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Revision History for A340675 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Exponential of Mangoldt function conjugated by Tek's flip: a(n) = A225546(A014963(A225546(n))).
(history; published version)
#29 by N. J. A. Sloane at Sun Feb 07 21:14:34 EST 2021
STATUS

proposed

approved

#28 by Antti Karttunen at Sun Feb 07 14:30:37 EST 2021
STATUS

editing

proposed

Discussion
Sun Feb 07
15:38
Peter Munn: @Antti. Thanks. I will look at the new sequences, and the possible relationships you mentioned, tomorrow.
#27 by Antti Karttunen at Sun Feb 07 14:29:19 EST 2021
DATA

1, 2, 2, 4, 2, 2, 2, 1, 4, 2, 2, 1, 2, 2, 2, 16, 2, 1, 2, 1, 2, 2, 2, 1, 4, 2, 1, 1, 2, 2, 2, 1, 2, 2, 2, 4, 2, 2, 2, 1, 2, 2, 2, 1, 1, 2, 2, 1, 4, 1, 2, 1, 2, 1, 2, 1, 2, 2, 2, 1, 2, 2, 1, 1, 2, 2, 2, 1, 2, 2, 2, 1, 2, 2, 1, 1, 2, 2, 2, 1, 16, 2, 2, 1, 2, 2, 2, 1, 2, 1, 2, 1, 2, 2, 2, 1, 2, 1, 1, 4, 2, 2, 2, 1, 2

STATUS

proposed

editing

Discussion
Sun Feb 07
14:30
Antti Karttunen: Please do not abridge such one-digit term sequences (regardless of what there is written about 260 chars in the old style sheet). For 1-digit term sequences, the de-facto standard is 105 terms, 313 characters.
#26 by Metin Sariyar at Sun Feb 07 14:26:23 EST 2021
STATUS

editing

proposed

#25 by Metin Sariyar at Sun Feb 07 14:26:14 EST 2021
DATA

1, 2, 2, 4, 2, 2, 2, 1, 4, 2, 2, 1, 2, 2, 2, 16, 2, 1, 2, 1, 2, 2, 2, 1, 4, 2, 1, 1, 2, 2, 2, 1, 2, 2, 2, 4, 2, 2, 2, 1, 2, 2, 2, 1, 1, 2, 2, 1, 4, 1, 2, 1, 2, 1, 2, 1, 2, 2, 2, 1, 2, 2, 1, 1, 2, 2, 2, 1, 2, 2, 2, 1, 2, 2, 1, 1, 2, 2, 2, 1, 16, 2, 2, 1, 2, 2, 2, 1, 2, 1, 2, 1, 2, 2, 2, 1, 2, 1, 1, 4, 2, 2, 2, 1, 2

STATUS

proposed

editing

#24 by Antti Karttunen at Sun Feb 07 14:15:39 EST 2021
STATUS

editing

proposed

#23 by Antti Karttunen at Sun Feb 07 14:04:35 EST 2021
CROSSREFS

Positions of terms > 1: A340682, of terms > 2: A340674.

Discussion
Sun Feb 07
14:15
Antti Karttunen: Okay, submitted them as  A340681 and A340682 (with you as a co-author). Please do any fine-tuning, for example, the names of them. Meanwhile I push this for proposal.
#22 by Antti Karttunen at Sun Feb 07 13:54:13 EST 2021
CROSSREFS

Positions of 1's: {1} U A340681, 2's: A005117 \ {1}, of 4's: A062503 \ {1}, of 16's: A113849.

#21 by Antti Karttunen at Sun Feb 07 13:22:16 EST 2021
CROSSREFS

Positions of 2's: A005117 \ {1}, of 4's: A062503 \ {1}, of 16's: A113849, A340674 (of terms > 2).

Positions of terms > 2: A340674.

#20 by Antti Karttunen at Sun Feb 07 13:20:28 EST 2021
FORMULA

If A340673(n) = 1, then a(n) = 1, otherwise a(n) = 2^A297108(A340673(n)).

CROSSREFS

Sequences used in a definition of this sequence: A014963, A048298, A225546, A267116, A297108, A340676.

Cf. A051903, A051144, A297108, A331591, A340673.