CN105305658B - Wireless power transmission methods, devices and systems - Google Patents
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Abstract
本发明公开了一种无线电能传输方法、装置和系统,其中,方法包括:发射装置通过发射装置中的励磁线圈将获取的交流电对应的能量传递给发射装置中的发射线圈;发射装置通过发射线圈向接收装置传输电能,该电能由发射线圈依据能量产生的;其中,发射线圈的线径与传输距离除以发射线圈的半径的立方成正比,并且分别与真空磁导率、发射线圈的第一电导率、发射线圈工作的第一谐振角频率的负二分之一次方成正比;所述发射装置与接收装置之间的距离为传输距离。发射线圈采用上述线径时,可以使得整个电能传输系统处于临界耦合状态,使得传输效率得到明显提高。
The invention discloses a wireless energy transmission method, device and system, wherein the method includes: the transmitting device transmits the energy corresponding to the obtained alternating current to the transmitting coil in the transmitting device through the exciting coil in the transmitting device; Transmitting electric energy to the receiving device, the electric energy is generated by the transmitting coil according to the energy; wherein, the wire diameter of the transmitting coil is proportional to the cube of the transmission distance divided by the radius of the transmitting coil, and is respectively related to the vacuum magnetic permeability, the first transmission coil The conductivity and the first resonant angular frequency of the transmitting coil are directly proportional to the power of negative one-half; the distance between the transmitting device and the receiving device is the transmission distance. When the transmitting coil adopts the above wire diameter, the entire power transmission system can be in a critical coupling state, so that the transmission efficiency can be significantly improved.
Description
技术领域technical field
本发明涉及电能传输技术,尤其涉及一种无线电能传输方法、装置和系统。The present invention relates to power transmission technology, in particular to a wireless power transmission method, device and system.
背景技术Background technique
电能作为人们生活中不可或缺的能源,它的主要传输方式是通过电线来实现的,迄今为止,这种输电方式的地位仍然是无可取代的。但是随着科技的蓬勃发展,传统的供电方式也变得越来越不能满足生产和生活的实际需求,现代人对无线输电的需求越来越的迫切。As an indispensable source of energy in people's lives, electric energy is mainly transmitted through wires. So far, the status of this transmission method is still irreplaceable. However, with the vigorous development of science and technology, the traditional power supply methods have become increasingly unable to meet the actual needs of production and life, and modern people's demand for wireless power transmission is becoming more and more urgent.
目前,磁耦合谐振式无线电能传输是无线电能传输的一种实现方式。具体的,该磁耦合谐振式无线电能利用谐振原理,使得其在中等距离(传输距离一般为传输线圈直径的几倍)传输时,仍能得到较高的效率和较大的功率,并且电能传输不受空间非磁性障碍物的影响,具有传输距离较远,且对电磁环境的影响较小,且功率较大的优点。At present, the magnetic coupling resonant wireless power transmission is an implementation method of wireless power transmission. Specifically, the magnetically coupled resonant wireless energy utilizes the principle of resonance, so that it can still obtain high efficiency and high power when transmitting at a medium distance (the transmission distance is generally several times the diameter of the transmission coil), and the power transmission Not affected by non-magnetic obstacles in space, it has the advantages of longer transmission distance, less impact on the electromagnetic environment, and higher power.
但是,现有技术的无线电能传输方法中,无线电能传输系统的能量传输效率并非一直处于最大值,能量传输效率低下。因此,亟需一种无线电能传输方法可以提高无线电能传输时的能量传输效率。However, in the wireless power transmission method in the prior art, the energy transmission efficiency of the wireless power transmission system is not always at the maximum value, and the energy transmission efficiency is low. Therefore, there is an urgent need for a wireless power transmission method that can improve energy transmission efficiency during wireless power transmission.
发明内容Contents of the invention
本发明的目的是提供一种无线电能传输方法、装置和系统,用以解决现有技术中的无线电能传输方法的能量传输效率并非一直处于最大值,能量传输效率低下的问题。The purpose of the present invention is to provide a wireless power transmission method, device and system to solve the problem that the energy transmission efficiency of the wireless power transmission method in the prior art is not always at the maximum value and the energy transmission efficiency is low.
为实现上述目的,本发明一方面提供了无线电能传输方法,包括:To achieve the above object, the present invention provides a wireless power transmission method, including:
发射装置通过所述发射装置中的励磁线圈将获取的交流电对应的能量传递给所述发射装置中的发射线圈;The transmitting device transfers the energy corresponding to the obtained alternating current to the transmitting coil in the transmitting device through the exciting coil in the transmitting device;
所述发射装置通过所述发射线圈向接收装置传输电能,所述电能由所述发射线圈依据所述能量产生的;The transmitting device transmits electric energy to the receiving device through the transmitting coil, and the electric energy is generated by the transmitting coil according to the energy;
其中,所述发射线圈的线径与传输距离除以发射线圈的半径的立方成正比,并且分别与真空磁导率、发射线圈的第一电导率、发射线圈工作的第一谐振角频率的负二分之一次方成正比;所述发射装置与接收装置之间的距离为传输距离。Wherein, the wire diameter of the transmitting coil is directly proportional to the cube of the transmission distance divided by the radius of the transmitting coil, and is respectively proportional to the vacuum magnetic permeability, the first electrical conductivity of the transmitting coil, and the negative of the first resonant angular frequency of the transmitting coil. One-half power is proportional; the distance between the transmitting device and the receiving device is the transmission distance.
本发明的另一方面还提供了一种无线电能传输方法,包括:Another aspect of the present invention also provides a wireless power transmission method, including:
接收装置通过所述接收装置的接收线圈接收发射装置传输的电能;The receiving device receives the electric energy transmitted by the transmitting device through the receiving coil of the receiving device;
所述接收装置通过所述接收线圈将所述电能传输至所述接收装置中的负载线圈中;The receiving device transmits the electric energy to the load coil in the receiving device through the receiving coil;
其中,所述接收线圈的线径与传输距离除以接收线圈的半径的立方成正比,并且分别与真空磁导率、接收线圈的第二电导率、接收线圈工作的第二谐振角频率的负二分之一次方成正比;Wherein, the wire diameter of the receiving coil is proportional to the cube of the transmission distance divided by the radius of the receiving coil, and is respectively proportional to the vacuum magnetic permeability, the second electrical conductivity of the receiving coil, and the negative of the second resonant angular frequency of the receiving coil. One-half power is proportional;
所述发射装置与接收装置之间的距离为传输距离。The distance between the transmitting device and the receiving device is the transmission distance.
本发明的又一方面提供了一种无线电能传输装置,包括:Another aspect of the present invention provides a wireless power transmission device, including:
用于将获取的交流电对应的能量传递给发射线圈的励磁线圈,以及用于将依据所述能量产生的电能传输给无线电能接收装置的所述发射线圈;An exciting coil for transferring energy corresponding to the obtained alternating current to the transmitting coil, and for transmitting electric energy generated according to the energy to the transmitting coil of the wireless energy receiving device;
其中,所述发射线圈的线径与传输距离除以发射线圈的半径的立方成正比,并且分别与真空磁导率、发射线圈的第一电导率、发射线圈工作的第一谐振角频率的负二分之一次方成正比;Wherein, the wire diameter of the transmitting coil is directly proportional to the cube of the transmission distance divided by the radius of the transmitting coil, and is respectively proportional to the vacuum magnetic permeability, the first electrical conductivity of the transmitting coil, and the negative of the first resonant angular frequency of the transmitting coil. One-half power is proportional;
所述发射装置与接收装置之间的距离为传输距离。The distance between the transmitting device and the receiving device is the transmission distance.
