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CN103944376B - Isolated equalizing circuit based on bus type equalising network - Google Patents

Isolated equalizing circuit based on bus type equalising network Download PDF

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CN103944376B
CN103944376B CN201410196673.9A CN201410196673A CN103944376B CN 103944376 B CN103944376 B CN 103944376B CN 201410196673 A CN201410196673 A CN 201410196673A CN 103944376 B CN103944376 B CN 103944376B
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CN103944376A (en
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凌睿
但强
张婕
舒志辉
朱哲人
刘楠
王传鑫
罗杨
王理智
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Chongqing University
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Abstract

本发明公开了一种基于总线式均衡网络的隔离式均衡电路,第一电感一端连接输入电源正极,所述第一电感另一端连接第一功率开关漏极,所述第二电感连接一端连接输入电源负极,所述第二电感另一端连接第一功率开关源极,所述第三电感连接一端连接第二功率开关源极,所述第三电感另一端连接第二电容一端,所述第四电感连接一端连接第二功率开关漏极,所述第四电感另一端连接第二电容另一端,所述第一a电容一端连接第一功率开关漏极,所述第一a电容另一端连接第二功率开关源极,所述第一b电容一端连接第一功率开关源极,所述第一b电容另一端连接第二功率开关漏极。

The invention discloses an isolated equalization circuit based on a bus-type equalization network. One end of a first inductance is connected to the positive pole of an input power supply, the other end of the first inductance is connected to the drain of a first power switch, and one end of the second inductance is connected to an input The negative pole of the power supply, the other end of the second inductance is connected to the source of the first power switch, one end of the third inductance is connected to the source of the second power switch, the other end of the third inductance is connected to one end of the second capacitor, and the fourth One end of the inductance is connected to the drain of the second power switch, the other end of the fourth inductance is connected to the other end of the second capacitor, one end of the first a capacitor is connected to the drain of the first power switch, and the other end of the first a capacitor is connected to the second Two power switch sources, one end of the first b capacitor is connected to the first power switch source, and the other end of the first b capacitor is connected to the second power switch drain.

Description

基于总线式均衡网络的隔离式均衡电路Isolated Equalization Circuit Based on Bus Equalization Network

技术领域technical field

本发明涉及自动化控制领域,尤其涉及一种基于总线式均衡网络的隔离式均衡电路。The invention relates to the field of automatic control, in particular to an isolated equalization circuit based on a bus equalization network.

背景技术Background technique

均衡电路主要分为耗散型和非耗散型,耗散型将多余的能量全部消耗在电阻上,效率低,非耗散型将多余能量通过电路转移,效率较高。Buck-boost是一种典型级联式均衡电路,其网路结构如图8是基于buck-boost的级联式均衡网路级联式均衡网路的结构相对简单,但它具有一个很明显的劣势:能量只能逐级转移。例如,控制器作为B1将能量转移到B3的策略,必须将策略分解为:首先B1将能量传递到B2,然后B2将能量转移到B3;能量的逐级转移使得整个均衡网络的均衡速度降低,由于每级传递均衡能量的损耗,造成均衡效率较低。The equalization circuit is mainly divided into dissipative and non-dissipative. The dissipative type consumes all the excess energy on the resistor, which has low efficiency. The non-dissipative type transfers excess energy through the circuit and has high efficiency. Buck-boost is a typical cascaded equalization circuit, and its network structure is shown in Figure 8. The structure of the cascaded equalization network based on buck-boost is relatively simple, but it has an obvious Disadvantage: Energy can only be transferred level by level. For example, as a strategy for B1 to transfer energy to B3, the controller must decompose the strategy into: first B1 transfers energy to B2, then B2 transfers energy to B3; the gradual transfer of energy reduces the equilibrium speed of the entire equilibrium network, Due to the loss of equalization energy delivered by each stage, the equalization efficiency is low.

发明内容Contents of the invention

本发明旨在至少解决现有技术中存在的技术问题,特别创新地提出了一种基于总线式均衡网络的隔离式均衡电路。The present invention aims at at least solving the technical problems existing in the prior art, and particularly innovatively proposes an isolated equalization circuit based on a bus equalization network.

为了实现本发明的上述目的,本发明提供了一种基于总线式均衡网络的隔离式均衡电路,其关键在于,包括第一电感、第四电感、第一a电容、第一b电容、第二电容、第一功率开关、第二功率开关;In order to achieve the above object of the present invention, the present invention provides an isolated equalization circuit based on a bus-type equalization network, the key of which is to include a first inductance, a fourth inductance, a first a capacitor, a first b capacitor, a second a capacitor, a first power switch, and a second power switch;

所述第一电感一端连接电源正极,所述第一电感另一端连接第一功率开关漏极,所述第一功率开关源极连接电源负极,所述第一功率开关源极还连接第一b电容一端,所述第一b电容另一端连接第四电感一端,所述第四电感另一端连接第二电容一端,所述第二电容另一端连接第一a电容另一端,所述第二电容另一端还连接第二功率开关源极,所述第二功率开关漏极连接第一b电容另一端。One end of the first inductor is connected to the positive pole of the power supply, the other end of the first inductor is connected to the drain of the first power switch, the source of the first power switch is connected to the negative pole of the power supply, and the source of the first power switch is also connected to the first b One end of the capacitor, the other end of the first b capacitor is connected to one end of the fourth inductance, the other end of the fourth inductance is connected to one end of the second capacitor, the other end of the second capacitor is connected to the other end of the first a capacitor, and the second capacitor The other end is also connected to the source of the second power switch, and the drain of the second power switch is connected to the other end of the first b capacitor.

