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P. Bala, <a href="/A251592/a251592.pdf">Fractional iteration of a series inversion operator</a>
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a(n) = (1/(n+1)) * [x^n] ( 1/(1-x) * (1+x^2)^3 )^(n+1) / (n+1). - Seiichi Manyama, Feb 14 2024
a(n) = [x^n] ( 1/(1-x) * (1+x^2)^3 )^(n+1) / (n+1). - Seiichi Manyama, Feb 14 2024
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a(n) = (1/(n+1)) * Sum_{k=0..floor(n/2)} binomial(3*n+3,k) * binomial(2*n-2*k,n-2*k).