本发明的再一方面提供了一种无线电能传输装置,包括:Another aspect of the present invention provides a wireless power transmission device, including:
用于接收发射装置传输的电能的接收线圈,以及用于接收所述接收线圈传输的电能的负载线圈;a receiving coil for receiving the electric energy transmitted by the transmitting device, and a load coil for receiving the electric energy transmitted by the receiving coil;
其中,所述接收线圈的线径与传输距离除以发射线圈的半径的立方成正比,并且分别与第二真空磁导率、第二电导率、第二谐振角频率的负二分之一次方成正比;Wherein, the wire diameter of the receiving coil is proportional to the cube of the transmission distance divided by the radius of the transmitting coil, and is proportional to the negative half of the second vacuum permeability, the second electrical conductivity, and the second resonant angular frequency, respectively. The square is proportional;
所述发射装置与接收装置之间的距离为传输距离。The distance between the transmitting device and the receiving device is the transmission distance.
本发明的另一方面提供了一种无线电能传输系统,包括:上市任一无线电能发射装置和上述任一无线电能接收装置,其中,发射线圈的线径和接收线圈的线径相等,第一谐振角频率和第二谐振角频率相等,第一电导率和第二电导率相等,发射线圈的半径和接收线圈的半径相等。Another aspect of the present invention provides a wireless power transmission system, including: any wireless power transmitting device on the market and any of the above wireless power receiving devices, wherein the wire diameter of the transmitting coil is equal to the wire diameter of the receiving coil, and the first The resonant angular frequency is equal to the second resonant angular frequency, the first conductivity is equal to the second conductivity, and the radius of the transmitting coil is equal to the radius of the receiving coil.
由以上技术方案可知,本发明提供的无线电能传输方法、装置和系统中,在发射装置与接收装置之间的传输距离D固定,接收线圈的材料、线圈半径以及谐振工作频率已经固定的情况下,此时接收线圈的线径若与传输距离除以接收线圈的半径的立方成正比,并且分别与真空磁导率、第二电导率、第二谐振角频率的负二分之一次方成正比时,则接收装置接收发射装置传输的电能时,整个电能传输系统处于临界耦合状态,使得传输效率得到明显提高。It can be seen from the above technical solutions that in the wireless power transmission method, device and system provided by the present invention, when the transmission distance D between the transmitting device and the receiving device is fixed, and the material, coil radius and resonant operating frequency of the receiving coil are fixed , at this time, if the wire diameter of the receiving coil is proportional to the cube of the transmission distance divided by the radius of the receiving coil, and is respectively proportional to the negative half power of the vacuum permeability, the second electrical conductivity, and the second resonant angular frequency When proportional, when the receiving device receives the electric energy transmitted by the transmitting device, the entire electric energy transmission system is in a critical coupling state, so that the transmission efficiency is significantly improved.
附图说明Description of drawings
图1为本发明实施例提供的无线电能传输方法的流程图;FIG. 1 is a flowchart of a wireless power transmission method provided by an embodiment of the present invention;
图2是本发明另一实施例提供的无线电能传输方法的流程图;Fig. 2 is a flowchart of a wireless power transmission method provided by another embodiment of the present invention;
图3为本发明一实施例提供的发射装置和接收装置的等效电路图;3 is an equivalent circuit diagram of a transmitting device and a receiving device provided by an embodiment of the present invention;
图4为本发明又一实施例提供的无线电能传输方法的流程图;FIG. 4 is a flow chart of a wireless power transmission method provided in another embodiment of the present invention;
图5为本发明再一实施例提供的无线电能传输方法的流程图;FIG. 5 is a flow chart of a wireless power transmission method provided in yet another embodiment of the present invention;
图6为本发明另一实施例提供的无线电能发射装置的电路示意图;FIG. 6 is a schematic circuit diagram of a wireless energy transmitting device provided in another embodiment of the present invention;
图7为本发明又一实施例提供的无线电能接收装置的电路示意图。Fig. 7 is a schematic circuit diagram of a wireless power receiving device according to another embodiment of the present invention.
具体实施方式Detailed ways
实施例一Embodiment one
图1为本发明实施例提供的无线电能传输方法的流程图,本实施例的执行主体为发射装置,如图1所示,该无线电能传输方法包括:Fig. 1 is a flowchart of a wireless power transmission method provided by an embodiment of the present invention. The execution subject of this embodiment is a transmitting device. As shown in Fig. 1, the wireless power transmission method includes:
步骤101,发射装置通过发射装置中的励磁线圈将获取的交流电对应的能量传递给发射装置中的发射线圈,其中,发射线圈的线径与传输距离除以发射线圈的半径的立方成正比,并且分别与真空磁导率、发射线圈的第一电导率、发射线圈工作的第一谐振角频率的负二分之一次方成正比,发射装置与接收装置之间的距离为传输距离。Step 101, the transmitting device transmits the energy corresponding to the acquired alternating current to the transmitting coil in the transmitting device through the excitation coil in the transmitting device, wherein the wire diameter of the transmitting coil is proportional to the cube of the transmission distance divided by the radius of the transmitting coil, and They are respectively proportional to the vacuum magnetic permeability, the first conductivity of the transmitting coil, and the negative half power of the first resonant angular frequency of the transmitting coil. The distance between the transmitting device and the receiving device is the transmission distance.
其中,第一电导率是由发射线圈的材料确定,发射线圈可以采用铜线或铝线,传输距离、发射线圈的半径可以根据实际需要进行选择,例如可以选择传输距离为50厘米,为了限制发射装置的体积,发射线圈的半径可以选为10厘米。Among them, the first conductivity is determined by the material of the transmitting coil, the transmitting coil can be copper wire or aluminum wire, the transmission distance and the radius of the transmitting coil can be selected according to actual needs, for example, the transmission distance can be selected as 50 cm, in order to limit the emission The volume of the device, the radius of the transmitting coil can be selected as 10 cm.
步骤102,发射装置通过发射线圈向接收装置传输电能,该电能由发射线圈依据所述能量产生的。Step 102, the transmitting device transmits electric energy to the receiving device through the transmitting coil, and the electric energy is generated by the transmitting coil according to the energy.
具体的,励磁线圈由激励源和单匝线圈组成。励磁线圈与发射线圈之间是通过直接耦合关系将能量从励磁线圈传输至发射线圈的。其中,发射装置的发射线圈要与接收装置的接收线圈同轴放置。Specifically, the excitation coil is composed of an excitation source and a single-turn coil. Between the exciting coil and the transmitting coil, energy is transferred from the exciting coil to the transmitting coil through a direct coupling relationship. Wherein, the transmitting coil of the transmitting device should be placed coaxially with the receiving coil of the receiving device.
可以看出,在发射装置与接收装置之间的传输距离D固定,发射线圈的材料、线圈半径以及谐振工作频率已经固定的情况下,此时发射线圈的线径若与传输距离除以发射线圈的半径的立方成正比,并且分别与真空磁导率、第一电导率、第一谐振角频率的负二分之一次方成正比时,则可以使得发射装置向接收装置传输电能时发射装置处于临界耦合状态,使得传输效率得到明显提高。It can be seen that when the transmission distance D between the transmitting device and the receiving device is fixed, and the material, coil radius and resonant operating frequency of the transmitting coil have been fixed, if the wire diameter of the transmitting coil is divided by the transmission distance by the transmitting coil is proportional to the cube of the radius, and is proportional to the negative half power of the vacuum magnetic permeability, the first electrical conductivity, and the first resonant angular frequency respectively, then it can make the transmitting device transmit electric energy to the receiving device when the transmitting device Being in a critical coupling state, the transmission efficiency is significantly improved.
