The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A367068 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
Showing entries 1-10 | older changes

A367068

a(n) = ((Sum_{i=1..n} A340510(i))-1)/(n+1).
(history; published version)

#16 by R. J. Mathar at Tue Jan 30 09:58:01 EST 2024

STATUS

editing

approved

#15 by R. J. Mathar at Tue Jan 30 09:57:50 EST 2024

COMMENTS

Is this a duplicate of A005379? For n<=1300 at least a(n)=A005379(n). - R. J. Mathar, Jan 23 30 2024

MAPLE

A367068 := proc(n)

add(A340510(i), i=1..n)-1 ;

%/(n+1) ;

end proc:

seq(A367068(n), n=1..50) ; # R. J. Mathar, Jan 30 2024

STATUS

approved

editing

#14 by R. J. Mathar at Wed Jan 24 05:26:06 EST 2024

STATUS

proposed

approved

#13 by R. J. Mathar at Tue Jan 23 12:34:08 EST 2024

STATUS

editing

proposed

#12 by R. J. Mathar at Tue Jan 23 12:34:05 EST 2024

COMMENTS

Is this a duplicate of A005379? - R. J. Mathar, Jan 23 2024

STATUS

approved

editing

#11 by N. J. A. Sloane at Mon Jan 22 06:34:29 EST 2024

STATUS

proposed

approved

#10 by Alois P. Heinz at Thu Dec 21 14:20:37 EST 2023

STATUS

editing

proposed

#9 by Alois P. Heinz at Thu Dec 21 14:20:32 EST 2023

NAME

a(n) = ((Sum_{i=1..n} A340510(i))-1)/(n+1).

COMMENTS

Define the Avdispahić-Zejnulahi means sequence AZM(k) by a(n) = ((Sum_{i=1..n} b(i))-k)/(n+k). This is the AZM(1) sequence.

STATUS

proposed

editing

#8 by Michel Marcus at Thu Dec 21 13:18:54 EST 2023

STATUS

editing

proposed

#7 by Michel Marcus at Thu Dec 21 13:18:48 EST 2023

NAME

a(n) = ((Sum_{i=1..n} A340510(i))-1)/(n+1)

STATUS

proposed

editing