Displaying 1-7 of 7 results found.
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0, 0, 1, 3, 1, 7, 3, 11, 15, 7, 15, 13, 31, 3, 13, 3, 17, 23, 63, 19, 39, 27, 63, 65, 43, 69, 127, 51, 35, 91, 81, 39, 15, 1, 237, 9, 51, 255, 47, 115, 105, 281, 87, 33, 117, 121, 87, 33, 59, 207, 181, 63, 235, 511, 141, 409, 243, 517, 87, 343, 295, 249, 75, 615, 363
COMMENTS
Except for the first 2 terms, all terms are odd.
PROG
(PARI) lista(nn) = {for (n=1, nn, if (issquare(n) || (!(n%2) && issquare(n/2)), print1(sigma(n) % eulerphi(n), ", "); ); ); }
Balanced numbers: numbers k such that phi(k) ( A000010) divides sigma(k) ( A000203).
+10
93
1, 2, 3, 6, 12, 14, 15, 30, 35, 42, 56, 70, 78, 105, 140, 168, 190, 210, 248, 264, 270, 357, 418, 420, 570, 594, 616, 630, 714, 744, 812, 840, 910, 1045, 1240, 1254, 1485, 1672, 1848, 2090, 2214, 2376, 2436, 2580, 2730, 2970, 3080, 3135, 3339, 3596, 3720, 3828
COMMENTS
If 2^p-1 is prime (a Mersenne prime) then m = 2^(p-2)*(2^p-1) is in the sequence because when p = 2 we get m = 3 and phi(3) divides sigma(3) and for p > 2, phi(m) = 2^(p-2)*(2^(p-1)-1); sigma(m) = (2^(p-1)-1)*2^p hence sigma(m)/phi(m) = 4 is an integer. So for each n, A133028(n) = 2^( A000043(n)-2)*(2^ A000043(n)-1) is in the sequence. - Farideh Firoozbakht, Nov 28 2005
Phi and sigma are both multiplicative functions and for this reason if m and n are coprime and included in this sequence then m*n is also in this sequence. - Enrique Pérez Herrero, Sep 05 2010
There are 544768 balanced numbers < 10^14. - Jud McCranie, Sep 10 2017
REFERENCES
D. Chiang, "N's for which phi(N) divides sigma(N)", Mathematical Buds, Chap. VI pp. 53-70 Vol. 3 Ed. H. D. Ruderman, Mu Alpha Theta 1984.
EXAMPLE
sigma(35) = 1+5+7+35 = 48, phi(35) = 24, hence 35 is a term.
MATHEMATICA
Select[ Range[ 4000 ], IntegerQ[ DivisorSigma[ 1, # ]/EulerPhi[ # ] ]& ]
(* Second program: *)
Select[Range@ 4000, Divisible[DivisorSigma[1, #], EulerPhi@ #] &] (* Michael De Vlieger, Nov 28 2017 *)
PROG
(Magma) [ n: n in [1..3900] | SumOfDivisors(n) mod EulerPhi(n) eq 0 ]; // Klaus Brockhaus, Nov 09 2008
(Python)
from sympy import totient, divisor_sigma
print([n for n in range(1, 4001) if divisor_sigma(n)%totient(n)==0]) # Indranil Ghosh, Jul 06 2017
(Python)
from math import prod
from itertools import count, islice
from sympy import factorint
def A020492_gen(startvalue=1): # generator of terms >= startvalue
for m in count(max(startvalue, 1)):
f = factorint(m)
if not prod(p**(e+2)-p for p, e in f.items())%(m*prod((p-1)**2 for p in f)):
yield m
CROSSREFS
Cf. A000010, A000043, A000203, A000668, A011257, A023897, A133028, A291565, A291566, A292422, A351114 (characteristic function).
Characteristic function of balanced numbers: a(n) = 1 if phi(n) divides sigma(n), otherwise 0.
+10
10
1, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1
COMMENTS
A balanced number k is a number such that phi(k) | sigma(k).
FORMULA
a(n) = c(sigma(n)/phi(n)), where c(n) = 1 - ceiling(n) + floor(n).
MATHEMATICA
a[n_] := Boole[Divisible[DivisorSigma[1, n], EulerPhi[n]]]; Array[a, 100] (* Amiram Eldar, Feb 01 2022 *)
PROG
(Python)
from math import prod
from sympy import factorint
f = factorint(n)
return int(not prod(p*(p**(e+1)-1) for p, e in f.items()) % (n*prod((p-1)**2 for p in f))) # Chai Wah Wu, Feb 01 2022
EXTENSIONS
Data section extended up to a(105) and the name amended with a formula by Antti Karttunen, Jan 01 2023
Numbers k such that sigma(k) == 4 (mod phi(k)).