实施例二Embodiment two
图2为本发明另一实施例提供的无线电能传输方法的流程图,如图2所示,该无线电能传输方法包括:Fig. 2 is a flowchart of a wireless power transmission method provided by another embodiment of the present invention. As shown in Fig. 2, the wireless power transmission method includes:
步骤201,发射装置通过发射装置中的励磁线圈将获取的交流电对应的能量传递给发射装置中的发射线圈。其中,发射线圈的线径a1满足如下公式:Step 201 , the transmitting device transmits the energy corresponding to the acquired alternating current to the transmitting coil in the transmitting device through the excitation coil in the transmitting device. Wherein, the wire diameter a1 of the transmitting coil satisfies the following formula:
其中,D为传输距离,μ0为真空磁导率,ω1为第一谐振角频率,σ1为第一电导率,r1为发射线圈的半径。Among them, D is the transmission distance, μ 0 is the vacuum magnetic permeability, ω 1 is the first resonant angular frequency, σ 1 is the first electrical conductivity, and r 1 is the radius of the transmitting coil.
根据上述公式可以推导出即发射线圈的线径与传输距离除以发射线圈的半径的立方成正比,并且分别与真空磁导率、发射线圈的第一电导率、发射线圈工作的第一谐振角频率的负二分之一次方成正比。According to the above formula, it can be deduced that That is, the wire diameter of the transmitting coil is proportional to the cube of the transmission distance divided by the radius of the transmitting coil, and is respectively negative half of the vacuum magnetic permeability, the first conductivity of the transmitting coil, and the first resonant angular frequency of the transmitting coil. The first square is proportional.
步骤202,发射装置通过发射线圈向接收装置传输电能,电能由发射线圈依据所述能量产生的。Step 202, the transmitting device transmits electric energy to the receiving device through the transmitting coil, and the electric energy is generated by the transmitting coil according to the energy.
为了便于理解本实施例所给出的技术方案,下面给出上述公式的获取方法。In order to facilitate understanding of the technical solution provided in this embodiment, the method for obtaining the above formula is given below.
具体的,对于发射装置而言,可以将励磁线圈的电路反射到发射线圈,即相当于在发射线圈中加入一个感应电动势。对于接收装置而言,接收装置包括接收线圈和负载线圈,可以将负载线圈反射到接收线圈,即相当于接收线圈增加了一个反射阻抗。图3为本发明一实施例提供的发射装置和接收装置的等效电路图,根据对图3的等效电路图的分析可得到如下公式:Specifically, for the transmitting device, the circuit of the excitation coil can be reflected to the transmitting coil, which is equivalent to adding an induced electromotive force to the transmitting coil. For the receiving device, the receiving device includes a receiving coil and a load coil, which can reflect the load coil to the receiving coil, which is equivalent to adding a reflection impedance to the receiving coil. Fig. 3 is the equivalent circuit diagram of the transmitting device and the receiving device provided by an embodiment of the present invention, according to the analysis of the equivalent circuit diagram of Fig. 3, the following formula can be obtained:
其中,US为发射装置的励磁线圈等效到发射线圈的感应电动势,为US的振幅向量,R1为励磁线圈的激励源的内阻和励磁线圈的第一等效电容等效到发射线圈的阻抗之和,R2为发射线圈的第二损耗电阻、第二辐射电阻以及励磁线圈的第一损耗电阻、第一辐射电阻的阻抗之和;M23为发射线圈和接收线圈之间的互感系数,R3为接收线圈的第三损耗电阻、第三辐射电阻以及负载线圈的第四损耗电阻、第四辐射电阻之和,R4为接收装置的负载线圈的负载和第四等效电容等效到接收线圈的阻抗之和。L2为发射线圈的第二电感,L3为接收线圈的第三电感,C2为发射线圈的第二等效电容,C3为接收线圈的第三等效电容。j为虚数单位,I1为流过发射装置的电流,为I1的振幅向量,I2为流过接收装置的电流,为I2的振幅向量,ω为发射装置或接收装置的角频率,I1和I2的电流方向在图3中为顺时针方向。Among them, U S is the induced electromotive force equivalent to the transmitting coil from the exciting coil of the transmitting device, is the amplitude vector of U S , R 1 is the sum of the internal resistance of the excitation source of the exciting coil and the first equivalent capacitance of the exciting coil equivalent to the impedance of the transmitting coil, R 2 is the second loss resistance of the transmitting coil, the second Radiation resistance and the sum of the first loss resistance of the exciting coil and the impedance of the first radiation resistance; M 23 is the mutual inductance coefficient between the transmitting coil and the receiving coil, R 3 is the third loss resistance of the receiving coil, the third radiation resistance and The sum of the fourth loss resistance of the load coil and the fourth radiation resistance, R4 is the sum of the load of the load coil of the receiving device and the impedance of the fourth equivalent capacitance equivalent to the receiving coil. L 2 is the second inductance of the transmitting coil, L 3 is the third inductance of the receiving coil, C 2 is the second equivalent capacitance of the transmitting coil, and C 3 is the third equivalent capacitance of the receiving coil. j is the imaginary unit, I 1 is the current flowing through the transmitter, is the amplitude vector of I 1 , I 2 is the current flowing through the receiving device, is the amplitude vector of I 2 , ω is the angular frequency of the transmitter or receiver, and the current directions of I 1 and I 2 are clockwise in Figure 3.
可选的,发射装置和接收装置可以设计为相同的尺寸和机械结构,此时则有,R1+R2=R2+R3,L2=L3,C2=C3,其中,令R1+R2=R2+R3=R,L2=L3=L,C2=C3=C,M23=M,并且引入广义失谐因子ξ:Optionally, the transmitting device and the receiving device can be designed to have the same size and mechanical structure. In this case, R 1 +R 2 =R 2 +R 3 , L 2 =L 3 , C 2 =C 3 , where, Let R 1 +R 2 =R 2 +R 3 =R, L 2 =L 3 =L, C 2 =C 3 =C, M 23 =M, and introduce a generalized detuning factor ξ:
其中,Q为品质因数,ω0为谐振频 率,进而根据公式(1)则可以得到如下等式: in, Q is the quality factor, ω0 is the resonant frequency, and then according to the formula (1), the following equation can be obtained:
进一步的,定义耦合因数η,其中,则可以根据公式(2)获取得到接收装置接收到的电压为:Further, define the coupling factor η, where, Then the voltage received by the receiving device can be obtained according to formula (2):
其中,U为接收装置的负载接收到的电能的接收电压,为U的向量表示。Wherein, U is the receiving voltage of the electric energy received by the load of the receiving device, is the vector representation of U.
根据该接收电压U可以获取接收电压的模值为:According to the received voltage U, the modulus value of the received voltage can be obtained as:
其中,|U|为U的模值。Among them, |U| is the modulus value of U.