上述技术方案的有益效果为:该均衡方案不采用变压器,而使用电容进行电路隔离,其体积相对于变压器较小;该均衡电路完全对称,能量双向流动分析一致。The beneficial effects of the above technical solution are: the balancing solution does not use a transformer, but uses a capacitor for circuit isolation, and its volume is smaller than that of the transformer; the balancing circuit is completely symmetrical, and the energy bidirectional flow analysis is consistent.

所述的基于总线式均衡网络的隔离式均衡电路,优选的,还包括:第一二极管和第二二极管;所述第一二极管正极连接第一功率开关源极,所述第一二极管负极连接第一功率开关漏极,所述第二二极管正极连接第二功率开关源极,所述第二二极管负极连接第二二极管漏极。The isolated equalization circuit based on the bus type equalization network preferably further includes: a first diode and a second diode; the anode of the first diode is connected to the source of the first power switch, and the The cathode of the first diode is connected to the drain of the first power switch, the anode of the second diode is connected to the source of the second power switch, and the cathode of the second diode is connected to the drain of the second diode.

上述技术方案的有益效果为:所述第一二极管和第二二极管能够提高相应功率开关的开关速度。The beneficial effect of the above technical solution is: the first diode and the second diode can increase the switching speed of the corresponding power switch.

所述的基于总线式均衡网络的隔离式均衡电路,优选的,还包括:第二电感,The isolated equalization circuit based on the bus equalization network preferably further includes: a second inductor,

所述第二电感一端连接电源负极,所述第二电感另一端连接第一功率开关源极。One end of the second inductor is connected to the negative pole of the power supply, and the other end of the second inductor is connected to the source of the first power switch.

上述技术方案的有益效果为:该均衡电路用于总线式均衡网络中,各均衡电路可以实现独立工作,相互干扰很小。The beneficial effects of the above technical solution are: when the equalization circuit is used in a bus-type equalization network, each equalization circuit can work independently with little mutual interference.

所述的基于总线式均衡网络的隔离式均衡电路,优选的,还包括:第三电感,The isolated equalization circuit based on the bus equalization network preferably further includes: a third inductor,

所述第三电感一端连接第二功率开关源极,所述第三电感另一端连接第三电容另一端。One end of the third inductor is connected to the source of the second power switch, and the other end of the third inductor is connected to the other end of the third capacitor.

上述技术方案的有益效果为:该均衡电路用于总线式均衡网络中,各均衡电路可以实现独立工作,相互干扰很小。The beneficial effects of the above technical solution are: when the equalization circuit is used in a bus-type equalization network, each equalization circuit can work independently with little mutual interference.

综上所述,由于采用了上述技术方案,本发明的有益效果是:In summary, owing to adopting above-mentioned technical scheme, the beneficial effect of the present invention is:

1该均衡方案不采用变压器,而使用电容进行电路隔离,其体积相对于变压器较小;1 This equalization scheme does not use a transformer, but uses a capacitor for circuit isolation, and its volume is smaller than that of the transformer;

2该均衡电路完全对称,能量双向流动分析一致;2. The equalization circuit is completely symmetrical, and the two-way energy flow analysis is consistent;

3该均衡电路用于总线式均衡网络中,各均衡电路可以实现独立工作,相互干扰很小。3. The equalization circuit is used in a bus-type equalization network, and each equalization circuit can work independently with little mutual interference.

本发明的附加方面和优点将在下面的描述中部分给出,部分将从下面的描述中变得明显,或通过本发明的实践了解到。Additional aspects and advantages of the invention will be set forth in the description which follows, and in part will be obvious from the description, or may be learned by practice of the invention.

附图说明Description of drawings

本发明的上述和/或附加的方面和优点从结合下面附图对实施例的描述中将变得明显和容易理解,其中:The above and/or additional aspects and advantages of the present invention will become apparent and comprehensible from the description of the embodiments in conjunction with the following drawings, wherein:

图1是本发明基于总线式均衡网络的隔离式均衡电路连接示意图;Fig. 1 is the connection schematic diagram of the isolated equalization circuit based on the bus type equalization network of the present invention;

图2是本发明基于总线式均衡网络的隔离式均衡电路工作第一阶段;Fig. 2 is the first stage of work of the isolated equalization circuit based on the bus type equalization network of the present invention;

图3是本发明基于总线式均衡网络的隔离式均衡电路工作第二阶段;Fig. 3 is the second stage of work of the isolated equalization circuit based on the bus type equalization network of the present invention;

图4是本发明基于总线式均衡网络的隔离式均衡电路的等效电路;Fig. 4 is the equivalent circuit of the isolated type equalization circuit based on the bus type equalization network of the present invention;

图5是本发明基于总线式均衡网络的隔离式均衡电路的简化等效电路图;Fig. 5 is the simplified equivalent circuit diagram of the isolated equalization circuit based on the bus type equalization network of the present invention;

图6是本发明基于总线式均衡网络的隔离式均衡电路的两回路;Fig. 6 is the two loops of the isolated type equalization circuit based on the bus type equalization network of the present invention;

图7是本发明基于总线式均衡网络的隔离式均衡电路等效的cuk工作时其中A/B两点电流流向;Fig. 7 is the current flow direction of A/B two points when the equivalent cuk of the isolated equalization circuit based on the bus equalization network of the present invention works;

