 at the current moment, the obtained data includes the k-mode current phase angle 306 at the nodes at both ends of the segment, the k-mode voltage 307 at the nodes at both ends of the segment, and the k-mode current at the nodes at both ends of the segment 308. The series k-mode impedance 309 per line unit length and the parallel k-mode admittance 310 per line unit length, wherein the series k-mode impedance 309 per line unit length and the parallel k-mode admittance 310 per line unit length are from Fig. 1 The data sent by the information processing and data calculation module 113 in the main fault location device 110 to the fault judgment and protection control module 114;
流程三、将区段的线路长度303、区段线路的额定电压304、区段的模电流差流检测控制信号305、区段两端节点处的k模电流相角306、区段两端节点处的k模电压307、区段两端节点处的k模电流308、线路单位长度的串联k模阻抗309以及线路单位长度的并联k模导纳310整合为数据信息311;Process 3, the line length 303 of the section, the rated voltage 304 of the line of the section, the mode current differential current detection control signal 305 of the section, the k-mode current phase angle 306 at the nodes at both ends of the section, the node at both ends of the section The k-mode voltage 307 at , the k-mode current 308 at the nodes at both ends of the section, the series k-mode impedance 309 per unit length of the line, and the parallel k-mode admittance 310 per unit length of the line are integrated into data information 311;
流程四、利用适用于含分布式电源的配电网的区段线路空载检测方法,进行区段线路空载检测312,得出检测结果,并判断区段线路是否为空载状态313:若空载,则进入流程十二;若非空载,则进入流程五;Process 4. Use the section line no-load detection method applicable to the distribution network containing distributed power sources to perform no-load detection 312 on the section line, obtain the detection result, and judge whether the section line is in the no-load state 313: if If it is empty, enter process 12; if it is not empty, enter process 5;
流程五、根据数据信息311中的区段的模电流差流检测控制信号305,判断是否进行区段的k模电流差流检测314:若进行检测,则进入流程六;若不进行检测,则进入流程七;Process five: According to the mode current differential current detection control signal 305 of the section in the data information 311, judge whether to perform the k-mode current differential current detection 314 of the section: if the detection is performed, then enter the process six; if not, then Enter process seven;
流程六、利用适用于含分布式电源的配电网内区段的模电流差流检测方法,进行区段的k模电流差流检测315,得出检测结果,并判断区段的k模电流差流是否过流316:若过流,则进入流程七;若不过流,则进入流程十二;Process 6. Use the mode current differential current detection method applicable to the section of the distribution network containing distributed power sources to detect the k-mode current differential current of the section 315, obtain the detection result, and judge the k-mode current of the section Whether the differential current is over-current 316: if it is over-current, enter process 7; if not, enter process 12;
流程七、进行区段的k模电流相角差值计算317,得出区段的k模电流相角差值318,利用适用于含分布式电源的配电网的等效单相区段故障判定方法,完成区段的故障判定319,并保存判定结果,将判定结果发送至控制中心320;Process 7. Carry out the k-mode current phase angle difference calculation 317 of the section, obtain the k-mode current phase angle difference 318 of the section, and use the equivalent single-phase section fault applicable to the distribution network containing distributed power Judgment method, complete the fault judgment 319 of the section, save the judgment result, and send the judgment result to the control center 320;
流程八、根据判定结果,判定区段是否发生故障321:若是,则进入流程九;若否,则进入流程十二;Process 8. According to the judgment result, determine whether a fault occurs in the section 321: if yes, enter process 9; if not, enter process 12;
流程九、发出保护跳闸信号,隔离故障区段323;Process Nine: Send a protection trip signal to isolate the fault section 323;
流程十、将判定结果置为发生故障并发送至控制中心324;Process 10. Set the judgment result as failure and send it to the control center 324;
流程十一、判定是否接到人工复位指令325:若是,则返回流程一;若否,则返回流程十;Process 11. Determine whether a manual reset command is received 325: if yes, return to process 1; if not, return to process 10;
流程十二、进入下一个时刻322,返回流程二。Process twelve, enter the next moment 322, and return to process two.
图5为实施例的控制中心115的工作原理图。如图5所示,控制中心115的工作原理如下所述,共包含以下七个流程:FIG. 5 is a working principle diagram of the control center 115 of the embodiment. As shown in Fig. 5, the working principle of the control center 115 is as follows, including the following seven processes:
流程一、初始化设置401;Process 1. Initialization setting 401;
流程二、接收当前时刻所有区段的故障判定结果402;Process 2: Receive the fault determination results of all sections at the current moment 402;
流程三、根据所得信息,生成系统故障判定矩阵403,该系统故障判定矩阵404为一个行矩阵,其中每一个元素均与一个区段的故障判定结果相对应:当区段的故障判定结果为正常运行时,其对应于系统故障判定矩阵404内的元素值为0;当区段的故障判定结果为发生故障时,其对应于系统故障判定矩阵404内的元素值为1;Process 3. Generate a system failure judgment matrix 403 according to the obtained information, and the system failure judgment matrix 404 is a row matrix, wherein each element corresponds to the failure judgment result of a section: when the failure judgment result of the section is normal During operation, the element value corresponding to the system failure judgment matrix 404 is 0; when the failure judgment result of the section is a failure, the element value corresponding to the system failure judgment matrix 404 is 1;
流程四、在所得的系统故障判定矩阵404中,判定系统故障判定矩阵内所有元素是否均为0 405:若为0,则进入流程五;若不为0,则进入流程六;Process 4. In the obtained system fault judgment matrix 404, determine whether all elements in the system fault judgment matrix are 0. 405: if it is 0, then enter process five; if not 0, then enter process six;
流程五、判定结果为:含分布式电源的配电网正常运行406,输出判定结果407,并进入流程七;Process five, the judgment result is: the distribution network including distributed power supply is running normally 406, the judgment result is output 407, and enters the process seven;
流程六、判定结果为:含分布式电源的配电网内发生故障408,立即搜索系统故障判定矩阵内所有为1的元素,保存这些元素所对应的区段编号409,并发出故障指示,输出故障判定结果以及故障区段的编号410;Process 6. The judgment result is: a fault 408 occurs in the distribution network containing distributed power, immediately search for all the elements of 1 in the system fault judgment matrix, save the section number 409 corresponding to these elements, issue a fault indication, and output Fault judgment result and the number 410 of the fault section;
流程七、进入下一个时刻,返回流程二。Process seven, enter the next moment, and return to process two.
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