对接收电压的模值|U|求导,令可以得到在ξ1=0和处得到接收电压模值的极值,该接收电压模值的极值|Umax|为: Take the derivative of the modulus |U| of the received voltage, so that It can be obtained that at ξ 1 =0 and The extreme value of the received voltage modulus is obtained at the place, and the extreme value |U max | of the received voltage modulus is:
那么,将接收装置的负载接收到的电能的接收电压进行归一化,具体的归一化方法是利用接收电压模值除以接收电压模值的极值,得到归一化电压α为:Then, the received voltage of the electric energy received by the load of the receiving device is normalized. The specific normalization method is to divide the received voltage modulus by the extreme value of the received voltage modulus to obtain the normalized voltage α as:
根据对公式(5)的分析可以知道,当ξ=0,即当发射装置工作在谐振频率ω=ω0时:According to the analysis of formula (5), it can be known that when ξ=0, that is, when the transmitter works at the resonant frequency ω=ω 0 :
且在时,接收装置的负载接收到的电压为最大值;and in , the voltage received by the load of the receiving device is the maximum value;
在η>1处,会存在频率分裂现象,即在电能传输过程中会出现两个不相同的谐振频率的现象即为频率分裂,但是不管在哪个谐振频率位置,负载仍能接收到电压最大值;At η>1, there will be a phenomenon of frequency splitting, that is, there will be two different resonant frequencies in the process of power transmission, which is frequency splitting, but no matter which resonant frequency position is, the load can still receive the maximum voltage ;
在η<1处,随着耦合系数的减小负载所能接收到的电压急剧下降。At η<1, the voltage that the load can receive drops sharply as the coupling coefficient decreases.
进一步的,由于发射装置和接收装置之间的互感系数M为:Further, since the mutual inductance coefficient M between the transmitting device and the receiving device is:
其中,μ0为真空磁导率,n1为发送装置中发射线圈的匝数,n2为接收装置中接收线圈的匝数,r1为发射线圈的半径,r2为接收线圈的半径,D为传输距离。由于发射线圈与接收线圈的结构尺寸相同,因此,n1=n2,r1=r2,公式(6)记为:Among them, μ 0 is the magnetic permeability of vacuum, n 1 is the number of turns of the transmitting coil in the sending device, n 2 is the number of turns of the receiving coil in the receiving device, r 1 is the radius of the transmitting coil, r 2 is the radius of the receiving coil, D is the transmission distance. Since the structural dimensions of the transmitting coil and the receiving coil are the same, n 1 =n 2 , r 1 =r 2 , formula (6) is written as:
并且,一般而言,磁耦合谐振工作频率为1兆赫兹至50兆赫兹之间,在此高频条件下发射线圈的损耗电阻R0为:And, generally speaking, the magnetic coupling resonant operating frequency is between 1 MHz and 50 MHz, and the loss resistance R 0 of the transmitting coil under this high frequency condition is:
其中,ω为发射装置的角频率,σ1为发射线圈的电导率,即第一电导率,a1为发射线圈的线径。需要说明的时,发射线圈的损耗电阻R0即为R1与R2的和值。Among them, ω is the angular frequency of the transmitting device, σ1 is the conductivity of the transmitting coil, that is, the first conductivity, and a1 is the wire diameter of the transmitting coil. When it needs to be explained, the loss resistance R 0 of the transmitting coil is the sum of R 1 and R 2 .
当发射装置工作在谐振频率,即时,接收装置的负载接收到的电压为 最大值,将公式(7)和公式(8)代入可以得到 When the transmitting device works at the resonant frequency, the voltage received by the load of the receiving device is the maximum value, and the formula (7) and formula (8) can be substituted into
由于发射装置的谐振频率与接收装置的谐振频率相等,即ω=ω1=ω2,其中,ω1为发射装置的谐振频率,记为第一谐振角频率,ω2为接收装置的谐振频率,记为第二谐振角频率。因此, Since the resonant frequency of the transmitting device is equal to the resonant frequency of the receiving device, that is, ω=ω 1 =ω 2 , where ω 1 is the resonant frequency of the transmitting device, recorded as the first resonant angular frequency, and ω 2 is the resonant frequency of the receiving device , recorded as the second resonant angular frequency. therefore,
由此可以看出,在发射装置与接收装置之间的传输距离D固定,发射线圈的材料、线圈半径以及谐振工作频率已经固定的情况下,此时发射线圈的线径若与传输距离除以发射线圈的半径的立方成正比,并且分别与真空磁导率、第一电导率、第一谐振角频率的负二分之一次方成正比时,则可以使得发射装置向接收装置传输电能时发射装置处于临界耦合状态,使得传输效率得到明显提高。It can be seen from this that, when the transmission distance D between the transmitting device and the receiving device is fixed, and the material, coil radius, and resonant operating frequency of the transmitting coil have been fixed, at this time, if the wire diameter of the transmitting coil is divided by the transmission distance When the cube of the radius of the transmitting coil is proportional to the vacuum permeability, the first electrical conductivity, and the negative half power of the first resonant angular frequency, the transmitting device can transmit electric energy to the receiving device. The transmitting device is in a critical coupling state, so that the transmission efficiency is significantly improved.
实施例三Embodiment Three
图4为本发明又一实施例提供的无线电能传输方法的流程图,本实施例提供的无线电能传输方法的执行主体为接收装置,如图4所示,该无线电能传输方法包括:Fig. 4 is a flow chart of a wireless power transmission method provided in another embodiment of the present invention. The execution subject of the wireless power transmission method provided in this embodiment is a receiving device. As shown in Fig. 4, the wireless power transmission method includes:
步骤301,接收装置通过接收装置的接收线圈接收发射装置传输的电能。Step 301, the receiving device receives the electric energy transmitted by the transmitting device through the receiving coil of the receiving device.
步骤302,接收装置通过所述接收线圈将电能传输至接收装置中的负载线圈中,其中,接收线圈的线径与传输距离除以接收线圈的半径的立方成正比,并且分别与真空磁导率、接收线圈的第二电导率、接收线圈工作的第二谐振角频率的负二分之一次方成正比,发射装置与接收装置之间的距离为传输距离。Step 302, the receiving device transmits electric energy to the load coil in the receiving device through the receiving coil, wherein the wire diameter of the receiving coil is proportional to the cube of the transmission distance divided by the radius of the receiving coil, and is respectively proportional to the vacuum magnetic permeability , the second conductivity of the receiving coil, and the second resonant angular frequency of the receiving coil are proportional to the negative half of the power, and the distance between the transmitting device and the receiving device is the transmission distance.
其中,第二电导率是由接收线圈的材料确定,接收线圈可以采用铜线或铝线,传输距离、发射线圈的线圈半径可以根据实际需要进行选择,例如可以选择传输距离为50厘米,为了限制接收装置的体积,接收线圈的半径可以选为10厘米。Wherein, the second conductivity is determined by the material of the receiving coil, the receiving coil can be copper wire or aluminum wire, the transmission distance, the coil radius of the transmitting coil can be selected according to actual needs, for example, the transmission distance can be selected as 50 cm, in order to limit The volume of the receiving device, the radius of the receiving coil can be selected as 10 cm.
可以看出,在接收装置与发射装置之间的传输距离D固定,接收装置的接收线圈的材料、线圈半径以及谐振工作频率已经固定的情况下,此时接收线圈的线径若与传输距离除以接收线圈的半径的立方成正比,并且分别与真空磁导率、第二电导率、第二谐振角频率的负二分之一次方成正比时,则可以使得接收装置接收发送装置传输的电能时接收装置处于临界耦合状态,使得传输效率得到明显提高。It can be seen that when the transmission distance D between the receiving device and the transmitting device is fixed, and the material, coil radius and resonant operating frequency of the receiving coil of the receiving device are fixed, if the wire diameter of the receiving coil is divided by the transmission distance When it is proportional to the cube of the radius of the receiving coil, and is proportional to the vacuum magnetic permeability, the second electrical conductivity, and the negative half power of the second resonant angular frequency, the receiving device can receive the transmitted signal transmitted by the sending device. When receiving electric energy, the receiving device is in a critical coupling state, so that the transmission efficiency is significantly improved.