图8是本发明基于总线式均衡网络的隔离式均衡电路的充放电示意图;8 is a schematic diagram of charge and discharge of the isolated equalization circuit based on the bus equalization network of the present invention;

图9是本发明基于总线式均衡网络的隔离式均衡电路应用在总线式结构中的电路示意图;9 is a schematic circuit diagram of the application of the isolated equalization circuit based on the bus equalization network in the bus structure according to the present invention;

图10是本发明基于总线式均衡网络的隔离式均衡电路连接示意图;Fig. 10 is a schematic diagram of connection of an isolated equalization circuit based on a bus equalization network in the present invention;

图11是本发明基于总线式均衡网络的隔离式均衡电路连接示意图;Fig. 11 is a schematic diagram of connection of an isolated equalization circuit based on a bus equalization network in the present invention;

图12是本发明基于总线式均衡网络的隔离式均衡电路连接示意图;Fig. 12 is a schematic diagram of connection of an isolated equalization circuit based on a bus equalization network in the present invention;

图13是本发明基于总线式均衡网络的隔离式均衡电路连接示意图。FIG. 13 is a schematic diagram of connection of an isolated equalization circuit based on a bus equalization network according to the present invention.

具体实施方式detailed description

下面详细描述本发明的实施例,所述实施例的示例在附图中示出,其中自始至终相同或类似的标号表示相同或类似的元件或具有相同或类似功能的元件。下面通过参考附图描述的实施例是示例性的,仅用于解释本发明,而不能理解为对本发明的限制。Embodiments of the present invention are described in detail below, examples of which are shown in the drawings, wherein the same or similar reference numerals designate the same or similar elements or elements having the same or similar functions throughout. The embodiments described below by referring to the figures are exemplary only for explaining the present invention and should not be construed as limiting the present invention.

在本发明的描述中,需要理解的是,术语“纵向”、“横向”、“上”、“下”、“前”、“后”、“左”、“右”、“竖直”、“水平”、“顶”、“底”“内”、“外”等指示的方位或位置关系为基于附图所示的方位或位置关系,仅是为了便于描述本发明和简化描述,而不是指示或暗示所指的装置或元件必须具有特定的方位、以特定的方位构造和操作,因此不能理解为对本发明的限制。In describing the present invention, it should be understood that the terms "longitudinal", "transverse", "upper", "lower", "front", "rear", "left", "right", "vertical", The orientation or positional relationship indicated by "horizontal", "top", "bottom", "inner", "outer", etc. are based on the orientation or positional relationship shown in the drawings, and are only for the convenience of describing the present invention and simplifying the description, rather than Nothing indicating or implying that a referenced device or element must have a particular orientation, be constructed, and operate in a particular orientation should therefore not be construed as limiting the invention.

在本发明的描述中,除非另有规定和限定,需要说明的是,术语“安装”、“相连”、“连接”应做广义理解,例如,可以是机械连接或电连接,也可以是两个元件内部的连通,可以是直接相连,也可以通过中间媒介间接相连,对于本领域的普通技术人员而言,可以根据具体情况理解上述术语的具体含义。In the description of the present invention, unless otherwise specified and limited, it should be noted that the terms "installation", "connection" and "connection" should be understood in a broad sense, for example, it can be mechanical connection or electrical connection, or two The internal communication of each element may be directly connected or indirectly connected through an intermediary. Those skilled in the art can understand the specific meanings of the above terms according to specific situations.

如图1所示,本发明提供了一种基于总线式均衡网络的隔离式均衡电路,其关键在于,包括第一电感、第四电感、第一a电容、第一b电容、第二电容、第一功率开关、第二功率开关;As shown in Figure 1, the present invention provides an isolated equalization circuit based on a bus-type equalization network, the key of which is to include a first inductance, a fourth inductance, a first capacitor a, a first capacitor b, a second capacitor, a first power switch, a second power switch;

所述第一电感一端连接电源正极,所述第一电感另一端连接第一功率开关漏极,所述第一功率开关源极连接电源负极,所述第一功率开关源极还连接第一b电容一端,所述第一b电容另一端连接第四电感一端,所述第四电感另一端连接第二电容一端,所述第二电容另一端连接第一a电容另一端,所述第二电容另一端还连接第二功率开关源极,所述第二功率开关漏极连接第一b电容另一端。One end of the first inductor is connected to the positive pole of the power supply, the other end of the first inductor is connected to the drain of the first power switch, the source of the first power switch is connected to the negative pole of the power supply, and the source of the first power switch is also connected to the first b One end of the capacitor, the other end of the first b capacitor is connected to one end of the fourth inductance, the other end of the fourth inductance is connected to one end of the second capacitor, the other end of the second capacitor is connected to the other end of the first a capacitor, and the second capacitor The other end is also connected to the source of the second power switch, and the drain of the second power switch is connected to the other end of the first b capacitor.

上述技术方案的有益效果为:该均衡方案不采用变压器,而使用电容进行电路隔离,其体积相对于变压器较小;该均衡电路完全对称,能量双向流动分析一致。The beneficial effects of the above technical solution are: the balancing solution does not use a transformer, but uses a capacitor for circuit isolation, and its volume is smaller than that of the transformer; the balancing circuit is completely symmetrical, and the energy bidirectional flow analysis is consistent.

