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CN105141566B - A kind of PTS method reducing SCMA systems PAPR - Google Patents

A kind of PTS method reducing SCMA systems PAPR Download PDF

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CN105141566B
CN105141566B CN201510511470.9A CN201510511470A CN105141566B CN 105141566 B CN105141566 B CN 105141566B CN 201510511470 A CN201510511470 A CN 201510511470A CN 105141566 B CN105141566 B CN 105141566B
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杨霖
何向东
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University of Electronic Science and Technology of China
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    • HELECTRICITY
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Abstract

本发明属于无线通信技术领域,尤其涉及一种稀疏码分多址(Sparse Code Multiple Access,SCMA)系统中正交频分复用(Orthogonal Frequency Division Multiplexing,OFDM)信号峰均功率比(Peak‑to‑average power ratio,PAPR)的抑制方法。一种降低SCMA系统PAPR的PTS方法,利用SCMA的多址传输特性,在用户和频点两个维度上对时域资源块进行相位旋转,并利用码本的稀疏特性,通过少量低维IFFT运算即可获得较多的备选序列。

The invention belongs to the technical field of wireless communication, in particular to an Orthogonal Frequency Division Multiplexing (Orthogonal Frequency Division Multiplexing, OFDM) signal peak-to-average power ratio (Peak-to ‑average power ratio, PAPR) suppression method. A PTS method for reducing the PAPR of SCMA system, which uses the multiple access transmission characteristics of SCMA to perform phase rotation on time-domain resource blocks in the two dimensions of user and frequency point, and uses the sparseness of the codebook to perform a small number of low-dimensional IFFT operations More candidate sequences can be obtained.

Description

一种降低SCMA系统PAPR的PTS方法A PTS Method for Reducing PAPR of SCMA System

技术领域technical field

本发明属于无线通信技术领域,尤其涉及一种稀疏码分多址(Sparse CodeMultiple Access,SCMA)系统中正交频分复用(Orthogonal Frequency DivisionMultiplexing,OFDM)信号峰均功率比(Peak-to-average power ratio,PAPR)的抑制方法。The invention belongs to the technical field of wireless communication, and in particular relates to a peak-to-average power ratio (Peak-to-average) signal peak-to-average power ratio (Peak-to-average) of a sparse code division multiple access (Sparse Code Multiple Access, SCMA) system (Orthogonal Frequency Division Multiplexing, OFDM) power ratio, PAPR) inhibition method.

背景技术Background technique

随着LTE系统投入商用,面对不断增长的用户数量、无处不在的网络接入以及更高的通信质量需求,人们开始了对5G的研究。With the commercialization of the LTE system, in the face of the ever-increasing number of users, ubiquitous network access, and higher communication quality requirements, people began to study 5G.

SCMA系统因为其优于LTE系统的链路传输质量和成倍的系统容量而成为新的研究热点。然而与其他基于OFDM的系统一样,基于OFDM的SCMA系统存在高峰均比(PAPR)问题,使得信号在功放后产生非线性失真,且实际过。The SCMA system has become a new research hotspot because of its better link transmission quality and doubled system capacity than the LTE system. However, like other OFDM-based systems, the OFDM-based SCMA system has a peak-to-average ratio (PAPR) problem, which causes nonlinear distortion of the signal after the power amplifier, which is too practical.

SCMA系统中,由于用户信号数目较多,高PAPR的缺陷更为明显,因此,根据SCMA系统的信号传输方式,降低系统的PAPR是必要的。传统的部分传输序列(Partial TransmitSequence,PTS)技术仍然可以应用于SCMA系统中降低OFDM信号的PAPR,但该方法的计算复杂度较高,影响了该方法在实际中的应用。In the SCMA system, due to the large number of user signals, the defect of high PAPR is more obvious. Therefore, according to the signal transmission mode of the SCMA system, it is necessary to reduce the PAPR of the system. The traditional Partial Transmit Sequence (PTS) technology can still be applied to reduce the PAPR of OFDM signals in SCMA systems, but the computational complexity of this method is high, which affects the practical application of this method.