实施例四Embodiment four
图5为本发明再一实施例提供的无线电能传输方法的流程图,如图5所示,该无线电能传输方法包括:Fig. 5 is a flow chart of a wireless power transmission method provided by another embodiment of the present invention. As shown in Fig. 5, the wireless power transmission method includes:
步骤401,接收装置通过接收装置的接收线圈接收发射装置传输的电能。Step 401, the receiving device receives the electric energy transmitted by the transmitting device through the receiving coil of the receiving device.
步骤402,接收装置通过所述接收线圈将所述电能传输至所述接收装置中的负载线圈中。Step 402, the receiving device transmits the electric energy to a load coil in the receiving device through the receiving coil.
其中,接收线圈的线径a2满足如下公式: Wherein, the wire diameter a2 of the receiving coil satisfies the following formula :
其中,D为传输距离,a2为接收线圈的线径,μ0为真空磁导率,ω2为第二谐振角频率,σ2为第二电导率,r2为接收线圈的半径。Among them, D is the transmission distance, a 2 is the wire diameter of the receiving coil, μ 0 is the vacuum magnetic permeability, ω 2 is the second resonant angular frequency, σ 2 is the second electrical conductivity, and r 2 is the radius of the receiving coil.
根据上述公式可以推导出 According to the above formula, it can be deduced that
为了便于理解本实施例所给出的技术方案,下面给出上述公式的获取方法。In order to facilitate understanding of the technical solution provided in this embodiment, the method for obtaining the above formula is given below.
具体的,对于接收装置而言,接收装置包括接收线圈和负载线圈,可以将负载线圈反射到接收线圈,即相当于接收线圈增加了一个反射阻抗。对于发射装置而言,可以将励磁线圈的电路反射到发射线圈,即相当于在发射线圈中加入一个感应电动势。同理,如图3所示,根据对图3的简化电路图的分析可得到如下公式:Specifically, for the receiving device, the receiving device includes a receiving coil and a load coil, which can reflect the load coil to the receiving coil, which is equivalent to adding a reflection impedance to the receiving coil. For the transmitting device, the circuit of the excitation coil can be reflected to the transmitting coil, which is equivalent to adding an induced electromotive force to the transmitting coil. Similarly, as shown in Figure 3, the following formula can be obtained according to the analysis of the simplified circuit diagram in Figure 3:
US为发射装置的励磁线圈等效到发射线圈的感应电动势,为US的振幅向量,R1为励磁线圈的激励源的内阻和励磁线圈的第一等效电容等效到发射线圈的阻抗之和,R2为发射线圈的第二损耗电阻、第二辐射电阻以及励磁线圈的第一损耗电阻、第一辐射电阻的阻抗之和;M23为发射线圈和接收线圈之间的互感系数,R3为接收线圈的第三损耗电阻、第三辐射电阻以及负载线圈的第四损耗电阻、第四辐射电阻之和,R4为接收装置的负载线圈的负载和第四等效电容等效到接收线圈的阻抗之和。L2为发射线圈的第二电感,L3为接收线圈的第三电感,C2为发射线圈的第二等效电容,C3为接收线圈的第三等效电容。j为虚数单位,I1为流过发射装置的电流,为I1的振幅向量,I2为流过接收装置的电流,为I2的振幅向量,ω为发射装置或接收装置的角频率,I1和I2的电流方向在图3中为顺时针方向。U S is the induced electromotive force equivalent to the excitation coil of the transmitter to the transmitter coil, is the amplitude vector of U S , R 1 is the sum of the internal resistance of the excitation source of the exciting coil and the first equivalent capacitance of the exciting coil equivalent to the impedance of the transmitting coil, R 2 is the second loss resistance of the transmitting coil, the second Radiation resistance and the sum of the first loss resistance of the exciting coil and the impedance of the first radiation resistance; M 23 is the mutual inductance coefficient between the transmitting coil and the receiving coil, R 3 is the third loss resistance of the receiving coil, the third radiation resistance and The sum of the fourth loss resistance of the load coil and the fourth radiation resistance, R4 is the sum of the load of the load coil of the receiving device and the impedance of the fourth equivalent capacitance equivalent to the receiving coil. L 2 is the second inductance of the transmitting coil, L 3 is the third inductance of the receiving coil, C 2 is the second equivalent capacitance of the transmitting coil, and C 3 is the third equivalent capacitance of the receiving coil. j is the imaginary unit, I 1 is the current flowing through the transmitter, is the amplitude vector of I 1 , I 2 is the current flowing through the receiving device, is the amplitude vector of I 2 , ω is the angular frequency of the transmitter or receiver, and the current directions of I 1 and I 2 are clockwise in Figure 3.
可选的,发射装置和接收装置可以设计为相同的尺寸和机械结构,此时则有,R1+R2=R2+R3,L2=L3,C2=C3,其中,令R1+R2=R2+R3=R,L2=L3=L,C2=C3=C,M23=M,并且引入广义失谐因子ξ:Optionally, the transmitting device and the receiving device can be designed to have the same size and mechanical structure. In this case, R 1 +R 2 =R 2 +R 3 , L 2 =L 3 , C 2 =C 3 , where, Let R 1 +R 2 =R 2 +R 3 =R, L 2 =L 3 =L, C 2 =C 3 =C, M 23 =M, and introduce a generalized detuning factor ξ:
其中,Q为品质因数,ω0为谐振频 率,进而根据公式(1)则可以得到如下等式: in, Q is the quality factor, ω0 is the resonant frequency, and then according to the formula (1), the following equation can be obtained:
进一步的,定义耦合因数η,其中,则可以根据公式(2)获取得到接收装置接收到的电压为:Further, define the coupling factor η, where, Then the voltage received by the receiving device can be obtained according to formula (2):
其中,U为接收装置的负载接收到的电能的接收电压,为U的向量表示。Wherein, U is the receiving voltage of the electric energy received by the load of the receiving device, is the vector representation of U.
根据该接收电压U可以获取接收电压的模值为:According to the received voltage U, the modulus value of the received voltage can be obtained as:
其中,|U|为U的模值。Among them, |U| is the modulus value of U.
对接收电压的模值|U|求导,令可以得到在ξ1=0和处得到接收电压模值的极值,该接收电压模值的极值|Umax|为: Take the derivative of the modulus |U| of the received voltage, so that It can be obtained that at ξ 1 =0 and The extreme value of the received voltage modulus is obtained at the place, and the extreme value |U max | of the received voltage modulus is:
那么,将接收装置的负载接收到的电能的接收电压进行归一化,具体的归一化方法为利用接收电压模值除以接收电压模值的极值,可以得到归一化电压α为:Then, the received voltage of the electric energy received by the load of the receiving device is normalized. The specific normalization method is to divide the received voltage modulus by the extreme value of the received voltage modulus, and the normalized voltage α can be obtained as:
根据对公式(5)的分析可以知道,ξ=0,即当发射装置工作在谐振频率ω=ω0时:According to the analysis of formula (5), it can be known that ξ=0, that is, when the transmitter works at the resonant frequency ω=ω 0 :
且在时,接收装置的负载接收到的电压为最大值;and in , the voltage received by the load of the receiving device is the maximum value;
在η>1处,会存在频率分裂现象,即在电能传输过程中会出现两个不相同的谐振频率的现象即为频率分裂,但是不管在哪个谐振频率位置,负载仍能接收到电压最大值;At η>1, there will be a phenomenon of frequency splitting, that is, there will be two different resonant frequencies in the process of power transmission, which is frequency splitting, but no matter which resonant frequency position is, the load can still receive the maximum voltage ;
在η<1处,随着耦合系数的减小负载所能接收到的电压急剧下降。At η<1, the voltage that the load can receive drops sharply as the coupling coefficient decreases.