所述的基于总线式均衡网络的隔离式均衡电路,优选的,还包括:第一二极管和第二二极管;所述第一二极管正极连接第一功率开关源极,所述第一二极管负极连接第一功率开关漏极,所述第二二极管正极连接第二功率开关源极,所述第二二极管负极连接第二二极管漏极,所述二极管和功率开关的连接还可以进行变换;The isolated equalization circuit based on the bus type equalization network preferably further includes: a first diode and a second diode; the anode of the first diode is connected to the source of the first power switch, and the The cathode of the first diode is connected to the drain of the first power switch, the anode of the second diode is connected to the source of the second power switch, the cathode of the second diode is connected to the drain of the second diode, and the diode The connection with the power switch can also be transformed;

例如:所述第一二极管正极连接第一功率开关漏极,所述第一二极管负极连接第一功率开关源极,所述第二二极管正极连接第二功率开关漏极,所述第二二极管负极连接第二二极管源极。For example: the anode of the first diode is connected to the drain of the first power switch, the cathode of the first diode is connected to the source of the first power switch, and the anode of the second diode is connected to the drain of the second power switch, The cathode of the second diode is connected to the source of the second diode.

上述技术方案的有益效果为:所述第一二极管和第二二极管能够提高相应功率开关的开关速度。The beneficial effect of the above technical solution is: the first diode and the second diode can increase the switching speed of the corresponding power switch.

所述的基于总线式均衡网络的隔离式均衡电路,优选的,还包括:第二电感,The isolated equalization circuit based on the bus equalization network preferably further includes: a second inductor,

所述第二电感一端连接电源负极,所述第二电感另一端连接第一功率开关源极。One end of the second inductor is connected to the negative pole of the power supply, and the other end of the second inductor is connected to the source of the first power switch.

上述技术方案的有益效果为:该均衡电路用于总线式均衡网络中,各均衡电路可以实现独立工作,相互干扰很小。The beneficial effects of the above technical solution are: when the equalization circuit is used in a bus-type equalization network, each equalization circuit can work independently with little mutual interference.

所述的基于总线式均衡网络的隔离式均衡电路,优选的,还包括:第三电感,The isolated equalization circuit based on the bus equalization network preferably further includes: a third inductor,

所述第三电感一端连接第二功率开关源极,所述第三电感另一端连接第三电容另一端。One end of the third inductor is connected to the source of the second power switch, and the other end of the third inductor is connected to the other end of the third capacitor.

上述技术方案的有益效果为:该均衡电路用于总线式均衡网络中,各均衡电路可以实现独立工作,相互干扰很小。The beneficial effects of the above technical solution are: when the equalization circuit is used in a bus-type equalization network, each equalization circuit can work independently with little mutual interference.

本方案利用隔离式cuk电路进行电池均衡,需使其工作在连续模式,即隔离式cuk电路中所有电感在平衡状态时始终有电流流过。This solution uses the isolated cuk circuit for battery balancing, and it needs to work in continuous mode, that is, all the inductors in the isolated cuk circuit always have current flowing when they are in a balanced state.

该电路工作时分为两个阶段,图2为第一阶段;The circuit is divided into two stages when it works, and Figure 2 is the first stage;

该阶段分为两个回路,粗实线回路和虚线回路,Q1处于开通状态,此时Q1两端的电压为0,流过Q2的电流为0。This stage is divided into two loops, the thick solid line loop and the dotted line loop. Q1 is in the open state. At this time, the voltage across Q1 is 0, and the current flowing through Q2 is 0.

图3为cuk工作的第二阶段;Figure 3 is the second stage of cuk work;

此阶段,Q1截止,Q1两端的电压为:uQ1=VC1a+VC1b;流过Q2的电流为:iQ2=i1+i2,其中uQ1为第一功率开关Q1两端的电压值,VC1a为第一电容的电压值,VC1b为第二电容的电压值,i1为流过L1和L2的电流,i2为流过L3和L4的电流。At this stage, Q1 is cut off, and the voltage across Q1 is: u Q1 =V C1a +V C1b ; the current flowing through Q2 is: i Q2 =i 1 +i 2 , where u Q1 is the voltage across Q1 of the first power switch , V C1a is the voltage value of the first capacitor, V C1b is the voltage value of the second capacitor, i 1 is the current flowing through L1 and L2, and i 2 is the current flowing through L3 and L4.

设有周期性单位脉冲函数,With a periodic unit pulse function,

其中g1(t),g2(t)分别表示cuk工作的第一阶段和第二阶段的单位脉冲函数,t为时间变量,T为一个开关周期,t1为一个周期内开关Q1导通时间或关断时刻则Q1两端的电压以及流过Q2的电流可以表示为:Among them, g 1 (t), g 2 (t) respectively represent the unit pulse function of the first stage and the second stage of cuk work, t is a time variable, T is a switching cycle, t 1 is the switch Q1 conduction in a cycle Time or turn-off moment, the voltage across Q1 and the current flowing through Q2 can be expressed as:

UQ1=uQ1g2 U Q1 = u Q1 g 2

IQ2=iQ2g2 I Q2 = i Q2 g 2

将Q1和Q2分别用周期性电压源和电流源代替,其等效电路图如图4所示。Replace Q1 and Q2 with periodic voltage source and current source respectively, and its equivalent circuit diagram is shown in Figure 4.

根据cuk电路的工作模式,可以再次将等效电路图简化,由于在全过程中,电感L1和L2电流一致,可以合并成一个电感,电感L3和L4电流一致,可以合并成一个电感,流过电容C1a和C1b的电流也一致,同样可以合并成一个电容,得到更加简化模型,其各个阶段电路分析不会改变。According to the working mode of the cuk circuit, the equivalent circuit diagram can be simplified again. Since in the whole process, the currents of the inductors L1 and L2 are consistent, they can be combined into one inductor, and the currents of the inductors L3 and L4 are consistent, so they can be combined into one inductor and flow through the capacitor. The currents of C1a and C1b are also consistent, and can also be combined into one capacitor to obtain a more simplified model, and the circuit analysis of each stage will not change.