+10
3
24, 27, 44, 66, 75, 170, 944, 1200, 16064, 260864, 4189184, 17179541504, 274876596224
COMMENTS
a(14) > 10^12. 1125899822956544 and 4611686013058678784 are also terms. - Donovan Johnson, Feb 29 2012
a(14) > 10^13. If 2^j-5 is prime ( A059608) and j > 3, then 2^(j-2)*(2^j-5) is a term. - Giovanni Resta, Mar 29 2020
Smallest m such that sigma(m) == n (mod phi(m)) or 0 if no solution exists.
+10
2
4, 5, 8, 24, 0, 22, 16, 21, 450, 40, 25, 48, 50, 136, 32, 110, 100, 90, 144, 88, 0, 656, 121, 102, 0, 80, 169, 96, 0, 68, 64, 55, 676, 464, 289, 65, 0, 117, 162, 91, 0, 116, 225, 85, 0, 272, 529, 95, 0, 148, 288, 133, 0, 164, 0, 115, 0, 160, 841, 147, 0, 333, 128, 247
COMMENTS
Warning: It is only conjectured that there are no solutions for n such that a(n) = 0. The search for solutions tested all m <= 10^10 for these n.
For odd remainders a(n) is a square or twice a square. See A028982, except terms 1 and 2.
All zeros corresponding to odd terms a(n) with n < 64 confirmed up to m <= 10^24. - Giovanni Resta, Apr 02 2020
FORMULA
a(n) = Min{x; Mod( A000203(x), A000010(x))=n} or 0 if apparently no solutions.
EXAMPLE
For n=4: a(4)=24 since sigma(24)=60, phi(24)=8 and Mod(60, 8)=4.
MATHEMATICA
f[x_] := Mod[DivisorSigma[1, x], EulerPhi[x]] t=Table[0, {100}]; Do[s=f[n]; If[s<101&&t[[s]]==0, t[[s]]=n], {n, 1, 10000000000}];
Distance from sigma(n) to nearest multiple of phi(n).
+10
1
0, 0, 0, 1, 2, 0, 2, 1, 1, 2, 2, 0, 2, 0, 0, 1, 2, 3, 2, 2, 4, 4, 2, 4, 9, 6, 4, 4, 2, 0, 2, 1, 8, 6, 0, 5, 2, 6, 8, 6, 2, 0, 2, 4, 6, 6, 2, 4, 15, 7, 8, 2, 2, 6, 8, 0, 8, 6, 2, 8, 2, 6, 4, 1, 12, 4, 2, 2, 8, 0, 2, 3, 2, 6, 4, 4, 24, 0, 2, 6, 13, 6, 2, 8, 20, 6, 8, 20, 2, 6, 32, 8, 8, 6, 24, 4, 2, 3, 24, 17
COMMENTS
Numbers n such that a(n) <> A063514(n) are 8, 16, 21, 22, 25, 28, 32, 36, 40, 48, 50, 54, 55, 63, 64, 65, 68, 76, 77, 80, ...
Numbers n such that a(n) = 1 are 4, 8, 9, 16, 32, 64, 128, 256, 400, 512, 1024, 2048, 4096, 8192, 16384, ...
FORMULA
a(2^k) = 1 for k > 1.
a(p) = 2 for prime p > 3.
EXAMPLE
a(21) = 4 because sigma(21) = 32 and phi(21) = 12; 12*3 - 32 = 4 is the smallest corresponding distance.
MATHEMATICA
dsp[n_]:=Module[{s=DivisorSigma[1, n], p=EulerPhi[n], m}, m=Floor[s/p]; Abs[ Nearest[ {m*p, (m+1)p}, s]-s]]; Array[dsp, 100][[All, 1]] (* Harvey P. Dale, Apr 29 2018 *)
PROG
(PARI) a(n) = {my(k=0, s=sigma(n), p=eulerphi(n)); while((s+k) % p != 0 && (s-k) % p != 0, k++); k; }
Smallest m such that sigma(m) == 2*n (mod phi(m)) or 0 if no solution exists.
+10
1
1, 5, 24, 22, 21, 40, 48, 136, 110, 90, 88, 656, 102, 80, 96, 68, 55, 464, 65, 117, 91, 116, 85, 272, 95, 148, 133, 164, 115, 160, 147, 333, 247, 212, 145, 243968, 155, 244, 217, 405, 230, 11072, 185, 292, 259, 1184, 205, 237824, 215, 657, 301, 356, 189, 343, 329, 388, 559, 404
COMMENTS
a(221) <= 288230257234804736 = 2^(k-2)*(2^k-443) for k=30. - Michel Marcus, Apr 02 2020
PROG
(PARI) g(n) = my(f=factor(n)); sigma(f) % eulerphi(f);
a(n) = {n *= 2; my(k=1); while (g(k) != n, k++); k; } \\ Michel Marcus, Mar 30 2020
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