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CN104134976B - Fault identification method in power transmission line distance protection - Google Patents

Fault identification method in power transmission line distance protection Download PDF

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CN104134976B
CN104134976B CN201410398743.9A CN201410398743A CN104134976B CN 104134976 B CN104134976 B CN 104134976B CN 201410398743 A CN201410398743 A CN 201410398743A CN 104134976 B CN104134976 B CN 104134976B
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phase
voltage
positive sequence
protection
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CN104134976A (en
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柳焕章
周泽昕
王德林
王兴国
杜丁香
李锋
谢俊
陈祥文
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State Grid Corp of China SGCC
China Electric Power Research Institute Co Ltd CEPRI
Central China Grid Co Ltd
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State Grid Corp of China SGCC
China Electric Power Research Institute Co Ltd CEPRI
Central China Grid Co Ltd
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Abstract

The invention provides a fault identification method in power transmission line distance protection, which comprises the following steps: acquiring three-phase voltage and three-phase current at a protection installation position; is determined byPositive sequence voltage, positive sequence current, negative sequence current and zero sequence current with phases as references; determining a current asymmetry at the protective installation; determining an included angle between the positive sequence voltage and the positive sequence current; and identifying the fault according to the plane of the current asymmetry. The comprehensive utilization of current asymmetry andthe characteristics realize fault identification in distance protection and improve the action performance of the existing power transmission line distance protection in the process of fault and overload in oscillation.

Description

一种输电线路距离保护中故障识别方法A Fault Identification Method in Transmission Line Distance Protection

技术领域technical field

本发明涉及一种距离保护领域的方法,具体讲涉及一种输电线路距离保护中故障识别方法。The invention relates to a method in the field of distance protection, in particular to a fault identification method in the distance protection of transmission lines.

背景技术Background technique

距离保护分为三段,其中距离I、II段,故障开放150ms之后,进入振荡闭锁,在闭锁期间,需要进行故障再开放,影响距离保护动作速度,对于距离保护III段,当输电线路输送容量的增加及线路故障后负荷的转移会造成线路过负荷,负荷阻抗进入距离保护动作区,会造成距离保护误动作,进而造成负荷进一步转移,引发连锁故障,导致事故范围扩大,严重时会造成大面积停电。The distance protection is divided into three sections. Among them, distance I and II section, after 150ms after the fault is opened, enter the oscillation lock. The increase of the load and the transfer of the load after the line fault will cause the line overload. Area without power.

现有技术中,采取振荡闭锁故障再开放条件是单独利用m(开放不对称故障)和(开放对称故障),对于不对称故障,单相接地故障过渡电阻较大时,不能开放,对于对称故障,开放时间较长,针对过负荷下距离保护可能误动作的问题,目前采取的措施主要是在阻抗平面上整定负荷限制线来躲过负荷,而这种方法会牺牲距离保护的灵敏度,随着负荷不断增大,距离保护的动作区会大幅减小,对于单相接地故障,由于过渡电阻变化范围较大,当过渡电阻较大时,由于负荷限制线的影响,距离保护拒动作,距离保护的耐受过渡电阻能力被大幅削弱。In the prior art, the re-opening condition of oscillation blocking fault is to use m (open asymmetric fault) and (open symmetrical faults), for asymmetrical faults, when the transition resistance of a single-phase ground fault is large, it cannot be opened. It is to set the load limit line on the impedance plane to avoid the load, and this method will sacrifice the sensitivity of the distance protection. As the load continues to increase, the action area of the distance protection will be greatly reduced. The range of resistance change is large. When the transition resistance is large, due to the influence of the load limit line, the distance protection will refuse to operate, and the ability of the distance protection to withstand transition resistance will be greatly weakened.

因此,需要提供一种能快速开放距离保护输电线路距离保护中故障识别方法,提高距离保护耐过渡电阻能力,克服传统方法仅利用单一特征的不足。Therefore, it is necessary to provide a fault identification method in distance protection of transmission lines that can quickly open distance protection, improve the ability of distance protection to withstand transition resistance, and overcome the shortcomings of traditional methods that only use a single feature.

发明内容Contents of the invention

为克服上述现有技术的不足,本发明提供一种输电线路距离保护中故障识别方法,该方法利用在电流不对称度m-正序电压余弦分量平面上,同时利用m和两种特征识别线路故障,在振荡闭锁期间发生线路故障时能够快速开放距离保护,提高了不对称故障开放的灵敏度和对称故障开放的快速性。In order to overcome the deficiencies of the above-mentioned prior art, the present invention provides a fault identification method in distance protection of transmission lines, which uses the current asymmetry m-positive sequence voltage cosine component plane, using both m and The two kinds of features identify line faults, and can quickly open the distance protection when a line fault occurs during the oscillation blocking period, which improves the sensitivity of asymmetric fault opening and the rapidity of symmetrical fault opening.

