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CN104936089B - A kind of multi-channel system compressing method - Google Patents

A kind of multi-channel system compressing method Download PDF

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CN104936089B
CN104936089B CN201510214877.5A CN201510214877A CN104936089B CN 104936089 B CN104936089 B CN 104936089B CN 201510214877 A CN201510214877 A CN 201510214877A CN 104936089 B CN104936089 B CN 104936089B
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replaced
speakers
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loudspeakers
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胡瑞敏
王松
王晓晨
方博伟
李诗晴
杨乘
武庭照
张灵鲲
杨玉红
涂卫平
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Wuhan University WHU
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Abstract

一种多声道系统精简方法,设待替换扬声器组和替换扬声器组位于同一个球面上,球面的球心为听音点,获取所有扬声器的位置信息,计算替换扬声器组替换单个待替换的扬声器的初始分配系数,得到替换扬声器组的信号并删除待替换的扬声器,通过求和的方法得到替换扬声器组中各个扬声器的最终信号。传统方法使用三个扬声器替换一个待替换扬声器,可以将22.2多声道系统精简到10声道、8声道系统,但是未能完全保持听音点处重建声音的物理性质,本发明使用替换扬声器组中的全部扬声器参与替换,更充分保持听音点处声音的物理性质,可以获得多个扬声器替换一个扬声器的最优分配系数,有利于多声道系统精简之后重建声场效果的提升。

A multi-channel system simplification method, assuming that the speaker group to be replaced and the replacement speaker group are located on the same spherical surface, the center of the sphere is the listening point, the position information of all speakers is obtained, and the replacement speaker group is calculated to replace a single speaker to be replaced The initial distribution coefficient of , get the signal of the replacement speaker group and delete the speaker to be replaced, and get the final signal of each speaker in the replacement speaker group by summing. The traditional method uses three loudspeakers to replace a loudspeaker to be replaced, which can simplify the 22.2 multi-channel system to 10-channel and 8-channel systems, but fails to fully maintain the physical properties of the reconstructed sound at the listening point. The present invention uses the replacement loudspeaker All the speakers in the group participate in the replacement, which can more fully maintain the physical properties of the sound at the listening point, and can obtain the optimal distribution coefficient for multiple speakers to replace one speaker, which is conducive to the improvement of the sound field effect after the multi-channel system is simplified.

Description

一种多声道系统精简方法A Streamlined Method for Multi-channel System

技术领域technical field

本发明属于声学领域,尤其涉及一种多声道系统精简方法。The invention belongs to the field of acoustics, in particular to a method for simplifying a multi-channel system.

背景技术Background technique

随着三维电视和三维电影技术的发展,三维音频技术成为了多媒体领域的一个研究热点。三维平移是一种在三维声场中使用若干扬声器制造虚拟声源的技术。在三维平移方法中,基于向量的幅度平移技术(vector based amplitude panning简记为VBAP)被广泛认可。在三维VBAP中,虚拟声源用三个扬声器合成,起点在听音点,终点在虚拟声源所在位置的单位向量可以用另外三个向量线性表示(每个向量起点在听音点,终点在每个向量所对应扬声器所在位置,长度为1)。三个向量表示的系数经过归一化之后,作为权重系数使得虚拟声源的信号分配到表示向量所对应的三个扬声器。如果表示虚拟声源使用的扬声器数目多于三个,VBAP技术将整个重建扬声器空间按三个扬声器一组分为若干个子空间,在每个子空间中按照VBAP进行信号分配。With the development of 3D TV and 3D movie technology, 3D audio technology has become a research hotspot in the field of multimedia. Three-dimensional panning is a technique that uses several speakers in a three-dimensional sound field to create a virtual sound source. Among the three-dimensional panning methods, a vector based amplitude panning technique (vector based amplitude panning abbreviated as VBAP) is widely recognized. In three-dimensional VBAP, the virtual sound source is synthesized by three speakers, the starting point is at the listening point, and the unit vector ending at the position of the virtual sound source can be linearly represented by three other vectors (the starting point of each vector is at the listening point, and the ending point is at Each vector corresponds to the position of the loudspeaker, and the length is 1). After the coefficients represented by the three vectors are normalized, they are used as weight coefficients so that the signals of the virtual sound source are distributed to the three speakers corresponding to the representation vectors. If the number of speakers used to represent the virtual sound source is more than three, the VBAP technology divides the entire reconstructed speaker space into several subspaces in groups of three speakers, and distributes signals in each subspace according to VBAP.