图5中,在简化的同时引入一个不确定性负载,以下过程负载电流大小与输出电压无关。In Figure 5, an uncertain load is introduced while simplifying, and the load current in the following process has nothing to do with the output voltage.

根据图6,可以得到两个回路的电压方程According to Figure 6, the voltage equations of the two loops can be obtained

其中L为电感值,Lp为L1与L2的等效电感,ig为流过Lp的电流,LO1为L3与L4的等效电感,io1为流过LO1的电流,dig、dio1分别表示ig,io1的微分,dt为时间的微分,Vg输入侧电压。Where L is the inductance value, L p is the equivalent inductance of L1 and L2, i g is the current flowing through L p , L O1 is the equivalent inductance of L3 and L4, i o1 is the current flowing through L O1 , di g , di o1 represent i g , the differential of i o1 respectively, dt is the differential of time, V g input side voltage.

其中,UQ1=VC1g2 (2)Among them, U Q1 = V C1 g 2 (2)

将(2)式带入(1)式Bring (2) into (1)

A:由基尔霍夫电流定律有dVc1表示Vc1微分、dt表示时间的微分,其中IQ1=(ig+io1)g2,则可得A: According to Kirchhoff's current law dV c1 represents the differential of V c1 , and dt represents the differential of time, where I Q1 = (i g +i o1 )g 2 , then we can get

B:由基尔霍夫电流定律有dVc2表示Vc2微分,Is代表负载电流,B: According to Kirchhoff's current law dV c2 means V c2 differential, I s means load current,

but

取ig,io1,VC1,VC2为状态变量,可得Taking i g , i o1 , V C1 , V C2 as state variables, we can get

x代表状态空间。 x represents the state space.

采用平均值法,由于g2只在第二阶段有效,其有效时间占总时间的比例为1-D,其中D为开关的占空比,则(6)式可变为:Using the average value method, since g2 is only effective in the second stage, the ratio of its effective time to the total time is 1-D, where D is the duty cycle of the switch, then the formula (6) can be changed into:

由于该电路可由控制器控制变量的占空比为D,将(7)式化为:Since the circuit can be controlled by the controller, the duty cycle of the variable is D, formula (7) can be transformed into:

在总线式均衡网络中,电池通过均衡电路与能量传输总线连接,可实现能量在总线和电池上双向传递,多余能量的转移只需经过两次均衡电路,提高了均衡效率和均衡速度。另外总线式均衡网络使得电池组的扩展便捷,对于应对电池组实际需求相当有效。In the bus-type equalization network, the battery is connected to the energy transmission bus through the equalization circuit, which can realize the two-way transmission of energy on the bus and the battery, and the transfer of excess energy only needs to go through the equalization circuit twice, which improves the equalization efficiency and equalization speed. In addition, the bus-type equalization network makes the expansion of the battery pack convenient, which is quite effective in meeting the actual needs of the battery pack.

图7是本发明基于总线式均衡网络的隔离式均衡电路等效的cuk工作时其中A/B两点电流流向;Fig. 7 is the current flow direction of A/B two points when the equivalent cuk of the isolated equalization circuit based on the bus equalization network of the present invention works;

图8是本发明基于总线式均衡网络的隔离式均衡电路的充放电示意图;8 is a schematic diagram of charge and discharge of the isolated equalization circuit based on the bus equalization network of the present invention;

图9是本发明基于总线式均衡网络的隔离式均衡电路应用在总线式结构中的电路示意图;9 is a schematic circuit diagram of the application of the isolated equalization circuit based on the bus equalization network in the bus structure according to the present invention;

图10是本发明具体实施方式基于总线式均衡网络的隔离式均衡电路连接示意图;10 is a schematic diagram of the connection of an isolated equalization circuit based on a bus-type equalization network according to a specific embodiment of the present invention;

图11是本发明具体实施方式基于总线式均衡网络的隔离式均衡电路连接示意图;11 is a schematic diagram of the connection of an isolated equalization circuit based on a bus equalization network according to a specific embodiment of the present invention;

图12是本发明具体实施方式基于总线式均衡网络的隔离式均衡电路连接示意图;12 is a schematic diagram of the connection of an isolated equalization circuit based on a bus-type equalization network according to a specific embodiment of the present invention;

图13是本发明具体实施方式基于总线式均衡网络的隔离式均衡电路连接示意图。FIG. 13 is a schematic diagram of connection of an isolated equalization circuit based on a bus equalization network according to a specific embodiment of the present invention.

本发明的有益效果是:The beneficial effects of the present invention are:

1该均衡方案不采用变压器,而使用电容进行电路隔离,其体积相对于变压器较小;1 This equalization scheme does not use a transformer, but uses a capacitor for circuit isolation, and its volume is smaller than that of the transformer;

2该均衡电路完全对称,能量双向流动分析一致;2. The equalization circuit is completely symmetrical, and the two-way energy flow analysis is consistent;

3该均衡电路用于总线式均衡网络中,各均衡电路可以实现独立工作,相互干扰很小。3. The equalization circuit is used in a bus-type equalization network, and each equalization circuit can work independently with little mutual interference.