实现上述目的所采用的解决方案为:The solution adopted to achieve the above purpose is:

一种输电线路距离保护中故障识别方法,其改进之处在于:所述方法包括以下步骤:A method for identifying faults in distance protection of transmission lines, the improvement of which is that the method includes the following steps:

I、获取保护安装处的三相电压和三相电流;I. Obtain the three-phase voltage and three-phase current at the place where the protection is installed;

II、确定以相为基准的正序电压、正序电流、负序电流和零序电流;II. Determine to Phase-based positive sequence voltage, positive sequence current, negative sequence current and zero sequence current;

III、确定所述保护安装处的电流不对称度;III. Determine the current asymmetry at the protective installation;

IV、确定所述正序电压和所述正序电流之间的夹角;IV, determining the angle between the positive sequence voltage and the positive sequence current;

V、根据电流不对称度平面进行故障识别。V. Carry out fault identification according to the plane of current asymmetry.

进一步的,所述步骤II中,根据所述三相电压和三相电流按下式分别确定以相为基准的正序电流负序电流零序电流和正序电压 Further, in the step II, according to the three-phase voltage and the three-phase current respectively determined by the following formula Phase-based positive sequence current negative sequence current Zero sequence current and positive sequence voltage

式中,相电流;分别为其它两相的电流;相电压;相的滞后相电压,相的超前相电压。,为φ相的滞后相电压,为φ相的超前相电压。In the formula, for phase current; are the currents of the other two phases respectively; for phase voltage; for phase lagging phase voltage, for The leading phase voltage of the phase. , is the lagging phase voltage of φ phase, is the leading phase voltage of φ phase.

进一步的,所述步骤III中,按下式确定所述电流不对称度m:Further, in the step III, the current asymmetry m is determined according to the following formula:

式中,分别为以相为基准的正序电流、负序电流、零序电流。In the formula, respectively Phase-based positive sequence current, negative sequence current, zero sequence current.

进一步的,所述步骤IV中,按下式确定所述正序电压和所述正序电流之间的夹角:Further, in the step IV, the angle between the positive sequence voltage and the positive sequence current is determined as follows:

式中,为以φ相为基准的正序电压,为以φ相为基准的正序电流;φ1为正序电压和正序电流之间的夹角,为以正序电压幅值,,为标幺值,基准为保护安装处φ相电压。In the formula, is the positive sequence voltage based on φ phase, is the positive sequence current based on φ phase; φ 1 is the positive sequence voltage and positive sequence current the angle between, is the positive sequence voltage amplitude, It is the value per unit, and the benchmark is the φ-phase voltage at the place where the protection is installed.

进一步的,所述步骤V中,根据所述保护安装处的电流不对称度和电流不对称度平面进行故障识别。Further, in the step V, fault identification is performed according to the current asymmetry degree and the current asymmetry degree plane at the protection installation site.

进一步的,所述步骤V包括以下步骤:Further, said step V includes the following steps:

S501、判断是否成立,成立则判断为不对称故障,开放距离保护,否则进入步骤S502;S501. Judgment If it is established, if it is established, it will be judged as an asymmetric fault, and the distance protection will be enabled, otherwise, go to step S502;

S502、判断是否成立,成立则追记前一周波的电流不对称平面否则,闭锁距离保护;S502. Judgment If it is established, if it is established, the current asymmetry plane of the previous cycle will be added Otherwise, block the distance protection;

S503、比对所述前一周波的电流不对称平面和0.3pu,若则判断为对称故障,开放距离保护;S503. Comparing the current asymmetry plane of the previous cycle and 0.3pu, if If it is judged as a symmetrical fault, open distance protection;

则延时开放距离保护I、II段,开放距离保护III段,pu为单位:标幺值。like Then delay open distance protection section I and II, and open distance protection section III, the unit of pu is per unit value.

与现有技术相比,本发明具有以下有益效果:Compared with the prior art, the present invention has the following beneficial effects:

1、本发明方法综合利用电流不对称度和U1cosφ特征,提高现有输电线路距离保护在振荡中故障及过负荷时的动作性能;1. The method of the present invention comprehensively utilizes the current asymmetry and U1cosφ characteristics to improve the action performance of the existing transmission line distance protection in the event of a fault or overload during oscillation;

2、本发明方法可以准确识别不对称故障和对称故障,同时提高接地距离保护的耐过渡电阻能力;2. The method of the present invention can accurately identify asymmetrical faults and symmetrical faults, and at the same time improve the resistance to transition resistance of grounding distance protection;

3、本发明的方法中无需进行人工整定,避免了误整定;3. In the method of the present invention, there is no need for manual adjustment, which avoids false adjustment;

4、本发明的方法对电网的安全稳定运行及限制事故范围扩大具有极为重要的意义;4. The method of the present invention is of great significance to the safe and stable operation of the power grid and the expansion of the scope of limiting accidents;