5.1多声道系统曾经是非常流行的家庭影院声音系统。但是随着3D视频技术的发展,对音频技术提出了更高的要求,现在多声道音频研究专注于更加先进的带有更多声道的系统,可以为人们提供更好的沉浸感。例如,日本广播协会实验室的22.2多声道系统已经被用于超高清电视转播。这一先进的多声道系统要求按照自己独特的扬声器摆放方法放置扬声器才能产生最好的声音效果。尽管24个扬声器可以按照最优的方法摆放在剧院,但是在家庭应用时摆放麻烦。“下混”是多声道系统中很好的减少扬声器声道的方法。从5.1下混到两声道立体声或单声道已经被ITU-R Recommendation标准化,并被用于一些电视接收器。尽管这一下混方法十分高效,但是它并不适用于任意数量的扬声器配置。为了使得多个系统之间的下混变得可行,人们迫切需要一种新的声场重建或转化技术。5.1 multi-channel systems used to be very popular home theater sound systems. However, with the development of 3D video technology, higher requirements are placed on audio technology. Now multi-channel audio research focuses on more advanced systems with more channels, which can provide people with a better sense of immersion. For example, the 22.2 multi-channel system of NHK Laboratories has been used for UHD TV broadcasting. This advanced multi-channel system requires speakers to be placed in their own unique way to produce the best sound. Although 24 loudspeakers can be placed optimally in a theater, they can be cumbersome to place in a home application. "Downmixing" is a great way to reduce speaker channels in multi-channel systems. Downmixing from 5.1 to two-channel stereo or mono has been standardized by the ITU-R Recommendation and is used in some TV receivers. Although this downmixing method is very efficient, it is not suitable for any number of loudspeaker configurations. In order to make the downmix between multiple systems feasible, a new sound field reconstruction or conversion technology is urgently needed.

2011年日本广播协会实验室的Akio Ando提出了一种新的下混方法,此方法利用在同一球面上的三个扬声器替换此三个扬声器构成的球面三角形包围的一个扬声器(此四个扬声器位于同一球面上,球面中心为听音点),保证替换前后听音点位置处的声压大小和质子速度方向不变,该方法为VBAP技术提供了物理基础理论,反复利用该方法可以逐渐把22.2多声道系统精简到10声道或8声道系统(两个低频声道不作处理),听音效果优于传统的下混方法。声音的物理性质可以由声压和质子速度共同表示,声压为标量,只有大小,质子速度为向量,具有大小和方向。因此Akio Ando的方法只保证了精简前后声压大小和质子速度的方向,忽略了质子速度的大小,将会给22.2多声道系统重建带来误差。In 2011, Akio Ando of the Japan Broadcasting Association Laboratory proposed a new downmixing method, which uses three speakers on the same spherical surface to replace a speaker surrounded by a spherical triangle formed by the three speakers (these four speakers are located at On the same sphere, the center of the sphere is the listening point), to ensure that the sound pressure and the direction of the proton velocity at the listening point before and after replacement remain unchanged. This method provides a physical basis for the VBAP technology. Repeated use of this method can gradually change the 22.2 The multi-channel system is reduced to a 10-channel or 8-channel system (the two low-frequency channels are not processed), and the listening effect is better than the traditional down-mixing method. The physical properties of sound can be represented by both sound pressure and proton velocity. Sound pressure is a scalar with only magnitude, and proton velocity is a vector with magnitude and direction. Therefore, Akio Ando's method only guarantees the sound pressure before and after the streamlining and the direction of the proton velocity, ignoring the proton velocity, which will bring errors to the reconstruction of the 22.2 multi-channel system.

发明内容Contents of the invention

本发明针对现有技术的不足,提供一种多声道系统精简方法。Aiming at the deficiencies of the prior art, the present invention provides a multi-channel system simplification method.

本发明技术方案提供一种多声道系统精简方法,包括以下步骤,The technical solution of the present invention provides a multi-channel system simplification method, comprising the following steps,

步骤1,设替换扬声器组和待替换扬声器组均位于同一球面上,待替换扬声器组包括m个扬声器Spv1、Spv2、…、Spvm,扬声器Spv1、Spv2、…、Spvm的原始信号均为S,替换扬声器组包括n个扬声器Sp1、Sp2、…、Spn,n<m,球面的球心位置为听音点;获得n个扬声器Sp1、Sp2、…、Spn替换单个待替换扬声器Spvh所分配得到的信号,h=1,2,…,m,包括以下子步骤,Step 1, assume that the replacement speaker group and the speaker group to be replaced are located on the same spherical surface, the speaker group to be replaced includes m speakers Spv1, Spv2, ..., Spvm, and the original signals of the speakers Spv1, Spv2, ..., Spvm are all S, the replacement The loudspeaker group includes n loudspeakers Sp1, Sp2, ..., Spn, n<m, and the position of the center of the sphere is the listening point; obtain n loudspeakers Sp1, Sp2, ..., Spn to replace a single loudspeaker Spvh to be replaced. , h=1, 2,..., m, including the following sub-steps,

步骤101,获得m个扬声器Spv1、Spv2、…、Spvm分别的位置信息,n个扬声器Sp1、Sp2、…、Spn分别的位置信息;Step 101, obtaining the respective position information of m loudspeakers Spv1, Spv2, ..., Spvm, and the respective position information of n loudspeakers Sp1, Sp2, ..., Spn;

步骤102,计算确定n个扬声器Sp1、Sp2、…、Spn的初始分配系数wh1,wh2,…,whn,包括Step 102, calculate and determine the initial distribution coefficients w h1 , w h2 , ..., w hn of n loudspeakers Sp1, Sp2 , ..., Spn, including