在本说明书的描述中,参考术语“一个实施例”、“一些实施例”、“示例”、“具体示例”、或“一些示例”等的描述意指结合该实施例或示例描述的具体特征、结构、材料或者特点包含于本发明的至少一个实施例或示例中。在本说明书中,对上述术语的示意性表述不一定指的是相同的实施例或示例。而且,描述的具体特征、结构、材料或者特点可以在任何的一个或多个实施例或示例中以合适的方式结合。In the description of this specification, descriptions referring to the terms "one embodiment", "some embodiments", "example", "specific examples", or "some examples" mean that specific features described in connection with the embodiment or example , structure, material or characteristic is included in at least one embodiment or example of the present invention. In this specification, schematic representations of the above terms do not necessarily refer to the same embodiment or example. Furthermore, the specific features, structures, materials or characteristics described may be combined in any suitable manner in any one or more embodiments or examples.

尽管已经示出和描述了本发明的实施例,本领域的普通技术人员可以理解:在不脱离本发明的原理和宗旨的情况下可以对这些实施例进行多种变化、修改、替换和变型,本发明的范围由权利要求及其等同物限定。Although the embodiments of the present invention have been shown and described, those skilled in the art can understand that various changes, modifications, substitutions and modifications can be made to these embodiments without departing from the principle and spirit of the present invention. The scope of the invention is defined by the claims and their equivalents.

Claims (1)