5、本发明提供的一种基于二维平面,综合利用电流不对称度和两种特征识别对称故障与不对称故障,快速开放距离保护的方法,克服了传统方法仅利用单一特征的不足,同时提高距离保护耐过渡电阻能力,对于电网的安全稳定运行及限制事故范围扩大具有极为重要的意义;5, a kind of based on that the present invention provides Two-dimensional plane, comprehensive use of current asymmetry and Two kinds of characteristics identify symmetrical faults and asymmetrical faults, and the method of quickly opening distance protection overcomes the shortcomings of traditional methods that only use a single characteristic, and at the same time improves the ability of distance protection to withstand transition resistance, which is of great significance to the safe and stable operation of the power grid and the expansion of the scope of limited accidents. of great importance;

6、本发明针对输电线路距离保护在振荡闭锁期间故障再开放而设计,利用平面表征线路故障,相比传统开放条件,对于不对称故障,利用m与相结合可以提高经较大过渡电阻接地故障,利用变化量可以提高对称故障的开放速度。6. The present invention is designed for the re-opening of the transmission line distance protection during the oscillation blocking period, and utilizes The plane characterizes line faults. Compared with traditional open conditions, for asymmetric faults, using m and combined can improve ground faults via larger transition resistances, utilizing Variations can increase the opening speed of symmetric faults.

附图说明Description of drawings

图1为本发明的方法流程图;Fig. 1 is method flowchart of the present invention;

图2为本发明中电流不对称度m与关系图。Fig. 2 is current asymmetry m and relation chart.

具体实施方式detailed description

下面结合附图对本发明的具体实施方式做进一步的详细说明。The specific embodiments of the present invention will be further described in detail below in conjunction with the accompanying drawings.

如图1所示,图1为本发明的方法流程图,本发明提供的一种输电线路距离保护中故障识别方法包括以下步骤:As shown in Figure 1, Figure 1 is a flow chart of the method of the present invention, a fault identification method in the distance protection of a transmission line provided by the present invention includes the following steps:

步骤一、获取保护安装处的三相电压和三相电流;Step 1. Obtain the three-phase voltage and three-phase current at the place where the protection is installed;

步骤二、确定以相为基准的正序电压、正序电流、负序电流和零序电流;Step 2. Determine to Phase-based positive sequence voltage, positive sequence current, negative sequence current and zero sequence current;

步骤三、确定所述保护安装处的电流不对称度;Step 3, determining the current asymmetry at the protection installation site;

步骤四、确定所述正序电压和所述正序电流之间的夹角 Step 4. Determine the angle between the positive sequence voltage and the positive sequence current

步骤五、根据电流不对称度平面进行故障识别。Step 5: Carry out fault identification according to the current asymmetry plane.

步骤一中,运用电压传感器和电流传感器分别获取保护安装处的三相电压和三相电流。In step 1, the voltage sensor and the current sensor are used to obtain the three-phase voltage and three-phase current at the protection installation site respectively.

步骤二中,根据所述三相电压和三相电流按下式分别确定以相为基准的正序电流负序电流零序电流和正序电压 In step 2, according to the three-phase voltage and three-phase current, the following formulas are used to determine Phase-based positive sequence current negative sequence current Zero sequence current and positive sequence voltage

以A相为基准的正序电流、负序电流、零序电流和正序电压分别如下式:The positive sequence current, negative sequence current, zero sequence current and positive sequence voltage based on phase A are as follows:

以B相为基准的正序电流、负序电流、零序电流和正序电压分别如下式:The positive sequence current, negative sequence current, zero sequence current and positive sequence voltage based on phase B are as follows:

以C相为基准的正序电流、负序电流、零序电流和正序电压分别如下式:The positive sequence current, negative sequence current, zero sequence current and positive sequence voltage based on phase C are as follows:

步骤三中,按下式确定所述电流不对称度:In step 3, the current asymmetry degree is determined according to the formula:

式中,分别为以任一相为基准的正序电流、负序电流、零序电流。In the formula, They are the positive-sequence current, negative-sequence current and zero-sequence current based on any phase, respectively.

步骤四中,按下式确定所述正序电压和所述正序电流之间的夹角:In step 4, the angle between the positive sequence voltage and the positive sequence current is determined according to the following formula:

式中,为以相为基准的正序电压,为以相为基准的正序电流;为正序电压和正序电流之间的夹角,为以相为基准的正序电压,为以相为基准的正序电流,的取值为A、B、C三相,为标幺值,基准为保护安装处相电压。In the formula, for phase-based positive sequence voltage, for Phase-based positive sequence current; is the positive sequence voltage and positive sequence current the angle between, for phase-based positive sequence voltage, for phase-based positive sequence current, The value of is A, B, C three-phase, is the per unit value, and the benchmark is the protection installation place phase voltage.

