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Revision History for A348298 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

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Decimal expansion of imaginary part of the second nontrivial root of sin(z) = z in the first quadrant.
(history; published version)
#8 by N. J. A. Sloane at Mon Oct 11 18:50:53 EDT 2021
STATUS

editing

approved

#7 by N. J. A. Sloane at Mon Oct 11 18:50:51 EDT 2021
NAME

Imaginary Decimal expansion of imaginary part of the second nontrivial root of sin(z) = z in the first quadrant.

STATUS

proposed

editing

#6 by Amiram Eldar at Sun Oct 10 13:22:12 EDT 2021
STATUS

editing

proposed

#5 by Amiram Eldar at Sun Oct 10 13:22:10 EDT 2021
MATHEMATICA

RealDigits[y /. FindRoot[{Re[Sin[x + I*y]] == x, Im[Sin[x + I*y]] == y}, {{x, 14}, {y, 3}}, WorkingPrecision -> 100], 10, 90][[1]] (* Amiram Eldar, Oct 10 2021 *)

STATUS

proposed

editing

#4 by Jianing Song at Sun Oct 10 11:54:35 EDT 2021
STATUS

editing

proposed

#3 by Jianing Song at Sun Oct 10 11:52:21 EDT 2021
COMMENTS

In general, all roots of sin(z) = z are given by z = 0 and z = +-(x_k)+-(y_k)*i, where x_k is the root of cos(x) * sqrt((x/sin(x))^2 - 1) - log(x/sin(x) + sqrt(arccosh(x/sin(x))^2 - 1)) = 0 in the range (2*k*Pi, (2*k+1/2)*Pi), y_k is the positive root of cosh(y) * sqrt(1 - (y/sinh(y))^2) - arccos(y/sinh(y)) = 2*k*Pi.

EXAMPLE

z = 13.8999597139... + 3.3522098848...*i is the unique root of sin(z) = z in the region {z: 4*Pi <= Re(z) < 6*Pi, Im(z) >= 0}.

CROSSREFS

Cf. A348297 (real part), A138282 (real part of the first nontrivial root), A138283 (imaginary part of the first nontrivial root).

#2 by Jianing Song at Sun Oct 10 11:02:59 EDT 2021
NAME

allocated for Jianing SongImaginary part of the second nontrivial root of sin(z) = z in the first quadrant.

DATA

3, 3, 5, 2, 2, 0, 9, 8, 8, 4, 8, 5, 3, 5, 0, 4, 9, 0, 5, 1, 9, 4, 9, 4, 6, 6, 6, 7, 4, 9, 6, 9, 6, 5, 2, 2, 1, 6, 2, 7, 0, 9, 2, 7, 9, 2, 6, 6, 6, 6, 9, 7, 5, 6, 9, 3, 8, 8, 2, 4, 1, 7, 5, 1, 5, 3, 9, 7, 2, 5, 5, 3, 6, 2, 0, 5, 9, 5, 4, 0, 1, 7, 6, 0, 0, 9, 3, 1, 5, 8, 4, 2, 3, 2, 7, 0, 5, 4, 0, 5

OFFSET

1,1

COMMENTS

Positive root of cosh(y) * sqrt(1 - (y/sinh(y))^2) - arccos(y/sinh(y)) = 4*Pi.

In general, all roots of sin(z) = z are given by z = 0 and z = +-(x_k)+-(y_k)*i, where x_k is the root of cos(x) * sqrt((x/sin(x))^2 - 1) - log(x/sin(x) + sqrt((x/sin(x))^2 - 1)) = 0 in the range (2*k*Pi, (2*k+1/2)*Pi), y_k is the positive root of cosh(y) * sqrt(1 - (y/sinh(y))^2) - arccos(y/sinh(y)) = 2*k*Pi.

PROG

(PARI) solve(y=3.3, 3.4, cosh(y) * sqrt(1 - (y/sinh(y))^2) - acos(y/sinh(y)) - 4*Pi)

CROSSREFS

Cf. A138283 (imaginary part of the first nontrivial root).

KEYWORD

allocated

nonn,cons

AUTHOR

Jianing Song, Oct 10 2021

STATUS

approved

editing

#1 by Jianing Song at Sun Oct 10 10:48:36 EDT 2021
NAME

allocated for Jianing Song

KEYWORD

allocated

STATUS

approved