The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A328339 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
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A328339

Simple continued fraction expansion of Gamma(exp(gamma)+1).
(history; published version)

#23 by N. J. A. Sloane at Tue Nov 05 10:37:49 EST 2019

STATUS

proposed

approved

#22 by Michel Marcus at Mon Nov 04 13:21:47 EST 2019

STATUS

editing

proposed

#21 by Michel Marcus at Mon Nov 04 13:21:41 EST 2019

PROG

(PARI) contfrac(gamma(exp(Euler)+1)) \\ Michel Marcus, Nov 04 2019

STATUS

proposed

editing

#20 by Daniel Hoyt at Tue Oct 29 20:31:25 EDT 2019

STATUS

editing

proposed

#19 by Daniel Hoyt at Tue Oct 29 20:28:02 EDT 2019

FORMULA

Gamma(exp(gamma)+1) = Gamma(exp(gamma)) / * exp(-gamma).

STATUS

proposed

editing

Discussion

Tue Oct 29

20:31

Daniel Hoyt: Rewritten. Side note: I've found Spouge's approximation the way to go for computing this value. (I do everything manually).

#18 by Daniel Hoyt at Sun Oct 27 17:21:45 EDT 2019

STATUS

editing

proposed

#17 by Daniel Hoyt at Sun Oct 27 17:21:00 EDT 2019

COMMENTS

Gamma(exp(gamma)+1) is equal to exp(gamma)!, where '!' is the factorial function, 'Gamma' is the gamma function, and 'gamma' is the Euler-Mascheroni constant.

Approximation of Gamma(exp(gamma)! +1) in decimal: 1.6501566139104548059...

FORMULA

Gamma(exp(gamma)! +1) = Gamma(exp(gamma)) / exp(-gamma).

STATUS

proposed

editing

#16 by Daniel Hoyt at Sun Oct 27 17:17:30 EDT 2019

STATUS

editing

proposed

#15 by Daniel Hoyt at Sun Oct 27 17:17:06 EDT 2019

NAME

Simple continued fraction expansion of Gamma(exp(gamma)!+1).

#14 by Sean A. Irvine at Sun Oct 27 16:59:46 EDT 2019

STATUS

proposed

editing