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Revision History for A338092 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

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a(n) = A337226(A338091(n)); the unique A337226(k) such that A337226(k) = A337226(k + n).
(history; published version)
#10 by N. J. A. Sloane at Tue Oct 13 14:30:24 EDT 2020
STATUS

proposed

approved

#9 by Peter Kagey at Mon Oct 12 17:49:32 EDT 2020
STATUS

editing

proposed

#8 by Peter Kagey at Mon Oct 12 17:48:06 EDT 2020
LINKS

Peter Kagey, <a href="/A338092/b338092.txt">Table of n, a(n) for n = 1..2000</a>

STATUS

approved

editing

#7 by N. J. A. Sloane at Mon Oct 12 14:45:23 EDT 2020
STATUS

proposed

approved

#6 by Peter Kagey at Fri Oct 09 21:19:12 EDT 2020
STATUS

editing

proposed

#5 by Peter Kagey at Fri Oct 09 15:31:38 EDT 2020
EXAMPLE

For n = 6, a(6) = 3 because A337226(5) = A337226(5 + 6) = 23.

Discussion
Fri Oct 09
15:33
Peter Kagey: Maybe something like "The only positive integer that appears exactly n steps after itself in A337226."?
#4 by Peter Kagey at Fri Oct 09 15:31:24 EDT 2020
EXAMPLE

For n = 6, a(6) = 3 because A337226(5) = A337226(5 + 6) = 2.

#3 by Peter Kagey at Fri Oct 09 15:27:20 EDT 2020
FORMULA

a(n) = A337226(A338091(n)).

Discussion
Fri Oct 09
15:27
Peter Kagey: Could I get help with the name from another editor?
#2 by Peter Kagey at Fri Oct 09 15:26:13 EDT 2020
NAME

allocated for Peter Kageya(n) = A337226(A338091(n)); the unique A337226(k) such that A337226(k) = A337226(k + n).

DATA

1, 1, 1, 2, 1, 3, 1, 1, 4, 2, 5, 1, 6, 2, 3, 7, 1, 8, 1, 1, 3, 9, 4, 10, 2, 11, 5, 12, 1, 13, 6, 4, 14, 15, 2, 3, 16, 5, 2, 7, 1, 17, 18, 6, 8, 1, 19, 1, 1, 20, 3, 21, 22, 9, 23, 7, 3, 4, 24, 10, 25, 2, 8, 26, 11, 27, 5, 28, 13, 12, 29, 6, 1, 30, 31, 9, 32, 33

OFFSET

1,4

CROSSREFS
KEYWORD

allocated

nonn

AUTHOR

Peter Kagey, Oct 09 2020

STATUS

approved

editing

#1 by Peter Kagey at Fri Oct 09 14:52:16 EDT 2020
NAME

allocated for Peter Kagey

KEYWORD

allocated

STATUS

approved