进一步的,由于发射装置和接收装置之间的互感系数M为:Further, since the mutual inductance coefficient M between the transmitting device and the receiving device is:
其中,μ0为真空磁导率,n1为发送装置中发射线圈的匝数,n2为接收装置中接收线圈的匝数,r1为发射线圈的半径,r2为接收线圈的半径,D为传输距离。由于发射线圈与接收线圈的结构尺寸相同,因此,n1=n2,r1=r2,公式(6)记为:Among them, μ 0 is the magnetic permeability of vacuum, n 1 is the number of turns of the transmitting coil in the sending device, n 2 is the number of turns of the receiving coil in the receiving device, r 1 is the radius of the transmitting coil, r 2 is the radius of the receiving coil, D is the transmission distance. Since the structural dimensions of the transmitting coil and the receiving coil are the same, n 1 =n 2 , r 1 =r 2 , formula (6) is written as:
并且,一般而言,磁耦合谐振工作频率为1兆赫兹至50兆赫兹之间,在此高频条件下接收线圈的损耗电阻R0'为:And, generally speaking, the magnetic coupling resonant operating frequency is between 1 MHz and 50 MHz, and the loss resistance R 0 ' of the receiving coil under this high frequency condition is:
其中,ω为接收装置的角频率,σ2为发射线圈的电导率,即第二电导率,a2为接收线圈的线径。需要说明的是,接收线圈的损耗电阻R0'即为R3与R4的和值。Among them, ω is the angular frequency of the receiving device, σ2 is the conductivity of the transmitting coil, that is, the second conductivity, and a2 is the wire diameter of the receiving coil. It should be noted that the loss resistance R 0 ′ of the receiving coil is the sum of R 3 and R 4 .
当接收装置工作在谐振频率,即时,接收装置的负载接收到的电压为 最大值,将公式(7*)和公式(8*)代入可以得到 When the receiving device works at the resonant frequency, that is, the voltage received by the load of the receiving device is the maximum value, and formula (7 * ) and formula (8 * ) can be substituted into
由于接收装置的谐振频率与发射装置的谐振频率相等,即ω=ω1=ω2,其中,ω2为接收装置的谐振频率,记为第二谐振角频率,ω1为发射装置的谐振频率,记为第一谐振角频率。因此, Since the resonant frequency of the receiving device is equal to the resonant frequency of the transmitting device, that is, ω=ω 1 =ω 2 , where ω 2 is the resonant frequency of the receiving device, recorded as the second resonant angular frequency, and ω 1 is the resonant frequency of the transmitting device , denoted as the first resonant angular frequency. therefore,
可以看出,在发射装置与接收装置之间的传输距离D固定,接收线圈的材料、线圈半径以及谐振工作频率已经固定的情况下,此时接收线圈的线径若与传输距离除以接收线圈的半径的立方成正比,并且分别与真空磁导率、第二电导率、第二谐振角频率的负二分之一次方成正比时,则接收装置接收发射装置传输的电能时接收装置处于临界耦合状态,使得传输效率得到明显提高。It can be seen that when the transmission distance D between the transmitting device and the receiving device is fixed, and the material, coil radius and resonant operating frequency of the receiving coil have been fixed, if the wire diameter of the receiving coil is divided by the transmission distance by the receiving coil is proportional to the cube of the radius, and is proportional to the vacuum permeability, the second electrical conductivity, and the negative half power of the second resonant angular frequency respectively, when the receiving device receives the electric energy transmitted by the transmitting device, the receiving device is at The critical coupling state makes the transmission efficiency significantly improved.
实施例五Embodiment five
本实施例提供一种无线电能发射装置,用于执行实施例一和实施例二的无线电能传输方法,图6为本实施例提供的无线电能发射装置的电路示意图,如图6所示,该无线电能发射装置包括:用于将获取的交流电对应的能量传递给发射线圈的励磁线圈11,以及用于将依据上述能量产生的电能传输给无线电能接收装置的发射线圈12。This embodiment provides a wireless power transmission device, which is used to implement the wireless power transmission method in Embodiment 1 and Embodiment 2. FIG. 6 is a schematic circuit diagram of the wireless power transmission device provided in this embodiment. As shown in FIG. 6, the The wireless power transmitting device includes: an exciting coil 11 for transferring the energy corresponding to the acquired alternating current to the transmitting coil, and a transmitting coil 12 for transmitting electric energy generated according to the above energy to the wireless power receiving device.
其中,发射线圈12的线径与传输距离除以发射线圈的半径的立方成正比,并且分别与真空磁导率、发射线圈的第一电导率、发射线圈工作的第一谐振角频率的负二分之一次方成正比;发射装置与接收装置之间的距离为传输距离。Wherein, the wire diameter of transmitting coil 12 is directly proportional to the cube of the transmission distance divided by the radius of the transmitting coil, and is respectively proportional to the vacuum magnetic permeability, the first electrical conductivity of the transmitting coil, and the minus two of the first resonant angular frequency of the transmitting coil. It is proportional to the power of one-third; the distance between the transmitting device and the receiving device is the transmission distance.
其中,励磁线圈11包括相互串联的激励源和单匝线圈,发射线圈12为多匝线圈。发射线圈12的线圈匝数可以根据发射装置工作时的谐振频率确定。Wherein, the excitation coil 11 includes an excitation source and a single-turn coil connected in series, and the transmitting coil 12 is a multi-turn coil. The number of turns of the transmitting coil 12 can be determined according to the resonant frequency of the transmitting device when it is working.
在发射装置与接收装置之间的传输距离D固定,发射线圈12的材料、线圈半径以及谐振工作频率已经固定的情况下,此时发射线圈12的线径若与传输距离除以发射线圈12的半径的立方成正比,并且分别与真空磁导率、第一电导率、第一谐振角频率的负二分之一次方成正比时,则可以使得发射装置向接收装置传输电能时发送装置处于临界耦合状态,使得传输效率得到明显提高。When the transmission distance D between the transmitting device and the receiving device is fixed, and the material, coil radius and resonant operating frequency of the transmitting coil 12 have been fixed, if the wire diameter of the transmitting coil 12 is divided by the transmission distance by the transmission distance of the transmitting coil 12 When the cube of the radius is proportional to the vacuum magnetic permeability, the first electrical conductivity, and the negative half power of the first resonant angular frequency, the transmitting device can be in the The critical coupling state makes the transmission efficiency significantly improved.
实施例六Embodiment six
本实施例是对上述实施例进一步的补充说明,其中,发射线圈12的线径a1满足如下公式:This embodiment is a further supplementary description to the above embodiment, wherein the wire diameter a1 of the transmitting coil 12 satisfies the following formula:
其中,D为传输距离,a1为发射线圈的线径,μ0为真空磁导率,ω1为第一谐振角频率,σ1为第一电导率,r1为发射线圈的半径。Among them, D is the transmission distance, a 1 is the wire diameter of the transmitting coil, μ 0 is the vacuum magnetic permeability, ω 1 is the first resonant angular frequency, σ 1 is the first electrical conductivity, and r 1 is the radius of the transmitting coil.
