The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A357832 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
Showing entries 1-10 | older changes

A357832

a(n) = Sum_{k=0..floor((n-1)/3)} 2^k * |Stirling1(n,3*k+1)|.
(history; published version)

#20 by Alois P. Heinz at Sun Oct 16 16:35:11 EDT 2022

STATUS

proposed

approved

#19 by Jean-François Alcover at Sun Oct 16 09:17:58 EDT 2022

STATUS

editing

proposed

#18 by Jean-François Alcover at Sun Oct 16 09:17:50 EDT 2022

MATHEMATICA

a[n_] := With[{v = 2^(1/3), w = (-1 + Sqrt[3]*I)/2}, Round[(Pochhammer[v, n] + w^2*Pochhammer[v*w, n] + w*Pochhammer[v*w^2, n])/(3*v)]];

Table[a[n], {n, 0, 22}] (* Jean-François Alcover, Oct 16 2022, after 3rd PARI code *)

STATUS

approved

editing

#17 by Michael De Vlieger at Sat Oct 15 08:08:48 EDT 2022

STATUS

reviewed

approved

#16 by Joerg Arndt at Sat Oct 15 05:57:21 EDT 2022

STATUS

proposed

reviewed

#15 by Seiichi Manyama at Sat Oct 15 05:24:04 EDT 2022

STATUS

editing

proposed

#14 by Seiichi Manyama at Sat Oct 15 05:24:01 EDT 2022

CROSSREFS

Cf. A357831, A357833.

STATUS

proposed

editing

#13 by Seiichi Manyama at Sat Oct 15 05:12:28 EDT 2022

STATUS

editing

proposed

#12 by Seiichi Manyama at Sat Oct 15 00:55:37 EDT 2022

FORMULA

a(n) = ( (2^(1/3))_n + + w^2 * (2^(1/3)*w)_n + w * (2^(1/3)*w^2)_n )/(3*2^(1/3)), where (x)_n is the Pochhammer symbol.

#11 by Seiichi Manyama at Sat Oct 15 00:54:24 EDT 2022

FORMULA

a(n) = ( (2^(1/3))_n + + w^2 * (2^(1/3)*w)_n + w * (2^(1/3)*w^2)_n )/(3*2^(1/3, )), where (x)_n is the Pochhammer symbol.