步骤五中,根据所述保护安装处的电流不对称度和电流不对称度平面进行故障识别。具体包括以下步骤:In step five, fault identification is performed according to the current asymmetry degree and the current asymmetry degree plane at the protection installation site. Specifically include the following steps:

S501、判断是否成立,成立则判断为不对称故障,开放距离保护,否则进入步骤S502;S501. Judgment If it is established, if it is established, it will be judged as an asymmetric fault, and the distance protection will be enabled, otherwise, go to step S502;

S502、判断是否成立,成立则追记前一周波的电流不对称平面否则,闭锁距离保护;S502. Judgment If it is established, if it is established, the current asymmetry plane of the previous cycle will be added Otherwise, block the distance protection;

S503、比对所述前一周波的电流不对称平面和0.3pu,若则判断为对称故障,开放距离保护;S503. Comparing the current asymmetry plane of the previous cycle and 0.3pu, if If it is judged as a symmetrical fault, open distance protection;

则延时开放距离保护I、II段,直接开放距离保护III段,pu为单位:标幺值。like Then open the distance protection sections I and II with a delay, and open the distance protection section III directly, and the unit of pu is per unit value.

如图2所示,图2为本发明中电流不对称度m与关系图;横轴为电流不对称度m,纵轴为正序电压余弦分量其中电流不对称度m表征不对称故障,表征对称故障,同时利用m和可以表征经高阻接地故障,其中弧线的数学表达式曲线右侧为表征发生不对称故障,左侧表征对称情况(正常运行或对称故障)。As shown in Figure 2, Figure 2 is the current asymmetry m and Relationship diagram; the horizontal axis is the current asymmetry degree m, and the vertical axis is the cosine component of the positive sequence voltage Among them, the current asymmetry degree m represents the asymmetric fault, Characterize symmetric faults using both m and Can characterize the high-resistance ground fault, where the mathematical expression of the arc The right side of the curve is An asymmetric fault is represented on the left, a symmetrical case (normal operation or a symmetrical fault) is represented on the left.

最后应当说明的是:以上实施例仅用于说明本申请的技术方案而非对其保护范围的限制,尽管参照上述实施例对本申请进行了详细的说明,所属领域的普通技术人员应当理解:本领域技术人员阅读本申请后依然可对申请的具体实施方式进行种种变为更、修改或者等同替换,但这些变更、修改或者等同替换,均在申请待批的权利要求保护范围之内。Finally, it should be noted that the above embodiments are only used to illustrate the technical solutions of the present application rather than limit the scope of protection thereof. Although the present application has been described in detail with reference to the above embodiments, those of ordinary skill in the art should understand that: After reading this application, those skilled in the art can still make various changes, modifications or equivalent replacements to the specific implementation of the application, but these changes, modifications or equivalent replacements are all within the protection scope of the pending claims of the application.

Claims (3)

1. in a kind of transmission line distance protecting fault recognition method it is characterised in that:The method comprising the steps of:
I, the three-phase voltage obtaining protection installation place and three-phase current;
II, determine withPositive sequence voltage on the basis of phaseForward-order current, negative-sequence current and zero-sequence current;
III, determine the current asymmetry degree m of described protection installation place:In formula,Point Be not withForward-order current on the basis of phase, negative-sequence current, zero-sequence current,
IV, determine angle between described positive sequence voltage and described forward-order current;
V, the current asymmetry degree according to described protection installation place and current asymmetry degree plane carry out Fault Identification, specifically include Following steps:
S501, judgementWhether set up, set up and be then judged as unbalanced fault, open away from From protection, otherwise enter step S502; For positive sequence voltage and forward-order current angle;
S502, judgementWhether set up, set up and then write afterwards previous cycleOtherwise, locking away from From protection;
S503, comparison electric current unsymmetrical planAnd 0.3pu, if Then it is judged as symmetric fault, open distance is protected;
IfThen time delay open distance protection I, II section, open distance protects III section;For perunit value, benchmark is protection installation placePhase voltage, pu is unit:Perunit value.
2. the method for claim 1 it is characterised in that:In described step II, according to described three-phase voltage and three-phase electricity Stream determine respectively as the following formula withForward-order current on the basis of phaseNegative-sequence currentZero-sequence currentAnd positive sequence voltage
In formula,ForPhase current;It is respectively other biphase electric currents;ForPhase voltage;ForThe delayed phase of phase Voltage,ForThe advanced phase voltage of phase.
3. the method for claim 1 it is characterised in that:In described step IV, determine as the following formula described positive sequence voltage and Angle between described forward-order current
In formula,Be withPositive sequence voltage on the basis of phase,Be withForward-order current on the basis of phase;For positive sequence voltageAnd forward-order currentBetween angle.
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