1. a kind of isolated equalizing circuit based on bus type equalising network, it is characterised in that including the first inductance, the second electricity Sense, the 3rd inductance, the 4th inductance, the first a electric capacity, the first b electric capacity, the second electric capacity, the first power switch, the second power switch, First diode and the second diode;
First isolated equalizing circuit one end connects the first discharge and recharge power supply, the first isolated equalizing circuit other end connection energy Bus, second isolated equalizing circuit one end connects the second discharge and recharge power supply, the second isolated equalizing circuit other end connection energy Bus is measured, n-th isolated equalizing circuit one end connects the n-th discharge and recharge power supply, the n-th isolated equalizing circuit other end connection energy Bus, wherein in parallel between the first isolated equalizing circuit, the second isolated equalizing circuit, the n-th isolated equalizing circuit;
Described first inductance one end connects discharge and recharge positive source, and the first inductance other end connects the leakage of the first power switch Pole, the first power switch source electrode connects second inductance one end, and the second inductance other end connects discharge and recharge power cathode, The first power switch drain electrode is also connected with the first a electric capacity one end, and the first power switch source electrode is also connected with the first b electric capacity one End, the first b electric capacity other end connects the 4th inductance one end and the drain electrode of the second power switch, and the 4th inductance other end connects Second electric capacity one end is connect, the second electric capacity other end connects the 3rd inductance one end, and the 3rd inductance other end connects the first a The electric capacity other end and the second power switch source electrode;
First diode cathode connects the first power switch source electrode, and first diode cathode connects the first power switch Drain electrode, second diode cathode connects the second power switch source electrode, and second diode cathode connects the second diode Drain electrode;
The isolated equalizing circuit progress based on bus type equalising network is battery balanced, it need to be made to be operated in continuous mode, All inductance have electric current to flow through all the time in poised state;
The circuit is divided into two stages when working:First stage is divided into two loops, and the first power switch is in opening state, this When the first power switch two ends voltage be 0, flow through the second power switch electric current be 0;
Second stage, the first power switch ends, and the voltage at the first power switch two ends is:uQ1=VC1a+VC1b;Flow through the second work( Rate switching current is:iQ2=i1+i2, wherein uQ1For the magnitude of voltage at the first power switch two ends, VC1aFor the voltage of the first a electric capacity Value, VC1bFor the magnitude of voltage of the first b electric capacity, VC2For the magnitude of voltage of the second electric capacity, i1To flow through the electricity of the first inductance and the second inductance Stream, i2To flow through the electric current of the 3rd inductance and the 4th inductance;
Provided with periodicity unit impulse function,
Wherein g1(t), g2(t) first stage of circuit work and the unit impulse function of second stage are represented respectively, when t is Between variable, T is switch periods, t1For the first power switch ON time or turn-off time in a cycle, then the first work( The voltage of rate switch ends and flow through the electric current of the second power switch and be expressed as:
<mrow> <mtable> <mtr> <mtd> <mrow> <msub> <mi>U</mi> <mrow> <mi>Q</mi> <mn>1</mn> </mrow> </msub> <mo>=</mo> <msub> <mi>u</mi> <mrow> <mi>Q</mi> <mn>1</mn> </mrow> </msub> <msub> <mi>g</mi> <mn>2</mn> </msub> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <msub> <mi>I</mi> <mrow> <mi>Q</mi> <mn>2</mn> </mrow> </msub> <mo>=</mo> <msub> <mi>i</mi> <mrow> <mi>Q</mi> <mn>2</mn> </mrow> </msub> <msub> <mi>g</mi> <mn>2</mn> </msub> </mrow> </mtd> </mtr> </mtable> <mo>;</mo> </mrow>
According to the mode of operation of the circuit, again by the circuit reduction, because in overall process, the first inductance and the second inductance are electric Stream is consistent, is merged into an inductance, and the 3rd inductance and the 4th inductive current are consistent, are merged into an inductance, flow through the first a electric capacity It is also consistent with the electric current of the first b electric capacity, an electric capacity is merged into, a uncertain load is introduced while simplifying, is obtained The voltage equation in two loops
<mrow> <mfenced open = "{" close = ""> <mtable> <mtr> <mtd> <mrow> <msub> <mi>U</mi> <mrow> <mi>Q</mi> <mn>1</mn> </mrow> </msub> <mo>+</mo> <msub> <mi>L</mi> <mi>p</mi> </msub> <mfrac> <mrow> <msub> <mi>di</mi> <mi>g</mi> </msub> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> <mo>=</mo> <msub> <mi>V</mi> <mi>g</mi> </msub> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <msub> <mi>U</mi> <mrow> <mi>Q</mi> <mn>1</mn> </mrow> </msub> <mo>+</mo> <msub> <mi>L</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> <mfrac> <mrow> <msub> <mi>di</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> <mo>+</mo> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>2</mn> </mrow> </msub> <mo>=</mo> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>1</mn> </mrow> </msub> </mrow> </mtd> </mtr> </mtable> </mfenced> <mo>;</mo> </mrow>
Wherein L is inductance value, LpFor the equivalent inductance of the first inductance and the second inductance, igTo flow through LpElectric current, LO1For the 3rd electricity Sense and the equivalent inductance of the 4th inductance, io1To flow through LO1Electric current, dig、dio1I is represented respectivelyg, io1Differential, dt is the time Differential, VgInput side voltage;
Wherein, UQ1=VC1g2
By UQ1=VC1g2Bring intoObtain
<mrow> <mfenced open = "{" close = ""> <mtable> <mtr> <mtd> <msub> <mover> <mi>i</mi> <mo>&amp;CenterDot;</mo> </mover> <mi>g</mi> </msub> <mo>=</mo> <mo>-</mo> <mfrac> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>1</mn> </mrow> </msub> <msub> <mi>L</mi> <mi>p</mi> </msub> </mfrac> <msub> <mi>g</mi> <mn>2</mn> </msub> <mo>+</mo> <mfrac> <msub> <mi>V</mi> <mi>g</mi> </msub> <msub> <mi>L</mi> <mi>p</mi> </msub> </mfrac> </mtd> </mtr> <mtr> <mtd> <msub> <mover> <mi>i</mi> <mo>&amp;CenterDot;</mo> </mover> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> <mo>=</mo> <mfrac> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>1</mn> </mrow> </msub> <msub> <mi>L</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mfrac> <mo>(</mo> <mn>1</mn> <mo>-</mo> <msub> <mi>g</mi> <mn>2</mn> </msub> <mo>)</mo> <mo>-</mo> <mfrac> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>2</mn> </mrow> </msub> <msub> <mi>L</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mfrac> </mtd> </mtr> </mtable> </mfenced> <mo>;</mo> </mrow>