此外,可以将励磁线圈11的内部电阻、电容等进行等效,得到励磁线圈11的等效电路,如图6所示,该等效电路包括:相互串联的第一辐射电阻Rrad1和励磁线圈11由于趋肤效应等因素而产生的第一损耗电阻Rp1、激励源的内阻Rs、第一等效电容C1、第一电感L1。In addition, the internal resistance and capacitance of the excitation coil 11 can be equivalent to obtain the equivalent circuit of the excitation coil 11, as shown in Figure 6, the equivalent circuit includes: the first radiation resistance R rad1 and the excitation coil connected in series 11 The first loss resistance R p1 , the internal resistance R s of the excitation source, the first equivalent capacitance C 1 , and the first inductance L 1 due to skin effect and other factors.
同理,发射线圈12也可以得到等效电路,如图6所示,发射线圈12的等效电路包括:相互串联的第二辐射电阻Rrad2、发射线圈12由于趋肤效应等因素而产生的第二损耗电阻Rp2、第二等效电容C2和第二电感L2。Similarly, the equivalent circuit of the transmitting coil 12 can also be obtained. As shown in FIG. 6, the equivalent circuit of the transmitting coil 12 includes: the second radiation resistance R rad2 connected in series, The second loss resistor R p2 , the second equivalent capacitor C 2 and the second inductance L 2 .
进一步的,可以将励磁线圈11的等效电路反射到发射线圈12,得到发射装置的等效电路,如图3所示,其中,发射装置的等效电路包括:励磁线圈11的激励源的内阻Rs和励磁线圈11的第一等效电容C1等效到发射线圈12的阻抗之和R1、励磁线圈11的第一损耗电阻Rp1及第一辐射电阻Rrad1和发射线圈12的第二损耗电阻Rp2及第二辐射电阻Rrad2等效到发射线圈12的阻抗之和R2、发射线圈12的第二电感L2、发射线圈12的第二等效电容C2。Further, the equivalent circuit of the exciting coil 11 can be reflected to the transmitting coil 12 to obtain the equivalent circuit of the transmitting device, as shown in Figure 3, wherein the equivalent circuit of the transmitting device includes: The resistance R s and the first equivalent capacitance C 1 of the exciting coil 11 are equivalent to the sum R 1 of the impedance of the transmitting coil 12, the first loss resistance R p1 of the exciting coil 11 and the first radiation resistance R rad1 and the impedance of the transmitting coil 12 The second loss resistance R p2 and the second radiation resistance R rad2 are equivalent to the sum R 2 of the impedance of the transmitting coil 12 , the second inductance L 2 of the transmitting coil 12 , and the second equivalent capacitance C 2 of the transmitting coil 12 .
具体的,发射线圈12的线径的获取方法可以参照实施例二的详细说明,在此不再赘述。Specifically, the method for obtaining the wire diameter of the transmitting coil 12 may refer to the detailed description of the second embodiment, and details are not repeated here.
在发射装置与接收装置之间的传输距离D固定,发射线圈11的材料、线圈半径以及谐振工作频率已经固定的情况下,此时发射线圈的线径若与传输距离除以发射线圈的半径的立方成正比,并且分别与真空磁导率、第一电导率、第一谐振角频率的负二分之一次方成正比时,则可以使得发射装置向接收装置传输电能时发射装置处于临界耦合状态,使得传输效率得到明显提高。When the transmission distance D between the transmitting device and the receiving device is fixed, and the material, coil radius and resonant operating frequency of the transmitting coil 11 are fixed, if the wire diameter of the transmitting coil is equal to the transmission distance divided by the radius of the transmitting coil is proportional to the cube, and is proportional to the vacuum permeability, the first electrical conductivity, and the negative half power of the first resonant angular frequency respectively, then the transmitting device can be in critical coupling when the transmitting device transmits electric energy to the receiving device state, so that the transmission efficiency is significantly improved.
实施例七Embodiment seven
本实施例提供了一种无线电能接收装置,用于执行实施例三和实施例四的无线电能传输方法,图7为本实施例提供的无线电能接收装置的电路示意图,如图7所示,该无线电能接收装置包括:用于接收发射装置传输的电能的接收线圈21,以及用于接收接收线圈21传输的电能的负载线圈22。This embodiment provides a wireless power receiving device, which is used to implement the wireless power transmission method in Embodiment 3 and Embodiment 4. FIG. 7 is a schematic circuit diagram of the wireless power receiving device provided in this embodiment, as shown in FIG. 7 , The wireless power receiving device includes: a receiving coil 21 for receiving the power transmitted by the transmitting device, and a load coil 22 for receiving the power transmitted by the receiving coil 21 .
具体的,接收线圈21为多匝线圈,负载线圈22包括相互串联的负载和单匝线圈。Specifically, the receiving coil 21 is a multi-turn coil, and the load coil 22 includes a load and a single-turn coil connected in series.
其中,接收线圈21的线径与传输距离除以接收线圈的半径的立方成正比,并且分别与第二真空磁导率、第二电导率、第二谐振角频率的负二分之一次方成正比,发射装置与接收装置之间的距离为传输距离。Wherein, the wire diameter of the receiving coil 21 is proportional to the cube of the transmission distance divided by the radius of the receiving coil, and is proportional to the negative half power of the second vacuum permeability, the second electrical conductivity, and the second resonant angular frequency, respectively. In direct proportion, the distance between the transmitting device and the receiving device is the transmission distance.
具体的,接收线圈21为多匝线圈,负载线圈22包括相互串联的负载和单匝线圈。Specifically, the receiving coil 21 is a multi-turn coil, and the load coil 22 includes a load and a single-turn coil connected in series.
其中,第二电导率是由接收线圈21的材料确定,接收线圈21可以采用铜线或铝线,传输距离、接收线圈21的半径可以根据实际需要进行选择,例如可以选择传输距离为50厘米,为了限制接收装置的体积,接收线圈21的半径可以选为10厘米。Wherein, the second conductivity is determined by the material of the receiving coil 21, the receiving coil 21 can adopt copper wire or aluminum wire, the transmission distance, the radius of the receiving coil 21 can be selected according to actual needs, for example, the transmission distance can be selected as 50 cm, In order to limit the volume of the receiving device, the radius of the receiving coil 21 can be selected as 10 cm.
可以看出,在接收装置与发射装置之间的传输距离D固定,接收装置的接收线圈21的材料、线圈半径以及谐振工作频率已经固定的情况下,此时接收线圈21的线径若与传输距离除以接收线圈21的半径的立方成正比,并且分别与真空磁导率、第二电导率、第二谐振角频率的负二分之一次方成正比时,则可以使得接收装置接收发送装置传输的电能时接收装置处于临界耦合状态,使得传输效率得到明显提高。It can be seen that when the transmission distance D between the receiving device and the transmitting device is fixed, and the material, coil radius and resonant operating frequency of the receiving coil 21 of the receiving device are fixed, if the wire diameter of the receiving coil 21 is the same as that of the transmission When the distance is proportional to the cube of the radius of the receiving coil 21, and is proportional to the negative half power of the vacuum permeability, the second electrical conductivity, and the second resonant angular frequency respectively, then the receiving device can be made to receive and send When the electric energy transmitted by the device is received, the receiving device is in a critical coupling state, so that the transmission efficiency is significantly improved.