发明内容Contents of the invention

为了解决现有技术的不足,本发明结合SCMA系统的特点,提供一种降低SCMA系统PAPR的PTS方法,该方法利用SCMA的多址传输特性,在用户和频点两个维度上对时域资源块进行相位旋转,并利用码本的稀疏特性,通过少量低维IFFT运算即可获得较多的备选序列。In order to solve the deficiencies of the prior art, the present invention combines the characteristics of the SCMA system to provide a PTS method for reducing the PAPR of the SCMA system. This method utilizes the multiple access transmission characteristics of SCMA to optimize the time domain resources in the two dimensions of users and frequency points. Blocks are phase rotated, and using the sparseness of the codebook, more candidate sequences can be obtained through a small number of low-dimensional IFFT operations.

一种降低SCMA系统PAPR的PTS方法,具体方法如下:A kind of PTS method that reduces SCMA system PAPR, concrete method is as follows:

S1、在发送端对频域信号进行处理,具体为:S1. Process the frequency domain signal at the sending end, specifically:

S11、将第i层长度为N/2的信号比特流经过码本E映射后,获得长度为N的频域序列Xi,其中,i=1,2,3,…,J,J表示信号比特流层数;S11. After mapping the signal bit stream of the i-th layer with a length of N/2 through the codebook E, a frequency-domain sequence Xi with a length of N is obtained, where i=1, 2, 3, ..., J, J represent the signal number of bitstream layers;

S12、将S11所述Xi交织分割成W个长度为N的频域子块其中,W表示每个码字中非零元素个数,w=1,2,3,…,W;S12. Interleave and divide X i described in S11 into W frequency-domain sub-blocks with a length of N Wherein, W represents the number of non-zero elements in each codeword, w=1, 2, 3,..., W;

S13、去掉S12所述中的零元素后获得长度为N/4频域短序列 S13, remove the above mentioned in S12 After the zero element in the short sequence of length N/4 frequency domain is obtained

S2、在发射端对时域信号进行处理,得到时域备选序列,具体为:S2. Process the time-domain signal at the transmitting end to obtain a time-domain candidate sequence, specifically:

S22、根据SCMA的因子图,将所得到的J*W个时域短序列进行组合,获得K个时域短序列其中,K表示因子图中的频点个数,k=1,2,3,...,K;S22. According to the factor diagram of SCMA, the obtained J*W time-domain short sequences are obtained Combining to obtain K time-domain short sequences Among them, K represents the number of frequency points in the factor diagram, k=1, 2, 3,..., K;

Wk-1=[1,exp(j2π(k-1)/N),...,exp(j2π(k-1)(N-1)/N)];W k-1 = [1,exp(j2π(k-1)/N),...,exp(j2π(k-1)(N-1)/N)];

S25、将时域子块叠加获得时域备选信号由此,可获的多个不同的时域备选信号;S25. Sub-blocks in the time domain Obtain alternative signals in time domain by superposition which is Thus, a plurality of different time-domain candidate signals can be obtained;

S3、在时域备选信号中选择出PAPR最小的信号,并串转换后,加入循环前缀,经过D/A转换单元、HPA单元和上变频单元进行发射;S3. Select the signal with the smallest PAPR from the candidate signals in the time domain, add a cyclic prefix after the parallel-to-serial conversion, and transmit through the D/A conversion unit, the HPA unit, and the up-conversion unit;

S4、在接收端对接收到的时域信号进行处理得到频域信号Y;S4. Process the received time-domain signal at the receiving end to obtain a frequency-domain signal Y;

S5、在接收端对S42所述频域信号Y进行处理,具体如下:S5. Process the frequency domain signal Y described in S42 at the receiving end, specifically as follows:

S51、将S4所述频域信号Y交织分割成K个频域子块YkS51. Interleaving and dividing the frequency domain signal Y described in S4 into K frequency domain sub-blocks Y k ;

S52、对每个频域子块乘上相位因子后叠加起来获得频域信号 S52. Multiply each frequency-domain sub-block by a phase factor and superimpose to obtain a frequency-domain signal

S53、对S1所述码本E进行旋转获得新的码本 S53. Rotate the codebook E described in S1 to obtain a new codebook

S6、将S52中获得的频域信号和S53中获得的码本E输入到MPA接收器中,最后输出每层对应的发送信号。S6, the frequency domain signal obtained in S52 and the codebook E obtained in S53 are input to the MPA receiver, and finally the corresponding transmission signal of each layer is output.