构建方程如下,The construction equation is as follows,

其中,in,

Wh=(wh1 wh2 … whn)T,T表示矩阵转置,whj表示替换扬声器Spj针对待替换扬声器Spvh的信号分配系数,j=1,2,…,n;W h = (w h1 w h2 ... w hn ) T , T represents matrix transposition, w hj represents the signal distribution coefficient of the replacement speaker Spj for the speaker Spvh to be replaced, j=1, 2,..., n;

E1=(0 0 1)TE 1 =(0 0 1) T ;

θvh表示待替换的扬声器Spvh所在位置与原点O之间连线在XOY平面的射影与X轴之间的夹角,h=1,2,…,m;θ vh represents the angle between the projection of the line between the position of the speaker Spvh to be replaced and the origin O on the XOY plane and the X axis, h=1, 2,..., m;

表示待替换的扬声器Spvh所在位置与原点O之间连线与XOY平面之间的夹角,h=1,2,…,m; Indicates the angle between the line between the position of the speaker Spvh to be replaced and the origin O and the XOY plane, h=1, 2, ..., m;

θj表示扬声器Spj所在位置与原点O之间连线在XOY平面的射影与X轴之间的夹角,j=1,2,…,n;θ j represents the angle between the projection of the line between the position of the speaker Spj and the origin O on the XOY plane and the X axis, j=1, 2,..., n;

表示扬声器Spj所在位置与原点O之间连线与XOY平面之间的夹角,j=1,2,…,n;步骤103,将单个待替换的扬声器Spvh的信号分别乘以步骤102所得初始分配系数 Represent the angle between the line between the position of the speaker Spj and the origin O and the XOY plane, j=1, 2,..., n; Step 103, multiply the signal of the single speaker Spvh to be replaced by the initial value obtained in step 102 respectively Partition coefficient

wh1,wh2,…,whn后分配到相应扬声器Sp1、Sp2、…、Spn中,删除待替换的扬声器Spvh,h=1,2,…,m;After w h1 , w h2 ,...,w hn are assigned to corresponding speakers Sp1, Sp2,..., Spn, delete the speaker Spvh to be replaced, h=1, 2,..., m;

步骤2,计算得到扬声器Sp1、Sp2、…、Spn分别的信号,包括将步骤1中所得扬声器Spj分配得到的一系列相应信号求和,扬声器Spj的最终分配信号计算公式如下:Step 2, calculate and obtain the respective signals of the speakers Sp1, Sp2, ..., Spn, including summing a series of corresponding signals obtained by distributing the loudspeaker Spj obtained in step 1, the final distribution signal calculation formula of the loudspeaker Spj is as follows:

其中,j=1,2,…,n。Wherein, j=1, 2, . . . , n.

而且,n=10,m=22。Also, n=10, m=22.

采用本发明提供的m个扬声器系统精简为n个扬声器系统的方法,相较于AkioAndo在2011年提出的下混方法仅能保证替换前后听音点处声压大小和质子速度的方向不变,本专利的方法既保证了替换前后听音点处声压大小和质子速度的方向不变,又保证替换前后质子速度大小的误差最小,有利于提升合成虚拟声源的效果。本发明可以对包含任意多个扬声器的多声道系统进行精简处理,具备很好的普适性。Compared with the down-mixing method proposed by AkioAndo in 2011, the m loudspeaker systems provided by the present invention can be simplified into n loudspeaker systems, which can only ensure that the sound pressure and the direction of the proton velocity at the listening point remain unchanged before and after replacement. The method of this patent not only ensures that the sound pressure at the listening point and the direction of the proton velocity remain unchanged before and after the replacement, but also ensures that the error of the proton velocity before and after the replacement is the smallest, which is conducive to improving the effect of synthesizing the virtual sound source. The invention can simplify the multi-channel system including any number of loudspeakers, and has good universality.

附图说明Description of drawings

图1为本发明的基本流程图。Fig. 1 is the basic flowchart of the present invention.

图2是本发明实施例的待替换扬声器摆放位置图。Fig. 2 is a diagram showing the placement of speakers to be replaced according to the embodiment of the present invention.

图3是本发明实施例的替换扬声器摆放位置图。Fig. 3 is a diagram showing placement positions of replacement loudspeakers according to the embodiment of the present invention.

具体实施方式Detailed ways

本发明针对摆放在同一球面上的多声道系统,提出了一种多声道系统精简方法,该方法的核心技术是利用任意多个扬声器替换一个待替换扬声器,以下结合附图和具体实施例详细说明本发明技术方案。The present invention proposes a multi-channel system simplification method for multi-channel systems placed on the same spherical surface. The core technology of the method is to use any number of speakers to replace a speaker to be replaced. The following is combined with the accompanying drawings and specific implementation Examples illustrate the technical solution of the present invention in detail.

