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Revision History for A348598 (Underlined text is an addition; strikethrough text is a deletion.)

Showing entries 1-10 | older changes
A348598 Least prime p of the form k^2+1 such that p == A002496(n) (mod A002496(n+1)) with p>A002496(n), or 0 if no such p exists.
(history; published version)
#54 by Michael De Vlieger at Wed Jun 22 09:25:22 EDT 2022
STATUS

reviewed

approved

#53 by Michel Marcus at Wed Jun 22 09:20:16 EDT 2022
STATUS

proposed

reviewed

#52 by Dumitru Damian at Wed Jun 22 09:06:02 EDT 2022
STATUS

editing

proposed

#51 by Dumitru Damian at Wed Jun 22 09:05:48 EDT 2022
NAME

Least prime p of the form k^2+1 such that such that p == A002496(n) (mod A002496(n+1)) with p>A002496(n), or 0 if no such p exists.

STATUS

approved

editing

#50 by Michael De Vlieger at Thu Mar 24 08:04:17 EDT 2022
STATUS

reviewed

approved

#49 by Michel Marcus at Thu Mar 24 06:35:18 EDT 2022
STATUS

proposed

reviewed

#48 by Michel Lagneau at Thu Mar 24 06:33:29 EDT 2022
STATUS

editing

proposed

Discussion
Thu Mar 24 06:35
Michel Marcus: ok; I get same terms
#47 by Michel Lagneau at Thu Mar 24 06:31:35 EDT 2022
COMMENTS

We state a conjecture which shows that two prime numbers of the form k^2+1 A002496(n) and A002496(n+1) are related to a third prime number p of the same form, p > A002496(n).

STATUS

proposed

editing

Discussion
Thu Mar 24 06:32
Michel Lagneau: Right! Michel. Comments corrected.
#46 by Michel Marcus at Thu Mar 24 04:05:14 EDT 2022
STATUS

editing

proposed

#45 by Michel Marcus at Thu Mar 24 04:04:22 EDT 2022
COMMENTS

Conjecture:: Consider the smallest prime p of the form k^2+1 such that p is congruent to A002496(n) modulo q, q prime of the form m^2+1 > A002496(n). Then q = A002496(n+1).

Consider the smallest prime p of the form k^2+1 such that p is congruent to A002496(n) modulo q, q prime of the form m^2+1 > A002496(n). Then q = A002496(n+1).

Corollary:: For any pair (A002496(n), A002496(n+1)), there exist two integers m, k such that A002496(m) = A002496(n) + k*A002496(n+1), m>n+1 and n=1,2,3,...

For any pair (A002496(n), A002496(n+1)), there exist two integers m, k such that A002496(m) = A002496(n) + k*A002496(n+1), m>n+1 and n=1,2,3,...

STATUS

reviewed

editing

Discussion
Thu Mar 24 04:05
Michel Marcus: I don't see why you need the paragraph: "We state a conjecture .... ", when the Conjecture is stated in the next paragraph ???

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Last modified August 30 00:57 EDT 2024. Contains 375520 sequences. (Running on oeis4.)