Had by Kirchhoff's current law (KCL)dVc1Represent Vc1Differential, dt represent the differential of time, wherein IQ1 =(ig+io1)g2, then
<mrow> <msub> <mover> <mi>V</mi> <mo>&amp;CenterDot;</mo> </mover> <mrow> <mi>C</mi> <mn>1</mn> </mrow> </msub> <mo>=</mo> <mfrac> <msub> <mi>i</mi> <mi>g</mi> </msub> <msub> <mi>C</mi> <mn>1</mn> </msub> </mfrac> <msub> <mi>g</mi> <mn>2</mn> </msub> <mo>-</mo> <mfrac> <msub> <mi>i</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> <msub> <mi>C</mi> <mn>1</mn> </msub> </mfrac> <mrow> <mo>(</mo> <mn>1</mn> <mo>-</mo> <msub> <mi>g</mi> <mn>2</mn> </msub> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
Had by Kirchhoff's current law (KCL)dVc2Represent Vc2Differential, IsRepresent load current,
Then
Take ig,io1,VC1,VC2For state variable, obtain
X represents state space;
Using mean value method, due to g2Only in second stage effectively, the ratio that its effective time accounts for total time is 1-D, and wherein D is The dutycycle of switch, then above formula be changed into:
<mrow> <mover> <mi>x</mi> <mo>&amp;CenterDot;</mo> </mover> <mo>=</mo> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <msub> <mover> <mi>i</mi> <mo>&amp;CenterDot;</mo> </mover> <mi>g</mi> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mover> <mi>i</mi> <mo>&amp;CenterDot;</mo> </mover> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mover> <mi>V</mi> <mo>&amp;CenterDot;</mo> </mover> <mrow> <mi>C</mi> <mn>1</mn> </mrow> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mover> <mi>V</mi> <mo>&amp;CenterDot;</mo> </mover> <mrow> <mi>C</mi> <mn>2</mn> </mrow> </msub> </mtd> </mtr> </mtable> </mfenced> <mo>=</mo> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <mn>0</mn> </mtd> <mtd> <mn>0</mn> </mtd> <mtd> <mrow> <mo>-</mo> <mfrac> <mrow> <mn>1</mn> <mo>-</mo> <mi>D</mi> </mrow> <msub> <mi>L</mi> <mi>p</mi> </msub> </mfrac> </mrow> </mtd> <mtd> <mn>0</mn> </mtd> </mtr> <mtr> <mtd> <mn>0</mn> </mtd> <mtd> <mn>0</mn> </mtd> <mtd> <mfrac> <mi>D</mi> <msub> <mi>L</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mfrac> </mtd> <mtd> <mrow> <mo>-</mo> <mfrac> <mn>1</mn> <msub> <mi>L</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mfrac> </mrow> </mtd> </mtr> <mtr> <mtd> <mfrac> <mrow> <mn>1</mn> <mo>-</mo> <mi>D</mi> </mrow> <msub> <mi>C</mi> <mn>1</mn> </msub> </mfrac> </mtd> <mtd> <mrow> <mo>-</mo> <mfrac> <mi>D</mi> <msub> <mi>C</mi> <mn>1</mn> </msub> </mfrac> </mrow> </mtd> <mtd> <mn>0</mn> </mtd> <mtd> <mn>0</mn> </mtd> </mtr> <mtr> <mtd> <mn>0</mn> </mtd> <mtd> <mfrac> <mn>1</mn> <msub> <mi>C</mi> <mn>2</mn> </msub> </mfrac> </mtd> <mtd> <mn>0</mn> </mtd> <mtd> <mn>0</mn> </mtd> </mtr> </mtable> </mfenced> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <msub> <mi>i</mi> <mi>g</mi> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mi>i</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>1</mn> </mrow> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>2</mn> </mrow> </msub> </mtd> </mtr> </mtable> </mfenced> <mo>+</mo> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <mfrac> <msub> <mi>V</mi> <mi>g</mi> </msub> <msub> <mi>L</mi> <mi>p</mi> </msub> </mfrac> </mtd> </mtr> <mtr> <mtd> <mn>0</mn> </mtd> </mtr> <mtr> <mtd> <mn>0</mn> </mtd> </mtr> <mtr> <mtd> <mo>-</mo> <mfrac> <msub> <mi>I</mi> <mi>s</mi> </msub> <msub> <mi>C</mi> <mn>2</mn> </msub> </mfrac> </mtd> </mtr> </mtable> </mfenced> </mrow>
Because the circuit can be controlled the dutycycle of variable to be D by controller, above formula is turned to:
<mrow> <mover> <mi>x</mi> <mo>&amp;CenterDot;</mo> </mover> <mo>=</mo> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <msub> <mover> <mi>i</mi> <mo>&amp;CenterDot;</mo> </mover> <mi>g</mi> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mover> <mi>i</mi> <mo>&amp;CenterDot;</mo> </mover> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mover> <mi>V</mi> <mo>&amp;CenterDot;</mo> </mover> <mrow> <mi>C</mi> <mn>1</mn> </mrow> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mover> <mi>V</mi> <mo>&amp;CenterDot;</mo> </mover> <mrow> <mi>C</mi> <mn>2</mn> </mrow> </msub> </mtd> </mtr> </mtable> </mfenced> <mo>=</mo> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <mn>0</mn> </mtd> <mtd> <mn>0</mn> </mtd> <mtd> <mrow> <mo>-</mo> <mfrac> <mn>1</mn> <msub> <mi>L</mi> <mi>p</mi> </msub> </mfrac> </mrow> </mtd> <mtd> <mn>0</mn> </mtd> </mtr> <mtr> <mtd> <mn>0</mn> </mtd> <mtd> <mn>0</mn> </mtd> <mtd> <mn>0</mn> </mtd> <mtd> <mrow> <mo>-</mo> <mfrac> <mn>1</mn> <msub> <mi>L</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mfrac> </mrow> </mtd> </mtr> <mtr> <mtd> <mfrac> <mn>1</mn> <msub> <mi>C</mi> <mn>1</mn> </msub> </mfrac> </mtd> <mtd> <mn>0</mn> </mtd> <mtd> <mn>0</mn> </mtd> <mtd> <mn>0</mn> </mtd> </mtr> <mtr> <mtd> <mn>0</mn> </mtd> <mtd> <mfrac> <mn>1</mn> <msub> <mi>C</mi> <mn>2</mn> </msub> </mfrac> </mtd> <mtd> <mn>0</mn> </mtd> <mtd> <mn>0</mn> </mtd> </mtr> </mtable> </mfenced> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <msub> <mi>i</mi> <mi>g</mi> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mi>i</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>1</mn> </mrow> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>2</mn> </mrow> </msub> </mtd> </mtr> </mtable> </mfenced> <mo>+</mo> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <mfrac> <msub> <mi>V</mi> <mi>g</mi> </msub> <msub> <mi>L</mi> <mi>p</mi> </msub> </mfrac> </mtd> </mtr> <mtr> <mtd> <mn>0</mn> </mtd> </mtr> <mtr> <mtd> <mn>0</mn> </mtd> </mtr> <mtr> <mtd> <mo>-</mo> <mfrac> <msub> <mi>I</mi> <mi>s</mi> </msub> <msub> <mi>C</mi> <mn>2</mn> </msub> </mfrac> </mtd> </mtr> </mtable> </mfenced> <mo>+</mo> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <mfrac> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>1</mn> </mrow> </msub> <msub> <mi>L</mi> <mi>p</mi> </msub> </mfrac> </mtd> </mtr> <mtr> <mtd> <mfrac> <msub> <mi>V</mi> <mrow> <mi>C</mi> <mn>1</mn> </mrow> </msub> <msub> <mi>L</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mfrac> </mtd> </mtr> <mtr> <mtd> <mo>-</mo> <mfrac> <mrow> <msub> <mi>i</mi> <mi>g</mi> </msub> <mo>+</mo> <msub> <mi>i</mi> <mrow> <mi>o</mi> <mn>1</mn> </mrow> </msub> </mrow> <msub> <mi>C</mi> <mn>1</mn> </msub> </mfrac> </mtd> </mtr> <mtr> <mtd> <mn>0</mn> </mtd> </mtr> </mtable> </mfenced> <mi>D</mi> <mo>;</mo> </mrow>
In bus type equalising network, battery is connected by equalizing circuit with energy transfer bus, realizes energy in bus and electricity Bi-directional on pond.
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