实施例的目标是将包含22个扬声器Spv1、Spv2、…、Spv22的多声道系统精简到包含10个扬声器Sp1、Sp2、…、Sp10的多声道系统。假设22个扬声器Spv1、Spv2、…、Spv22为待替换扬声器组,每个扬声器的原始信号均为S,10个扬声器Sp1、Sp2、…、Sp10为替换扬声器组。因此本发明主要利用10个扬声器替换一个待替换扬声器,并逐渐将22个扬声器Spv1、Spv2、…、Spv22用Sp1、Sp2、…、Sp10替换。替换扬声器组和待替换扬声器组均位于同一球面上,球面半径为2米,球面的球心位置为听音点。The goal of an embodiment is to reduce a multi-channel system comprising 22 loudspeakers Spv1, Spv2, ..., Spv22 to a multi-channel system comprising 10 loudspeakers Sp1, Sp2, ..., Sp10. It is assumed that 22 speakers Spv1, Spv2, ..., Spv22 are speaker groups to be replaced, and the original signal of each speaker is S, and 10 speakers Sp1, Sp2, ..., Sp10 are replacement speaker groups. Therefore, the present invention mainly uses 10 speakers to replace a speaker to be replaced, and gradually replaces 22 speakers Spv1, Spv2, . . . , Spv22 with Sp1, Sp2, . . . , Sp10. Both the replacement speaker group and the speaker group to be replaced are located on the same spherical surface, the radius of the spherical surface is 2 meters, and the position of the center of the spherical surface is the listening point.

具体实施时,本发明方法可采用计算机软件技术实现自动运行流程。实施例采用10个扬声器替换一个待替换扬声器的方法逐渐实现22.2多声道系统的精简过程,参见图1,实施例所提供流程包含以下步骤:During specific implementation, the method of the present invention can use computer software technology to realize the automatic operation process. The embodiment uses 10 loudspeakers to replace a loudspeaker to be replaced and gradually realizes the simplification process of the 22.2 multi-channel system. Referring to FIG. 1, the process provided by the embodiment includes the following steps:

步骤1,设m个扬声器Spv1、Spv2、…、Spvm位于同一个球面上,扬声器Spv1、Spv2、…、Spvm的原始信号均为S,扬声器Spv1、Spv2、…、Spvm为待替换扬声器组;n个扬声器Sp1、Sp2、…、Spn为替换扬声器组(n<m),用于精简待替换扬声器组Spv1、Spv2、…、Spvm,扬声器Sp1、Sp2、…、Spn可以与扬声器Spv1、Spv2、…、Spvm中部分扬声器所在位置相同,也可以完全不相同。获得n个扬声器Sp1、Sp2、…、Spn替换一个待替换扬声器Spvh(h=1,2,…,m)所分配得到的信号,替换扬声器组和待替换扬声器组均位于同一球面上,球面的球心位置为听音点。具体实施时,本领域技术人员可自行根据具体情况确定的n、m取值,实现方式相同。Step 1, assuming that m speakers Spv1, Spv2, ..., Spvm are located on the same spherical surface, the original signals of the speakers Spv1, Spv2, ..., Spvm are all S, and the speakers Spv1, Spv2, ..., Spvm are the speaker groups to be replaced; n Speakers Sp1, Sp2, ..., Spn are replacement speaker groups (n<m), which are used to simplify speaker groups Spv1, Spv2, ..., Spvm to be replaced, and speakers Sp1, Sp2, ..., Spn can be connected with speakers Spv1, Spv2, ... 1. The positions of some speakers in Spvm are the same, or they can be completely different. Obtain n loudspeakers Sp1, Sp2, ..., Spn to replace a loudspeaker Spvh (h=1, 2, ..., m) to be replaced by distributing the obtained signal, the replacement loudspeaker group and the loudspeaker group to be replaced are all located on the same spherical surface, and the spherical surface The center of the ball is the listening point. During specific implementation, those skilled in the art can determine the values of n and m according to specific situations, and the implementation methods are the same.

实施例获得10个扬声器Sp1、Sp2、…、Sp10替换单个待替换扬声器所分配得到的信号。包括以下子步骤,The embodiment obtains the signals distributed by replacing a single speaker to be replaced by 10 speakers Sp1, Sp2, . . . , Sp10. Include the following sub-steps,

步骤101,获得22个待替换的扬声器Spv1、Spv2、…、Spv22分别的位置信息,10个替换扬声器Sp1、Sp2、…、Sp10分别的位置信息;Step 101, obtaining the respective position information of 22 loudspeakers Spv1, Spv2, ..., Spv22 to be replaced, and the respective position information of 10 replacement loudspeakers Sp1, Sp2, ..., Sp10;

