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Revision History for A347793 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

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Intersection of Beatty sequences for 2^(1/3) and 2^(2/3).
(history; published version)
#6 by N. J. A. Sloane at Sat Nov 20 21:25:56 EST 2021
STATUS

proposed

approved

#5 by Michel Marcus at Tue Nov 02 02:33:16 EDT 2021
STATUS

editing

proposed

Discussion
Tue Nov 02
15:19
Clark Kimberling: yes
Mon Nov 15
08:42
Clark Kimberling: ok
#4 by Michel Marcus at Tue Nov 02 02:33:09 EDT 2021
EXAMPLE

a(n) Intersection = (0,1,3,6,7,11,12,...).

STATUS

proposed

editing

Discussion
Tue Nov 02
02:33
Michel Marcus: ok ?
#3 by Clark Kimberling at Mon Nov 01 20:13:39 EDT 2021
STATUS

editing

proposed

#2 by Clark Kimberling at Mon Nov 01 20:13:32 EDT 2021
NAME

allocated Intersection of Beatty sequences for Clark Kimberling2^(1/3) and 2^(2/3).

DATA

0, 1, 3, 6, 7, 11, 12, 15, 17, 20, 22, 23, 25, 26, 28, 30, 31, 34, 36, 39, 41, 42, 44, 46, 47, 49, 50, 52, 55, 57, 60, 61, 65, 66, 68, 69, 71, 73, 74, 76, 79, 80, 84, 85, 88, 90, 93, 95, 98, 100, 103, 104, 107, 109, 112, 114, 115, 117, 119, 120, 122, 123

OFFSET

0,3

COMMENTS

Let d(n) = a(n) - 2n. Conjecture: (d(n)) is unbounded below and above, and d(n) = 0 for infinitely many n.

In general, if r and s are irrational numbers greater than 1, and a(n) is the n-th term of the intersection of the Beatty sequences for r and s, then a(n) = floor(r*ceiling(a(n)/r)) = floor(s*ceiling(a(n)/s)).

EXAMPLE

Beatty sequence for 2^(1/3): (0,1,2,3,5,6,7,8,10,11,...)

Beatty sequence for 2^(2/3): (0,1,3,4,6,7,9,11,12,,...)

a(n) = (0,1,3,6,7,11,12,...).

MATHEMATICA

z = 200; r = 2^(1/3); s = 2^(2/3);

u = Table[Floor[n r], {n, 0, z}]; (* A038129 *)

v = Table[Floor[n s], {n, 0, z}]; (* A347792 *)

Intersection[u, v] (* A347793 *)

CROSSREFS
KEYWORD

allocated

nonn

AUTHOR

Clark Kimberling, Nov 01 2021

STATUS

approved

editing

#1 by Clark Kimberling at Mon Sep 13 17:31:44 EDT 2021
NAME

allocated for Clark Kimberling

KEYWORD

allocated

STATUS

approved