实施例八Embodiment Eight
本实施例是对上述实施例进一步的解释说明,其中,接收线圈21的线径a2满足如下公式:This embodiment is a further explanation of the above embodiment, wherein the wire diameter a2 of the receiving coil 21 satisfies the following formula:
其中,D为传输距离,a2为接收线圈的线径,μ0为真空磁导率,ω2为第二谐振角频率,σ2为第二电导率,r2为接收线圈的半径。Among them, D is the transmission distance, a 2 is the wire diameter of the receiving coil, μ 0 is the vacuum magnetic permeability, ω 2 is the second resonant angular frequency, σ 2 is the second electrical conductivity, and r 2 is the radius of the receiving coil.
另外,可以将接收线圈21的内部电阻、电容等进行等效,得到接收线圈21的等效电路,如图7所示,该等效电路包括:相互串联的第三辐射电阻Rrad3和接收线圈21由于趋肤效应等因素而产生的第三损耗电阻Rp3、第三等效电容C3、第三电感L3。In addition, the internal resistance and capacitance of the receiving coil 21 can be equivalent to obtain the equivalent circuit of the receiving coil 21, as shown in Figure 7, the equivalent circuit includes: the third radiation resistor R rad3 and the receiving coil connected in series 21 The third loss resistance R p3 , the third equivalent capacitance C 3 , and the third inductance L 3 generated due to skin effect and other factors.
同理,负载线圈22也可以得到等效电路,如图7所示,负载线圈22的等效电路包括:相互串联的第四辐射电阻Rrad4和负载线圈22由于趋肤效应等因素而产生的第四损耗电阻Rp4、第四电感L4、第四等效电容C4以及负载RL。Similarly, the load coil 22 can also obtain an equivalent circuit, as shown in Figure 7, the equivalent circuit of the load coil 22 includes: the fourth radiation resistor R rad4 connected in series and the load coil 22 due to factors such as skin effect The fourth loss resistor R p4 , the fourth inductor L 4 , the fourth equivalent capacitor C 4 and the load R L .
进一步的,可以将负载线圈22的等效电路反射到接收线圈21,得到接收装置的等效电路,如图3所示,其中,接收装置的等效电路包括:接收线圈21的第三辐射电阻Rrad3及第三损耗电阻Rp3和负载线圈22的第四辐射电阻Rrad4及第四损耗电阻Rp4的阻抗之和R3、负载线圈22的负载RL和第四电容C4等效到接收线圈21的阻抗之和R4、接收线圈21的第三等效电容C3、接收线圈21的第三电感L3。Further, the equivalent circuit of the load coil 22 can be reflected to the receiving coil 21 to obtain the equivalent circuit of the receiving device, as shown in FIG. 3 , wherein the equivalent circuit of the receiving device includes: the third radiation resistance of the receiving coil 21 R rad3 and the third loss resistance R p3 and the fourth radiation resistance R rad4 of the load coil 22 and the impedance sum of the fourth loss resistance Rp4 R 3 , the load R L of the load coil 22 and the fourth capacitance C 4 are equivalent to the receiver The sum R 4 of the impedance of the coil 21 , the third equivalent capacitance C 3 of the receiving coil 21 , and the third inductance L 3 of the receiving coil 21 .
具体的,接收线圈21的线径的获取方法可以参照实施例四的详细说明,在此不再赘述。Specifically, the method for obtaining the wire diameter of the receiving coil 21 may refer to the detailed description of Embodiment 4, and details are not repeated here.
在发射装置与接收装置之间的传输距离D固定,接收线圈的材料、线圈半径以及谐振工作频率已经固定的情况下,此时接收线圈的线径若与传输距离除以接收线圈的半径的立方成正比,并且分别与真空磁导率、第二电导率、第二谐振角频率的负二分之一次方成正比时,则可以接收装置接收发射装置传输的电能时接收装置处于临界耦合状态,使得传输效率得到明显提高。When the transmission distance D between the transmitting device and the receiving device is fixed, and the material, coil radius and resonant operating frequency of the receiving coil have been fixed, if the wire diameter of the receiving coil is the cube of the transmission distance divided by the radius of the receiving coil When it is directly proportional to the vacuum magnetic permeability, the second electrical conductivity, and the negative half power of the second resonant angular frequency, the receiving device can be in a critical coupling state when the receiving device receives the electric energy transmitted by the transmitting device , so that the transmission efficiency is significantly improved.
实施例九Embodiment nine
本实施例提供了一种电能传输系统,如图3所示,该无线电能传输系统包括上述实施例提供的电能发射装置1和无线电能接收装置2,其中,发射线圈的线径和接收线圈的线径相等,第一谐振角频率和第二谐振角频率相等,第一电导率和第二电导率相等,发射线圈的半径和接收线圈的半径相等。即发射装置和接收装置可设计为相同的尺寸和机械结构。并且,发射线圈和接收线圈为螺旋线圈并且同轴放置。This embodiment provides a power transmission system. As shown in FIG. 3, the wireless power transmission system includes the power transmitting device 1 and the wireless power receiving device 2 provided in the above embodiment, wherein the wire diameter of the transmitting coil and the diameter of the receiving coil The wire diameters are equal, the first resonant angular frequency is equal to the second resonant angular frequency, the first conductivity is equal to the second conductivity, and the radius of the transmitting coil is equal to the radius of the receiving coil. That is, the transmitting device and the receiving device can be designed to have the same size and mechanical structure. Also, the transmitting coil and the receiving coil are helical coils and coaxially placed.
可以看出,在发射装置与接收装置之间的传输距离D固定,接收线圈的材料、线圈半径以及谐振工作频率已经固定的情况下,此时接收线圈的线径若与传输距离除以接收线圈的半径的立方成正比,并且分别与真空磁导率、第二电导率、第二谐振角频率的负二分之一次方成正比时,则接收装置接收发射装置传输的电能时,整个电能传输系统处于临界耦合状态,使得传输效率得到明显提高。It can be seen that when the transmission distance D between the transmitting device and the receiving device is fixed, and the material, coil radius and resonant operating frequency of the receiving coil have been fixed, if the wire diameter of the receiving coil is divided by the transmission distance by the receiving coil is proportional to the cube of the radius, and is proportional to the vacuum magnetic permeability, the second electrical conductivity, and the negative half power of the second resonant angular frequency respectively, when the receiving device receives the electric energy transmitted by the transmitting device, the entire electric energy The transmission system is in a critically coupled state, so that the transmission efficiency is significantly improved.
最后应说明的是:以上实施例仅用以说明本发明的技术方案,而非对其限制;尽管参照前述实施例对本发明进行了详细的说明,本领域的普通技术乘客应当理解:其依然可以对前述各实施例所记载的技术方案进行修改,或者对其中部分技术特征进行等同替换;而这些修改或者替换,并不使相应技术方案的本质脱离本发明各实施例技术方案的精神和范围。Finally, it should be noted that: the above embodiments are only used to illustrate the technical solutions of the present invention, but not to limit them; although the present invention has been described in detail with reference to the foregoing embodiments, passengers of ordinary skill in the art should understand that: it can still be Modifications are made to the technical solutions described in the foregoing embodiments, or equivalent replacements are made to some of the technical features; and these modifications or replacements do not make the essence of the corresponding technical solutions deviate from the spirit and scope of the technical solutions of the various embodiments of the present invention.
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