设以听音点为坐标原点O建立三维直角坐标系XYZ,本发明采用极坐标形式,如点A的坐标(ρAA,)中,ρA表示点A与坐标原点之间的距离,θA表示点A与原点O之间连线在XOY平面的射影与X轴之间的夹角,表示点A与原点O之间连线与XOY平面之间的夹角。假设单个待替换扬声器Spvh(h=1,2,…,22)坐标为(ρ,θvh,),10个替换扬声器Sp1、Sp2、…、Sp10的坐标分别为(ρ,θ1,)、(ρ,θ2,)、(ρ,θ3,)、(ρ,θ4,)、(ρ,θ5,)、(ρ,θ6,)、(ρ,θ7,)、(ρ,θ8,)、(ρ,θ9,)、(ρ,θ10,)。Let the listening point be the coordinate origin O to set up a three-dimensional rectangular coordinate system XYZ, the present invention adopts the polar coordinate form, such as the coordinates of point A (ρ A , θ A , ), ρ A represents the distance between point A and the origin of the coordinates, θ A represents the angle between the projection of the line between point A and origin O on the XOY plane and the X axis, Indicates the angle between the line between point A and origin O and the XOY plane. Assume that the coordinates of a single speaker Spvh (h=1, 2, ..., 22) to be replaced are (ρ, θ vh , ), the coordinates of the 10 replacement speakers Sp1, Sp2, ..., Sp10 are (ρ,θ 1 , ), (ρ,θ 2 , ), (ρ,θ 3 , ), (ρ,θ 4 , ), (ρ,θ 5 , ), (ρ,θ 6 , ), (ρ,θ 7 , ), (ρ,θ 8 , ), (ρ,θ 9 , ), (ρ,θ 10 , ).

假设本实施例中,空心点表示听音点的位置,实心点表示扬声器所在位置。替换扬声器Sp1、Sp2、…、Sp10分别位于球O表面的点,参见图3,扬声器主要分布于高角度Elevation=45°、0°、-30°处,坐标分别为:Sp1(2,0°,90°)、Sp2(2,0°,45°)、Sp3(2,90°,45°)、Sp4(2,180°,45°)、Sp5(2,0°,0°)、Sp6(2,60°,0°)、Sp7(2,120°,0°)、Sp8(2,180°,0°)、Sp9(2,270°,0°)、Sp10(2,90°,-30°),待替换扬声器组Spv1、Spv2、…、Spv22分别位于球O表面的点,参见图2,坐标分别为:Spv1(2,0°,90°)、Spv2(2,0°,45°)、Spv3(2,45°,45°)、Spv4(2,90°,45°)、Spv5(2,135°,45°)、Spv6(2,180°,45°)、Spv7(2,225°,45°)、Spv8(2,270°,45°)、Spv9(2,315°,45°)、Spv10(2,0°,0°)、Spv11(2,30°,0°)、Spv12(2,60°,0°)、Spv13(2,90°,0°)、Spv14(2,120°,0°)、Spv15(2,150°,0°)、Spv16(2,180°,0°)、Spv17(2,225°,0°)、Spv18(2,270°,0°)、Spv19(2,315°,0°)、Spv20(2,45°,-30°)、Spv21(2,90°,-30°)、Spv22(2,135°,-30°)。Assume that in this embodiment, the hollow dots indicate the location of the listening point, and the solid dots indicate the location of the speaker. The replacement speakers Sp1, Sp2, ..., Sp10 are respectively located at points on the surface of the ball O, see Figure 3, the speakers are mainly distributed at high angles Elevation=45°, 0°, -30°, and the coordinates are: Sp1(2,0° ,90°), Sp2(2,0°,45°), Sp3(2,90°,45°), Sp4(2,180°,45°), Sp5(2,0°,0°), Sp6(2 ,60°,0°), Sp7(2,120°,0°), Sp8(2,180°,0°), Sp9(2,270°,0°), Sp10(2,90°,-30°), speakers to be replaced Groups Spv1, Spv2, ..., Spv22 are respectively located at points on the surface of the ball O, see Figure 2, the coordinates are: Spv1(2,0°,90°), Spv2(2,0°,45°), Spv3(2, 45°,45°), Spv4(2,90°,45°), Spv5(2,135°,45°), Spv6(2,180°,45°), Spv7(2,225°,45°), Spv8(2,270°, 45°), Spv9(2,315°,45°), Spv10(2,0°,0°), Spv11(2,30°,0°), Spv12(2,60°,0°), Spv13(2, 90°,0°), Spv14(2,120°,0°), Spv15(2,150°,0°), Spv16(2,180°,0°), Spv17(2,225°,0°), Spv18(2,270°,0° ), Spv19(2,315°,0°), Spv20(2,45°,-30°), Spv21(2,90°,-30°), Spv22(2,135°,-30°).

步骤102,计算确定10个替换扬声器Sp1、Sp2、…、Sp10的初始分配系数。Step 102, calculate and determine the initial allocation coefficients of the 10 replacement speakers Sp1, Sp2, . . . , Sp10.

按照单个待替换的扬声器Spvh(h=1,2,…,m)在听音点处产生的声压大小和质子速度方向与n个替换扬声器在听音点处产生的声压大小和质子速度方向严格相等,单个待替换扬声器Spvh(h=1,2,…,m)在听音点处产生的质子速度大小与n个替换扬声器在听音点处产生的质子速度大小的误差尽可能小的原则,本发明提出初始分配系数计算方案:According to the sound pressure magnitude and proton velocity direction produced by a single loudspeaker Spvh (h=1, 2, ..., m) to be replaced at the listening point and the sound pressure magnitude and proton velocity produced by n replacement loudspeakers at the listening point The directions are strictly equal, and the error between the proton velocity generated by a single speaker Spvh (h=1, 2, ..., m) at the listening point and the proton velocity generated by n replacement speakers at the listening point is as small as possible Based on the principle, the present invention proposes an initial distribution coefficient calculation scheme:

实施例计算单个待替换扬声器Spvh(h=1,2,…,22)的信号分配到10个替换扬声器信号的初始分配系数wh1,wh2,…,wh10(h=1,2,…,22)。The embodiment calculates the initial allocation coefficients w h1 , w h2 , ..., w h10 (h=1, 2, ... ,twenty two).

