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Revision History for A345242 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

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G.f. A(x) satisfies: A(x) = x + x^2 * exp(4 * Sum_{k>=1} A(x^k) / k).
(history; published version)
#5 by Alois P. Heinz at Fri Jun 11 21:15:36 EDT 2021
STATUS

proposed

approved

#4 by Ilya Gutkovskiy at Fri Jun 11 19:52:51 EDT 2021
STATUS

editing

proposed

#3 by Ilya Gutkovskiy at Fri Jun 11 19:23:35 EDT 2021
NAME

G.f. A(x) satisfies: A(x) = x + x^2 * exp(4 * Sum_{k>=1} A(x^k) / k).

#2 by Ilya Gutkovskiy at Fri Jun 11 19:03:58 EDT 2021
NAME

allocated for Ilya Gutkovskiy

G.f. A(x) satisfies: A(x) = x + x^2 * exp(4 * Sum{k>=1} A(x^k) / k).

DATA

1, 1, 4, 14, 52, 205, 832, 3492, 14960, 65322, 289384, 1298064, 5882712, 26897352, 123919576, 574718308, 2681028168, 12571650355, 59222213028, 280139215118, 1330101884932, 6336757979653, 30282375754944, 145124083402256, 697293746743760, 3358385599930269, 16210842955175380

OFFSET

1,3

FORMULA

G.f.: x + x^2 / Product_{n>=1} (1 - x^n)^(4*a(n)).

a(n+2) = (4/n) * Sum_{k=1..n} ( Sum_{d|k} d * a(d) ) * a(n-k+2).

MATHEMATICA

nmax = 27; A[_] = 0; Do[A[x_] = x + x^2 Exp[4 Sum[A[x^k]/k, {k, 1, nmax}]] + O[x]^(nmax + 1) // Normal, nmax + 1]; CoefficientList[A[x], x] // Rest

a[1] = a[2] = 1; a[n_] := a[n] = (4/(n - 2)) Sum[Sum[d a[d], {d, Divisors[k]}] a[n - k], {k, 1, n - 2}]; Table[a[n], {n, 1, 27}]

CROSSREFS
KEYWORD

allocated

nonn

AUTHOR

Ilya Gutkovskiy, Jun 11 2021

STATUS

approved

editing

#1 by Ilya Gutkovskiy at Fri Jun 11 19:03:58 EDT 2021
NAME

allocated for Ilya Gutkovskiy

KEYWORD

allocated

STATUS

approved