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Revision History for A349300 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
G.f. A(x) satisfies: A(x) = 1 / ((1 + x) * (1 - x * A(x)^4)).
(history; published version)
#18 by Michael De Vlieger at Thu Jun 06 08:24:00 EDT 2024
STATUS

reviewed

approved

#17 by Joerg Arndt at Thu Jun 06 06:13:37 EDT 2024
STATUS

proposed

reviewed

#16 by Peter Bala at Thu Jun 06 05:14:17 EDT 2024
STATUS

editing

proposed

#15 by Peter Bala at Sun Jun 02 06:14:24 EDT 2024
FORMULA

From Peter Bala, Jun 02 2024: (Start)

A(x) = 1/(1 + x)*F(x/(1 + x)^4), where F(x) = Sum_{n >= 0} A002294(n)*x^n.

A(x) = 1/(1 + x) + x*A(x)^5. (End)

KEYWORD

nonn,easy

STATUS

approved

editing

#14 by Alois P. Heinz at Fri Nov 19 07:13:32 EST 2021
STATUS

proposed

approved

#13 by Seiichi Manyama at Fri Nov 19 06:53:59 EST 2021
STATUS

editing

proposed

#12 by Seiichi Manyama at Fri Nov 19 06:35:18 EST 2021
LINKS

Seiichi Manyama, <a href="/A349300/b349300.txt">Table of n, a(n) for n = 0..500</a>

STATUS

approved

editing

#11 by Vaclav Kotesovec at Sun Nov 14 06:20:20 EST 2021
STATUS

editing

approved

#10 by Vaclav Kotesovec at Sun Nov 14 06:11:45 EST 2021
FORMULA

a(n) ~ sqrt(1 - 3*r) / (2 * 5^(3/4) * sqrt(2*Pi*(1+r)) * n^(3/2) * r^(n + 1/4)), where r = 0.136824361675510443450981569282313811786270109272790613523286... is the root of the equation 5^5 * r = 4^4 * (1+r)^4. - Vaclav Kotesovec, Nov 14 2021

STATUS

reviewed

editing

#9 by Joerg Arndt at Sun Nov 14 03:29:13 EST 2021
STATUS

proposed

reviewed