单个待替换扬声器Spvh在听音点处产生的声压pvh为:The sound pressure p vh produced by a single speaker Spvh to be replaced at the listening point is:

10个替换扬声器Sp1、Sp2、…、Sp10在听音点处产生的声压为phThe sound pressure produced by 10 replacement speakers Sp1, Sp2, ..., Sp10 at the listening point is ph :

其中:in:

ρ表示单个待替换扬声器Spvh所在位置与坐标原点O之间的距离;ρ represents the distance between the position of a single speaker Spvh to be replaced and the coordinate origin O;

G表示在与一个扬声器单位距离处该扬声器的声压与扬声器处产生声压之比例系数;G represents the proportional coefficient between the sound pressure of the speaker at a unit distance from the speaker and the sound pressure generated by the speaker;

e为数学常数;e is a mathematical constant;

i为虚部单位;i is the imaginary unit;

k为波数,f为声音信号频率;k is the wave number, f is the sound signal frequency;

c为声音在空气中的传播速度;c is the speed of sound in air;

whj表示替换扬声器Spj针对待替换扬声器Spvh的信号分配系数,j=1,2,…,10,h=1,2,…,22;w hj represents the signal distribution coefficient of the replacement loudspeaker Spj for the loudspeaker Spvh to be replaced, j=1,2,...,10, h=1,2,...,22;

s(ω)表示扬声器输入信号的傅里叶变换。s(ω) represents the Fourier transform of the speaker input signal.

由(1)与(2)式相等计算得到:Calculated by formula (1) and formula (2):

wh1+wh2+…+wh10=1 (3)w h1 +w h2 +…+w h10 =1 (3)

单个待替换扬声器Spvh在听音点处产生的质子速度uvh为:The proton velocity u vh produced by a single speaker Spvh to be replaced at the listening point is:

其中:in:

ρ表示单个待替换扬声器Spvh所在位置与坐标原点O之间的距离;ρ represents the distance between the position of a single speaker Spvh to be replaced and the coordinate origin O;

θvh表示单个待替换扬声器Spvh所在位置与原点O之间连线在XOY平面的射影与X轴之间的夹角;θ vh represents the angle between the projective projection of the single speaker Spvh to be replaced and the origin O on the XOY plane and the X axis;

表示单个待替换扬声器Spvh所在位置与原点O之间连线与XOY平面之间的夹角; Represent the angle between the line between the position of the single speaker Spvh to be replaced and the origin O and the XOY plane;

G表示在与一个扬声器单位距离处该扬声器的声压与扬声器处产生声压之比例系数;G represents the proportional coefficient between the sound pressure of the speaker at a unit distance from the speaker and the sound pressure generated by the speaker;

e为数学常数;e is a mathematical constant;

i为虚部单位;i is the imaginary unit;

k为波数,f为声音信号频率;k is the wave number, f is the sound signal frequency;

c为声音在空气中的传播速度;c is the speed of sound in air;

λ为空气密度;λ is the air density;

s(ω)表示扬声器输入信号的傅里叶变换。s(ω) represents the Fourier transform of the speaker input signal.

10个替换扬声器Sp1、Sp2、…、Sp10在听音点处产生的质子速度为:Proton velocity produced by 10 replacement speakers Sp1, Sp2, ..., Sp10 at the listening point for:

Wh=(wh1 wh2 … wh10)T W h =(w h1 w h2 … w h10 ) T

其中:in:

θj表示替换扬声器Spj所在位置与原点O之间连线在XOY平面的射影与X轴之间的夹角,j=1,2,…,10;θ j represents the angle between the projection of the line between the position of the replacement speaker Spj and the origin O on the XOY plane and the X axis, j=1, 2, ..., 10;

表示替换扬声器Spj所在位置与原点O之间连线与XOY平面之间的夹角,j=1,2,…,10; Indicates the angle between the line between the position of the replacement speaker Spj and the origin O and the XOY plane, j=1, 2, ..., 10;

whj分别表示替换扬声器Spj的信号分配系数,j=1,2,…,10,h=1,2,…,22。w hj respectively represent the signal distribution coefficients of the replacement speakers Spj, j=1, 2, . . . , 10, h=1, 2, . . . , 22.