进一步地,S4所述得到频域信号Y,具体为:Further, the frequency-domain signal Y obtained in S4 is specifically:

S41、将接收到的信号经过下变频和A/D转换单元后,去掉循环前缀,串并转换后获得时域信号y;S41. After the received signal is down-converted and A/D conversion unit, the cyclic prefix is removed, and the time-domain signal y is obtained after serial-to-parallel conversion;

S42、将S41所述时域信号y进行FFT运算获得频域信号Y。S42. Perform an FFT operation on the time-domain signal y described in S41 to obtain a frequency-domain signal Y.

本发明的有益效果是:The beneficial effects of the present invention are:

本发明应用于5G的SCMA系统中,可以降低OFDM信号的PAPR,充分利用SCMA系统的多址传输特点和码本稀疏性,在用户和频点两个维度上对时域资源块进行相位旋转,通过低维IFFT运算获得较多的时域备选信号,明显降低了OFDM信号的PAPR,且发送端复杂度较低。The present invention is applied in the 5G SCMA system, which can reduce the PAPR of the OFDM signal, fully utilize the multiple access transmission characteristics and codebook sparsity of the SCMA system, and perform phase rotation on the time domain resource block in the two dimensions of user and frequency point, More time-domain candidate signals are obtained through low-dimensional IFFT operation, which significantly reduces the PAPR of OFDM signals, and the complexity of the sending end is low.

接收端利用码本旋转获得新码本,作为MPA接收器的输入,有效地恢复出原始发送信号。The receiving end uses the codebook rotation to obtain a new codebook, which is used as the input of the MPA receiver to effectively recover the original transmitted signal.

附图说明Description of drawings

图1为本发明的系统框图。Fig. 1 is a system block diagram of the present invention.

图2为SCMA的因子图。Figure 2 is the factor diagram of SCMA.

图3为本发明的接收端处理流程图。FIG. 3 is a flow chart of receiving end processing in the present invention.

图4为本发明的具体处理流程图。Fig. 4 is a specific processing flowchart of the present invention.

图5为PAPR性能曲线。Figure 5 is the PAPR performance curve.

具体实施方式Detailed ways

下面结合附图介绍本发明的具体实施方式:Introduce the specific embodiment of the present invention below in conjunction with accompanying drawing:

本实施例采用Matlab仿真平台进行实验,系统参数如下:子载波数为N=256,层数J=6,可用的频点数K=4,过载率为150%,相位旋转因子P1,j,P2,k∈[±1],仿真次数为105,所用码本如表1所示:In this embodiment, the Matlab simulation platform is used for experiments, and the system parameters are as follows: the number of subcarriers is N=256, the number of layers J=6, the number of available frequency points K=4, the overload rate is 150%, and the phase rotation factor P 1,j , P 2, k ∈ [±1], the number of simulations is 105, and the codebook used is shown in Table 1:

表1 4*6的码本集Table 1 4*6 codebook set

发送端处理:Sender processing:

各层长度为128的二进制比特流通过各自的码本映射成长度为256的复信号序列,对这些信号序列进行交织分割得到12个长度为256的子序列,然后将这些子序列去零后做64点的IFFT,得到时域短信号。The binary bit stream with a length of 128 in each layer is mapped into a complex signal sequence with a length of 256 through its respective codebook, and these signal sequences are interleaved and segmented to obtain 12 subsequences with a length of 256, and then these subsequences are dezeroed to do 64-point IFFT to obtain short signals in the time domain.

时域信号相位旋转产生备选序列。Phase rotation of the time-domain signal produces candidate sequences.

