The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A366268 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
Showing entries 1-10 | older changes

A366268

G.f. A(x) satisfies A(x) = 1 + x + x*A(x)^5.
(history; published version)

#18 by Joerg Arndt at Mon Oct 16 04:31:19 EDT 2023

STATUS

reviewed

approved

#17 by Amiram Eldar at Mon Oct 16 04:14:41 EDT 2023

STATUS

proposed

reviewed

#16 by Michel Marcus at Mon Oct 16 04:04:08 EDT 2023

STATUS

editing

proposed

#15 by Michel Marcus at Mon Oct 16 04:04:06 EDT 2023

LINKS

a(n) = Sum_{k=0..n} binomial(4*k+1,n-k) * binomial(5*k,k)/(4*k+1).

a(n) = A366273(n) + A366273(n-1).

G.f.: A(x) = 1/B(-x) where B(x) is the g.f. of A366366.

FORMULA

a(n) = Sum_{k=0..n} binomial(4*k+1,n-k) * binomial(5*k,k)/(4*k+1).

a(n) = A366273(n) + A366273(n-1).

G.f.: A(x) = 1/B(-x) where B(x) is the g.f. of A366366.

STATUS

approved

editing

#14 by Michael De Vlieger at Tue Oct 10 16:36:47 EDT 2023

STATUS

proposed

approved

#13 by Seiichi Manyama at Tue Oct 10 11:53:03 EDT 2023

STATUS

editing

proposed

#12 by Seiichi Manyama at Tue Oct 10 11:50:00 EDT 2023

CROSSREFS

Cf. A366273, A366366.

#11 by Seiichi Manyama at Tue Oct 10 11:45:45 EDT 2023

LINKS

G.f.: A(x) = 1/B(-x) where B(x) is the g.f. of A366366.

STATUS

approved

editing

#10 by Michael De Vlieger at Fri Oct 06 08:33:52 EDT 2023

STATUS

proposed

approved

#9 by Seiichi Manyama at Fri Oct 06 08:10:55 EDT 2023

STATUS

editing

proposed