由(4)与(5)式相等得到:From (4) and (5) are equal to get:

(6)式中第一行,第二行分别除以第三行得到:In the formula (6), the first line and the second line are respectively divided by the third line to get:

(7)式保证待替换扬声器Spvh在听音点处产生的的质子速度方向与10个替换扬声器Sp1、Sp2、…、Sp10在听音点处产生的质子速度方向相等。由方程(7)可以得到:Equation (7) ensures that the direction of the proton velocity generated by the speaker Spvh to be replaced at the listening point is equal to the direction of the proton velocity generated by the 10 replacement speakers Sp1, Sp2, . . . , Sp10 at the listening point. From equation (7), we can get:

联合(8)式和(3)式得到:Combine (8) and (3) to get:

其中:in:

听音点处质子速度大小的误差E(wh1,wh2,…,wh10)为:The error E(w h1 ,w h2 ,…,w h10 ) of the proton velocity at the listening point is:

对于一个给定信号s(ω),10个替换扬声器Sp1、Sp2、…、Sp10位置信息和单个待替换扬声器Spvh(h=1,2,…,22)位置信息,为一个常数。因此要使得质子速度大小的误差最小,即使得式E2取值最小即可。For a given signal s(ω), the position information of 10 replacement speakers Sp1, Sp2, ..., Sp10 and the position information of a single speaker Spvh (h=1, 2, ..., 22) to be replaced, as a constant. Therefore, to minimize the error of the proton velocity, that is, to minimize the value of the formula E2 .

则使用10个替换扬声器Sp1、Sp2、…、Sp10替换单个待替换扬声器Spvh(h=1,2,…,22)等价于求解:Then using 10 replacement speakers Sp1, Sp2, ..., Sp10 to replace a single speaker Spvh (h=1, 2, ..., 22) to be replaced is equivalent to solving:

其中,in,

Wh=(wh1 wh2 … whn)T,T表示矩阵转置;W h =(w h1 w h2 … w hn ) T , T means matrix transposition;

E1=(0 0 1)TE 1 =(0 0 1) T ;

θvh表示待替换扬声器Spvh所在位置与原点O之间连线在XOY平面的射影与X轴之间的夹角,h=1,2,…,m;θ vh represents the angle between the projection of the line between the position of the speaker Spvh to be replaced and the origin O on the XOY plane and the X axis, h=1, 2, ..., m;

表示待替换扬声器Spvh所在位置与原点O之间连线与XOY平面之间的夹角,h=1, Represent the angle between the line between the position of the speaker Spvh to be replaced and the origin O and the XOY plane, h=1,

2,…,m;2,...,m;

θj表示替换扬声器Spj所在位置与原点O之间连线在XOY平面的射影与X轴之间的夹角,j=1,2,…,n;θ j represents the angle between the projection of the line between the position of the replacement speaker Spj and the origin O on the XOY plane and the X axis, j=1, 2, ..., n;

表示替换扬声器Spj所在位置与原点O之间连线与XOY平面之间的夹角,j=1,2,…,n。 Indicates the angle between the line connecting the position of the replacement speaker Spj and the origin O and the XOY plane, j=1, 2, . . . , n.

方程(12)可以用已有成熟算法求解,本实施例采用信任域算法求解。其他n、m取值同样可以采用此方程。Equation (12) can be solved by an existing mature algorithm, and this embodiment uses a trust domain algorithm to solve it. This equation can also be used for other values of n and m.

本实施例中按照公式(12)可以求得使用10个替换扬声器Sp1、Sp2、…、Sp10分别替换单个待替换扬声器Spvh(h=1,2,…,22)得到10个替换扬声器Sp1、Sp2、…、Sp10的一系列初始分配系数,如表1所示。In this embodiment, according to formula (12), it can be obtained that 10 replacement speakers Sp1, Sp2, ..., Sp10 are used to replace a single speaker Spvh (h=1, 2, ..., 22) to be replaced respectively to obtain 10 replacement speakers Sp1, Sp2 , ..., a series of initial partition coefficients of Sp10, as shown in Table 1.

表1信号初始分配系数Table 1 Signal Initial Distribution Coefficient

步骤103,将单个待替换扬声器Spvh(h=1,2,…,22)的信号分别乘以步骤102所得初始分配系数wh1,wh2,…,wh10后分配到相应扬声器Sp1、Sp2、…、Sp10中,删除待替换扬声器Spvh(h=1,2,…,22);Step 103, the signal of a single speaker Spvh (h=1, 2, ..., 22) to be replaced is multiplied by the initial distribution coefficients w h1 , w h2 , ..., w h10 obtained in step 102, and then distributed to the corresponding speakers Sp1, Sp2, ..., Sp10, delete the speaker to be replaced Spvh (h=1, 2, ..., 22);

本实施例中,将待替换扬声器Spv1的信号分别乘以表1中的初始分配系数1,0,0,0,0,0,0,0,0,0即可得到扬声器Sp1、Sp2、…、Sp10的初始分配信号,删除待替换扬声器Spv1。其余待替换扬声器的信号依次进行类似操作。In this embodiment, the signal of the speaker Spv1 to be replaced is multiplied by the initial distribution coefficient 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 in Table 1 to obtain the speakers Sp1, Sp2, ... , the initial distribution signal of Sp10, and delete the speaker Spv1 to be replaced. Similar operations are performed on the signals of the remaining speakers to be replaced in turn.