将各层的时域子序列乘上相位因子P1,j后,根据SCMA因子图组合这些旋转后的子序列,得到4个长度为64的信号子块,然后再次对这些时域子块做P2,k的相位旋转,根据IFFT性质获得4个长度为256的子块,最后将这些子块相加获得时域备选序列。After multiplying the time-domain sub-sequences of each layer by the phase factor P 1,j , these rotated sub-sequences are combined according to the SCMA factor diagram to obtain 4 signal sub-blocks with a length of 64, and then these time-domain sub-blocks are processed again The phase rotation of P 2,k , according to the IFFT property, obtains 4 sub-blocks with a length of 256, and finally adds these sub-blocks to obtain the time-domain candidate sequence.

计算各备选序列的PAPR,选择出最小的。Calculate the PAPR of each candidate sequence and select the smallest one.

接收端处理:Receiver processing:

将接收到的信号经过下变频和A/D转换单元后,去掉循环前缀,再经过串并转换获得时域信号,然后将该时域信号进行FFT运算获得频域信号Y。After the received signal is down-converted and A/D conversion unit, the cyclic prefix is removed, and then the time-domain signal is obtained through serial-to-parallel conversion, and then the time-domain signal is subjected to FFT operation to obtain the frequency-domain signal Y.

将频域信号Y交织分割成4个频域子块Yk。对每个频域子块乘上相位因子P2,k后叠加起来获得频域信号对原始的码本组进行P1,j的旋转获得新的码本组 The frequency domain signal Y is interleaved and divided into 4 frequency domain sub-blocks Y k . Multiply the phase factor P 2,k for each frequency domain sub-block and then superimpose them to obtain the frequency domain signal Rotate the original codebook group by P 1,j to obtain a new codebook group

将频域信号和新码本组输入到MPA接收器中,最后输出每层对应的发送信号。frequency domain signal and the new codebook set Input to the MPA receiver, and finally output the corresponding transmission signal of each layer.

采用本发明所述方法进行仿真测试。比较所述方法与传统PTS(包括相邻,随机,交织分割)的PAPR性能。如图5所示,本发明的PAPR抑制性能与传统PTS(随机分割方式)相近,且优于传统PTS(交织或相邻方式)的PAPR抑制性能,然而,如表2所示,产生相同的备选序列情况下,本发明所需的复数乘法和复数加法次数远小于传统的PTS方法。The simulation test is carried out by adopting the method of the present invention. The PAPR performance of the method is compared with conventional PTS (including adjacent, random, interleaved partitions). As shown in Figure 5, the PAPR suppression performance of the present invention is similar to that of traditional PTS (random segmentation mode), and is better than the PAPR suppression performance of traditional PTS (interleaved or adjacent mode), yet, as shown in Table 2, the same In the case of alternative sequences, the number of complex multiplications and complex additions required by the present invention is much smaller than that of the traditional PTS method.

表2 主要发送端复杂度比较Table 2 Comparison of main sender complexity

Claims (1)