步骤2,计算得到扬声器Sp1、Sp2、…、Spn分别的信号,包括将步骤1中所得扬声器Spj分配得到的一系列相应信号求和,扬声器Spj的最终分配信号计算公式为其中,j=1,2,…,n。Step 2, calculate the respective signals of the speakers Sp1, Sp2, ..., Spn, including summing a series of corresponding signals obtained from the distribution of the speakers Spj obtained in step 1, the final distribution signal calculation formula of the speakers Spj is Wherein, j=1, 2, . . . , n.

实施例分别计算得到替换扬声器Sp1、Sp2、…、Sp10的信号,替换扬声器Spj(j=1,2,…,10)的最终分配信号计算公式如下:The embodiment calculates and obtains the signal of replacing loudspeaker Sp1, Sp2, ..., Sp10 respectively, and the final distribution signal calculation formula of replacing loudspeaker Spj (j=1, 2, ..., 10) is as follows:

本实施例中,替换扬声器Sp1在待替换扬声器Spv1、Spv2、…、Spv22的22次替换过程中得到的初始分配系数分别为:1,0,0,0,0,0,0.1464,0.5,0.1464,0,0,0,0,0,0,0,0,0,0,0,0,0,如表1第二列所示,按照公式(13)得到替换扬声器Sp1的最终分配信号为Sf1=1.7928S。进行类似计算可以得到其余替换扬声器的最终信号。In this embodiment, the initial allocation coefficients of the replacement speaker Sp1 obtained during the 22 replacements of the speakers Spv1, Spv2, ..., Spv22 to be replaced are respectively: 1, 0, 0, 0, 0, 0, 0.1464, 0.5, 0.1464 , 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, as shown in the second column of Table 1, according to formula (13), the final distribution signal of the replacement speaker Sp1 is Sf1 = 1.7928S. Similar calculations can be performed to obtain the final signal for the remaining replacement speakers.

本文中所描述的具体实施例仅仅是对本发明精神作举例说明。本发明所属技术领域的技术人员可以对所描述的具体实施例做各种各样的修改或补充或采用类似的方式替代,但并不会偏离本发明的精神或者超越所附权利要求书所定义的范围。The specific embodiments described herein are merely illustrative of the spirit of the invention. Those skilled in the art to which the present invention belongs can make various modifications or supplements to the described specific embodiments or adopt similar methods to replace them, but they will not deviate from the spirit of the present invention or go beyond the definition of the appended claims range.

Claims (2)

1. A multi-channel system reduction method, characterized by: comprises the following steps of (a) carrying out,
step 1, setting a replacement loudspeaker group and a to-be-replaced loudspeaker group to be located on the same spherical surface, wherein the to-be-replaced loudspeaker group comprises m loudspeakers Spv1, Spv2, … and Spvm, original signals of the loudspeakers Spv1, Spv2, … and Spvm are S, the replacement loudspeaker group comprises n loudspeakers Sp1, Sp2, … and Spn, n is less than m, and the spherical center position of the spherical surface is a listening point; obtaining the signals assigned by the n loudspeakers Sp1, Sp2, …, Spn to replace the single loudspeaker to be replaced Spvh, h being 1, 2, …, m, comprising the sub-steps of,
step 101, obtaining the position information of m loudspeakers Spv1, Spv2, … and Spvm respectively, and the position information of n loudspeakers Sp1, Sp2, … and Spn respectively;
102, calculating and determining initial distribution coefficients w of the n loudspeakers Sp1, Sp2, … and Spnh1,wh2,…,whnThe method comprises the following steps of constructing an equation,
s.t.LWh=E1
wh1,wh2,…whn≥0
wherein,
Wh=(wh1wh2… whn)Tt denotes the matrix transposition, whjA signal distribution coefficient representing the replacement speaker Spj for the speaker Spvh to be replaced, j being 1, 2, …, n;
E1=(0 0 1)T
θvhan included angle between the projection of the XOY plane and the X axis, which is a connecting line between the position of the speaker Spvh to be replaced and the origin O, is represented, and h is 1, 2, …, m;
representing the angle between the line between the position of the loudspeaker Spvh to be replaced and the origin O and the XOY plane,h=1,2,…,m;
θjan angle between the projection of the line between the position of the speaker Spj and the origin O on the XOY plane and the X axis is represented, j is 1, 2, …, n;
an included angle between a connecting line between the position of the speaker Spj and the origin O and the XOY plane is represented, and j is 1, 2, …, n; step 103, multiplying the signals of the individual speakers Spvh to be replaced by the initial distribution coefficients w obtained in step 102 respectivelyh1,wh2,…,whnThen, the signals are distributed to corresponding loudspeakers Sp1, Sp2, … and Spn, and the loudspeaker Spvh, h being 1, 2, … and m to be replaced is deleted;
step 2, calculating to obtain signals of the speakers Sp1, Sp2, … and Spn respectively, including summing a series of corresponding signals obtained by distributing the speakers Spj obtained in step 1, wherein a final distribution signal calculation formula of the speakers Spj is as follows:
wherein j is 1, 2, …, n.
2. The multi-channel system reduction method of claim 1, wherein: n is 10 and m is 22.
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