1.一种降低SCMA系统PAPR的PTS方法,其特征在于,包括以下步骤:1. a kind of PTS method that reduces SCMA system PAPR is characterized in that, comprises the following steps: S1、在发送端对频域信号进行处理,具体为:S1. Process the frequency domain signal at the sending end, specifically: S11、将第i层长度为N/2的信号比特流经过码本E映射后,获得长度为N的频域序列Xi,其中,i=1,2,3,…,J,J表示信号比特流层数;S11. After mapping the signal bit stream of the i-th layer with a length of N/2 through the codebook E, a frequency-domain sequence Xi with a length of N is obtained, where i=1, 2, 3, ..., J, J represent the signal number of bitstream layers; S12、将S11所述Xi交织分割成W个长度为N的频域子块其中,W表示每个码字中非零元素个数;S12. Interleave and divide X i described in S11 into W frequency-domain sub-blocks with a length of N Wherein, W represents the number of non-zero elements in each codeword; S13、去掉S12所述中的零元素后获得长度为N/4频域短序列 S13, remove the above mentioned in S12 After the zero element in the short sequence of length N/4 frequency domain is obtained S14、对S13所述进行N/4点IFFT运算获得时域短序列 S14, described in S13 Perform N/4-point IFFT operation to obtain short sequence in time domain which is S2、在发射端对时域信号进行处理,得到时域备选序列,具体为:S2. Process the time-domain signal at the transmitting end to obtain a time-domain candidate sequence, specifically: S21、将S14所述乘上相位旋转因子p1,i获得相位旋转后的时域短序列,即其中,P1,i∈{1,-1};S21, the S14 said Multiply the phase rotation factor p 1,i to obtain the time-domain short sequence after phase rotation, namely Among them, P 1,i ∈{1,-1}; S22、根据SCMA的因子图,将所得到的J*W个时域短序列进行组合,获得K个时域短序列其中,K表示因子图中的频点个数,k=1,2,3,...,K;S22. According to the factor diagram of SCMA, the obtained J*W time-domain short sequences are obtained Combining to obtain K time-domain short sequences Among them, K represents the number of frequency points in the factor diagram, k=1, 2, 3,..., K; S23、将时域短序列乘上相位旋转因子p2,k获得时域子序列其中,P2,k∈{1,-1};S23, the time domain short sequence Multiply the phase rotation factor p 2,k to obtain the time domain subsequence which is Among them, P 2,k ∈{1,-1}; S24、根据IFFT运算性质,将时域短序列进行变换后获得长度为N的时域子块其中,S24. According to the nature of the IFFT operation, the time-domain short sequence A time-domain sub-block of length N is obtained after transformation which is in, Wk-1=[1,exp(j2π(k-1)/N),...,exp(j2π(k-1)(N-1)/N)];W k-1 = [1,exp(j2π(k-1)/N),...,exp(j2π(k-1)(N-1)/N)]; S25、将时域子块叠加获得时域备选信号由此,可获的多个不同的时域备选信号;S25. Sub-blocks in the time domain Obtain alternative signals in time domain by superposition which is Thus, a plurality of different time-domain candidate signals can be obtained; S3、在时域备选信号中选择出PAPR最小的信号,并串转换后,加入循环前缀,经过D/A转换单元、HPA单元和上变频单元进行发射;S3. Select the signal with the smallest PAPR from the candidate signals in the time domain, add a cyclic prefix after the parallel-to-serial conversion, and transmit through the D/A conversion unit, the HPA unit, and the up-conversion unit; S4、在接收端对接收到的时域信号进行处理得到频域信号Y,具体为:S4. Process the received time-domain signal at the receiving end to obtain a frequency-domain signal Y, specifically: S41、将接收到的信号经过下变频和A/D转换单元后,去掉循环前缀,串并转换后获得时域信号y;S41. After the received signal is down-converted and A/D conversion unit, the cyclic prefix is removed, and the time-domain signal y is obtained after serial-to-parallel conversion; S42、将S41所述时域信号y进行FFT运算获得频域信号Y;S42. Perform an FFT operation on the time-domain signal y described in S41 to obtain a frequency-domain signal Y; S5、在接收端对S42所述频域信号Y进行处理,具体如下:S5. Process the frequency domain signal Y described in S42 at the receiving end, specifically as follows: S51、将S4所述频域信号Y交织分割成K个频域子块YkS51. Interleaving and dividing the frequency domain signal Y described in S4 into K frequency domain sub-blocks Y k ; S52、对每个频域子块乘上相位旋转因子后叠加起来获得频域信号 S52. Multiply each frequency domain sub-block by a phase rotation factor and then superimpose them to obtain a frequency domain signal S53、对S11所述码本E进行旋转获得新的码本 S53. Rotate the codebook E described in S11 to obtain a new codebook S6、将S52中获得的频域信号和S53中获得的码本输入到MPA接收器中,最后输出每层对应的发送信号。S6, the frequency domain signal obtained in S52 and the codebook obtained in S53 Input to the MPA receiver, and finally output the corresponding transmission signal of each layer.
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